RBO and Index access

Similar Questions

• order by clause and index access

  Hi all
  
  I have tried under request.
  
  SELECT e.employee_id, e.department_id
  E EMPLOYEES
  order by 2;
  
  Implementation plan...
  
  SELECT STATEMENT, GOAL = ALL_ROWS 4 107 856
  SORT ORDER BY 4 107 856
  TABLE ACCESS FULL     EMPLOYEES OF HR 3 107 856
  
  Below query Oracle by using the INDEX FULL SCAN. I'm not able to find an appropriate explanation. Pls how me oracle optimizer include order by clause while to fetch documents.
  
  -departmentId has index EMP_DEPARTMENT_IX, which is the normal index.
  
  SELECT e.employee_id, e.department_id
  E EMPLOYEES
  order by 1;
  
  SELECT STATEMENT, GOAL = ALL_ROWS 3 107 856
  TABLE ACCESS BY INDEX ROWID HR 3 107 856
  INDEX FULL SCAN     HR EMP_EMP_ID_PK 1 107
  
  
  Thank you.

  Consolidation of the index factor is used by the CBO to calculate how much is a scan interval index (the one that is followed by a table-access by rowid) for this index will be. The CBO calculates this option to select an index if two or more paths index are available.
  But it could also be used to decide between choosing a full index scan (to honor an order by clause and without having to sort after the scan) in the course of a full table scan that requires an extra sort (in honor of the order by clause) operation.

  There are many articles talking about this:

  http://www.oaktable.NET/category/tags/clustering-factor

  http://Oracle-Randolf.blogspot.com/2010/01/clusteringfactor-what-if-analysis.html

  http://mehrajdba.WordPress.com/2009/02/09/index-clustering-factor/

  I just realized today that in case you described: If department_id column is NULL-able, Oracle cannot use the index in department_id to honor the order by clause, because he would find all the lines (those with an id of NULL service), in this case.

• like clause and index access

  Hi all
  
  I went through the link below for the use of the index while using LIKE operator in SQL.
  [http://laurentschneider.com/wordpress/2009/07/how-to-tune-where-name-likebc.html]
  
  I tried the same approach in the Table Employees, but index not used.
  
  -There is a normal Index on the Job_id found: EMP_JOB_IX.
  
  SQL10.2 > select / * + INDEX (EMP_JOB_IX employees) * / e.job_id, e.first_name
  employees e where e.job_id like '%ABC% ';
  
  -Explain plan
  SELECT STATEMENT, GOAL = 3 5 80 ALL_ROWS
  TABLE ACCESS FULL 3 5 80 HR
  
  Pls know me why it's full table scan. (using version 10.2)
  
  Thank you

  you are the aliasing, try using the name of the table, but don't use do not alias to index...

  select /*+ INDEX(e ,EMP_JOB_IX)*/
  

  Ravi Kumar

• Partitioned Tables and indexes

  Hello
  
  
  I have a question on the table and index partitioning. My scenario is:
  
  Charge 2 mio records in table T once a month. Loaded records are added to existing records, and once loaded data is never changed.
  At some point, I want to delete the older recordings, so I intend to this partition table.
  
  T table looks like:
  

  create table t (id       number(10) not null  constraint t_pk primary key,
                  period   number(10) not null,
                  contract number(10) not null,
                  attr     number(10) not null);
  
  create unique index t_ux1 on t(contract,period);
  
  create index t_ix2 on t(period);

  My plan is to partition T over the period, and I'm trying to read through the concepts
  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14220/partconc.htm#g471747
  
  
  My question is now, how to manage the indexes, the t_pk, the t_ux1 and the t_ix2. Concepts of say,
  
  «1. If the table partitioning column is a subset of index keys, use a local index.»
  
  "2. If the index is unique, use a global index. If this is the case, you are finished. »
  
  
  So, that's how I read it
  -t_pk is unique, so this should be global
  -t_ux1 of columns is a subset, unless I have misunderstood (?), which should be local
  -index t_ix2 column is the same as the partitioning column, so it must be local
  
  Is this right, this t_ux1 should be a local partioned index, even if the period is the second column in the index?
  
  If true, what will happen when a partion fell?
  
  
  I am new in this area, so please feel the comment as you wish.
  
  
  Concerning
  Peter
  
  
  BANNER
  ----------------------------------------------------------------
  Oracle Database 10 g Enterprise Edition release 10.2.0.3.0 - 64bi
  PL/SQL version 10.2.0.3.0 - Production
  CORE Production 10.2.0.3.0
  AMT for IBM/AIX RISC System/6000: Version 10.2.0.3.0 - production
  NLSRTL Version 10.2.0.3.0 - Production

  Peter Gjelstrup wrote:

  My question is now, how to manage the indexes, the t_pk, the t_ux1 and the t_ix2. Concepts of say,

  «1. If the table partitioning column is a subset of index keys, use a local index.»

  "2. If the index is unique, use a global index. If this is the case, you are finished. »

  So, that's how I read it
  -t_pk is unique, so this should be global
  -t_ux1 of columns is a subset, unless I have misunderstood (?), which should be local
  -index t_ix2 column is the same as the partitioning column, so it must be local

  Is this right, this t_ux1 should be a local partioned index, even if the period is the second column in the index?

  A partitioned index locally can only be defined as unique if the partition key is part of the columns in the index. Imagine what the database would have to do if this is not the case: in order to verify if a newly added or updated value violates the uniqueness, it will have to travel all the partitions in a serialized operation - means that no one else could do the same thing at the same time. Since he is a killer of serious scalability in terms of locking and contention, this is not allowed.

  So: Your T_UX1 index can be defined as a unique index that is local because it contains the partition key. Although the index is not prefixed ("Prefix" means that it is divided by the left side of the columns in the index) which means that there may be access patterns where all partitions should be scanned or the optimizer cannot use a method of size of effective partition according to the way the index is reached.

  Your T_PK index cannot be set as local because it must be unique (you can not use a local non-unique index in this case), but does not contain your partition key. It must be a global index. An overall index can be partitioned as well (different from the underlying table) but it doesn't have to be.

  Depends on how you access your data you have not T_IX2 index when partitioning by this key because it corresponds to the partition key and therefore could not actually be used by the mechanism of partition pruning that limit your query to the scores of individuals.

  If you have more than one MAS environment where running queries are used longer, you should be fine with the index the in general (because they could be analyzed in parallel in parallel operations), but if you have an OLTP environment, then you should avoid local no prefix indexes due to the potential problem that you need to analyze all partitions.

  Be borne in mind that with partitioning adds an important layer of complexity to other areas: in particular the options available to the optimizer and analyze cost optimizer statistics. Depends on how you access your statistical data must be maintained on several levels now (level of score and at the global level, in the case of subpartitioning may be still at this level). If your data is important and you rely on "global" level statistics (these are always the case when the optimizer at the time analysis cannot limit access to a single partition) then in the pre - 11 g databases analyze these "global" level statistics can take a lot of time and resources, since actually , you need data several times (once for the partition and even global level).

  Presenting this partitioning may mean other potential problems in terms of execution that change (not for the better sometimes) plans and how to effectively collect statistics. Note that g 11 addresses the issue of 'statistics' by introducing the so-called "extra" global statistics. Greg Rahn wrote a [blog note | http://structureddata.org/2008/07/16/oracle-11g-incremental-global-statistics-on-partitioned-tables/] on this nice feature.

  >

  If true, what will happen when a partion fell?

  Since you're already on 10g, you can specify the database to update the scores of the local index using the UPDATE of the INDEX clause, while 9i could maintain only an overall index and it is up to you to rebuild the local index partitions after the partition DDL on the table (according to the DDL operation).

  Kind regards
  Randolf

  Oracle related blog stuff:
  http://Oracle-Randolf.blogspot.com/

  SQLTools ++ for Oracle (Open source Oracle GUI for Windows):
  http://www.sqltools-plusplus.org:7676 /.
  http://sourceforge.NET/projects/SQLT-pp/

  Published by: Randolf Geist on Sep 30, 2008 16:39

  Added statistics / optimizer warning when you use the partitioning

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  Hello

  Good evening everyone.

  I had a problem in Routing and remote access on windows 2003 server.  This server is already configured as a file server, domain server, and application server. Also configured as a router (thanks to access routing & remote) to connect the three different networks with each other. If this server has three NICs installed and each separate NIC network cards represent.

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  IPv4 routing table
  ===========================================================================
  List of the interface
  0x1 ........................... MS TCP Loopback interface
  0x2... 00 30 05 8f ad 5 c... Broadcom NetXtreme Gigabit Ethernet - Mi Teefer2
  niport
  0 x 3... 0E 00 c4 f8 a7 0c... Network Intel(r) PRO/1000 GT Desktop Adapter - Teefer2 M
  iniport
  0 x 4... 0E 00 0c a7 c5 85... Intel (r) PRO/1000 GT Desktop Adapter #2 - Teefer
  2 miniport
  ===========================================================================
  ===========================================================================
  Active routes:
  Network Destination gateway metric Interface subnet mask
  0.0.0.0 0.0.0.0 192.42.161.112 192.42.161.220 1
  127.0.0.0 255.0.0.0 127.0.0.1 127.0.0.1 1
  192.42.160.0 255.255.255.0 192.42.160.220 192.42.160.220 20
  192.42.160.220 255.255.255.255 127.0.0.1 127.0.0.1 20
  192.42.160.255 255.255.255.255 192.42.160.220 192.42.160.220 20
  192.42.161.0 255.255.255.0 192.42.161.220 192.42.161.220 20
  192.42.161.220 255.255.255.255 127.0.0.1 127.0.0.1 20
  192.42.161.255 255.255.255.255 192.42.161.220 192.42.161.220 20
  192.42.162.0 255.255.255.0 192.42.162.220 192.42.162.220 20
  192.42.162.220 255.255.255.255 127.0.0.1 127.0.0.1 20
  192.42.162.255 255.255.255.255 192.42.162.220 192.42.162.220 20
  224.0.0.0 240.0.0.0 192.42.160.220 192.42.160.220 20
  224.0.0.0 240.0.0.0 192.42.161.220 192.42.161.220 20
  224.0.0.0 240.0.0.0 192.42.162.220 192.42.162.220 20
  255.255.255.255 255.255.255.255 192.42.160.220 192.42.160.220 1
  255.255.255.255 255.255.255.255 192.42.161.220 192.42.161.220 1
  255.255.255.255 255.255.255.255 192.42.162.220 192.42.162.220 1
  Default gateway: 192.42.161.112
  ===========================================================================
  Persistent routes:
  None

  Sorry if I'm not able to explain properly. Please let me know if you have to explain more about it...

  Thank you all.

  Mahesh

  Hello Manu,

  Please post this question in the forums TechNet for Windows Server 2003. They will be able to guide you further.

  http://social.technet.Microsoft.com/forums/WindowsServer/en-us/home

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  The question you posted would be better suited to the MSN support. I suggest you to contact MSN support for assistance.

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  http://support.Microsoft.com/kb/940784
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  Hi budhihartono,

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• I'm going on vacation and need access to my computer then out. How can I do this?

  Original title: remote access

  I'm going on vacation and need access to my computer then out. How can I do this?

  Hello

  Which edition of windows XP you are using?

  See the articles that may be useful.
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