Recovery software data and the partition for Vista?

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• a sentence installed updated software, "OSx recovery software update" and the overview application still refuses to work however I try to launch it. He started and left immediately after recovery immediately, she leaves, she shows also a no document error

  I just installed new updates of software, "OSx recovery software update" and the Preview app still refuses to work, however I try to launch it. He launched and immediately closed unexpectedly after unexpectedly WARNING recovery he immediately left again, it also shows a notice of error document

  Please launch the Console application in one of the following ways:

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  ☞ In the Finder, select go utilities ▹ of menu bar or press the combination of keys shift-command-U. The application is in the folder that opens.

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  Each message in the journal begins with the date and time when it was entered. Select the messages since the time of the last fall, as appropriate. Copy to the Clipboard by pressing Control-C key combination. Paste into a reply to this message by pressing command + V.

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  original title: reorganize the C drive

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  Hello

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  see if this program helps you to determine what is take up space

  http://www.Jam-software.com/treesize_personal/

  by default system restore will have up to 15% of the capacity of the hard disk

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  http://www.Vistax64.com/tutorials/76227-system-restore-disk-space.html

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  http://www.Vistax64.com/tutorials/95418-disk-management-delete-extend.html

• Is no longer, I can download and install the updates for Vista SP2. I get error 80070490

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  Method 1:

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  I understand that you now have returned back to factory settings and have installed all updates except for service packs.

  .

  You will need to install the required service packs-

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  http://support.Microsoft.com/kb/935791

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• Look for the partition for the fact table

  Oracle version: Oracle 10.2
  
  I have a table of facts with daily partitions.
  I'm insertion of test data in this table for the old date 20100101.
  
  I am able to insert that record into this table as below
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  Select * from facT_table partition (d_20100101)
  
  but I am able to extract the data using
  
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  could you get it some please let me know how to find the partition in which these data could be inserted
  and if the partition date 20100101 is not present so why put so that the date doesn't work?

  user507531 wrote:
  However I noticed that the partition for this date does not exist in the table (all_tab_partitions) more I'm not able to select the data using

  Select * from facT_table partition (d_20100101)

  Wrong approach.

  but I am able to extract the data using

  Select * from facT_table where date_id = 20100101

  Correct approach.

  could you get it some please let me know how to find the partition in which these data could be inserted
  and if the partition date 20100101 is not present so why put so that the date doesn't work?

  Who says that the date is invalid. ? It is a partition of the range - which means that each partition covers a range. And if you bothered to read in the SQL Reference Guide on how the definition of a partition of the range, you will notice that each partition is defined with the value end of the range it covers. There is no starting value - as the end of the previous partition is the "+ border +" between this and the previous partition.

  I suggest that before you use a database feature first become familiar you with it. Another evil to use and making assumptions wrong about it, more than likely outcomes.

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  If another location, then Windows uses by default.
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  Hello

  Wow, you have a lot of questions. :) If I was sort of a support guy to it all with such question much. ;)

  No, I'm kidding; with regard to your questions:

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  The max temp is available on the website of intel. I think that the section is called "intel spec finder" or something similar.
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  Welcome them

• I have error code 8024200d when you try to update and install SP1 for Vista

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  Thank you!  Matt

  Matt,

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• Get the updated record the last based on the Date and the van of the user ID corresponding (multiple tables)

  Hello people,

  I currently have a working for this using PL/SQL solution, but it would be nice to have it using SQL. Any help is appreciated and once again, to your practice time.

  I'm looking to pick up the most recent date and the corresponding user that updated registration for a student in particular. There are two tables T1 and T2. The most recent date can be the create_date or modified_date of T1 or T2.

  Scripts for creating the table and INSERT statements:

  create table T1
    ( code           varchar2(4),
      create_date    date,
      create_userid  varchar2(20),
      modified_date  date,
      modify_userid  varchar2(20));
  
  create table T2
    ( code           varchar2(4),
      visit_id       number,
      visit_date     date,
      create_date    date,
      create_userid  varchar2(20),
      modified_date  date,
      modify_userid  varchar2(20));
  
  

  insert into T1 values ('1001',to_date('06-FEB-2013 09:12:12','DD-MON-YYYY HH24:Mi:SS'),'ROGER',to_date('12-APR-2013 13:01:12','DD-MON-YYYY HH24:Mi:SS'),'BRIAN');
  insert into T2 values ('1001',1,to_date('10-JAN-2013','DD-MON-YYYY'), to_date('10-JAN-2013 14:12:12','DD-MON-YYYY HH24:Mi:SS'),'ROGER',to_date('12-MAR-2013 12:01:06','DD-MON-YYYY HH24:Mi:SS'),'AMY');
  insert into T2 values ('1001',2,to_date('31-JAN-2013','DD-MON-YYYY'), to_date('12-MAY-2013 16:11:12','DD-MON-YYYY HH24:Mi:SS'),'GRACIE',null,null);
  
  insert into T1 values ('1002',to_date('12-JAN-2013 11:12:13','DD-MON-YYYY HH24:Mi:SS'),'LYNNELLE',to_date('12-APR-2013 13:01:12','DD-MON-YYYY HH24:Mi:SS'),'BRIAN');
  insert into T2 values ('1002',1,to_date('10-JAN-2012','DD-MON-YYYY'), to_date('10-JAN-2012 09:12:12','DD-MON-YYYY HH24:Mi:SS'),'ROGER',to_date('12-APR-2013 13:04:12','DD-MON-YYYY HH24:Mi:SS'),'AMY');
  insert into T2 values ('1002',2,to_date('10-JAN-2013','DD-MON-YYYY'), to_date('12-JAN-2013 11:12:13','DD-MON-YYYY HH24:Mi:SS'),'JOHN',null,null);
  
  insert into T1 values ('1003', to_date('04-FEB-2014 12:01:01', 'DD-MON-YYYY HH24:Mi:SS'), 'LYNNELLE', null, null);
  
  

  I want to show for the three codes are the following records:

  Code      Table Date                              User ID
  1001      T2  12-MAY-2013 16:11:12   GRACIE
  1002      T2 12-APR-2013 13:04:12   AMY
  1003 T1 04-FEB-2014 12:01:01 LYNNELLE
  
  

  1001 students, the most recent is the create_date of the visit count = 2 for the Code 1002, the most recent date comes from modified_date for visit 1 (its 3 seconds later than the T1 modified_date). Finally, for students 1003 (who did not all records in T2, the create_date is the only date and must be picked up.

  Thanks in advance.

  with t as)

  Select the code,

  NVL (MODIFIED_DATE, create_date) dt.

  case nvl (modified_date, create_date)

  When modified_date then modify_userid

  of other create_userid

  end userid,

  Tbl "T1".

  from t1

  Union of all the

  Select the code,

  NVL (MODIFIED_DATE, create_date) dt.

  case nvl (modified_date, create_date)

  When modified_date then modify_userid

  of other create_userid

  end userid,

  Tbl 'T2 '.

  the t2

  )

  Select the code,

  Max (TBL) keep (dense_rank last order by dt, tbl) tbl.

  Max (DT) dt,

  Max (UserID) keep (dense_rank last order by dt, tbl) userid

  t

  Code group

  order by code

  /

  CODE TO DT USERID
  ---- -- -------------------- --------------------
  1001 T2 MAY 12, 2013 16:11:12 GRACIE
  1002 T2 12 APRIL 2013 13:04:12 AMY
  1003 T1 4 FEBRUARY 2014 12:01:01 MANON

  SQL >

  SY.

• Update of the completion Date and the Date of booking

  I have a question regarding completion dates and the dates of reservation.
  
  If we have an online class that the learner is part of 01/01/2011 and ends on 01/01/2011.
  
  The user then goes back on 01/07/2011 and follows the course again that it does not refresh the completion date.
  
  If a new class is created under the same courses and the same offering and the user is part of the new class it auto fills the date of completion of the previous registration.
  
  How do some work around that?
  
  Thank you!

  Hi Mike,.

  For online courses that are not certifications, the completion date is still on the first date that the user completed the course. Once it's done, it's done, no matter how many times the user going in and going through the content again. You might look attempt data if necessary to see all attempts of the user and the State of each such attempt is "gross" as described by the content.

  What problem are you trying to solve?

  Scott
  http://www.seertechsolutions.com