recursion base (triangles of a single line)

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• converting and application of single line

  Greetings,
  
  The data tables and release date are on the bottom.
  Tables of process contains the id of the base of different dealing with the fabric. 1 single command will have (at most) 2 or 1 process different store (s). Need to create a query list all order no as well as names of processes, work shop. It also requires to convert each numeric field to 0 if the value is null. I was able to create a query as follows but stuck on do not know how the order number listed as single line more this conversion of numeric field when there are 2 different process no.. Can you help me? I know there are a lot of gurus here who can give me a lift. Thank you.
  
  Select
  B.porderno,
  Decode(pprocessno,1,A.Name,null) as '1 storename. "
  Decode(pprocessno,2,A.Name,null) as '2nd storename.
  Decode (pprocessno, 1, NVL(B.PLength,0), null) as "1 length."
  Decode (pprocessno, 2, NVL(B.PLength,0), null) as '2nd length.
  of test_store2 A, test_process B
  where A.storeid = B.pstoreid...
  
  
  
  CREATE TABLE test_store2
  (storeid NUMBER (3.0) not null,)
  (20) is not name VARCHAR2 null,
  addr VARCHAR2 (30) not null
  
  )
  /
  CREATE TABLE test_process
  (porderno NUMBER (10,0) not null,)
  pstoreid number (3.0) not null,
  pprocessno number (3.0) not null,
  PLength number (3.0).
  pwork VARCHAR2 (30)
  
  )
  
  /
  INSERT INTO test_store2 (storeid, name, address)
  VALUES (001, 'papas, 123 route1')
  INSERT INTO test_store2 (storeid, name, address)
  VALUES (002, "tcbi" ', ' st 652 sky ")
  INSERT INTO test_store2 (storeid, name, address)
  VALUES (003, 'tutu club' ', ' 888 grand ave ")
  INSERT INTO test_store2 (storeid, name, address)
  VALUES (004, "stinkys', ' 432 bobo st")
  /
  
  INSERT INTO test_process (porderno, pstoreid, pprocessno, plength, pwork)
  VALUES (811, 2, 1, null, "prepNdye")
  INSERT INTO test_process (porderno, pstoreid, pprocessno, plength, pwork)
  VALUES (811, 1,2,30, "cutting")
  
  INSERT INTO test_process (porderno, pstoreid, pprocessno, plength, pwork)
  VALUES (812, 1,1,10, 'dye')
  
  INSERT INTO test_process (porderno, pstoreid, pprocessno, plength, pwork)
  VALUES (813, 3,1,40, 'preparation')
  INSERT INTO test_process (porderno, pstoreid, pprocessno, plength, pwork)
  VALUES (813, 4.2, null, 'dye')
  /
  Search result page layout
  

  order  1st storename 2nd storename      1st length    2ndlength         1stwork            2nd work
  
  811     tcbi                papas             0             30            prepNdye           trimming
  812     papas                                 10             0            dye
  813     tutu club           stinks            40             0            prep               dye

  Hello

  I wanted to answer the OP, not Florian. I'm sorry.

  In your [last thread | http://forums.oracle.com/forums/message.jspa?messageID=3514404#3514404], we have treated the two stores as if they were in the two tables, using two copies of the test_store2 table.
  We can do the same thing with the process: the two process, as if they were in the two tables, using two copies of the process table.
  Since it may not be a 2nd treatment, the 2nd copy of the table of alternation (and the second copy of the table test_store2, which is distal in relation to it) must be attached to an outside.

  SELECT    p1.porderno
  ,       s1.name          AS "1st storename"
  ,       s2.name          AS "2nd storename"
  ,       NVL (p1.plength, 0)     AS "1st length"
  ,       NVL (p2.plength, 0)     AS "2nd length"
  ,       p1.pwork             AS "1st work"
  ,       p2.pwork             AS "2nd work"
  FROM            test_process     p1
  JOIN            test_store2     s1     ON     p1.pstoreid     = s1.storeid
                             AND     p1.pprocessno     = 1
  LEFT OUTER JOIN     test_process     p2     ON     p1.porderno     = p2.porderno
                                   AND     p2.pprocessno     = 2
  LEFT OUTER JOIN     test_store2     s2     ON     p2.pstoreid     = s2.storeid
  ORDER BY  p1.porderno
  ;
  

  Another approach, since you want to exit with a line by porderno, would be to start by creating a version of the process table that has one line per processid, using GROUP BY, as Florian, and then join two copies of the table of test_sorte2 this result set.

  Published by: Frank Kulash, June 9, 2009 10:45

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