Reg: Doubt dbms_scheduler
Hi Experts,
I have the script below-
(a) Proc_2 uses CREATE_JOB to call proc_1. In this case, I don't see the exit for ' *' and ' =' in my console dbms_output. But, the good works of the Insert (insert only once).
(b) if I Uncomment RUN_JOB, there are 2 INSERTS that passes for the same data, and I can see the outputs ' *' and ' =' in my console output - once printed.
{package_x}
PROC_1 {}
I'm in (slider)
loop
dbms_output.put_line('***');
INSERT INTO table_x values (i.some_value);
dbms_output.put_line('===');
end loop;
commit;
}
proc_2 {}
dbms_scheduler.create_job ('Task1', proc_1);
-/ / dbms_scheduler.run_job ('job1');
}
}
No idea why this phenomenon occurs? I haven't worked a lot with planners, but assumes that CREATE_JOB is called to step (a).
Please notify.
Thank you
-Nordine
(on Oracle 10.2.0.1.0)
No idea why this phenomenon occurs? I haven't worked a lot with planners, but assumes that CREATE_JOB is called to step (a).
Time to read the manual and then, isn't?
RUN_JOB performs the work in an interactive way, by default in your current session. That's why you can see DBMS_OUTPUT buffer.
-Running a task immediately. If use_current_session is TRUE the job is run the
-the user's current session. If use_current_session is set FALSE labor is running the
-background by a slave of dedicated work.
PROCEDURE run_job)
job_name IN VARCHAR2,
use_current_session IN DEFAULT BOOLEANTRUE,
event_message IN SYS. ANYDATA DEFAULT NULL);
CREATE_JOB (assuming you activate it) will submit JOB1 to be run as a background process.
If you call RUN_JOB immediately after, JOB1 still exists in the dictionary (assuming once again it is auto-dropable), and runs a second time.
Tags: Database
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