Replace NULL values with 0 to Pivot

Similar Questions

• Replace the Null values with zero in MDB

  Hello
  
  How can I replace Null values with zero in MDB. I tried NVL (column_name, 0), he said: syntax error.
  
  Thanks for your time and your help.

  Hello

  In the layer of Buisenss you always use IFNULL (column, 0)

  Concerning
  Adil

  Published by: adil.harrab on April 8, 2011 17:33

• Replace NULL values for PIVOT query

  Hello
  
  I'm working a table for sales, for certain values, when now columns, finishing with a null value. How can I handle these values 0 (zeros).
  
  WITH (AS PIVOT_DATA)
  SELECT S.ZONE_CODE, Z.ZONE_NAME, S.YEAR, S.PERIOD, S.SALES
  OF STAT_TABLE_SALES ADV
  AREAS OF JOIN Z ON S.COMP = Z.COMP AND S.ZONE_CODE = Z.ZONE_CODE
  WHERE S.COMP = '001'
  AND S.BRAND_CODE = '001'
  )
  SELECT *.
  OF PIVOT_DATA
  PIVOT)
  SUM (SALES) FOR THE PERIOD (YEAR) TO ((20091),
  (2009,2),
  (2009,3),
  (20094)
  (2009,5),
  (2009,6),
  (2009,7),
  (2009.8),
  (2009,9),
  (2009.10)
  (2009,11),
  (2009.12),
  (2010,1),
  (20102)
  (2010,3),
  (2010,4),
  (2010,5),
  (2010,6),
  (2010.7))
  )
  ORDER BY DESC NULLS LAST 14;
  
  This query returns the following:
  
  COD_ZONA NOM_ZONA 2009_3 2009_2 2009_1
  -------- ------------------------------ ---------------------- ---------------------- --------------------
  01 YEDUSIJH. 1382367.75 1559943.27 1441279.64
  02 C, ASKAK 711897.82 865854,05 1583232.3
  ASDFG 03 130443.03 205409,84 178633.69
  04 OSOIDSD 320118.32 439008,83 409251.18
  05 ODFSDF 300908.21 276301,59 260188.53
  06 CH 242749.65 325196,71 464938.9
  SOA 07 610312.31 606312,93 754569.82
  08 SAN 89426.8 81360,04 61649.27
  09 YP 284487.79 328281,31 267210.85
  10 TC 87043.28 158594,43 85195.8
  11 BAGNN 76778.78 68180,76 118530.04
  12 CRT 122023.7 143442,21 134744.85
  13 ABC 209992.79 196477,03 185222.14
  IDLIB 14
  15 ARE 23870.41 4137,33 16660.53
  
  * These are not all the columns and rows, but it is a piece of what it returns.
  
  How can I replace the NULL values with 0 (zeros).

  Still not sure why nvl shouldn't meet your needs:

  SQL> select ename, nvl (clerk_20, 0) clerk_20, nvl (sal_30, 0) sal_30
    from emp pivot (sum (sal)
             for (job, deptno)
             in ( ('CLERK', 20) clerk_20, ('SALESMAN', 30) sal_30))
  /
  ENAME             CLERK_20          SAL_30
  ---------- --------------- ---------------
  WARD                     0            1250
  JONES                    0               0
  TURNER                   0            1500
  ADAMS                 1100               0
  ALLEN                    0            1600
  SMITH                  800               0
  CLARK                    0               0
  KING                     0               0
  BLAKE                    0               0
  JAMES                    0               0
  FORD                     0               0
  SCOTT                    0               0
  MARTIN                   0            1250
  MILLER                   0               0
  
  14 rows selected.
  

• Need to null values with the values of filling the date before weekend/holidays

  I have a table with a Date column, column Type and rate column.
  
  The problem is when the weekends and holidays, column Type and rate column are null.
  
  I need all null values with the values of Type and fill rate before that date is the weekend and public holidays.
  
  Example:
  
  I have:
  
  RATE OF TYPE DATE
  07/01/2010 4510 PM 3.71
  07/01/2010 CETE28 4.59
  07/01/2010 TIIE28 4.95
  07/02/2010 4510 PM 3.82
  07/02/2010 CETE28 4.63
  07/02/2010 TIIE28 5.11
  * NULL NULL 07/03/2010 *.
  * NULL NULL 07/04/2010 *.
  07/05/2010 4510 PM 3.91
  07/05/2010 CETE28 4.74
  07/05/2010 TIIE28 5.25
  
  Will be:
  
  RATE OF TYPE DATE
  07/01/2010 4510 PM 3.71
  07/01/2010 CETE28 4.59
  07/01/2010 TIIE28 4.95
  07/02/2010 4510 PM 3.82
  07/02/2010 CETE28 4.63
  07/02/2010 TIIE28 5.11
  * 07/03/2010 4510 PM 3.82*
  * 07/03/2010 CETE28 4.63*
  * 07/03/2010 TIIE28 5.11*
  * 07/04/2010 4510 PM 3.82*
  * 07/04/2010 CETE28 4.63*
  * 07/04/2010 TIIE28 5.11*
  07/05/2010 4510 PM 3.91
  07/05/2010 CETE28 4.74
  07/05/2010 TIIE28 5.25
  
  What could I do?

  Hello

  You can use the analytic LAST_VALUE function to get the last day of work before each date into your table. It will be the same as the current day for every day of work.
  Do it a self-join to combine each current line (c) with the last day of work (l):

  WITH     got_last_work_day     AS
  (
       SELECT     dt, type, rate
       ,     LAST_VALUE ( CASE
                      WHEN  type  IS NOT NULL
                      THEN  dt
                     END
                     IGNORE NULLS
                    ) OVER (ORDER BY dt)     AS last_work_day
       FROM     table_x
  )
  SELECT       c.dt, l.type, l.rate
  FROM       got_last_work_day     c
  JOIN       got_last_work_day     l  ON       (    c.dt          = l.dt
                           AND  c.type          = l.type
                           )
                         OR     (    c.last_work_day     = l.dt
                           AND  c.type          IS NULL
                           )
  ORDER BY  c.dt
  ,       l.type
  ;
  

  Among other things, I guess that the type is NULL if (and only if) the line represents a holiday or weekend, and that the combination (dt, type) is uniuqe.

• management of NULL values in a statement PIVOT 11 g

  Hi all
  
  In the following code, how can I get the cell showing 80001_sum_sales for employee 234567 as a zero instead of a NULL value?
  

  with t1 as 
  (
   select 123456 as emp_id, 80000 as category, 10 as sales from dual union all 
   select 123456 as emp_id, 80001 as category, 20 as sales from dual union all
   select 234567 as emp_id, 80000 as category, 10 as sales from dual 
  )
  select *
    from t1 pivot ( sum(nvl(sales,0)) as sum_sales for category in (80000, 80001));

  I tried NVL in various parts of the application, but the problem is that the line does not actually exist to apply the NVL to. I also tried to add another level of subquery factoring to wrap each column in an NVL, something like:
  

  with t1 as 
  (
   select 123456 as emp_id, 80000 as category, 10 as sales from dual union all 
   select 123456 as emp_id, 80001 as category, 20 as sales from dual union all
   select 234567 as emp_id, 80000 as category, 10 as sales from dual 
  ), 
   t2 as (select *
          from t1 pivot ( sum(sales) as sum_sales for category in (80000, 80001)) )
  select emp_id,
         nvl(80000_sum_sales, 0) as "80000"
         nvl(80001_sum_sales, 0) as "80001"
         from t2;

  but Oracle has a problem with the fact that the column name starts with a number and get ORA-00911. Something like:
  

  with t1 as 
  (
   select 123456 as emp_id, 80000 as category, 10 as sales from dual union all 
   select 123456 as emp_id, 80001 as category, 20 as sales from dual union all
   select 234567 as emp_id, 80000 as category, 10 as sales from dual 
  ), 
   t2 as (select *
          from t1 pivot ( sum(sales)  for category in (80000, 80001)) )
  select emp_id,
         nvl(80000, 0) as "80000",
         nvl(80001, 0) as "80001"
         from t2;

  shows just the values 80000 and 80001 rather than actual sales amounts. Unfortunately, my requirement is that these column headers must be digital, as is an interface in another system. I try to avoid a full outer join a list of categories to all employees, as my employee table has 180 m files in there.
  
  Are there SQL gurus out there who can see a way around this problem, before I attempt an outer join complete?
  
  Thank you
  Matt

  Hello

  Try this

  with t1 as
  (
   select 123456 as emp_id, 80000 as category, 10 as sales from dual union all
   select 123456 as emp_id, 80001 as category, 20 as sales from dual union all
   select 234567 as emp_id, 80000 as category, 10 as sales from dual
  ),
   t2 as (select *
          from t1 pivot ( sum(sales)  for category in (80000, 80001)) )
  select emp_id,
         nvl("80000", 0) as "80000",
         nvl("80001", 0) as "80001"
         from t2;
  

  see you soon

  VT

• check NULL values with expressions

  I'm having a problem with an expression that I work with.

  I'm trying to produce a dynamic graph (among other information) that seems to be controlled by a stream - stream artificial is created by a handful of sliders and a wiggle expression.

  The chart is a simple graphic line which works very well. It is created with a null value (MarkPos) that the position is controlled by Captain wiggle expression that I've mentioned before, that follows.

  This next bit is where I have problems:

  I want to score minimum or maximum, the line has reached on the chart by moving a dotted line, one for weak points and the other for the top.

  Focus only on the bottom line;

  I have the following expression associated with the line, which brings together the current position of the value null (MarkPos) and compared with the current position of the line to see if it has all moved further away down, if she has it moving the line to the new pos are lower. However, all that happens is the line following the null value.

  x = thisComp.layer("MarkPos").transform.position.valueAtTime (time) [1];

  y = transform.position.valueAtTime (time) [1];

  z = transform.position.valueAtTime(time-thisComp.frameDuration) [1];

  If (x > y) {}

  [0, x]

  } else {}

  [0, z]

  }

  After a lot of debugging, I now know the issue is with the else statement - what his weight is compensating the to the high movement frame by frame 1 - so how do you define an order of "keep your current position in y ' in this case?

  [0.1] just it back to its original position and it is not possible to just have the ' if(x>y) {[0, x]} "bit without the"else {}.

  Suggestions fo how to fix this, or a better way to do it?

  This should give you the value of y min:

  p = thisComp.layer("MarkPos").transform.position;

  minVal = 999999;

  for (f = timeToFrames (time); f > = 0; f-) {}

  minVal = Math.min (digraph, p.valueAtTime (framesToTime (f)) [1]);

  }

  [value [0], minVal]

  and this should give you the most:

  p = thisComp.layer("MarkPos").transform.position;

  maxVal = - 999999;

  for (f = timeToFrames (time); f > = 0; f-) {}

  maxVal = Math.max (maxVal, p.valueAtTime (framesToTime (f)) [1]);

  }

  [value [0], maxVal]

  Dan

• Replace the NULL value with some characters

  Hi all
  
  I am writing a query to get the name of the contact and the age of a table. the age column has some value, I want these nulls to be replaced by "N/a".
  I user NVL ("age," n/a ")
  
  but it gives an error
  ORA-01722: invalid number
  
  Please suggest.
  
  Thank you

  Hello

  You must convert the age in tank to be replaced by the string of characters in the case opposite number

  Then use this

  select name, nvl(to_char(age),'N/A') from myage;
  

  Concerning

• replace NULL values for not null values prior

  Hi all
  
  I want to set to Null to override value not zero preious available. data are sorted by column Date DT
  

  WITH 
  TEMP AS (SELECT SYSDATE DT, 1005 ID1, NULL ID2 FROM DUAL    
  UNION ALL
  SELECT SYSDATE+1 DT, 1005    , NULL ID2 FROM DUAL
  UNION ALL
  SELECT SYSDATE+2 DT, 1006,    1005 ID2 FROM DUAL
  UNION ALL
  SELECT SYSDATE+3 DT, 1006    , NULL ID2 FROM DUAL
  UNION ALL
  SELECT SYSDATE+4 DT, 1007,    1006 ID2 FROM DUAL
  UNION ALL
  SELECT SYSDATE+5 DT, 1007    , NULL ID2 FROM DUAL
  UNION ALL
  SELECT SYSDATE+6 DT, 1007    , NULL ID2 FROM DUAL
  UNION ALL
  SELECT SYSDATE+7 DT, 1006,    1007 ID2 FROM DUAL
  )
  SELECT * FROM TEMP

  I want the output voltage:

  DT                     ID1      ID2     
  1/6/2012 9:54:11 AM    1005    NULL
  1/7/2012 9:54:11 AM    1005    NULL
  1/8/2012 9:54:11 AM    1006    1005
  1/9/2012 9:54:11 AM    1006    1005
  1/10/2012 9:54:11 AM    1007    1006
  1/11/2012 9:54:11 AM    1007    1006
  1/12/2012 9:54:11 AM    1007    1006
  1/13/2012 9:54:11 AM    1006    1007

  time added so far can be ignored.
  
  Thanks in advance.
  
  ... Vivek

  WITH temp AS (
  SELECT SYSDATE DT, 1005 ID1, NULL ID2 FROM DUAL UNION ALL
  SELECT SYSDATE+1 DT, 1005    , NULL ID2 FROM DUAL UNION ALL
  SELECT SYSDATE+2 DT, 1006,    1005 ID2 FROM DUAL UNION ALL
  SELECT SYSDATE+3 DT, 1006    , NULL ID2 FROM DUAL UNION ALL
  SELECT SYSDATE+4 DT, 1007,    1006 ID2 FROM DUAL UNION ALL
  SELECT SYSDATE+5 DT, 1007    , NULL ID2 FROM DUAL UNION ALL
  SELECT SYSDATE+6 DT, 1007    , NULL ID2 FROM DUAL UNION ALL
  SELECT SYSDATE+7 DT, 1006,    1007 ID2 FROM DUAL
  )
  SELECT dt, id1, last_value(id2 ignore nulls) over(order by dt) as id2
  FROM temp
  ORDER BY dt
  ;
  

• Replace null values

  Under the direction
  
  Published by: user610131 on May 1st, 2009 14:09

  select  case when ltrim(substr(txt,1,1))  is null  or ltrim(substr(txt,2,1)) is null  or ltrim(substr(txt,3,1)) is null
                then 'XXX' else txt  end  txt from t
  /
  

  SQL> with t as ( select ' DD' txt  from dual union all
    2                 select  'S D'  txt  from dual union all
    3                  select 'DD ' from dual )
    4  select  case when ltrim(substr(txt,1,1))  is null  or ltrim(substr(txt,2,1)) is null  or ltrim(
  substr(txt,3,1)) is null
    5                then 'XXX' else txt  end  txt from t
    6  /
  
  TXT
  ---
  XXX
  XXX
  XXX
  
  SQL> 
  

• RTF model - replace null with 0

  Hello
  
  I created an RTF model for burst into BI Publisher. For specific fields I use COUNT/SUM functions, I find here where there is no value returned in a calculation does not return NULL (Blank). Is is possible to replace with 0 instead? I am also using a conditional region where point is equivalent to... and using a COUNT/SUM function to roll up the data.
  
  I just want to replace NULL values with 0
  
  Can anyone help?
  
  Thank you

  Were you able to solve this problem?
  If not send an email with your sample xml and RTF

• PivotTables - replace null with 0

  Hello
  
  I created a PivotTable in summarizing the values against certain categories of responses. There seems to be several blank values summarized, I used the IFNULL expression on both the column in the answers and also layer MDB, I changed the phrase to include IFNULL on the fact column. It has not taken effect, is there another way to fill in NULL values with 0?
  
  Thank you

  Hello

  IFNULL won't work in Pivot.You can use this workaround by Kishore on the link below

  http://bischool.WordPress.com/

  Thank you
  Sandeep

• Fill with the previous 'not null' value ' Null' known values

  Hi all

  I have the following requirement to fill in missing values (null values) with the "Not null" values known previously available.

  Source of the example:

  Emp_Id	Start_Dt	LOC	Comm	Grade
  A101	01/01/2013	NJ	4000	B
  A101	15/03/2013	CA	4800
  A101

  15/05/2013

  3500C

  A101

  25/07/2013

  2500

  A101

  20/12/2013

  NY5800A

  A101

  14/02/2013

  5000

  A101

  20/05/2014

  DC6000A

  A101

  03/06/2014

  3600C

  A102

  24/05/2013

  THE5000A

  A102

  15/12/20134300

  Expected results values in columns LOC and grades:

  Emp_Id	Start_Dt	LOC	Comm	Grade
  A101	01/01/2013

  NJ4000BA101

  15/03/2013

  CA4800BA101

  15/05/2013

  CA3500CA101

  25/07/2013

  CA2500CA101

  20/12/2013

  NY5800AA101

  14/02/2013

  NY5000AA101

  20/05/2014

  DC6000AA101

  03/06/2014

  DC3600CA102

  24/05/2013

  THE5000AA102

  15/12/2013

  THE4300A

  Any suggestions would be helpful.

  Kind regards

  Arun

  Also, I think that this is a case of analytics. Last_value is perhaps the most appropriate function for the given task:

  Select emp_id

  start_dt

  last_value(loc ignore nulls) over (partition by emp_id arrested by start_dt) loc

  comm

  last_value(grade ignore nulls) about category (partition by emp_id arrested by start_dt)

  t

• Replace different values in different cells

  Hello

  I'm new to LabVIEW and work with a tool that retrieves its settings in an Excel file. I need to change these settings in Excel using LabVIEW. The Excel file is formatted as .xls (97-2003 version). The PC has Microsoft Office installed 2013.

  I'm using LabVIEW 2014 (64-bit).

  Task:
  I want to change the values in 3 different cells in an Excel worksheet and save the workbook (not save as).
  The main vi is saved in the library in the zip file, it is called 'change the 3 values in excel.vi '.
  The excel file is fixed separately.
  I don't think that it matters where these cells are in the Excel worksheet, Excel memory seems to remember the selection of cells in all cells but replaces the value with the last mentioned in the last under vi.

  Problem:
  (1) any change of cells to the same value that I set in the third sub vi.
  (2) Excel wonder SaveAs and does save not only on the existing file.
  (3) the Excel application is not closed, but I can't understand why.

  Please advice. Help on all these issues is highly appreciated.

  Thank you!

  Here is how I could do this.  I would use the Report Generation Toolkit (which is included in LabVIEW 2014).  This example is a simplified version of your task-you are given the name of an Excel workbook to change, the index of the worksheet to be used, the cell address Excel (in format Excel, for example, A1, for example) and the value of the cell that you want to insert here.

  

  The first function is the new report, which is a slight misnomer, as we use it as 'Report to replace' wiring on behalf of the State existing and specifying that we hear an Excel report (it opens Excel - if you don't want the workbook to be visible, open it reduced).  We then call get Excel spreadsheet (which is not necessary if we use the first worksheet...).  We use Excel table easy to put the value of the cell in the Excel cell chosedn.  To do this, we first use Excel Excel get a location to convert, say, B3, line/column indexes (B3 = 1, 2) and this group in a Cluster.  We also need to convert the value of the cell in a table 2D what we do by passing through two functions of table build.  Then save us report to the file using the original Excel workbook path and finally alienate us report goes out Excel.

  If you had multiple cells that you want to update, I would like to consolidate Excel cell and cell value in a cluster, build an array of clusters, then put the Excel easy table function in a loop, and do the updates one at a time.

  It should work very quickly - the whole process should take a fraction of a second.

  Bob Schor

• How to replace a. null value in obiee report

  Hi gurus,

  In a single column, we get. as the data, how to replace. with the null value

  Please provide your inputs

  Thank you for your time in advance

  Try it out below mentioned formula.

  REPLACE ('service request'. "RS #"(, '.', '') "

• display of the output cursor empty with null values

  I have the below procedure of the State where he is shown the output to the client.

  The requirement now is if the select statement does not return a value any with the input given then output parameter should see NULL values instead of no line at all.

  
  One method is to get the number of the select query that is written in "open p_out for." And then write the condition as if count is 0 then null other show data.

  Could you please suggest me any other alternative to this.

  Create or replace procedure test (p_empno in number , p_out out sys_refcursor) is
  
  begin
   open p_out for 
   select e.ename, d.deptname, s.sal , p.addr , v.age
    from emp e ,dept d, sal s, padress p , age v
   where e.deptno = d.deptno and d.deptno = s.deptno
   s.sal_id = p.sal_id and p.id = v.id
  and e.empno = p_empno ;
  
   
  exception when others then
   open p_out for 
   select null , null,null,null,null from dual;
  
   
  end test.
  

  Thank you

  Maybe NOT TESTED!

  Select x.ename, x.deptname, x.sal, x.addr, x.age

  of the double

  left outer join

  (select e.ename, d.deptname, s.sal, p.addr, v.age

  from emp e,.

  d Dept,

  SAL s,

  padress p,

  v of the age

  where e.deptno = d.deptno

  and d.deptno = s.deptno

  and s.sal_id = p.sal_id

  and p.id = v.id

  and e.empno = p_empno

  ) x

  1 = 1

  Concerning

  Etbin

  Select x.*

  of the double

  left outer join

  (select *)

  WCP

  where ename = 'ETBIN.

  ) x

  1 = 1

  EMPNO	ENAME	JOB	MGR	HIREDATE	SAL	COMM	DEPTNO
  -	-	-	-	-	-	-	-