Replace the text in the string

I would like to know how I could continue to write something that would allow a string of variable length to replace in a longer string, subject 'inner chain' is bounded by something.

In other words, assume the string is something like

Tiger Woods +15/09/2010+

where the character was more used as a delimiter. I would like to extract this possibility to leave Tiger Woods. I can't do a simple substr, because the string can be

+15/09/2010+ Tiger Woods

. It could even be

Tiger +15/09/2010+ Woods

. Or it could be

Tiger Woods +September 2010+

. In all cases, the correct return is plain Tiger Woods.

Point is, I want to remove everything between the two more brands wherever they appear and return what is left.

I'm guessing that maybe that's a job for regular expressions, but I dread, so yes, because I'm not very good for them!

Any help appreciated, so. :-)

and to be complete - as says hoek - regular expressions can do it well.

SQL> with t as (
  2      select 'Tiger Woods +15/09/2010+' str from dual union
  3      select '+15/09/2010+ Tiger Woods'  from dual union
  4      select 'Tiger +15/09/2010+ Woods' from dual union
  5      select 'Tiger Woods +September 2010+' from dual
  6      )
  7  select regexp_replace(str,'\+.+\+')
  8    from t;

REGEXP_REPLACE(STR,'\+.+\+')
--------------------------------
 Tiger Woods
Tiger  Woods
Tiger Woods
Tiger Woods

4 rows selected.

Although you will notice let outdoor spaces, you can do another to delete extra spaces.

Tags: Database

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Search and replace the string formatting

Hello

I try to do a search and replace the formatting of a string.

In the example, I'm looking for the string 'SUCCESSFUL', but it must also begin by usbflash and some number + PASSED.

I can't get the format to have a number between 1 and 99. The number of replacements should add up to 6 in this case. I tried with \d for any number, and I also tried [1-99].

Make a right-click on the function search and replace the string. There is an option to use regular Expressions. Then give it a try.

EDIT: You need to set the entry replace all to TRUE.

How to replace the string "\" on json webservice?

Hello

I have problem with this json

"{\"search_result\":[{\"name\":\"Mall Summarecon\",\"category\":\"BusinessEntity\",\"id\":\"1\"},{\"name\":\"Bamboo Dim Sum\",\"category\":\"BusinessEntity\",\"id\":\"2\"},{\"name\":\"Dimsum Ceker\",\"category\":\"Item\",\"id\":\"1\"}]}"

I want to replace the string "\".

the json are already working on my app via .cpp file

I already add json.replace on my qml

function simpleSearch(response){
        indicator.stop()
        model.clear()
        console.log("Response: "+response)
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        json = json.replace('\\', ' ') // this is how the way i replace
        if (json == "[]")
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        else
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but still does not work

is there a different way to replace it?

Thank you

Change your simpleSearchFinished as follows

....simpleSearchFinished()
{
    QNetworkReply *reply = qobject_cast(sender());
    if (!reply->error()){
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        response.replace("\\", "");
        if (response.startsWith("\"")){
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        }
        if (response.endsWith("\"")){
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        }
        emit simpleSearchDone(response);
    }else{
        const int httpCode = reply->attribute(QNetworkRequest::HttpStatusCodeAttribute).toInt();
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                "ErrorString" << reply->errorString();
        emit error(httpCode, reply->errorString());
    }
    reply->deleteLater();
    manager->deleteLater();
}

and QML

function simpleSearch(response){
    indicator.stop()
    model.clear()
    var json = JSON.parse(response)
    if (json){ // is VALID/PARSED
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}

As I wrote, it is not a good workaround solution. The best is to send VALID JSON string directly from your server. But it works

Replace the string value of table

with cte as)
Select val '123', 'abwec' double val1
Union of all the
Select "456" val, "mowerw" double val1
Union of all the
Select val '709', 'wkwere' double val1
Union of all the
Select val '078', 'awerwewerwreq' double val1
)
Select * from cte;
-incoming string
"asdasd123ewrwer@87w8eopiu456werwer@asdwer709@ewrwerewrwqqwezxder078 @..."
need to replace like 'abwec' 123 and 456 as "mowerw" and 709 as wkwere and 078 as 'awerwewerwreq '.
How to replace the string value of the string
I'm going to the table which will have mapping information I need to see the incoming string and replace the appropriate value of the val to val1
something like
Of
"asdasd123456werwer@asdwer709@ewrwerewrwqqwezxder078ewrwer@87w8eopiu @..."
TO
"asdasdabwecewrwer@87w8eopiumowerwwerwer@asdwerwkwere@ewrwerewrwqqwezxderawerwewerwreq@..."

By using the TYPE clause.

with cte as

(

Select val '123', 'abwec' double val1

Union of all the

Select "456" val, "mowerw" double val1

Union of all the

Select val '709', 'wkwere' double val1

Union of all the

Select val '078', 'awerwewerwreq' double val1

),

input_tbl

as

(

Select "asdasd123ewrwer@87w8eopiu456werwer@asdwer709@ewrwerewrwqqwezxder078 @..." input_str

of the double

)

Select max (input_str) Dungeon (first order by desc NWR dense_rank) input_str

de)

Select rno, input_str

de)

Select rownum NWR

val

val1

input_str

count (*) over() cnt

from cte

Cross

Join input_tbl

)

model

dimension (NWR)

measures (val, val1, cnt, CAST (input_str AS VARCHAR2 (4000)) input_str)

(

input_str [any] = replace (nvl (input_str [cv () - 1], input_str [cv ()]), val [cv ()], val1 [cv ()])

)

)

Replace the string with the formatted text

Hello all - I'm back to my beloved project...

I want to replace a string by a TextSelction (formatted text) and began with the famous feature of Jang FindAndReplaceString.
Since my replacement comes from another document (sourceDoc), I edited to targetDoc activeDoc and introduced a second document (sourceDoc).
The replacePara actually comes from a stone where he had been placed to avoid switch backwards between the documents in a book (where to find and replace) and source documents. In another function, I learned that information on the table requires the sourceDoc must remain open.

Of course, everything works fine until I want to insert the replacelement:
erase line 26 is the string
Given that I do not insert a string, I skip lines 28 and 29 and try try line 30
On line 30 DocumentSource is Document object and replacePare object TextSelection. However, sourceDoc.replacePara is not set and
(as a result?) line 31 past the current contents of the Clipboard.

Of course, there is a fog around me... and I need some sunshine.

function FindAndReplacePara (targetDoc, findString, sourceDoc, replacePara, loopMax) {
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  var restoreTR, frame = 0, loopCounter = 0, replacementCounter = 0;
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  var firstPgf = targetDoc.MainFlowInDoc.FirstTextFrameInFlow.FirstPgf;
  
  tr.beg.obj = tr.end.obj = firstPgf;             //  set up the starting text range as the very beginning
  tr.beg.offset = tr.end.offset = 0;              // of the flow. We'll move straight from beginning to end.
  trSaved = tr                                    // to come back after work

  findParams = AllocatePropVals(2);
  
  findParams[0].propIdent.num = Constants.FS_FindText;
  findParams[0].propVal.valType = Constants.FT_String;
  findParams[0].propVal.sval = findString;
  
  findParams[1].propIdent.num = Constants.FS_FindCustomizationFlags;
  findParams[1].propVal.valType = Constants.FT_Integer;
  findParams[1].propVal.ival = Constants.FF_FIND_CONSIDER_CASE;

  FA_errno = Constants.FE_Success;                // errno global, to be used to track the progress of the find and replace
  tr = targetDoc.Find(tr.beg, findParams);        // and do an initial find to get started.
  
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    targetDoc.Clear(0);                           // clear it
    
//    targetDoc.AddText(tr.beg, replacePara);       // insert the new text at the original beginning of the text range
//    tr.beg.offset += replacePara.length;          //  lets jimmy the text range in memory to place it directly after
    targetDoc.TextSelection = sourceDoc.replacePara;        // paste the whole replacement paragraph
    targetDoc.Paste (0);                          // <-- Current contents of clipboard is pasted !!!!
    if(FA_errno === Constants.FE_Success) {       // increment our return counter
      replacementCounter++;
    }
    FA_errno = Constants.FE_Success;              // ...  find the next instance. We'll reset FA_errno again just in case
    tr = targetDoc.Find(tr.beg, findParams);      // something screwy happened while we were replacing text.
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  targetDoc.ScrollToText(trSaved);                // we're done. Restore the document to it's original area of display
  return replacementCounter;
} // --- end FindAndReplacePara

Hi Klaus,

Thanks for the explanation. I remember something like that GetTabRange of the way back. You have been quite patient and persistent with this project, indeed.

So, as we are dealing with ranges of text here, I think that the only simple approach is to perform a copy and paste. There is no way to save a 'formatted' in a variable. The only super precise way would be to get a data structure of each text range TextItems in the sourceDoc, then meticulously recreate every element of the targetDoc. It would be very complicated, I think, so copy and paste seems the most logical. I wonder, though, if Miss me something, because I think that maybe you would have tried already so yes (?)

In any case, I would do something like that, from line 30 of your original code sample (code untested here):

App. ActiveDoc = sourceDoc;

sourceDoc.TextSelection = replacePara;

sourceDoc.Copy (0);

App. ActiveDoc = targetDoc;

targetDoc.Paste (0);

... etc.

Does make sense, or am I barking the wrong tree, as they say?

Russ

Replace the strings inside SWF's AS2/3

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I tried a few solutions, including FLASM (only works on AS2) and others don't bother naming such that they are no longer capable of displaying the AS3 code and not edit or replacement of classes.

I'm not 'try' anything. I inform you of your options.

If you do not find the source files and that you can not use a decompiler, you cannot change the source code.

Find and replace the string function replaces line breaks when I only replaced spaces?

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I use the regular expression [\s]+ and it works, but it is also to replace the end of lines (\r\n) too.

How can I replace the spaces but leave the end of the lines intact?

Right-click on the search string and to take '-' code display. Enter the space character (\s) correctly - you \\s right now.

Search and replace the string in a column

Hello

In the table the data stored with "" (double quotes), I need to remove these quotes please suggest me how to remove

Select the address of TECH_SOURCING_EMPLOYEE_DETAILS

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Thank you
Sudhir

Hello

UPDATE to modify existing rows in a table
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UPDATE     tech_sourcing_employee_details
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{code}

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Like this?
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Replace the string in BPEL
Hey all,.

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I have almost finished a project, (a software to manage the booking of hotel rooms and a database of passengers).

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Hi all
I need like below. FONT-FAMILY string twice, repeat with the lowercase and uppercase, highlited blue color.
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Like this?

SQL > ed
A written file afiedt.buf

1 with t as (select"

= "" color: #ff0000; "> it is arial black14pt"
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Replace the string, each value should double quotes around it
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dog, cat, john, mark

I would like to:

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Thank you

-weStsIdE
Hello

I answered my own question. Well nice for someone else. The function ListQualify will insert what you need before and after each element of individual list.

Actually powerful enough that you can just insert double quotation marks, for example around channels and leave intact numeric values.

-weStSidE

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Hi all
I use the oracle version below:
12 c Oracle database Release 12.1.0.1.0 - 64 bit Production
PL/SQL Release 12.1.0.1.0 - Production
CORE Production 12.1.0.1.0
AMT for Linux: Version 12.1.0.1.0 - Production
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I have a string like:
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something like:

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/

?

HTH

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Concerning

possible alternatives

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In your web.xml file, you have:

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Replace the text in the string

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