Reset point
Performing a reset to an earlier date for a fix, I constantly get a message telling me to reinstall the breakpoint as a mistake as due
. How can I do this?
Try a restore of the system to the restore point just before the one you used the first time and see if that solves the problem.
I hope this helps.
Good luck!
Lorien - MCSA/MCSE/network + / has + - if this post solves your problem, please click the 'Mark as answer' or 'Useful' button at the top of this message. Marking a post as answer, or relatively useful, you help others find the answer more quickly.
Tags: Windows
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------------------------
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I have a Nvidia 9500 GT vidocard in my pc running Windows 64-bit edition and do not use the pc for gaming.
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Hi, I write a code to make a QR code.
First, I write using selection... it's the relevant part:
for (var iy = 0; iy < riga; iy ++) {//riga is the number of modules in a row of the QR
for (ix var = 0; ix < riga; ix ++) {//QR is a square modules, even in columns
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var _x = ix * s; s is the size of the qr code squares little unit, in this case, its value is 8 pixel
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[_x + s + x, FLF + s + y],
[_x + s + x, FLF + 0 + y]
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Add to selection
MyDoc.Selection.Select (selectedRegion, SelectionType.EXTEND);
}
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}
Fill the selection with a solid color
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This work, but is very slow because it must create a selection square for more than 3000 times.
Now, I am using path and all the way of the Fund before this drawing in the document.
This is the code, but none work
/* lineArray var = []; arrn var = 0 for (iy = 0; iy < riga; iy ++) {}
for (ix var = 0; ix < riga; ix ++) {} If (qrcode [ix] [iy] == true) {} var _x = ix * s; FLF var = iy * s; for (i = 0; i < 4; i ++) {} Alert (IX) Alert (i) lineArray [arrn + i] = new PathPointInfo; [arrn + i] .kind lineArray = PointKind.CORNERPOINT; {Switch (i)} case 0: lineArray [arrn + i] .anchor = [parseInt (x + _x), parseInt (y + FLF)]; break; case 1: lineArray [arrn + i] .anchor = [parseInt (x + _x), parseInt (FLF, y + s)]; break; case 2: lineArray [arrn + i] .anchor = [parseInt (x + _x + s), parseInt (FLF, y + s)]; break; box 3: lineArray [arrn + i] .anchor = [parseInt (x + _x + s), parseInt (y + FLF)]; break; } Alert (lineArray [arrn + i]. Anchor) lineArray [arrn + i] .leftDirection = .anchor lineArray [arrn + i]; lineArray [arrn + i] .rightDirection = .anchor lineArray [arrn + i]; } Alert (arrn) arrn = arrn + 4; } } } var lineSubPathArray = new SubPathInfo();
lineSubPathArray.closed = true;
lineSubPathArray.operation = ShapeOperation.SHAPEADD;
lineSubPathArray.entireSubPath = lineArray;
var myPathItem = mydoc.pathItems.add ("myPath", [lineSubPathArray]) ;*/
the error is invalid parameter in the last line. I know that it is incomplete because the diagonal lines of one square to the other...
I just want to know if it is possible, or if you have an idea to make this generation of qr code faster... whit any method
Sorry for my bad English!
I answer myself.
This work very well
//Script by [email protected] //This script draw a QR code whit path //QR code matrix is generated by "qrcode.js" included script, search it whit google #include "includes/qrcode.js" var mydoc = app.documents.add( 600, 600, 72, "tmp", NewDocumentMode.RGB, DocumentFill.WHITE ); var bianco = new SolidColor; bianco.rgb.red = 255; bianco.rgb.green = 255; bianco.rgb.blue = 255; bianco.rgbcol = new RGBColor; bianco.rgbcol.hexValue = "FFFFFF"; var nero = new SolidColor; nero.rgb.red = 0; nero.rgb.green = 0; nero.rgb.blue = 0; nero.rgbcol = new RGBColor; nero.rgbcol.hexValue = "000000"; // FOR TESTING CLEAR DOCUMENT EVERY TEST /* mydoc.pathItems.removeAll(); mydoc.selection.selectAll(); mydoc.selection.fill(bianco.rgbcol,ColorBlendMode.NORMAL); mydoc.selection.deselect();*/ function disegnaQR(x,y,dim,contenuto){ //DRAW QR FUNCTION var qr = new QRCode(-1, QRErrorCorrectLevel.L) qr.addData(contenuto); qr.make(); var qrcode = qr.modules; //qrcode is the matrix array of modules (squares) of QR. Values of modules can be false if white, true if black. var rs = parseInt(qrcode.length*qrcode.length); //Total number of modules var riga = Math.floor(qrcode.length) //modules in a row var s = Math.floor((mydoc.width/riga)); //s is the value of every square of the qr in points unit. Path works only in points var PPI = new Array(); //array of all qr paths point. Is an Array of closed paths. var puntiFatti = new Array(); //array of points already done by the script var punt = 0 //counter for PPI points, it reset every time a path is closed var numPath = 0; //counter for PPI closed paths var lineSubPathArray = new Array() //the array formatted for create every single subpath for (iy = 0; iy < riga+1; iy++) { //for loop for assign false value to every element of "puntifatti". It become a void clone of qrcode. puntiFatti[iy] = new Array for (var ix = 0; ix < riga+1; ix++){ puntiFatti[iy][ix] = false } } for (var iy = 0; iy < riga; iy++) { //Loop trought all value of qr code column for (var ix = 0; ix < riga; ix++){ //Loop trought all value of qr code row bordo = calcolaBordo(ix,iy,riga); //"calcolabordo" function return where every square [ix,iy] is situated: if is at one border or at an angle. //It need for assign "false" value to square near the points that is not into the qrcode matrix. Example, first point in the top left //of the qr code, is surrounded by only 1 square, the first top left. The function "combinazione" need to know the pattern of //all 4 square that surrounding every point; by the result of calcolabordo, function "combinazione" assign false to the "virtual" squares //bottom left, top left and top right because qrcode has not that value (qrcode[-1,0],qrcode[-1,-1],qrcode[-1,0]). controlloPrimo = combinazione (ix, 0, iy, 0, bordo, qrcode, false); //combinazione function returns the direction of the path calculated from the pattern of 4 modules (squares) //around the point iy,ix if (qrcode[ix][iy] == true && puntiFatti[ix][iy] == false//if the module value is true (black square), if it is not done (var puntiFatti), && controlloPrimo != "bianco" && controlloPrimo != "no"){//if around the point there are not 4 black square or 4 white square. (sorry for "no" instead "nero" :) PPI[numPath] = new Array(); //declares that PPI[numPath] is an array var _x = (ix * s) + x; //move the start point of this module from the left var _y = (iy * s) + y; //move the start point of this module from the right var partenzax = _x; //save the first point x (is used for determinate when path is closed) var partenzay = _y; //save the first point y (is used for determinate when path is closed) PPI[numPath][punt] = new PathPointInfo; //create first point of the "numPath" path in the PPI array PPI[numPath][punt].kind = PointKind.CORNERPOINT; //create first point of the "numPath" path in the PPI array PPI[numPath][punt].anchor = [_x,_y]; //create first point of the "numPath" path in the PPI array PPI[numPath][punt].leftDirection = PPI[numPath][punt].anchor;//create first point of the "numPath" path in the PPI array PPI[numPath][punt].rightDirection = PPI[numPath][punt].anchor;//create first point of the "numPath" path in the PPI array puntiFatti[ix][iy] = true; //save the first point as done punt++; //increase point counter of PPI var xt = 0; //used in the while loop that follow the path around all black square. increase if direction is right, decrease if direction is left var yt = 0; //used in the while loop that follow the path around all black square. Increase if direction is down, decrease if direction is up var direzione = null; var chiuso = false; while(chiuso == false){ //while the path is not closed bordo = calcolaBordo(ix+xt,iy+yt,riga); direzione = combinazione(ix,xt,iy,yt,bordo,qrcode,false) switch(direzione){ //this switch make every point of the path only if there is an angle. In this mode path has a lot less points case "no": puntiFatti[ix+xt][iy+yt] = true; //This situation never occurs, but i add just for the devil :D chiuso = true; //end the while loop PPI.splice(punt-1, 1); //remove last point (the first path point) break; case "su": //case direction is up var ultimaDirezione = "su"; //ultimaDirezione (lastdirection) is used in particular cases. bordo = calcolaBordo(ix+xt,iy+yt-1,riga); prossimaDirezione = combinazione(ix,xt,iy,yt,bordo,qrcode,direzione); //this go look the next direction to decide if make a point or not if(prossimaDirezione == "su"){ //if the next direction is up again puntiFatti[ix+xt][iy+yt-1] = true;//save the point as don but dont make it yt = yt -1; //move the point to analyze } else{ PPI[numPath][punt] = new PathPointInfo; //create the point PPI[numPath][punt].kind = PointKind.CORNERPOINT; PPI[numPath][punt].anchor = [_x+(xt*s),_y+(yt*s)-s]; //position x,y-1 PPI[numPath][punt].leftDirection = PPI[numPath][punt].anchor; PPI[numPath][punt].rightDirection = PPI[numPath][punt].anchor; punt++; puntiFatti[ix+xt][iy+yt-1] = true;//save the point as done yt = yt - 1; } break; case "dx": //case direction is right var ultimaDirezione = "dx"; bordo = calcolaBordo(ix+xt+1,iy+yt,riga); prossimaDirezione = combinazione(ix,xt,iy,yt,bordo,qrcode,direzione); if(prossimaDirezione == "dx"){ puntiFatti[ix+xt+1][iy+yt] = true; xt = xt + 1; } else{ PPI[numPath][punt] = new PathPointInfo; PPI[numPath][punt].kind = PointKind.CORNERPOINT; PPI[numPath][punt].anchor = [_x+(xt*s)+s,_y+(yt*s)]; PPI[numPath][punt].leftDirection = PPI[numPath][punt].anchor; PPI[numPath][punt].rightDirection = PPI[numPath][punt].anchor; punt++; puntiFatti[ix+xt+1][iy+yt] = true; xt = xt + 1; } break; case "sx": //case direction is left var ultimaDirezione = "sx"; bordo = calcolaBordo(ix+xt-1,iy+yt,riga); prossimaDirezione = combinazione(ix,xt,iy,yt,bordo,qrcode,direzione); if(prossimaDirezione == "sx"){ puntiFatti[ix+xt-1][iy+yt] = true; xt = xt - 1; } else{ PPI[numPath][punt] = new PathPointInfo; PPI[numPath][punt].kind = PointKind.CORNERPOINT; PPI[numPath][punt].anchor = [_x+(xt*s)-s,_y+(yt*s)]; PPI[numPath][punt].leftDirection = PPI[numPath][punt].anchor; PPI[numPath][punt].rightDirection = PPI[numPath][punt].anchor; punt++; puntiFatti[ix+xt-1][iy+yt] = true; xt = xt - 1; } break; case "giu": //case direction is down var ultimaDirezione = "giu"; bordo = calcolaBordo(ix+xt,iy+yt+1,riga); prossimaDirezione = combinazione(ix,xt,iy,yt,bordo,qrcode,direzione); if(prossimaDirezione == "giu"){ puntiFatti[ix+xt][iy+yt+1] = true; yt = yt + 1; } else{ PPI[numPath][punt] = new PathPointInfo; PPI[numPath][punt].kind = PointKind.CORNERPOINT; PPI[numPath][punt].anchor = [_x+(xt*s),_y+(yt*s)+s]; PPI[numPath][punt].leftDirection = PPI[numPath][punt].anchor; PPI[numPath][punt].rightDirection = PPI[numPath][punt].anchor; punt++; puntiFatti[ix+xt][iy+yt+1] = true; yt = yt + 1; } break; case "sugiu": //case direction is up/down... hard to explain. Often the pattern has, in clockwise order, black white black white square. //in this cases "ultimaDirezione" is used to know the next direction. switch(ultimaDirezione){ case "dx": var ultimaDirezione = "giu"; bordo = calcolaBordo(ix+xt,iy+yt+1,riga); prossimaDirezione = combinazione(ix,xt,iy,yt,bordo,qrcode,ultimaDirezione); if(prossimaDirezione == "giu"){ puntiFatti[ix+xt][iy+yt+1] = true; yt = yt + 1; } else{ PPI[numPath][punt] = new PathPointInfo; PPI[numPath][punt].kind = PointKind.CORNERPOINT; PPI[numPath][punt].anchor = [_x+(xt*s),_y+(yt*s)+s]; PPI[numPath][punt].leftDirection = PPI[numPath][punt].anchor; PPI[numPath][punt].rightDirection = PPI[numPath][punt].anchor; punt++; puntiFatti[ix+xt][iy+yt+1] = true; yt = yt + 1; } break; case "sx": var ultimaDirezione = "su"; bordo = calcolaBordo(ix+xt,iy+yt-1,riga); prossimaDirezione = combinazione(ix,xt,iy,yt,bordo,qrcode,ultimaDirezione); if(prossimaDirezione == "su"){ puntiFatti[ix+xt][iy+yt-1] = true; yt = yt -1; } else{ PPI[numPath][punt] = new PathPointInfo; PPI[numPath][punt].kind = PointKind.CORNERPOINT; PPI[numPath][punt].anchor = [_x+(xt*s),_y+(yt*s)-s]; PPI[numPath][punt].leftDirection = PPI[numPath][punt].anchor; PPI[numPath][punt].rightDirection = PPI[numPath][punt].anchor; punt++; puntiFatti[ix+xt][iy+yt-1] = true; yt = yt - 1; } break; } break; case "sxdx": switch(ultimaDirezione){ case "su": var ultimaDirezione = "dx"; bordo = calcolaBordo(ix+xt+1,iy+yt,riga); prossimaDirezione = combinazione(ix,xt,iy,yt,bordo,qrcode,ultimaDirezione); //va a vedere la prossima direzione if(prossimaDirezione == "dx"){ //se la direzione prevista per il prossimo punto è sempre dx puntiFatti[ix+xt+1][iy+yt] = true;//salva il punto come fatto e non lo scrive xt = xt + 1; } else{ PPI[numPath][punt] = new PathPointInfo; //fa il puntio PPI[numPath][punt].kind = PointKind.CORNERPOINT; PPI[numPath][punt].anchor = [_x+(xt*s)+s,_y+(yt*s)]; //posizione x+1,y PPI[numPath][punt].leftDirection = PPI[numPath][punt].anchor; PPI[numPath][punt].rightDirection = PPI[numPath][punt].anchor; punt++; puntiFatti[ix+xt+1][iy+yt] = true;//salva il punto come fatto xt = xt + 1; } break; case "giu": var ultimaDirezione = "sx"; bordo = calcolaBordo(ix+xt-1,iy+yt,riga); prossimaDirezione = combinazione(ix,xt,iy,yt,bordo,qrcode,ultimaDirezione); if(prossimaDirezione == "sx"){ bordo = calcolaBordo(ix+xt+1,iy+yt+1,riga); switch(bordo){ //this is a special case.... very very hard to explain. it happend whe there are a single black square //bottom right where the path go down then go left. Without this switch the single square topleft point //become done and then, when the iy,ix value is thath square, the script jump it because its done.... //sorry is difficult to explain in english!! Leave this switch and see what append :D case "dx": if(qrcode[ix+xt][iy+yt] == true && qrcode[ix+xt][iy+yt+1] == false){ puntiFatti[ix+xt][iy+yt] = false; } break; case "giu": if(qrcode[ix+xt][iy+yt] == true && qrcode[ix+xt+1][iy+yt] == false){ puntiFatti[ix+xt][iy+yt] = false; } break; case "dxgiu": if(qrcode[ix+xt][iy+yt] == true){ puntiFatti[ix+xt][iy+yt] = false; } break; default: if(qrcode[ix+xt][iy+yt] == true && qrcode[ix+xt][iy+yt+1] == false && qrcode[ix+xt+1][iy+yt] == false){ puntiFatti[ix+xt][iy+yt] = false; } break; } puntiFatti[ix+xt-1][iy+yt] = true; xt = xt - 1; } else{ PPI[numPath][punt] = new PathPointInfo; PPI[numPath][punt].kind = PointKind.CORNERPOINT; PPI[numPath][punt].anchor = [_x+(xt*s)-s,_y+(yt*s)]; PPI[numPath][punt].leftDirection = PPI[numPath][punt].anchor; PPI[numPath][punt].rightDirection = PPI[numPath][punt].anchor; punt++; bordo = calcolaBordo(ix+xt+1,iy+yt+1,riga); switch(bordo){ case "dx": if(qrcode[ix+xt][iy+yt] == true && qrcode[ix+xt][iy+yt+1] == false){ puntiFatti[ix+xt][iy+yt] = false; } break; case "giu": if(qrcode[ix+xt][iy+yt] == true && qrcode[ix+xt+1][iy+yt] == false){ puntiFatti[ix+xt][iy+yt] = false; } break; case "dxgiu": if(qrcode[ix+xt][iy+yt] == true){ puntiFatti[ix+xt][iy+yt] = false; } break; default: if(qrcode[ix+xt][iy+yt] == true && qrcode[ix+xt][iy+yt+1] == false && qrcode[ix+xt+1][iy+yt] == false){ puntiFatti[ix+xt][iy+yt] = false; } break; } puntiFatti[ix+xt-1][iy+yt] = true; xt = xt - 1; } break; } break; } if(xt==0 && yt==0){chiuso = true; ultimaDirezione = "su";} //when xt and yt return to 0 the path is closed. "ultimaDirezione" is set to up } lineSubPathArray[numPath] = new SubPathInfo(); //create subpathinfo lineSubPathArray[numPath].closed = true; lineSubPathArray[numPath].operation = ShapeOperation.SHAPEXOR; lineSubPathArray[numPath].entireSubPath = PPI[numPath]; numPath++; //increase numPath counter punt = 0; //reset point counter } } } var myPathItem = mydoc.pathItems.add("pathname", lineSubPathArray); //when all the paths of qr code are drawed it add the path to photoshop document myPathItem.fillPath(bianco, ColorBlendMode.DIFFERENCE,100,true,0,true,true) //and fill it of white in difference. //mydoc.pathItems.removeAll(); //uncomment for remove all paths when the work is done function calcolaBordo(ix,iy,riga){ if(iy == 0 && ix == 0) {return "sxsu";}// if(iy == 0 && ix == riga) {return "dxsu";}// if(iy == riga && ix == riga) {return "dxgiu";}// if(iy == riga && ix == 0) {return "sxgiu";}// if(iy == 0 && ix != 0 && ix != riga) {return "su";}// if(iy != 0 && ix == riga && iy != riga) {return "dx";}// if(iy == riga && ix != 0 && ix != riga) {return "giu";}// if(ix == 0 && iy != 0 && iy != riga) {return "sx";}// if(ix =! 0 && iy !=0 && ix != riga && iy != riga){return "no";}// } function combinazione(ix,xt,iy,yt,bordo,qrcode,direzione){ switch (direzione){ //switch the point to analyze in base of the direction. in this mode the function can analyze the 4 point near ix,iy to determinate next direction case false: var px = 0; var py = 0; break; case "su": var px = 0; var py = -1; break; case "giu": var px = 0; var py = 1; break; case "sx": var px = -1; var py = 0; break; case "dx": var px = 1; var py = 0; break; } switch (bordo){ //assign the value of the squares around the ix,iy point. //if the point is at a border or at an angle, the squares that is out the qrcode matrix assume false value case "sxsu": var a = false; var b = false; var c = qrcode[ix+xt+px][iy+yt+py]; var d = false; break; case "dxsu": var a = false; var b = false; var c = false; var d = qrcode[ix+xt-1+px][iy+yt+py]; break; case "dxgiu": var a = qrcode[ix+xt-1+px][iy+yt-1+py]; var b = false; var c = false; var d = false; break; case "sxgiu": var a = false; var b = qrcode[ix+xt+px][iy+yt-1+py]; var c = false; var d = false; break; case "su": var a = false; var b = false; var c = qrcode[ix+xt+px][iy+yt+py]; var d= qrcode[ix+xt-1+px][iy+yt+py]; break; case "dx": var a = qrcode[ix+xt-1+px][iy+yt-1+py]; var b = false; var c = false; var d = qrcode[ix+xt-1+px][iy+yt+py]; break; case "giu": var a = qrcode[ix+xt-1+px][iy+yt-1+py]; var b = qrcode[ix+xt+px][iy+yt-1+py]; var c = false; var d = false; break; case "sx": var a = false; var b = qrcode[ix+xt+px][iy+yt-1+py]; var c = qrcode[ix+xt+px][iy+yt+py]; var d = false; break; case "no": var a = qrcode[ix+xt-1+px][iy+yt-1+py]; var b = qrcode[ix+xt+px][iy+yt-1+py]; var c = qrcode[ix+xt+px][iy+yt+py]; var d = qrcode[ix+xt-1+px][iy+yt+py]; } //this is the patterns used for know the direction of the path if(a == true && b == true && c == true && d == true){return "no"}//A if(a == false && b == true && c == true && d == true){return "su"}//B if(a == true && b == false && c == true && d == true){return "dx"}//C if(a == true && b == true && c == false && d == true){return "giu"}//D if(a == true && b == true && c == true && d == false){return "sx"}//E if(a == false && b == false && c == true && d == true){return "dx"}//F if(a == true && b == false && c == false && d == true){return "giu"}//G if(a == true && b == true && c == false && d == false){return "sx"}//H if(a == false && b == true && c == true && d == false){return "su"}//I if(a == false && b == false && c == false && d == true){return "giu"}//L if(a == true && b == false && c == false && d == false){return "sx"}//M if(a == false && b == true && c == false && d == false){return "su"}//N if(a == false && b == false && c == true && d == false){return "dx"}//O if(a == false && b == true && c == false && d == true){return "sugiu"}//P if(a == true && b == false && c == true && d == false){return "sxdx"}//Q if(a == false && b == false && c == false && d == false){return "bianco"}//R } } var testoQR = prompt("testoQR","qrcode for photoshop by Fr4nZ82"); disegnaQR(0,0,600,testoQR); /*This is the pattern explained. Imagine the point is in the center surrounded by the for square. Depend on pattern the script decides where to move legend: # = black square 0 = white square ## 0# #0 ## ## 00 #0 ## 0# 00 #0 0# 00 0# #0 00 ## ## ## #0 0# ## #0 00 0# #0 00 00 0# #0 0# 00 A B C D E F G H I L M N O P Q R no up right down left right down left up down left up right up/down lf/rg white(no)*/
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Disorder by displaying all the lines in the classic report
Hello
I have a classic report coming out data based on the variable binding element (which is a selection list). Some entries should have about 200 lines, but the page shows only 15 lines.
I tried assign none to paging still don't see all the lines. Here is my setup for the pagination of the table: http://i.imgur.com/iQoG0.png
If I get my pagination back, then I have the chance to see all the lines by clicking next but I need to show all the lines in the page. Is this what I need to do besides assign none to paging?
Apex 4.1.1
See you soonHello
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I have a classic report coming out data based on the variable binding element (which is a selection list). Some entries should have about 200 lines, but the page shows only 15 lines.I tried assign none to paging still don't see all the lines. Here is my setup for the pagination of the table: http://i.imgur.com/iQoG0.png
>
The question of the number of lines determines the number of lines on the page. You have set to 999, which seems correct.
>
If I get my pagination back, then I have the chance to see all the lines by clicking next but I need to show all the lines in the page. Is this what I need to do besides assign none to paging?
>Add a paging process reset point treatment "before areas" (or anywhere before this) and you will be ok.
The browser cache does not clear the paging alone sometimes.See you soon,.
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Hello world
I can't build my project because I have a problem with the mapping of the field in a presentation, how can I map the field for an attribute to my BPM object?
Thank youHello
Examine the error message. In this, there is a domain name.
1 open the offending presentation.
2. open the 'Properties' tab on the right (if it is not present click on "Windows"-> "Reset point of view").
3. click in the field you're having problem (this is the field that appeared in the error message).
4. in the Properties tab, click the field "Referenced data"-> click inside the field and select the attribute that is to be bound to the field.Hope this helps,
Dan -
Hello
I have trouble downloading to iCloud the photos app in OS X.
It seems pictures are being developed and download is underway, until I reached a point where the download starts from the beginning again and the console shows the following message is displayed:
25/07/16 09:31:36, cloudphotosd 148 [315]: Reset Sync asked! Reason: Domain = CloudPhotoLibraryErrorDomain Code = 1 "version mismatch" error UserInfo = {NSLocalizedDescription = Version mismatch}
Does anyone know how difficult or can help me debug the problem?
It seems that the problem is related to evolution of photos from hidden to visible, and vice versa. or remove the tags to images (maybe generally, no changes to photos) before the download is finished, because that's what I was doing in the meantime.
Thanks for your help!
Version:
OS X 10.11.6 (15G 31)
Photos App Version 1.5 (370.42.0)
one thing to try is disabling ICPL on all devices and disconnect from iCLoud then reconnect you and put on a device at a time and see if that clears it
LN
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When I updated my iPhone 6 more iOS 9.3 my camera will not be to the point and seems blurred by far. I already reset my iPhone and my mother worked... Anything other ideas, might be a bug in the iOS update?
I would say "try and do a restore as new iPhone" like everyone else but I'm having a similar problem and nothing works! I've restored all the possible ways and nothing. I got my screen replaced and I still have the same home button but my phone updated with error 53 (makes the phone unusable) but the camera did work before the update. and Apple has released iOS 9.1.2 (13D 20) to correct the error 53 (mainly for other reasons) but when I go to use the camera, it is only black! If someone could help 'discovered' and I would be great!
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Resets the pointer speed after start/sleep
It's my first time having to do deal with this (I use a logitech g5 on my desktop which uses the set value), just got my t430 yesterday and I cannot get the 'pointer' speed to save. It keeps resetting default after that until he goes to sleep or restarts.
I use the max sensitivity for the 'pointer' (i.e. in this case the trackpad), so it is VERY sensitive when it resets to 50%
Not the exact solution, but after reviewing set points advanced settings I checked 'Settings Retain OS' and now he saves.
No idea why it works that way, given the set points is just for my wireless m510, but he did lol
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Wireless hub works, other computers are connected
On a laptop, I lost the ability to connect wirelessly to the internet (message: limited connectivity)
Recommended by the system solution: reset or repair your access point or wireless router
How can I do?
I think that what you aim for is "power cycle".
To do this, simply unplug the router/access point power adapter. Wait a minute. Then reconnect it.
Hope this helps
Post back if necessary
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Cisco ISE point endpoint assets use Reset
Hello
I have a Cisco ISE running version 1.1, and I was wondering if it would be possible to reset the license use/active end point shown on the dashboard? Noted after a restoration of EHT due to the replacement of the material and I noticed that endpoints use County/active license doesn't seem to go down.
The following methods have been tried, but without success:
1. reboot the Server/service of ise
2. turn off all devices in the network use the ise as there are no customers/device access; example of switch/wlc/etc...
3 remove all use of endpoints in the Group of identity/identities
4 disable profiling at the ise
As the ise has been installed with a basic license; not too sure if it can be either a bad restoration (all service/application work however) / accounting bad Ray which is not expired on the ise / etc...
Any help is appreciated on how to reset the active use of point of termination/license.
Thank you.
Here is a method to remove outdated records. Please try this:
http://www.Cisco.com/en/us/docs/security/ISE/1.1/api_ref_guide/ise_api_ref_ch2.html#wp1072950
Thank you
Tarik Admani
* Please note the useful messages *. -
Why point central keep resetting?
Just moved over Flash Pro. 10 minutes and an accident later, I have to scratch my head.
Here's the deal: I create a semicircle shape, convert to symbol and move the transformation/center point at the center of what would be a full circle (I use this shape as a mask to reveal parts of a pie chart). Create a keyframe at frame 15, suddenly the central point in resets a half circle in the center of the symbol, the default position. Huh? Then I click on return to the first image, and that point central has thus reset. Uh, what?
Flash would have given me the symbol in the same State it was in the first picture. I tried option drag/frame 1 to frame 15, with the same result. I need the transformation point to stay where I put it, otherwise it is useless to me.
Does anyone know what gives?
Thanks for sharing the screengrab!
Looks like that there are more than a single Movieclicp on your frame. (- indicates the symbols of different types are selected). When you have several selected and then things change the transformation point, it corresponds to the selection of the points of transformation and is only temporary.
Know if there is something else on the same chassis and do not select it. You can click on an empty area on stage (select none) and then click on the symbol to select this option instead of using the rect selection basis.
Let me know if the problem persists.
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Reset the transformation point
How do reset you the transformation in CC Flash point? SC6 one selected the object hit the free transform, has moved the transformation point and click with the right button to find "reset transformation point" from the context menu. Who went to CC! What is the process now? Thank you.
Then change the registration point of object: double-click the object > select and combine all the content then align them on stage using window Tools Align (horizontal center alignment & vertical center alignment).
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How to reset the curve point selection
I downloaded a free version of VSCO presets as a test. I'm trying to remove them from the LR CC.
I got them removed from the presets area by following the instructions here:
https://vscoVSCO-Film-for-Adobe-Lightroom-CC-6-5-4-How-do-I-delete-my-old-presets-.zendesk.com/hc/en-us/articles/200324840-However, how can I remove the curved Point selection menu (see screenshot)?
I asked the question above to support VSCO and their eventual response was:
I'm sorry to say, but I think that the best next step would be to contact Adobe to see how to reset this menu. If you would please join Adobe support, they would be more than happy to help and answer your questions
Here is a link to their support page: https://helpx.Adobe.com/support.html
Thanks in advance
@johnrellis thanks for the reply. The information provided is not the correct way to reset the Point curve menu.
However, your suggestion did point me in the right direction. For future readers, (in Windows 8 at least), go to the following location and delete the content in the folder:
C:\Users\\AppData\Roaming\Adobe\CameraRaw\Curves HIH
Maybe you are looking for
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My original battery died after four years. I thought that I'm ok with the machine in general and decided to buy a new battery... I found the following on a Russian in line-shop local, they say, these models will be adapted to my laptop (A100 psaan se
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I had problems to e-mail for a 1/2 years. 1 my hotmail email went to the outlook.com and my Verizon e-mail went to Apple Mail, they both used for go to Apple mail and Outlook.com for a few years. I posted this question a few months ago, how can I g
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How to use the view 'cover flow' in an open file dialog box?
I often post pictures, such as screenshots, Web - like the one I included here! I always use "cover flow" as an aid to make sure that I'm the one that I want to load the download. In El Capitan, I see "cover flow" in the Finder, but not in a file ope
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HP Pavilion Notebook 15-ab210t: upgrade Ram on HP Pavilion Notebook 15-ab210tx
I'm about to buy a laptop HP Pavilion 15-ab210tx, which is a product imported from Thailand. I would like to know how many memory modules that it? and what Ram is this support. There 6500U Intel i7 processor. I would really appreciate if someone boug
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Get rX rY position of an object
Hello I'm doing an internship project. But I keep getting stuck. What I do: It is a platform of Stewart. The platform can be moved to 6DDL. The actuators are muscle cylinder without bearings.I'm trying to get the xyz + rotation angles (rX rY rZ) of t