Retrieve the range of records using the string
I have a table with records inserted in the following columns: the half year.
Half will be in values such as 1 H and 2 H, representing the first half and second half of the year
Will be the year for example, 2014, 2015
How my sql are if I want a range of records? Example 1: 2013 against 2 H 2014?
... to get a range of records? Example 1: 2013 against 2 H 2014?
... year. "' between ' 20131 H ' and ' 20142 H.
Tags: Database
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Select substr (str, instr(str,',',1,2) + 1, instr(str,',',1,3) - instr(str,',',1,2) - 1) third_one,.
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Hello world.
Thank you to everyone who helps everyone. I need your help
1. Select regexp_replace ('Add freon to a 1/2 ',' [^ [: digit:]]') twice;
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Output
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But I need the output voltage
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Hi all
How to retrieve the values of character without the use of single quotes. Its Possible in Oracle SQL
Please answer me...
For example
Is actual query-> Select * from employees where name like in("SCOTT", "JAMES", "ALBERT",...);
I want to--> Select * from employees where name like(SCOTT, JAMES, ALBERT...); -without the use of single quotes.
Why I need this application, I need to retrieve the records more than 200 employees in a select statement by using name in where clause.
shagarmahabubjan wrote:
Hi all
How to retrieve the values of character without the use of single quotes. Its Possible in Oracle SQL
Please answer me...
For example
Actual query is---> Select * from employees where name like in("SCOTT", "JAMES", "ALBERT",...);
I want to---> Select * from employees where name like(SCOTT, JAMES, ALBERT...); -without the use of single quotes.
Why I need this application, I need to retrieve the records more than 200 employees in a select statement by using name in where clause.
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Place your items for the hash table and retrieve it through the string of unique keys.
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