Retrieves a number to a string

Similar Questions

• Fract/Exp Numbe display Format string

  I have a digital channel that has a decimal value with accuracy up to 16-digit figures. I want to convert this string to a numeric value, and I used a "Fract/Exp number necklace. In my VI I hae set:

  Data type: EXT (because it allows number of decimal digits of 15 to 20)
  Data format: covered Point
  Numbers: 16
  Precision Type: Digits of precision

  Here's my question: If the input string is composed of digits of precision = 15 Eg: 5.369607712106161
  Then I output = 5.3696077121061609, which is the same, but not the same number I sent.
  or 1.145152879691825 String gives me the number = 1.1451528796918251
  String 5.818356760119754 gives me the number = 5.8183567601197543

  Please suggest how I can make more specific output.

  Thank you.

  Kind regards

  H.

  Wire a constant to the default value with the entry of your string to the function of numbers and define the type of POSITION, it is default DBL (note the red dot on your meter).

• all VI to convert a number to a string?

  Hello

  Have we not all VI to convert a number to a string?

  See you soon,.

  Forrest

  Hello.. Have you tried ' string/number conversion'...? You can find that to do a right-click on the block diagram-string/number of all the function - string - conversion...

  Just a thought... It could be that useful...

• Check if there is a number to a string

  Hey guys,.

  If I had a '2 cats' string, how could use a tape Loop statement to check if there is a number in there

  I got this far:

  for (var i: Number = 0; i < string.length; i ++) {}

  If (Equation.charCodeAt (i) < = 57)

  {if (equation.charCodeAt (i) > = 48)}

  {trace ("Number")

  }

  }

  }

  It works, but is there a more effective to achieve AA?

  Any thoughts would be appreciated

  Thank you very much

  Chris

  You can also use exec() regexp method if you need to detect multiple instances. For example, this code:

  var string:String = "It is 12 o'clock 24 hours 365 days";
  var pattern:RegExp = /\d+/g;
  while (pattern.exec(string))
  {
      trace("exec", pattern.lastIndex);
  }
  

  Shows:

  Exec 8

  exec 19

  exec 29

  This means that the numbers are in positions 8, 19 and 29

• How can I retrieve the number of selection Indices in a ComboBox?

  Hi all

  I use a ComboBox which options are populated by a XML code snippet.

  Now, I said that the task of implementation selectedLabel ComboBox to an option delivered by a different XML snippet.  SelectedLabel is a read-only property, so I find myself with SelectedIndex.  My plan is to loop through all the clues of the ComboBox until the label matches the value that must be set to ComboBox.

  After some rigorous research, I was not able to find a way to retrieve the number of the option of a ComboBox control.

  Thanks in advance and I would like to know what other information you need I'll check back FRO answers often.

  -Mike

  myComboBox.dataProvider.length

  Sincerely,

  Michael

  El 30/04/2009 a las 09:35, greensyn [email protected]> escribio:

  >

  Hi all

  >

  I use a ComboBox which options are populated by a XML code snippet.

  >

  Now I have the selectedLabel said ComboBox for a task

  a different snippet of code XML option.  SelectedLabel is a

  ReadOnly property, so I find myself with SelectedIndex.  My plan is to

  to loop through all the clues of the ComboBox until the label corresponds to

  the value must have the ComboBox value.

  >

  After some rigorous research, I have not been able to find a way of

  retrieve the number of the option of a ComboBox control.

  >

  Thanks in advance and I would like to know what other information you need as

  I'll check back FRO answers often.

  >

  -Mike

  >

• How to retrieve the number of days of a number

  Hi everyone, from X number, I need to retrieve the number of days.
  For example:
  
  X = 10-number of days > = 0
  X = 12-number of days > = 0.5
  X = 24-number of days > = 1
  X = 25-number of days > = 1
  X = 34-number of days > = 1
  X = 36-number of days > = 1.5
  X = 37-number of days > = 2
  X = 72-number of days > = 3
  X = 70-number of days > = 3
  
  I tried with Round, but it did not work as I wanted, because with 36 he recover 2 (instead of 1.5).
  In practice, a half day (12 hours) must be ALWAYS considered 0.5 and unrounded.
  
  Any idea?
  Thanks in advance
  
  Alex

  WITH T AS (SELECT 10 X FROM DUAL UNION ALL
          SELECT 12 FROM DUAL UNION ALL
          SELECT 24  FROM DUAL UNION ALL
          SELECT 25 FROM DUAL UNION ALL
          SELECT 34 FROM DUAL UNION ALL
          SELECT 36 FROM DUAL UNION ALL
          SELECT 37 FROM DUAL UNION ALL
          SELECT 72 FROM DUAL UNION ALL
          SELECT 70 FROM DUAL)
  SELECT X, DECODE( MOD(X/24, 1), 0.5, X/24, ROUND(X/24))
  FROM T
  

• Query to retrieve the number of transactions in every 1 hour for the end

  Hello
  
  Could someone help to write a query to retrieve the number of transactions in every hour for the last month.
  
  Case:
  I / P
  
  If Timestamp1
  1 01/01/2008 00:00:01
  CAS2 01/01/2008 00:01:01
  case3 01/01/2008 01:00:01
  1 01/01/2008 01:02:01
  case4 01/01/2008 01:10:01
  Service5 01/02/2008 02:00:01
  Case6 01/02/2008 02:10:01
  case7 2008-02-01 23:00:01
  .............................
  
  .............................
  case... 2008-01-31 00:24:00
  
  
  O/P
  cases of to_time of time
  2008-01-01 00:00:00 01/01/2008 01:00 2
  2008-01-01 01:00:01 01/01/2008 02:00 3
  
  .........................
  .........................
  
  etc.
  
  Any help really appreciated

  We can do this by using analytic functions

  Here's what I did:

  create table timestamp1 (date of ts)

  Select * from timestamp1
  2008-10-30 15:41:13
  2008-10-30 15:41:05
  2008-10-30 15:40:03
  2008-10-30 14:58:26
  2008-10-30 14:29:45
  2008-10-30 13:17:48
  2008-10-30 08:29:50
  2008-10-30 06:05:51
  2008-10-30 03:41:52
  2008-10-30 02:29:54

  Select distinct to_char (ts, 'hh24') frmhrs,
  TO_CHAR (ts, 'hh24') + 1 tohrs, count (ts) OVER (order by to_number (to_char (ts, 'hh24')) RANK BEFORE (1/24))
  of timestamp1
  When trunc (ts) = trunc (sysdate) - I added this just to make sure that I get for data of today
  order of frmhrs

  FRMHRS TOHRS CNT
  1-3-02
  03-4-1
  06 7 1
  1-9-08
  13 14 1
  14 15 2
  15 16 3

  You can customizeas by your need.

• Identify the Position of the Alphabet or number in given string

  Hi all
  

  Oracle9i Enterprise Edition Release 9.2.0.5.0 - Production
  PL/SQL Release 9.2.0.5.0 - Production
  CORE     9.2.0.6.0     Production
  TNS for 32-bit Windows: Version 9.2.0.5.0 - Production
  NLSRTL Version 9.2.0.5.0 - Production

  I have string value approximately 15000 records, I need to retrieve these archives with the length of 12 n identify the position of the character and the number.
  

  Ex:  Record Set 
  =================
  
  A12345T11111
  A12345F12222
  A12345F13333
  A12345F14444

  In this case, the first character is an alphabet followed 5 digits and 7 th position is an alphabet and followed by 5 digits...
  
  I pick up these format record only...
  
  
  There are some files like these
  
  -In the example below the 2nd charater is an alphabet its invalid
  AA2345512345
  -In this area, the 7th character is not an alphabet
  BA2345512345
  
  These documents must be eliminated...
  
  Valid format: 99999 99999 X X
  ==============
  
  Invalid format: XX9999999999, XX999999999X, X 99999999999
  
  
  I have one query, which gives me a result if string has an alphabet or not, if I tried present alphabets how are present.
  
  This helped me to identify the number of characters, but I need to get the positions...

  select LENGTH('A12345T11111') LEN#, LENGTH(TRANSLATE('A12345T11111','A1234567890','A')) from dual where LENGTH(TRANSLATE('A12345T11111','A1234567890','A'))=2

  Any ideas or thoughts on the same...
  
  Thank you
  Ananda

  with data as
  (
  select 'A12345T11111' as val from dual union all
  select 'AA2345512345' from dual
  )
  select val from data where regexp_like(val, '[[:upper:]][[:digit:]]{5}[[:upper:]][[:digit:]]{5}')
  /
  
  VAL
  ------------
  A12345T11111 
  
  1 rows selected
  

  EDIT: Just read your version of Oracle. I do not think that REGEXP_LIKE is supported in 9.2

  Perhaps instead you can use the translation:

  with data as
  (
  select 'A12345T11111' as val from dual union all
  select 'AA2345512345' from dual
  )
  select val
  from   data
  where  length(val) = 12
  and    translate(substr(val, 1, 1), 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', '..........................') = '.'
  and    translate(substr(val, 2, 5), '1234567890', '..........') = '.....'
  and    translate(substr(val, 7, 1), 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', '..........................') = '.'
  and    translate(substr(val, 8, 5), '1234567890', '..........') = '.....'
  /
  
  VAL
  ------------
  A12345T11111 
  
  1 rows selected
  

  Published by: Cyn on December 17, 2009 10:28

• Number of the string syntax - padding zeros in keeping the decimal values

  Hello team,

  I'm trying to get a number, paved with up to 3 zeros to the left and keep the two decimal places of it.

  IE: If the number is 6.25 then I want the string "006.25".

  If it's 60.125 I want to make "060.12" (rounded to the hundredth decimal closest)

  I tried using the 'String Format"with variations of differnet from the '% 03d' and '.2f '. but I can't have one the right combination of both of them in a single order. Am I missing something here?

  With the help of LV2011

  Thank you

  Have you tried %06.2f?

• Maximum value such as a number or a string

  Hallo,

  I calculated the maximum value of a channel. The next step is to use this value for further computation. My problem is that I can't use this value as a number. It is just a string. I tried with

  ChnPropGet then I got the number. But I can't use it for calculations. Anyone have an idea how I can fix this problem?

  I've attached a screenshot of my script. I use the German version of 12 DIAdem.

  Thanks for the help...

  Hello LePot,

  the properties. The function returns the property in its native type. If you navigate to the maximum property of a channel, it will return the value as a floating point number. You can check this by running the following script:

  (The script assumes that the dataset example is which has a number of Group 3 with a channel named "Res_Schall_1". But your chains should give you the same result with the message box showing "double."

  Dim Maximum
  Maximum = Data.Root.ChannelGroups (3). Channels ("Res_Schall_1"). Properties ('minimum'). Value
  MsgBox (TypeName (Maximum))

  If you ever want to convert a number represented as a string, be careful when you use "CDbl". This VBScript function assumes that the number is formatted by using the language of oyur BONES, especially the decimal setting (in '. 'or', '). If the setting of the operating system does not match the way the number is converted to a string, you have a problem. That's why the offer DIAdem::Str() to go a certain number to string s and Val() to go the opposite direction. Using CDbl can create rellay average errors that are difficult to detect.

  Andreas

• Find the number in a string

  Hello

  I had a string of characters from an editbox

  For example, the user put 12.4 or jaimelepate in the editbox

  It returns me the value "12.4" or "jaime lepate" (text format)

  I want to check if the value is text or a real number, then turn it into a real (I think that this is done by Val ("myvalue")

  How can I check the type of value?

  Thanks for your help

  Best regards

  Fred

  Hi Fred,.

  You can check with IsNumeric (InputValue).

  Brad Turpin

  Tiara Product Support Engineer

  National Instruments

• Hexadecimal number to hex string

  Dear moderators of Labview and experts.

  I'm looking for a simple tool, but could not know.

  Could you help me?

  I want to convert a hexadecimal string, Hex number unchanged.

  I mean digital Hex display shows E8 and I convert it to a string and I have Open indicator string Hex window and get the same answer E8.

  Someone knows how to do?

  I thank very you much in advance!

  cast will do what you want.

  

  (Make sure that digital is U8 and the string is defined to display hex.)

• Convert a decimal number to a string

  I work with a gas mixer and I try to transmit data rates. The mixer takes only decimal values, for example, if you want to 2500 cc debit you must pass it 2500.0. I tried to use the function of decimal string number and do a type cast but I get an error every time machine. The only thing that works is by using a control of the chain and entering the value, but I would like to do it with a digital command. Someone at - it tips or advice?

  

  Note that you have provided only a sample size. In addition, 2500.0 isn't a decimal number, it is a floating point value.

  It is also not clear if how you talk to the machine. You said that you used a Type Cast. For what? How do you communicate with the machine?

• Number in hexadecimal string conversion problem

  Hello

  for a serial communication, I need to send byte-code in an ascii hexadecimal string. When I use the constants and send them by VISA to the COM port it works fine, but if I use converters numbers it doesn't. Can someone show me what I'm doing wrong?

  deepearth

  --------------------------------

  Windows XP SP3, LV 8.5.1

  Since your string indicator is set to hexadecimal display, it seems you want to a hexadecimal string, a single byte/number.

  (You are currently using a hexadecimally format string, composed exclusively of ASCII of the 2 characters/byte "0.F" characters.) This is not what you want!).

  Here is another solution using type conversion:

  

• When I open Outlook Express I get an error message, the messages could be retrieved, error number: 0x800420CD.

  When I opened O/E I receive my messages but then it gives me an error msg

  Number 47 of the message could not be found. Account: 'pop.att.yahoo.com', server: 'pop.att.yahoo.com', Protocol: POP3, server response: '-ERR problem retrieving message.', Port: 995, secure (SSL): Yes, Server error: 0x800CCC90, error number: 0x800420CD

  If I send a msg, it works very well.

  I could not find Outlook Express menu.

  Thank you

  OE is in the category windows Messaging. That error means that the message is correct.  Log on to the online account and see what message hasn't been minimum and delete it.