Retriving all records in table
HelloTo retrieve all records from the table, procedure below has been used, but the performance gets only a single record in the output.
Procedure (proc_env) has been wrapped into the package (packg)
This package gets the call from the java environment to extract all records in the table.
Procedure wrapped in packaging
--------------------------------------------------
PROCEDURE proc_test (cursor1 OUT TestCursor)
IS
BEGIN
OPEN FOR Cursor1
SELECT col1,
col2,
COL3
Table_name FROM
END;
procedure called for execution
-----------------------------------------
DECLARE
v_col1 table.col_name%TYPE;
v_col2 table.col_name%TYPE;
v_col3 table.col_name%TYPE;
v_cur packg. TestCursor;
BEGIN
packg.proc_test (v_cur);
EXTRACT the v_cur IN v_col1, v_col2, v_col3;
DBMS_OUTPUT. ENABLE;
Dbms_output.put_line (v_col1 |) ',' || v_col2 | «, » || v_col3);
END;
/
How to retrieve all the records in the table?
What is missing in the code?
Regarding
SET SERVEROUTPUT ON
DECLARE
v_col1 table.col_name%TYPE;
v_col2 table.col_name%TYPE;
v_col3 table.col_name%TYPE;
v_cur packg.TestCursor;
BEGIN
DBMS_OUTPUT.ENABLE;
packg.proc_test(v_cur);
LOOP
FETCH v_cur INTO v_col1,v_col2,v_col3;
EXIT WHEN v_cur%NOTFOUND;
DBMS_OUTPUT.put_line(v_col1||','||v_col2||','||v_col3);
END LOOP;
CLOSE v_cur;
END;
/
SY.
Tags: Database
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Using this rule (and this example) I want a record between 1997 and 1981, between 1982 and 1982, others from 1983 to 1985, from 1986 until 1986, and so on like this:
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The results you want with these new data sample even as the results that you have published with the latest data from the sample?
Filipe_Almeida wrote:
The line with COD = 2 is a different record that cod = 1. Have the same value of UC, but have a different PE_CODIGO. So it is another record.Yes, it's another record. This is exactly why I don't understand why you want to see cod = 1 in the output for the line where pe_codigo = 10000.
If you wish, you can put 'B' in the column of the CPU for recording with COD = 2...
You say there is a line in the output with the cod = 2? In the results of the sample you have validated, cod = 1 on all lines. Mayber, you need to verify that the results are accurate and post the correct results if they are not.
in tables DIS1 and DIS2 and ID = line 150 CRED table, as well.
Sorry, I'm dion can't understand this. In the examples of new data, is not uc = 'A' for all rows in all tables? Why is - it normal to have a CPU = "B" in the output?
END_YEAR = NULL means that, after INITIAL_YEAR, UC, this number of credits to infinity. For example (using DIS2), UC = 'A' with PE_CODIGO = 10024, in the year 2011 or the year 9999 is worthless credits. The same CPU, but in the year 1989 have 3 credits. But the year 1984 have no credit.
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