Return of first plan - need to refresh
When I go out of my application, I just go to the background
blackberry.app.requestBackground ();
When I return in the application by clicking on its icon. I go to the same page as I was before.
I would like to automatically refresh this page.
How can I do? The onload event does not work because the page is already loaded.
try to do in the onForeground case.
http://www.BlackBerry.com/developers/docs/widgetapi/Summary_app.html
Tags: BlackBerry Developers
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I have a request as well as 2 pages.
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http://www.munkyben.WordPress.com
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Hello
I have a query which can be simplified to the following data, if
Assume that it is my dataset, with THE_VALUE of
Sign (Anum) therefore,-1, 0 or 1.
* (Sorry for crushed registration. "I can't understand this website's rich text formatting.) *
THE_VALUE THE_DATE THE_MEMBER
1 0 1 January 2007
1 0 1 February 2007
1 0 1 March 2007
1. 1 April 1, 2007
1 1 1 May 2007
1 0 1 June 2007
1. 1 July 1, 2007
1. 1 August 1, 2007
1 0 01 - sep - 2007
2 0 1 January 2007
2 1 February 1, 2007
2 0 1 March 2007
2. 1 April 1, 2007
2 1 1 May 2007
2 0 1 June 2007
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2. 1 August 1, 2007
2. 1 01-sep-2007
3 0 1 January 2007
3. 1 February 1, 2007
3 0 1 March 2007
3 0 1 April 2007
3. 1 May 1, 2007
3 0 1 June 2007
3. 1 July 1, 2007
3. 1 August 1, 2007
3 0 01 - sep - 2007
I need to get the lines with the THE_MEMBER, the values of the first and the last
THE_DATE, where the value is - 1, and the date range is the last
set of lines to the Member, with the same value of THE_VALUE.
I tried the following to get the dates of first and last for a set
consecutive months with the same value for the Member.
SELECT the_member
the_value
the_date
first_value (the_date)
in the first_date (PARTITION the_member, ORDER BY the_member the_value, the_date)
last_value (the_date)
during the last_date (PARTITION the_member, ORDER BY the_member the_value, the_date)
OF togola
ORDER BY the_member
the_date;
At first, it seems to work, but then, when the return value
an old value, FIRST_DATE will be the first of all the lines containing
This value for the Member rather than the first of consecutive
rows with this value for the Member. Apparently the partitioning
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THE_MEMBER THE_VALUE THE_DATE FIRST DATE LAST DATE
1 0 January 1, 2007 January 1, 2007 January 1, 2007
1 0 1 February 2007 1 January 2007 1 February 2007
1 0 1 March 2007 1 January 2007 March 1, 2007
1. 1 April 1, 2007 April 1, 2007 April 1, 2007
1. 1 May 1, 2007 April 1, 2007 may 1, 2007
1-0 June 1, 2007 January 1, 2007 June 1, 2007
1. 1 July 1, 2007 April 1, 2007 July 1, 2007
1. 1 August 1, 2007 April 1, 2007 August 1, 2007
1 0 01 - sep - 2007 1 January 2007 01-Sep-2007
2 0 January 1, 2007 January 1, 2007 January 1, 2007
2 1 1 February 2007 February 1, 2007 February 1, 2007
2 0 1 March 2007 1 January 2007 March 1, 2007
2. 1 April 1, 2007 February 1, 2007 April 1, 2007
2 1 1 May 2007 February 1, 2007 may 1, 2007
2-0 June 1, 2007 January 1, 2007 June 1, 2007
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2. 1 August 1, 2007 February 1, 2007 August 1, 2007
2. 1 01-sep-2007 1 February 2007 01-Sep-2007
3 0 January 1, 2007 January 1, 2007 January 1, 2007
3. 1 February 1, 2007 February 1, 2007 February 1, 2007
3 0 1 March 2007 1 January 2007 March 1, 2007
3 0 April 1, 2007 January 1, 2007 April 1, 2007
3. 1 May 1, 2007 February 1, 2007 may 1, 2007
3 0 June 1, 2007 January 1, 2007 June 1, 2007
3. 1 July 1, 2007 February 1, 2007 July 1, 2007
3. 1 August 1, 2007 February 1, 2007 August 1, 2007
3 0 01 - sep - 2007 1 January 2007 01-Sep-2007
That's what I need to get in the end.
THE_MEMBER FIRST DAY DATE OF LAST
July 2 1 2007-01 - Sep - 2007
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Published by: user10700981 on December 17, 2008 13:57Hello
We'll call the lines whose the_value =-1 'good' lines and lines with the_value! =-1 ranks of 'bad '.
For each value of the_value, we need the first and last values of the_date where
the last row in the group is good
(b) the current line is good
(c) there is a lot of lines from the current line to the end of the Group
Condition (a) is just a special case of (c).
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Best regards.
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