rewrite the left join

Work according to code, but I want to rewrite them in the left join on style, how
Select *.
of a, b, c, d, e
v_codeNumber f
where a.my_numb = '5582017'
and a.username = b.username
and c.username = b.username
and c.DEPARTMENT_CODE = d.TDEPT_CODE
and c.discipline_num = f.discipline_num (+)

You mean you want the ANSI syntax?

select *
from a join b on (a.username = b.username)
       join c on (c.username = b.username)
       join d on (c.DEPARTMENT_CODE= d.TDEPT_CODE)
       cross join e
       left join v_codeNumber f on (c.discipline_num = f.discipline_num)
where a.my_numb ='5582017' 

Tags: Database

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    create table EMP
    (
      EMPID   NUMBER(10,2),
      EMPNAME VARCHAR2(100)
    );

    INSERT INTO emp (empid,empname) values (1, 'abc');
    INSERT INTO emp (empid,empname) values (2, 'xyz');
    INSERT INTO emp (empid,empname) values (3, 'UNJ');

    create table EMP_Type
    (
      ID          NUMBER(10,2),
      EMPID       NUMBER(10,2),
      TYPE_ID     NUMBER(10,2),
      END_DATE    DATE
    );

    INSERT INTO EMP_Type(id, empid, TYPE_ID, END_DATE) values (100, 2, 1, SYSDATE);

    select *
      from emp e
      left outer join emp_Type t
        on e.empid = t.empid
    and t.type_id = 1

    returns.

            EMPID     EMPNAME     ID             EMPID     TYPE_ID     END_DATE
         2.00             xyz            100.00     2.00             1.00             10/9/2012 5:18:59 PM
         3.00             UNJ                    
         1.00             abc                    


    select *
      from emp e
      left outer join emp_Type t
        on e.empid = t.empid
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    returns

            EMPID     EMPNAME     ID             EMPID     TYPE_ID     END_DATE
         2.00             xyz                 
         3.00             UNJ                    
         1.00             abc          

    but instead I want

            EMPID     EMPNAME     ID             EMPID     TYPE_ID     END_DATE
         3.00             UNJ                    

    Your conditions of conflict
    >
    and t.type_id = 1
    and t.empid = 3
    >
    There is a record with t.empid 3

    select *
      from empx e, empx_Type t
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      and e.empid = t.empid (+)
    
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    (

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    SELECT '20', 'Wayne', 'Bruce' OF THE double

    UNION ALL

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    UNION ALL

    SELECT "40", "Parker", "Peter" OF THE double

    UNION ALL

    SELECT '50', 'Last', 'Tony' FROM dual

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    ),

    emp_contracts AS

    (

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    UNION ALL

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    UNION ALL

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    To_date '20', SELECT (January 1, 2011 ',' MON-DD-YYYY ""), to_date (1 January 2012 ',' MON-DD-YYYY') OF double

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    To_date '30', SELECT (January 1, 2011 ',' MON-DD-YYYY ""), to_date (1 January 2012 ',' MON-DD-YYYY') OF double

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    To_date '40', SELECT (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

    UNION ALL

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    UNION ALL

    To_date '50', SELECT (January 1, 2010 ',' MON-DD-YYYY ""), to_date (December 31, 2011 ',' MON-DD-YYYY') OF double

    UNION ALL

    To_date '50', SELECT (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

    UNION ALL

    To_date '60', SELECT (January 1, 2011 ',' MON-DD-YYYY ""), to_date (1 January 2012 ',' MON-DD-YYYY') OF double

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    To_date '60', SELECT (January 1, 2010 ',' MON-DD-YYYY ""), to_date (December 31, 2011 ',' MON-DD-YYYY') OF double

    UNION ALL

    To_date '60', SELECT (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

    ),

    emp_positions AS

    (

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    UNION ALL

    SELECT ' 10', '47NT', to_date (January 1, 2010 ',' MON-DD-YYYY ""), to_date (December 31, 2011 ',' MON-DD-YYYY') OF double

    UNION ALL

    SELECT ' 10', '41JE', to_date (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

    UNION ALL

    SELECT ' 20', '48AW', to_date (January 1, 2011 ',' MON-DD-YYYY ""), to_date (1 January 2012 ',' MON-DD-YYYY') OF double

    UNION ALL

    SELECT ' 20', '42KD', to_date (January 1, 2010 ',' MON-DD-YYYY ""), to_date (December 31, 2011 ',' MON-DD-YYYY') OF double

    UNION ALL

    SELECT ' 20', '46LD', to_date (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

    UNION ALL

    SELECT ' 30 ', 45 MI', to_date (January 1, 2011 ',' MON-DD-YYYY'), to_date (1 January 2012 ',' MON-DD-YYYY') FROM dual

    UNION ALL

    SELECT ' 30', '44KH', to_date (January 1, 2010 ',' MON-DD-YYYY ""), to_date (December 31, 2011 ',' MON-DD-YYYY') OF double

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    SELECT ' 40', '42DX', to_date (January 2, 2012 ',' MON-DD-YYYY ""), double NULL

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    UNION ALL

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    )

    SELECT

    1. ES.emp_id,
    2. ES.last_name,
    3. ES.first_name,
    4. EP.title_id,
    5. EP.position_start,
    6. EP.position_end

    Employees are

    LEFT JOIN emp_contracts ec

    ON ec.emp_id = es.first_name

    LEFT JOIN emp_positions ep

    ON ep.emp_id = es.emp_id

    WHERE ec.contract_end IS NULL AND ep.position_end IS NULL

    Hello

    AquaNX4 wrote:

    Good day ladies------Gentlemen\ gurus-Experts-and Al:

    Just when I thought I got my mind wrapped around the notion of NULL value, as defined by Oracle, I met what follows below.  Basically, what you are watching is how our employees of the human resources tables are set up (for the most part).  We have the employees, employee contracts table and the tables of positions.  When I want to make a list of active staff, I always use the filter end date, you will see below in the Super request, essentially looking for staff who do not have a contract AND a position end date entered in the DB.  It works like a charm.  However, today, I noticed an official on the list, who has never had a position is entered in the comic book, and he had an 'open' contract  In my example below, why would "Hal Jordan" appear on the active staff list?  Yes, he spends the first part of my predicate (contract_end is null), but it does not work (at least by my understanding) past the second part of the predicate which is position_end has the value NULL because there not even a record is entered in the comics!  Why would he appear?  Is it because of the LEFT JOIN or a NULL rule type, I'm not aware of?  ...

    It's the outer join.

    When you say

    Employees are

    LEFT JOIN emp_positions ON ep.emp_id = es.emp_id ep

    then, at the time when the WHERE clause is evaluated, the result set contains at least 1 row for each line of employees.  If there is no line in emp_postitions that meet the join condition, then all the columns that should be provided by the emp_positions table will be NULL. This is precisely what concerns the outer join.

    Think about it for a minute.  NULL means the absence of any value.  Is there is no corresponding row in the emp_positions table, then there is no value for emp_position.position_end.  If so doesn't; "have a value, then, by definition, it is NULL.

    It if were not NULL, then this would mean that it had a value.  Would what value?  Why the request would give him one value rather than another?

    Thanks for the display of the data of the sample; It's always useful!

  • LEFT JOIN DUPLICATION PROBLEM

    Hello

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    001100001A50
    001100001B250

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    Thank you.

    Note that your query uses an inner join. Your original question mentioned a join left, generally interpreted as meaning a left OUTER join.

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    WITH table1 AS (
      SELECT '001' AS task1
           , 100 AS price
      FROM   dual
    ), table2 AS (
      SELECT '001' AS task1
           , 'A' AS resources
           , 50 AS price
      FROM   dual
      UNION ALL
      SELECT '001' AS task1
           , 'B' AS resources
           , 250 AS price
      FROM   dual
    )
    SELECT DECODE(ROW_NUMBER() OVER (PARTITION BY t1.task1, t1.price ORDER BY t2.resources, t2.price),1,t1.task1) AS task1_alt
         , DECODE(ROW_NUMBER() OVER (PARTITION BY t1.task1, t1.price ORDER BY t2.resources, t2.price),1,t1.price) AS price_alt
         , t2.task1 AS task_with_resource
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    FROM   table1 t1
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  • Left join with three-table join query

    I am trying to create a query that left me speechless. Most of the query is simple enough, but I have a problem I do not know how to solve.

    Background:
    We have stock stored in i_action.

    We have the attributes available for each type of action. The attributes available for each action are described in shared_action_attribute. Each type of action can have three attributes or none at all.

    We have the values stored for the attributes in i_attribute_value.

    An example says:
    We have a transfer action (action_code B4). The action of B4 entry into i_action records the fact that the transfer took place and the date at which he spoke. The attributes available for a transfer action are the function code receiver, the receiving unit number and the reason of transfer code. These types of attributes available and their order are stored in shared_action_attribute. The actual values of the attributes for a specific action of transfer are stored in i_attribute_value.

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    There are two questions. First of all, I want only the first two attributes. To specify the attributes of the first two, I also i_attribute_value a link to shared_action_attribute (which is where the order is stored). I can build a simple query (without the left join) which connects the three tables, but then shares without attributes would be excluded from my result (see Query 2 below).

    The second problem is that I'd actually a row returned for each action with first_attribute and second_attribute in the form of columns instead of two lines.

    The final query will be used to create a materialized view.

    Here are the tables and examples of what is stored in the:

    TABLE i_action
    Name Type
    ----
    ACTION_SEQ NUMBER (10)
    DATE OF ACTION_DATE
    ACTION_CODE VARCHAR2 (3)
    VARCHAR2 (1) DELETED

    EXAMPLE OF LINES
    ACTION_SEQ ACTION_DATE DELETED ACTION_CODE
    ----
    45765668 9 OCTOBER 09 B2 HAS
    45765670 9 OCTOBER 09 BA HAS
    45765672 B6 9 OCTOBER 09A
    45765673 9 OCTOBER 09 B4 HAS
    45765674 9 OCTOBER 09 G1 HAS
    45765675 9 OCTOBER 09 M3 HAS

    TABLE i_attribute_value
    Name Type
    ---
    IA_ACTION_SEQ NUMBER (10)
    SACTATT_SACT_CODE VARCHAR2 (3)
    SACTATT_SAT_TYPE VARCHAR2 (3)
    VARCHAR2 VALUE (50)

    EXAMPLE OF LINES
    IA_ACTION_SEQ SACTATT_SACT_CODE SACTATT_SAT_TYPE VALUE
    ----
    45765668 B2 COA 37 B
    45765670 BA ROA D
    45765670 BA ROR P
    45765672 B6 CAT C
    B4 45765673 RFC E
    45765673 B4 TRC P
    B4 45765673 RUN 7
    45765674 G1 SS 23567
    G1 45765674 ASG W

    TABLE shared_action_attribute
    Name Type
    ---
    SACT_CODE VARCHAR2 (3)
    SAT_TYPE VARCHAR2 (3)
    ORDER NUMBER (2)
    TITLE VARCHAR2 (60)

    EXAMPLE OF LINES
    SACT_CODE SAT_TYPE UNDER THE ORDER
    ----
    B2 ACO 1 Office code
    BA ROR 1 reason to re-open
    Authority of BA ROA 2 reopen
    B6 CAT 1 category
    B4 RFC 1 reception function code
    B4 RUN 2 receives the unit code
    B4 TRC 3 transfer of reason code
    Sequence of G1 SS 1 personal
    Reason for G1 ASG 2 assignment

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    AND iav.sactatt_sat_type = 'SS '.
    THEN THE VALUE
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    THEN '67089'
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    IA.serial_number, ia.action_seq),
    '67089'
    ) staff_seq,.
    value
    From i_action LEFT JOIN i_attribute_value iav AI
    ON iav.ia_action_seq = ia.action_seq
    WHERE ia.deleted = 'A ';

    ACTION_SEQ ACTION_DA COD STAFF_SEQ VALUE
    ----
    45765668 9 OCTOBER 09 B2 67089 37 B
    45765670 9 OCTOBER 09 BA D 67089
    45765670 9 OCTOBER 09 BA 67089 P
    45765672 9 OCTOBER 09 B6 67089 C
    45765673 9 OCTOBER 09 B4 67089 E
    45765673 9 OCTOBER 09 B4 67089 P
    45765673 9 OCTOBER 09 67089 7 B4
    45765674 9 OCTOBER 09 23567 23567 G1
    45765674 9 OCTOBER 09 G1 23567 W
    45765675 9 OCTOBER 09 M3 23567

    QUERY 2:
    This query is limited to the first two attributes but he also filed actions which have no attributes, and it creates still several lines for each action instead of a single line with two columns for attributes.
    SELECT ia.action_seq, ia.action_date, ia.action_code cod,
    NVL
    (LAST_VALUE (CASE
    WHEN ia.action_code = "G1".
    AND iav.sactatt_sat_type = 'SS '.
    THEN THE VALUE
    WHEN ia.action_code IN ('A0', 'A1')
    THEN '67089'
    END IGNORE NULLS
    ) OVER (PARTITION BY ia.ici_charge_inquiry_seq ORDER BY ia.action_date,
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    '67089'
    ) staff_seq,.
    value
    OF shared_action_attribute saa, ims_action AI, ims_attribute_value iav
    WHERE iav.ia_action_seq = ia.action_seq
    AND iav.sactatt_sact_code = saa.sact_code
    AND iav.sactatt_sat_type = saa.sat_type
    AND saa.display_order IN ('1 ', ' 2')
    AND ia.deleted = 'A ';

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    ----
    45765668 9 OCTOBER 09 B2 67089 37 B
    45765670 9 OCTOBER 09 BA D 67089
    45765670 9 OCTOBER 09 BA 67089 P
    45765672 9 OCTOBER 09 B6 67089 C
    45765673 9 OCTOBER 09 B4 67089 E
    45765673 9 OCTOBER 09 67089 7 B4
    45765674 9 OCTOBER 09 23567 23567 G1
    45765674 9 OCTOBER 09 G1 23567 W

    I found it quite complex to try to write - I hope that I was clear.

    Thank you very much!

    Hello

    You can use an alias for column (such as staff_seq) in the ORDER BY. Unfortunately, it's the only place where you can use it in the same query, where it was defined.
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    WITH   ungrouped_data      AS
    (
        SELECT ia.action_seq, ia.action_date, ia.action_code,
              NVL
                  (LAST_VALUE (CASE
                                  WHEN ia.action_code = 'G1'
                                   AND sactatt_sat_type = 'SS'
                                     THEN VALUE
                                  WHEN ia.action_code IN ('A0', 'A1')
                                     THEN '67089'
                               END IGNORE NULLS
                              ) OVER (PARTITION BY ia.ici_charge_inquiry_seq ORDER BY ia.action_date, ia.action_seq),
                   '67089'
                  )staff_seq,
               (CASE
                  WHEN display_order = '1'
                  THEN VALUE
               END) first_attribute,
               (CASE
                  WHEN display_order = '2'
                  THEN VALUE
               END) second_attribute
          FROM i_action ia
          LEFT JOIN i_attribute_value iav
               ON iav.ia_action_seq = ia.action_seq
          LEFT JOIN shared_action_attribute
               ON sactatt_sact_code = sact_code
             AND sactatt_sat_type = sat_type
         WHERE ia.deleted = 'A'
    )
    SELECT       action_seq
    ,       action_date
    ,       action_code
    ,       staff_seq
    ,       MIN (first_attribute)          AS first_attribute
    ,       MIN (second_attribute)     AS second_attribute
    FROM       ungrouped_data
    GROUP BY  action_seq
    ,       action_date
    ,       action_code
    ,       staff_seq
    ;
    

    There are other alternatives for special cases, but none of them work in this particular case.

  • Left join for three tables

    Hello

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    b,
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    Thank you
    Radha K

    AJ99 wrote:

    SELECT a.acc_rk
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    LEFT JOIN c ON b.acc_rk = c.acc_rk;
    

    There is no need for media. ;)

    SELECT a.acc_rk
      FROM a LEFT JOIN b ON a.acc_rk = b.acc_rk
           LEFT JOIN c ON b.acc_rk = c.acc_rk;
    
  • LEFT JOIN increases the number of lines

    Hi guys,.

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    -1176 lines

    Select count (erg_ID) of

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    Why not just an inner join then?

  • Outer joins to the left... Please help!

    Hmm. Ive had trouble with this one for a while and have read and re-read docs etc.

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    Kind regards

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    E ENTITIES

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    P.amount

    PAYMENTS P

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    ON p.status_id = ps.status_id

    AND ps.forecast = 'Y '.

    ) IN.

    WE e.entity_id = in. entity_id

    LEFT OUTER

    JOIN BR BRI_RECON

    ON e.entity_id = br.entity_id

    E.entity GROUP

    ;

    I hope it helps.

    Best regards, David

    Post edited by: David Berger

  • How to avoid the union and use a left join

    Hello

    I have the following tables

    {code}

    create the table mainTable

    (col1 varchar2 (2) varchar2 (2) col2, col3 varchar2 (2), col4 varchar2 (2));

    create table secTable

    (col1 varchar2 (2));

    create the table secTable1

    (col2 varchar2 (2));

    create the table secTable2

    (col3 varchar2 (2));

    Insert in maintable

    values ('a', 'b', 'this,' would be ');

    Insert in maintable

    values (', 'o', 'n', 'p');

    insert into secTable

    values ('a');

    insert into secTable1

    values ('b');

    insert into secTable2

    values ('c');

    commit;

    {code}

    I made a request, drank, I would use join without clause union how can I change to receive the same result as the following query?

    {code}

    Select t1.*, 'bad value' | T1.Col1
    from maintable t1
    T1.Col1 left join t2 = t2.col1 sectable
    where t2.col1 is null
    Union of all the
    Select t1.*, 'bad value' | T1.col2
    from maintable t1
    Join t2 left on t1.col1 = t2.col2 sectable1
    where t2.col2 is null
    Union of all the
    Select t1.*, 'bad value' | T1. COL3
    from maintable t1
    Join t2 left on t1.col1 = t2.col3 sectable2
    where t2.col3 is null

    {code}

    Thank you

    Coco

    Like this?:

    SQL > SELECT col1, col2, col3, col4, xvalue

    2 from (SELECT m0.*

    3, NVL (t0.col1, 'bad value t0' | m0.col1) t0_col1

    4, NVL (t1.col2, 'bad value t1' | m0.col2) t0_col2

    5, NVL (t2.col3, 'bad value t2' | m0.col3) t0_col3

    Maintable m0 6

    LEFT OUTER JOIN sectable t0 7

    8. WE (m0.col1 = t0.col1

    9 AND t0.col1 IS NULL)

    10 LEFT OUTER JOIN sectable1 t1

    11. WE (m0.col1 t1.col2 =

    12 AND t1.col2 IS NULL)

    13 LEFT OUTER JOIN t2 sectable2

    14. WE (m0.col1 = t2.col3

    15 t2.col3 AND IS NULL))

    16 UNPIVOT INCLUDES NULL values (xvalue wrongly IN (t0_col1, t0_col2, t0_col3))

    17 ORDER BY xvalue

    18.

    COL1 COL2 COL3 COL4 XVALUE

    ------ ------ ------ ------ ---------------------------------------------------

    a b c d bad value t0 a

    m o n p bad value m t0

    a b c d bad value t1 b

    m o n p o t1 value of evil

    a b c d bad value t2 c

    m o n p value t2 n bad

    6 selected lines.

  • Left join of the two tables and multiple values into a single value separated by commas

    Hello

    I have following tables with their structures and their data as below.

    CREATE TABLE 'BETODI '. "" BETINFO ".

    (

    VARCHAR2 (8 BYTE) "CURRENTPRESS."

    ENABLE 'TYPEIDCONTAINER' VARCHAR2 (30 BYTE) NOT NULL

    )

    INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A24G', 'PMC');

    INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A24D', 'Pensky-MARTENS');

    INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ("A25D", "CMP");

    INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A25G', 'PMC');

    INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A26D', 'PMC');

    INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A26G', 'PMC');

    INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ("A32G", "V-BFC3");

    INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A32D', "V-BFC2");

    CREATE TABLE 'BETODI '. "" BETMASTER ".

    (

    ACTIVATE THE "CUREPRESS" TANK (5 BYTES) NOT NULL,

    ACTIVATE THE "TYPE" VARCHAR2 (5 BYTE) NOT NULL,

    NUMBER (5.0) "LASTPCIRIM".

    )

    INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A24', '45 M 8', 15);

    INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A25', 42 16', 15);

    INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A26", 16' 45, 15);

    INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A27", '45 M 34', 16);

    INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A28', '45 M 34', 16);

    INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A29', '45 M 34', 16);

    INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A30', '45MCH', 15);

    INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A31", "45MCH", 16);

    INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A32', '45MCH', 16);

    INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A33', '45MCH', 16);

    INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A34", "45MCH", 16);

    These two tables have left join as

    BETMASTER. CUREPRESS = substr (BETINFO. CURRENTPRESS, 1, 3)

    now I want to have the data in the two tables with fields Curepress, Lastpcirim, typeidcontainer.

    Also something like

    Make a group of typeidcontainer if this value is greater than 1 by press separated the values of semicolon (;)

    So, for example above, we should be given as

    A24 PMC 15; PENSKY-MARTENS

    A25 15 PMC

    A26 15 PMC

    A27 16 (NULL)

    A28 16 (NULL)

    A30 15 (NULL)

    A31 16 (NULL)

    A32 16 BFC2-V; V BFC3

    A33 16 (NULL)

    A34 16 (NULL)

    How could do?

    My current request is as

    Select distinct Curepress, lastpcirim, typeidcontainer

    BETMASTER STD left join INF BETINFO

    on the trim (STD. CUREPRESS) = substr (trim (INF. CURRENTPRESS), 1, 3)

    but I am unable to get the values separated by commas.

    Any help would be appreciated.

    Thank you

    Mahesh.

    Hi, Mahesh,

    If you want to only 1 row of output for each distinct combination of currentpress and lastpcirim?  This sounds like a job for GROUP BY.

    And you want the row to contain a list of all different typidcontainers-delimited?  This sounds like a job for the aggregate LISTAGG function.

    WITH joined_data AS

    (

    SELECT DISTINCT

    MST.curepress, mst.lastpcirim, inf.typeidcontainer

    OF betmaster STD

    LEFT JOIN betinfo ON TRIM (mst.curepress) inf = SUBSTR (TRIM (inf.currentpress)

    1

    3

    )

    )

    SELECT curepress, lastpcirim

    LISTAGG (typeidcontainer, ',')

    THE Group (ORDER BY typeidcontainer) AS container_list

    OF joined_data

    Curepress GROUP, lastpcirim

    ;

    Unfortunately, you can't say LISTAGG (DISTINCT ...), so you should always get the separate containers how you already are.  (Note that the subquery is just what you posted).

    Thanks for posting the CREATE TABLE and INSERT statements; It is very useful.  Don't forget to tell what version of Oracle you are using.  LISTAGG was new in Oracle 11.2.

    Why not add CHECK constraints (and perhaps triggers) to your tables, so that curepress and currentpress are not stored with the head or trailing spaces?  Then you wouldn't need to use the PAD in queries like this, and your code would be simpler and more effective.

  • Seen the lock of brain on Left Join

    Always on Oracle 11.2.0.1.0

    Examples of data
    CREATE TABLE theEmails (
    RID NUMBER(10) PRIMARY KEY,
    employee NUMBER(6),
    emailType VARCHAR2(4),
    emailAddress VARCHAR2(50),
    emailActive number(1)
    )
    ;
    INSERT INTO theEmails VALUES(778437,231509,'OTHR','[email protected]',0);
    INSERT INTO theEmails VALUES(847168,231509,'WRK1','[email protected]',0);
    INSERT INTO theEmails VALUES(784690,231509,'OTHR','[email protected]',1);
    INSERT INTO theEmails VALUES(1459884,239868,'OTHR','[email protected]',0);
    INSERT INTO theEmails VALUES(1485781,239868,'OTHR','[email protected]',1);
    INSERT INTO theEmails VALUES(1485782,239868,'WRK1','[email protected]',0);
    INSERT INTO theEmails VALUES(1501028,231509,'WRK1','[email protected]',1);
    INSERT INTO theEmails VALUES(1492288,239868,'WRK1','[email protected]',1);
    INSERT INTO theEmails VALUES(1456785,239865,'OTHR','[email protected]',0);
    INSERT INTO theEmails VALUES(1489166,239865,'WRK1','[email protected]',0);
    INSERT INTO theEmails VALUES(1482668,239865,'WRK1','[email protected]',0);
    INSERT INTO theEmails VALUES(1482667,239865,'OTHR','[email protected]',1);
    
    
    
    CREATE TABLE thePeople (
    employee NUMBER(6),
    recordNum NUMBER(2),
    lastName VARCHAR2(20),
    firstName VARCHAR2(20)
    )
    ;
    
    INSERT INTO thePeople VALUES(231509,0,'P','Michelle');
    INSERT INTO thePeople VALUES(239868,0,'K','Dan');
    INSERT INTO thePeople VALUES(239865,0,'T','Mary');
    So, here is my SQL that does not work well:
    SELECT p.employee, p.recordNum, p.lastName, p.firstName, e.emailaddress, e.emailactive, e.emailtype
    FROM thePeople p LEFT JOIN theemails e ON p.employee = e.employee
    WHERE (e.emailactive = 1)
          AND
          (e.emailtype = 'WRK1')
          AND
          (e.emailaddress LIKE '%school.edu')
    ;
    AND this:
    SELECT p.employee, p.recordNum, p.lastName, p.firstName, e.emailaddress, e.emailactive, e.emailtype
    FROM thePeople p LEFT JOIN theemails e ON p.employee = e.employee
    WHERE (e.emailactive = 1 OR e.emailactive IS NULL)
          AND
          (e.emailtype = 'WRK1' OR e.emailtype IS NULL)
          AND
          (e.emailaddress LIKE '%school.edu' OR e.emailaddress IS NULL)
    Both give me this:

    employee | record | lastName. firstName. emailAddress. emailActive | emailType
    231509 | 0 | P     | Michelle | [email protected] | 1. WRK1


    But what I need is the following:
    employee | record | lastName. firstName. emailAddress. emailActive | emailType
    239868 | 0 | K     | Dan |      |     |
    231509 | 0 | P     | Michelle | [email protected] | 1. WRK1
    239865 | 0 | T     | Mary |          |


    Email from Dan is not included, because his "wrk1" email does not stop it school.edu
    E-mail Mary is not included, because his 'wrk1' email is not active.
    However, I need to come back with their numbers of name registration and employee.


    Once it works, I'll add employee = number in the WHERE clause, because I only need to find a person both for the actual production.

    What I am doing wrong?

    Thank you!

    Michelle

    Hello

    WHERE is the filtering actually record the selection.

    In your case, you might want to include in your LEFT OUTER JOIN ON conditions:

    SELECT p.employee, p.recordnum, p.lastname, p.firstname
         , e.emailaddress, e.emailactive, e.emailtype
      FROM    thepeople p
           LEFT JOIN
              theemails e
           ON     p.employee = e.employee
              AND e.emailactive = 1
              AND e.emailtype = 'WRK1'
              AND e.emailaddress LIKE '%school.edu';
    

    If you put them in your JOIN conditions actually join Chronogram of table theemails that adapt to the conditions of membership.
    As you use LEFT [OUTER] JOIN unmatched chronogram thepeople table will be displayed even when the theemail table column appears with a NULL value in the output files

    I hope that I was able to unlock your brain. :-)

    Kind regards.
    Al

    Published by: Alberto Faenza on 25 October 2012 16:58
    Additional note added

  • Rewrite the query with joins, and group by

    Hello

    It's an interview question.

    Table names: bookshelf_checkout
    virtual library

    And the join condition between these two tables is title

    We need to rewrite under request without using the join condition and group by clause?

    SELECT b.title,max(bc.returned_date - bc.checkout_date) "Most Days Out"
               FROM bookshelf_checkout bc,bookshelf b
               WHERE bc.title(+)=b.title
               GROUP BY b.title;
    When I was in College, I read most of SELECT statements can be replaced by operations base SQL (DEFINE the OPERATORS). Now, I am rewriting the query with SET operators, but not able to get the exact result.

    Kindly help me on this.

    Thank you
    Suri

    Something like that?

      1  WITH books AS (
      2  SELECT 'title 1' title FROM dual UNION ALL
      3  SELECT 'title 2' FROM dual UNION ALL
      4  SELECT 'title 3' FROM dual ),
      5  bookshelf AS (
      6  SELECT 'title 1' title, DATE '2012-05-01' checkout_date, DATE '2012-05-15' returned_date FROM dual UNION ALL
      7  SELECT 'title 1' title, DATE '2012-05-16' checkout_date, DATE '2012-05-20' returned_date FROM dual UNION ALL
      8  SELECT 'title 2' title, DATE '2012-04-01' checkout_date, DATE '2012-05-15' returned_date FROM dual )
      9  SELECT bs.title, MAX(bs.returned_date - bs.checkout_date) OVER (PARTITION BY title) FROM bookshelf bs
     10  UNION
     11  (SELECT b.title, NULL FROM books b
     12  MINUS
     13* SELECT bs.title, NULL FROM bookshelf bs)
    SQL> /
    
    TITLE   MAX(BS.RETURNED_DATE-BS.CHECKOUT_DATE)OVER(PARTITIONBYTITLE)
    ------- ------------------------------------------------------------
    title 1                                                           14
    title 2                                                           44
    title 3
    

    Lukasz

  • Get the error invalid identifier in the left outer join

    I wrote a query and get the invalid identifier error during execution:
    the exact error is: ORA-00904: "D". "" ACCT_NO ": invalid identifier
    This query is not able to access the parent table alias in the subquery of the left outer join.

    This is the query:
    SELECT D.PROD_DESC_TX, BASE. ASSET_NUM, BASE. PROD_ID, BASE.NAME
    OF TABLE1 D
    LEFT OUTER JOIN
    (
    SELECT ASSET_NUM, PROD_ID, B.SID
    FROM TABLE2 E
    JOIN IN-HOUSE TABLE3 HAS IT E.PROD_ID = A.ROW_ID
    JOIN INTERNAL TABLE 4 C ON A.PAR_PROD_INT_ID = C.ROW_ID
    INTERNAL TABLE5 JOIN B ON C.ROW_ID = B.PAR_ROW_ID
    AND B.TYPE = 'VALUE '.
    AND B.NAME = 'VALUE '.
    WHERE E.ASSET_NUM = ((CASE WHEN LTRIM (RTRIM (D.BANK_NO)) = '021 ' THEN '021' ELSE ' 020' END) |) LTRIM (RTRIM (D.APPL_CD)). LTRIM (RTRIM (D.ACCT_NO)))
    ) BASE ON ((CASE WHEN LTRIM (RTRIM (D.BANK_NO)) = '021 ' THEN '021' ELSE ' 020' END) |) LTRIM (RTRIM (D.APPL_CD)). LTRIM (RTRIM (D.ACCT_NO))) = BASE. ASSET_NUM
    WHERE D.BANK_NO = 'VALUE '.
    AND D.APPL_CD = 'VALUE '.
    AND D.ACCT_NO = 'VALUE '.

    Edited by: user648525 13 Sep, 2011 01:21

    I can easily look at your request at this time (using my iPhone on a train).

    But trying out this line in the WHERE (the one with the invalid reference) clause in the main query.

    Who is... in the view of inline, use only the logic of the join (the clauses).

    Overflow the filtering logic (WHERE clause) to the main request. You may need to select some additional inline view columns to make these references work.

  • Must use the nested left join syntax?

    I am currently an editing view. The view has one with a followed left join to an inner join such as this:

    Select
    T1.a,
    T2.b,
    T3.c
    Of
    (select 1 as a Union double all the)
    Select 2 as double
    ) t1
    left join
    (select 1A, 11 b of all the double union)
    Select 2A, 12 b of the double
    ) t2
    on t1.a = t2.a
    Join
    T3 (select 11 b, 14-c double)
    on t2.b = t3.b;
    / * - Try out: -.
    A, B AND C
    ------- ------- -------
    1-11-14
    */

    The inner join converts left join in an inner join "de facto"? should I use nested join syntax in order to get the other ranks:

    Select
    T1.a,
    T2.b,
    T3.c
    Of
    (select 1 as a Union double all the)
    Select 2 as double
    ) t1
    left join
    (select 1A, 11 b of all the double union)
    Select 2A, 12 b of the double
    ) t2
    on t1.a = t2.a
    Join
    T3 (select 11 b, 14-c double)
    on t2.b = t3.b;
    / * - Try out: -.
    A, B AND C
    ------- ------- -------
    1-11-14
    */

    Sorry, just saw your last join condition now:

    on t2.b = t3.b;
    

    This results in a JOIN INTERNAL to the EXTERNAL table JOINED to, will certainly lead to a result of diminshed set - not quite the same that forced an INNER JOIN, but the result is the same, Yes. So there are indeed of equivalence.

    This, however, would not have resulted a reduced resultset:

    on t1.a = t3.a;
    

    But of course it is not possible, since the t3 has a column "a".

  • Rewrite the query in 11 g

    Hello

    Can anyone suggest an idea to rewrite this query? This query takes longer than expected, probably
    they way the application is made is not fair? Thanks in advance! I use 11g
     SELECT   brand_id,
                          region_id,
                          sku_base_id,
                          desc_key,
                          (SELECT   MAX (cps.product_code)
                             FROM   cat_prod_sku_vw cps
                            WHERE       cps.brand_id = srl.brand_id
                                    AND cps.region_id = srl.region_id
                                    AND cps.brand_id = 4
                                    AND cps.region_id = 0
                                    AND (   cps.parent_cat_id
                                         || 'PROD'
                                         || cps.prod_base_id) = srl.desc_text)
                             AS desc_text
                   FROM   sku_rgn_lang_vw srl
                  WHERE       brand_id = 4
                          AND region_id = 0
                          AND desc_key LIKE 'www_pcode_%'
                          AND LENGTH (desc_text) > 6
                          AND desc_text LIKE 'CAT%' ;

    You should look at this thread {message identifier: = 9360003} to get an idea of what other information is required.

    However, I'd be inclined to re - write as an (external) join instead of a scalar select statement. Something more like:

    SELECT srl.brand_id, srl.region_id, srl.sku_base_id, srl.desc_key,
           cps.desc_text
    FROM sku_rgn_lang_vw srl
       left join (SELECT brand_id, region_id,
                         parent_cat_id||'PROD'||prod_base_id desc_text
                         MAX (product_code) product_code
                  FROM cat_prod_sku_vw cps
                  WHERE brand_id = 4
                    AND region_id = 0
                  GROUP BY brand_id, region_id,
                           parent_cat_id||'PROD'||prod_base_id) cps
          on cps.brand_id = srl.brand_id AND
             cps.region_id = srl.region_id AND
             cps.parent_cat_id||'PROD'||cps.prod_base_id = srl.desc_text
    WHERE srl.brand_id = 4
      AND srl.region_id = 0
      AND srl.desc_key LIKE 'www_pcode_%'
      AND LENGTH (cps.desc_text) > 6
      AND cps.desc_text LIKE 'CAT%' ;
    

    Although I'm not entirely sure, I had all the correct alias.

    John

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