Round function

Similar Questions

• Do not round-function digital

  Hello

  Anyone know why the function rounded on the digital palette, as well as the connector of indexation of the array 'index' - function "1.5" to "2" and "2.5" to round down to '2 '.

  I learned that a '5' after the decimal point are always rounded upward.

  Lorand

  Hi Lorand,

  This has been asked before and probably will ask again...

  But Wikipedia has the explanation: rounded acceptances is defined by default for an IEEE754 implementation.

• Question of the ROUND function

  Hello

  No idea if this is right?

  Select (1100.55*(1/30)), ROUND ((1100.55*(1/30)), 2) to double;

  should 36.685 be 36,69 rounding?

  Thank you

  Vignesh

  Think about it:

  Select

  Round(1100.55*1/30,2)

  , round (1100.55*(1/30), 2).

  of the double

  ROUND(1100.55*1/30,2),ROUND(1100.55*(1/30),2)

  «36,69 ', ' 36,68»

  1/30 is something on 0,3333333333333333333...

  So if you force to calculate 1/30 first your result would be something about 36 684...

  If round(, 2) will end at 36,68.

  But 1100.55 can be divided by 3 without rest.

  But 1100.55 can be divided by 30 so that the result is finite (infinite not like 0.33333...) can be kept full by the number of data type.

  So, if the calculation order is 1100.55 divided by 1, then didved by 30, this would translate exactly in 36 685.

  It seems to me the use of parentheses introduced some binary float during the calculation, because it can be assumed with regard to landfills:

  Select

  dump(1100.55*1/30)

  dump (1100.55*(1/30))

  of the double

  DUMP(1100.55*1/30),DUMP(1100.55*(1/30))

  ' Type = 2 Len = 4: 193,37,69,51 Typ ',' 2 Len = 21 =: 193,37,69,50,100,100,100,100,100,100,100,100,100,100,100,100,100,100,100,100,97 ".

  Therefore, the result is a bit small (in this case, could be another average round in other cases) and turn therefore not lead to the expected result.

  Without the parentheses all operands are considered as numbers and so round gives the desired result.

  The reason may lie in the fact that oracle doesn't really change the bytes when converting from float to the number:

  Select

  dump (0.3)

  truck (cast (0.3f as number))

  of the double

  DUMP (0.3), DUMP (CAST(0.3FASNUMBER))

  ' Type = 2 Len = 2: 192,31 Typ ',' = 2 Len = 6: 192,31,1,1,2,21 ".

  Post edited by: chris227 corrected and extended

  Post edited by: chris227

• ROUND understanding function

  I have a question about the feature rounded
  
  Round(###.###,1)
  
  The output of the round function will depend on 2nd digit after the comma too or not?

  Hello

  965749 wrote:
  I "think" I understand the function round.
  the only problem is when it comes '9' otherwise it's cool
  Example: (45.86,1) - thin result - 45.9
  But (45.96,1) - is tricky because we get a whole number without fractions :)

  Don't let how a number is displayed confused you. 46 is the same number as 46.0, and they are both exactly the same as 46.00000000000.

  45.9x, where x is a digit, rounded down to 45,9, or rounded up to 46.0. (If you use the display of the number by default, 46.0 will be displayed as 46, without decimal point, but, once again, it is exactly the same number as 46.0.) 45.96 is closer to 46.0 is 45.9, so it will be rounded upwards.

• Rounded in MDX function

  I have serious performance problems when I use the feature rounded in MDX. Is this normal? Everyone knows the same problem? I tried to search for the answer formus, but looks like I'm the only one. Makes me feel I'm doing something wrong.
  
  I have a formula which calculates my average balances by dividing a numeric value of the nth day of the year, and I try to round off the result to 3 values of precision.

  In a presentation by Steve Libermensch (I hope that I don't butcher his name) last year to Kscope, he spoke on optimizing MDX calculations. One of the first things he said to do has been to remove formatting like round functions and leave the rounding reporting tool. Because internally, things are stored as anyway even if more precision round you

• How to write the function or procedure to function 'Round' in oracle

  Hello friends,
  
  Last week I went to attend the interview. I asked a function, or a procedure to achieve the functionality of the 'Round' function in oracle manually. I couldn't reach it properly. Can someone let me know how I can do this? Is a mathematical idea behind it?
  
  Thank you and best regards,
  SB

  Hello

  create or replace
  function my_round_fn (p_number in number, number of Round_Val)
  Return number
  is
  whole v_round;
  Start
  v_round: = P_number * Power (10, Round_Val);
  Return v_round / (Power (10, Round_Val));
  end my_round_fn;

  It works in all cases.

  Kind regards
  Praveen

• Round or truncate a calculated numeric variable

  I am turn CPQuizInfoPointsScored into percentage and display this to the learner. Sometimes it comes out as a whole number and sometimes it shows something like 97.597613269726%, which is not really desirable. When I display the variable in a text box, I use the 'X' and 'maximum length' setting to 3, but this does not appear to have any effect.

  Any ideas how I can round off our truncate the computed variable?

  Is there a particular reason why you do not use the system variable cpInfoPercentage quiz?

  Workaround would need a JS, Math.Floor or Math.round () function

• How to do manual rounding?

  Hi all

  I am currently in the need to do a round of a particular number. I am aware that oracle has the round() but I can't because of my requirements differ so that the function will provide.

  Here is an example of my situation:

  I need to round to the nearest 5(i think)...

  Suppose I have a value:

  80.21 > > 80.20

  80.22 > > 80.20

  80.23 > > 80,25

  80.24 > > 80,25

  80.26 > > 80,25

  80.27 > > 80,25

  80,28 > > 80,30

  80.29 > > 80,30

  What is the best way I could write the sql code to respond to the situation described above? the round() function will do a round based on the number below and above 5. This district is really need to round cents.

  If someone could propose an idea, that I would be grateful

  or a little bit simpler:

  results of the col de 9g990d00

  with t

  Select col1,

  result of the Round(col1*20,0)/20

  t;

  concerning

  Kay

• No Math.round. Now what?

  I'm trying to round a number that comes out of one of my workflow to the first decimal place for reports, but VCO does not have the Math.round function.   Someone at - it none of the recommendations on another way to do it?

  vCO has Math.round (); Simply not documented in the research of the API...

  var float1 = 1.2345;
  System.log(Math.round(float1));
  

  [18:37:45.563 2012-05-16] [I] 1

• Oracle rounding problem

  Rather strange to see behaviour below
  
  Select round (104.093749988719,4) in the 104.0937 double yields, while mathematically, it should be 104.0938
  
  What function can I use to get 104.0938
  
  Thank you
  SN

  >
  The question is I need to compare 2 columns and there 104.093749988719 and other has the 104.0938 round. So my comparison is a failure
  >
  And if the other number was really rounded to 104.0938 that the comparison MUST fail.

  See the ROUND function in the doc of the SQL language
  http://docs.Oracle.com/CD/E11882_01/server.112/e10592/functions155.htm#i78633
  >
  ROUND is implemented using the following rules:

  1. If n is 0, then ALL the returns always 0 regardless of how whole.

  2. If n is negative, then ROUND (n, all) returns - ROUND (-n, whole).

  3. If n is positive, then

  Round (n, Integer) = FLOOR (n * POWER(10, integer) + 0.5) * POWER (10, - all over)
  >
  You can always just add a '5' in the correct position if you want to always round regardless of the fraction.

  select round(104.093749988719 + .00005,4) from dual
  
  ROUND(104.093749988719+.00005,4)
  104.0938
  

• Incompatible rounding of the attributes of the currency in the 10.2 screen labels

  Hi all
  
  I see certain behaviors rounded interesting on screen labels in v10.2:
  
  -> Value
  $100,505 - > $100,50 [bad]
  $100,515 - > $100,52 [good]
  $100,525 - > $100,52 [bad]
  $100,535 - > $100,54 [good]
  $100,545 - > $100,54 [bad]
  $100.545001 - > $100,55 [good]
  
  ... and so on. There is an easy workaround (the Round function), but I'm curious of there is a lesson in OPA I'm missing here. Thoughts?
  
  Thank you
  -Patrick

  Do not forget that if 100.505 is entered by a user into a numeric field, it is represented as an approximation of this value in binary form. What you are probably seeing is the actual binary representation is equivalent to 100.5049999 - which once rounded gets converted to 100,50.

  OPA takes care of this for you when you make comparisons (for example a rule which says that the value > = 100.505 will work, even if the value = 100.505). But when rounded to an existing value for display, OPA cannot help with that.

• Deliver the result rounded to 2 decimal places.

  Good day to all,

  I currently have a script format in order to get the average of 10 fields in my form that also ignores the empty fields. Here is my current script:

  Initialize variables

  var num = 0;

  var sum = 0;

  Check input fields

  for (var i = 1; i < 10; i ++) {}

  var f = getField ("Assesment_Rating" + i);

  If {(f.valueAsString)

  increment the counter to non-empty field

  NUM ++;

  Add the value of the running total field

  sum += + f.value;

  }

  }

  Calculate the average

  If {(num)

  Event.Value = sum / num;

  } else {}

  If the fields are empty, so put to white

  Event.Value = "";

  }

  He is currently working if I have a total of 1.4444444444444, this is what is displayed. I tried a few functions of Math.Round who give me "1.5" as a result that is not correct. I'm still learning so I could try a Math.Round function in the bad part of my code, but can not get the result I need.

  Thank you in advance for your help!

  This script should be a personalized calculation script that sets the value of the field. You can then set the type of number format and two decimal places.

• Always round

  I am trying to find a way to always round up to the next whole. For example if I 2.08 I to need to return 3. If I try this SELECT ROUND (2.08) FROM DUAL; It rounds to 2. I'm using Oracle 11 g. Any help would be appreciated. Thank you.

  792208 wrote:
  I am trying to find a way to always round up to the next whole. For example if I 2.08 I to need to return 3. If I try this SELECT ROUND (2.08) FROM DUAL; It rounds to 2. I'm using Oracle 11 g. Any help would be appreciated. Thank you.

  Add 0.5 before applying the ROUND() function

• [TOUR] Function of digital computing

  Hello everyone. I'm trying to put the [ROUND] function in my SQL statement, but nothing helped. It's my SQL statement:
  
  
  SELECT company
  (SELECT COUNT (VACANCY) OF THE MASTER WHERE VACANCY = 'NO') / (SELECT COUNT (COMPANY) OF MASTER WHERE COMPANY = 'XYZ') * 100 "PERCENT BUSY."
  THE MASTER
  where the COMPANY = "XYZ".
  Group of company
  
  
  After this SQL statement executes, there are like 20 decimal places to the right and I wan't no decimal point.
  Any help would be appreciated.

  Try

  SELECT company
  ROUND ((SELECT COUNT (VACANCE) OF THE MASTER WHERE VACANCY = 'NO') / (SELECT COUNT (COMPANY) OF MASTER WHERE COMPANY = 'XYZ') * 100, 2) "% BUSY."
  THE MASTER
  where the COMPANY = "XYZ".
  Group of company

• Round my values in the form of DATA

  Hello
  
  Are there opportunities that I could gather my values in forms of data?
  
  245.587 = 246
  
  
  Thank you

  Have you had a look at the accuracy of form settings - http://download.oracle.com/docs/cd/E17236_01/epm.1112/hp_admin/frameset.htm?form_opt.html
  Otherwise, you might have a business rule that rounds the values using the @ROUND function - http://download.oracle.com/docs/cd/E17236_01/epm.1112/esb_tech_ref/round.html

  See you soon

  John
  http://John-Goodwin.blogspot.com/