RV180W and counter traffic WAN (bug?)

Hello, this is a documented problem

WAN Download won't exceed 60Mbps for the RV180 when WAN Traffic Meter is enable.

WAN Download won't exceed 90Mbps for the RV180W when WAN Traffic Meter is enable.

- Firmware's: 1.0.0.30 and 1.0.1.9;

CSCtz81982




-Tom
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Amnesty International and counter sync + USB signal stream (USB-6210 vs USB-6341)
 
			 
Hi all
I'm at a stage of identification of a material suitable for the following tasks:
5 analog inputs (AIs) of reading at the same time, tensions at a rate of kSps (at least) 10,
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It work? Other recommendations?
Next is the USB data transfer: all HAVE 5 and 2 data entry of the meter must be correctly transferred to the host computer (the corresponding rates are shown above). USB-6210 is capable of 4 USB signal flow, device USB X range (6341) offers 8 of them. Unfortunately, I could not understand the exact meaning of the expression "signal flow" still. Do I need 1 flow of input signals (would be 7 for my application described) or 1 stream for all analog inputs and 1 for counter inputs (lead 2 streams for my request). Is there no further details on this approach (more than Streaming of signals of NOR) USB signal flow?
Any challenge to the described application that I might have forgotten? 6210 USB seems to a very limited number of entry PFI, maybe even too low for my meter participate application?
Looking forward to your comments and advice.
Concerning
jAwA
			 
1. I recommend the X-6341 series on the M-series 6210 sake of counters/timers.  It is more of them, and each of them is more capable.   It can also have a great FIFO embarked for meters that may be important in certain tasks, although I don't think that you currently deal with one of them.
2. your general concepts on timing & sync are satisfactory.  You will be able to share and to route signals that help ensure synchronization and determinism between the timestamps for your various tasks.  Note that for meter entry tasks, you need set up the trigger 'Arm Start' rather than the regular start trigger.
3 is not authoritarian, but I believe that the flow of signal # will correspond to the tasks #.  For you, it would be 1 task of HAVE and tasks CI 1 or 2.  (Not clear if you have 1 Encoder with 2-channel quad that would require 1 task of CI, or if you have 2 encoders with 4-way quad).
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Hi @Zarped ,
Thank you for visiting the HP Forums! A place where you can find solutions for your problems, with the help of the community!
I stumbled upon your post on the laptop and wanted to help you! I looked in your question on your HP ENVY 15-j012la Notebook and problems with it does not not with a Windows 10 update. Try perform a reset.
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Hello Board,
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Hi M.B.
6143 does not support Correlated DIO (i.e. clocked by the hardware), the 6133 (see-> digital I/o--> Timing). As a result, synchronized doing of entry works with the latter. Acquisition of meter in the buffer is available on both devices. The 6133 also authorizes analog and digital triggering.
To synchronize these tasks, you need to export a clock signal (sample clock HAVE for example) and take to the DIOs and counters for an acquisition in the buffer. An example for synchronization of AI and DI is given once you install the DAQmx driver in the folder when you are using Windows XP. Maybe you can start with that and gradually add your features.

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A protocol that would provide the service for IPv4 and IPv6 traffic?
RIPv1
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selection of special days and counting
 
			 Hi all
I need to select certain dates and the following days with the same criteria.
An example would be:


CREATE TABLE DEMO
(
EMP_ID NUMBER NOT NULL,
WORKING_DAY DATE NOT NULL,
ACTIVE_CODE NULL VARCHAR2 (1).
CONSTRAINT DEMO_PK
KEY ELEMENTARY SCHOOL (EMP_ID, WORKING_DAY)
USING INDEX
)




INSERT INTO DEMO (EMP_ID, WORKING_DAY, ACTIVE_CODE) VALUES (123, TO_DATE ('01.11.2010 00:00:00 '), '_');
INSERT INTO DEMO (EMP_ID, WORKING_DAY, ACTIVE_CODE) VALUES (123, TO_DATE ('02.11.2010 00:00:00 '), '_');
INSERT INTO DEMO (EMP_ID, WORKING_DAY, ACTIVE_CODE) VALUES (123, TO_DATE ('03.11.2010 00:00:00 '), 'K');
INSERT INTO DEMO (EMP_ID, WORKING_DAY, ACTIVE_CODE) VALUES (123, TO_DATE ('04.11.2010 00:00:00 '), 'K');
INSERT INTO DEMO (EMP_ID, WORKING_DAY, ACTIVE_CODE) VALUES (123, TO_DATE ('05.11.2010 00:00:00 '), 'K');
INSERT INTO DEMO (EMP_ID, WORKING_DAY, ACTIVE_CODE) VALUES (123, TO_DATE ('06.11.2010 00:00:00 '), NULL);
INSERT INTO DEMO (EMP_ID, WORKING_DAY, ACTIVE_CODE) VALUES (123, TO_DATE ('07.11.2010 00:00:00 '), NULL);
INSERT INTO DEMO (EMP_ID, WORKING_DAY, ACTIVE_CODE) VALUES (123, TO_DATE ('08.11.2010 00:00:00 '), 'K');
INSERT INTO DEMO (EMP_ID, WORKING_DAY, ACTIVE_CODE) VALUES (123, TO_DATE ('09.11.2010 00:00:00 '), '_');
INSERT INTO DEMO (EMP_ID, WORKING_DAY, ACTIVE_CODE) VALUES (123, TO_DATE ('10.11.2010 00:00:00 '), 'K');
INSERT INTO DEMO (EMP_ID, WORKING_DAY, ACTIVE_CODE) VALUES (123, TO_DATE ('11.11.2010 00:00:00 '), '_');


Now, I'm looking for the first day with Active_Code = 'K' and count the days that have 'K', too.
Expected result: November 3-> 4 Ks (because the 8 is after the weekend); 10 November-> 1 K


I hope that the example/explanation is not too bad...


I built a procedure which was to count the occurrences, if I give the first occurrence (here the 3rd and 8th).
But findign the first 'K' is my problem.
A solution would be:
AND
(SELECT T2. T2 DEMO ACTIVE_CODE
WHERE T2. EMP_ID = T1. EMP_ID AND T2. WORKING_DAY = T1. WORKING_DAY-1) <>'K '.
AND
(SELECT T2. T2 DEMO ACTIVE_CODE
WHERE T2. EMP_ID = T1. EMP_ID AND T2. WORKING_DAY = T1. WORKING_DAY-2) <>'K '.
AND
(SELECT T2. T2 DEMO ACTIVE_CODE
WHERE T2. EMP_ID = T1. EMP_ID AND T2. WORKING_DAY = T1. WORKING_DAY-3) <>'K '.


But it is pretty darn imperformant if I'm dealing with millions of records :-(


Could someone please give me a hint on how to solve this problem?
Thank you.


Best regards
Christian			 
Hi, Christian,.
Assumiung you have exactly one line for each working_day (where active_code is not NULL):
WITH     got_grp_num     AS
(
     SELECT     emp_id
     ,     working_day
     ,     active_code
     ,       ROW_NUMBER ()
                  OVER ( PARTITION BY  emp_id
                      ORDER BY          working_day
                    )
           - COUNT ( CASE
                   WHEN  active_code = 'K'
                   THEN  1
               END
                )     OVER ( PARTITION BY  emp_id
                      ORDER BY          working_day
                    )      AS grp_num
     FROM     demo
     WHERE     active_code     IS NOT NULL
--     AND     ...     -- Any filtering goes here
)
SELECT       emp_id
,       MIN (working_day)     AS first_day
,       COUNT (*)          AS cnt
FROM       got_grp_num
WHERE       active_code     = 'K'
GROUP BY  emp_id
,       grp_num
ORDER BY  emp_id
,         first_day
;

I'm guessing on the emp_id role in this problem.
The trickiest part of this problem is to obtain an appropriate value for the GROUP BY.
When you have several consecutive lines of 'K', the difference between the ROW_NUMBER (in cash lines no 'K', but not weekends) and the number of lines of 'K' previous will be constant. This is what grp_num is. (A non - adjacent lines 'K' also has the same grp_num, but that's OK, it will be rejected by the WHERE clause in the main query.)
Published by: Frank Kulash, November 4, 2010 05:43
		   
 
            
           
 
		     
Worn and counting on the same query?
 
			 I have a table with the following fields: groupname, FULL_NAME, DEFAULT_X, SUPPORT_GROUP_ID and PERSON_ID (among others)
A user (PERSON_ID) can be different times, they appear once for each group (SUPPORT_GROUP_ID) that they are assigned to.
When the DEFAULT_X == 0, this means that the user's default group is on this line. Each user should have only one only by default the group, but for some reason, the table was corrupted and there are a few users that don't have a default group.
What I'm trying to do is to select all the users (FULL_NAME, PERSON_ID) where the PERSON_ID COUNTY is equal to the SUM of DEFAULT_X
It sounds easy enough, but I don't even know where to start.
Any suggestions?			 
Hello
So you say
default_x = 0 if this is the default group, and
default_x = 1 in all other cases
Is this fair?
If so, you can say:
SELECT    person_id
FROM      table_x
GROUP BY  person_id
HAVING    COUNT (*) = SUM (default_x);

HAVING is similar to WHERE, except that HAVING is applied after the merger took place and functions of aggregation (like SUM and COUNT) were calculated.
However, your problem is that default_x is not entered correctly. If default_x is sometimes 1 to 0, are not concerned it may contain other errors, like having 2 or - 1, whereas she would have to have 1?
Here's a better way to find person_id who don't exactly have a single line with default_x = 0:
SELECT    person_id
FROM      table_x
GROUP BY  person_id
HAVING    SUM
          (
              CASE
                  WHEN  default_x = 0
                  THEN  1
                  ELSE  0
              END
          ) != 1;