Select a record for each Member of the Group

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• SQL query to retrieve a single record for each employee of the following table?

  Hi all

  Help me on the writing of SQL query to retrieve a single record for each employee of the following table? preferably a standard SQL.

  CREATE TABLE xxc_contact)

  empnum NUMBER,

  alternatecontact VARCHAR2 (100),

  relationship VARCHAR2 (10),

  phtype VARCHAR2 (10),

  Phone NUMBER

  );

  insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Cell', 9999999999)

  insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Work', 8888888888)

  insert into xxc_contact values (123457, 'Daryl Dixon', 'EN', 'Work', 7777777777)

  insert into xxc_contact values (123457, 'Daryl Dixon', 'EN', 'Home', 3333333333)

  insert into xxc_contact values (123456, 'Maggie Greene', 'CH', 'Cell', 9999999999)

  insert into xxc_contact values (123456, 'Maggie Greene', 'CH', 'Home', 9999999999)

  expected result:

  EmpNum AlternateContact Relationship PhType Phone       

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  Thanks in advance.

  994122 wrote:

  Thank you all, that I got a result

  http://www.orafaq.com/Forum/m/620305/#msg_620305

  By Lalit Kumar B...

  Specifically, the two simple solutions provided were:

  1 using the row_number, entitled Oracle ranking based on descending order of the inside telephone each empnum group. And finally selects the lines which has least rank (of least since that order is descending for phone).

  SQL > column alternatecontact format A20;

  SQL >

  SQL > SELECT empnum, alternatecontact, relationship, phtype, phone

  2 from (SELECT a.*, row_number() over r (PARTITION BY empnum ORDER BY phone / / DESC))

  3 FROM xxc_contact one)

  4. WHEN r = 1

  /

  EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE

  ---------- -------------------- ---------- ---------- ----------

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  2. with the help of MAX, Oracle automatically assigns the maximum phone for all the rows in each group of empnum. And finally selects the rows with the maximum phone. Order by clause is omitted here intentionally. You can find out why.

  SQL > SELECT empnum, alternatecontact, relationship, phtype, phone

  2 (SELECT a.*, MAX (phone) over (PARTITION BY empnum) rn FROM xxc_contact one)

  3 WHERE phone = rn

  4.

  EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE

  ---------- -------------------- ---------- ---------- ----------

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  Kind regards

  Lalit

• Ungroup a group and keep the scriptlabel for each item in the Group

  Hello

  does anyone know how to ungroup a group of rectangles with a certain tag (example groupA) give one every rectangle a clean label (the same text groupA)

  I can find the Group and ungroup it but I can't label the rectangles...

  var oPageItems = app.activeDocument.allPageItems;

  for (var j = oPageItems.length - 1;)  j > = 0; d-) {if (oPageItems [j] .label == ("groupA")) {oPageItems [j] .ungroup ()))}}

  ...???

  Help, please

  Hello

  front

  oPageItems [j] .ungroup ();

  go through the loop and set a label for each item within the Group:

  for (var k; k)< opageitems[j].length;="">

  oPageItems [j] [k] .label = "groupA";

  assuming that your oPageItems [j] is a group indeed.

  I hope that...

• Are there separate libraries for each Member in the family plan?

  We want to start the Apple family of music Plan in our House, but everyone in my family wants to add their own music and to keep it separate from the rest of the members of the plan.

  I have 2 questions about it:

  1. every member gets their own library of music that they can sort and customize without interfering with the music of other members?

  2. each member individually has the limit of 100,000 of the song, or is it 100 000 songs for the whole family?

  We will get the plan until these issues are addressed, if anything like that would be useful!

  Hi Josie1374,

  I understand that you have a few questions about the sharing of family in Apple music. I have some information for you which should be able to help answer these questions. First of all, you should know that each family member in the family of the Apple music-sharing plan will be themselves, individual account, Apple's music:

  A subscription to Apple's music for
  each Member of your family.

  With a family membership of Apple's music, up to 6 people in your family can enjoy unlimited access to music from Apple on their devices. Everyone gets full access and individual music library of Apple, recommendations of experts, radio world-wide 24/7 with 1 beats and radio on demand. This is the world of music for the creations of any

  iCloud - family sharing - Apple

  https://www.Apple.com/icloud/family-sharing/

  As is the case, this information applies to each individual account, which should solve your second question:

  How music Apple manages your downloaded songs

  • You can have up to 100 000 songs in your music library. Songs you purchased from the iTunes Store do not count against this limit.

  Add music to your collection to your music library Apple - Apple Support

  https://support.Apple.com/en-us/HT204925

  Be vigilant and thank you for visiting the communities of Apple Support.

• I need a query that selects the amount of records for each day of a table.

  I need a query that selects the amount of records for each day of a table.
  For example, the result would be:
  
  1 14 date
  Date 2-3
  
  etc.
  
  Any ideas?

  Sort:

  SELECT count ([IDCommentaire]), convert (varchar, dateAdded, 112)

  OF COMMENTSgroup by convert (varchar, dateAdded, 112)

• For all the records for each record double, I need to get a single column with null or 0.

  Hi all

  I have a requirement where I need to get all the records, for each record in double, I need to get a single column with null or 0.

  create table a1

  (

  Identification number,

  VARCHAR2 (100), the point

  part varchar2 (100));

  Insert into a1

  values (1, 'ABC', 'A1');

  Insert into a1

  values (2, 'DEF', 'A2');

  TABLE A

  PART ITEM ID

  1 ABC A1

  1 ABC A1

  1 ABC A1

  DEF 2 A2

  DEF 2 A2

  3 DEF A2

  O/P

  PART ITEM ID

  1 ABC A1

  1        ABC             0

  1        ABC             0

  DEF 2 A2

  2       DEF              0

  3       DEF              0

  Thanks in advance.

  Thanks for your help FrankKalush...

  This one will work.

  WITH got_r_num AS

  (

  SELECT NVL (a1.id, a1.id) as id

  NVL (a1.item, a1.item) AS element

  NVL (a1.part, a1.part) IN the framework

  a1.id AS a_id

  ROW_NUMBER () OVER (PARTITION BY a1.id

  ORDER BY NULL

  ) AS r_num

  BY the a1

  )

  SELECT id

  element

  CASE

  WHEN a_id IS NOT NULL

  AND r_num = 1

  THEN part

  ELSE ' 0'

  END in the framework

  OF got_r_num

  ;

• Select the last value for each day of the table

  Hello!
  
  I have a table that contains several measures for each day. I need two queries on this table, and I'm not sure how to write them.
  
  The table stores the rows (sample data)
  

  *DateCol1                 Value       Database*
  27.09.2009 12:00:00       100           DB1
  27.09.2009 20:00:00       150           DB1
  27.09.2009 12:00:00       1000          DB2
  27.09.2009 20:00:00       1100          DB2
  28.09.2009 12:00:00       200           DB1
  28.09.2009 20:00:00       220           DB1
  28.09.2009 12:00:00       1500          DB2
  28.09.2009 20:00:00       2000          DB2

  Explanation of the data in the sample table:
  We measure the size of the data files belonging to each database to one or more times a day. The value column indicates the size of the files of database for each database at some point (date in DateCol1 European model).
  
  
  What I need:
  Query 1:
  The query must return to the last action for each day and the database. Like this:

  *DateCol1       Value      Database*
  27.09.2009        150          DB1
  27.09.2009       1100          DB2
  28.09.2009        220          DB1
  28.09.2009       2000          DB2

  Query 2:
  The query should return the average measurement for each day and the database. Like this:

  *DateCol1       Value      Database*
  27.09.2009       125          DB1
  27.09.2009      1050          DB2
  28.09.2009       210          DB1
  28.09.2009      1750          DB2

  Could someone please help me to write these two queries?
  
  Please let me know if you need further information.
  
  Published by: user7066552 on September 29, 2009 10:17
  
  Published by: user7066552 on September 29, 2009 10:17

  Why two queries when it suffice ;)

  SQL> select dt
    2       , db
    3       , val
    4       , avg_val
    5    from (
    6  select dt
    7       , val
    8       , db
    9       , row_number () over (partition by db, trunc (dt)
   10                                 order by dt desc
   11                            ) rn
   12       , avg (val) over (partition by db, trunc (dt)) avg_val
   13    from test)
   14   where rn = 1
   15  order by dt
   16  /
  
  DT        DB           VAL    AVG_VAL
  --------- ----- ---------- ----------
  27-SEP-09 DB2         1100       1050
  27-SEP-09 DB1          150        125
  28-SEP-09 DB2         2000       1750
  28-SEP-09 DB1          220        210
  

• How can I make a cell formula will apply for the entire column? For example D2 appears B2 - C2. How can I copy this formula for each cell in the column?

  How can I make a cell formula will apply for the entire column? For example D2 appears B2 - C2. How can I copy this formula for each cell in the column?

  If you want the formula is the same (B2 - C2) in the cell of each column you must change it as ($B$ - 2$ C$ 2). Then copy it, select the whole column and paste.

• Where is 'Create a separate record for each volume' past? in VMware-converter - 4.0.1 - 161434.

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• Creation of 5 rows in table B for each row in the table has

  create table A
  (col1 number,
  col2 varchar2(20)
  )
  /
   
  create table B
  (col1 number,
  col2 varchar2(20)
  )
  /
  
  insert into A values (1,'Jane');
  insert into A values (2,'Kate');
  insert into A values (3,'Stomp');
  
  
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        COL1 COL2
  ---------- -----------------
           1 Jane
           2 Kate
           3 Stomp

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  ---------- -----------------
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           3 Jane
           4 Jane
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  A way

  insert into b
  select rownum*5  , col2 from a
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  JDeveloper 12.1.3.0.0

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• The opportunity to identify a specific storage for each user or security group.

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• Hierarchy with each Member of the child's repeated occurrences

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