Select help

Similar Questions

• When I select Help and support icon, I get an error message indicating that the feature could not start.

  help and support does not work

  When I select Help and support icon, I get an error message indicating that the feature could not start.

  I use a Vista 32 bits on a HP computer operating system model number m8300f.

  In addition, I bought a copy of Win 7, but who could not load freezing during installation.

  Hello

  Try to run the command in the elevated command prompt, follow the steps below, it could help us solve the problem.

  1. open the start menu, click programs principally made, select accessories.
  2. right click on command prompt, and then click "run as administrator ".
  3. type the following commands in the DOS prompt window and press ENTER at the end
  of each line:

  REGSVR32 MSXML3. DLL/U
  REGSVR32 MSXML3. DLL
  REGSVR32 MSXML6. DLL/U
  REGSVR32 MSXML6. DLL

  (At the elevated command prompt command should not give us any error).

  Restart the computer and try to access help and Support.

  For the problem of installation of windows 7.

  We would like to get more information about you to help solve your problem. You better, please answer the following questions.

  1. How did you start the installation process?

  2. you perform a new installation or an upgrade?

  3. what type of drive you are using for installation?

  4. at what stage of the installation has it stopped?

  5. have you received an error message?

  First of all, I would say that you disconnect external devices connected to the computer except the keyboard and mouse.

  If you have performed an upgrade suggests to restart the computer and you will be prompted for a roll back option.

  Once you're on the office suggests to run Upgrade Advisor and check what needs to be done before you start the upgrade.

  Before you begin the upgrade process to ensure that your computer meets the condition of equipment to install Windows 7 and check on the website of manufacturer computer if the computer is good to run windows 7 or not.

  Installing and reinstalling Windows

  http://Windows.Microsoft.com/en-us/Windows7/installing-and-reinstalling-Windows

• Sequence by select Help please:

  First of all, I'm rather at this new and need help please.

  I created the following sequence:

  CREATE SEQUENCES SQ_CASE_NUMB

  MINVALUE 1

  INCREMENT BY 1

  START WITH 1

  And from this sequence select it below:

  SELECT TO_CHAR (SQ_CASE_NUMB. NEXTVAL)

  | | To_char (SYSDATE, "fm/MM/yy")

  Case_NUMB

  OF THE DOUBLE

  Result:

  Case_NUMB

  08/01/14

  08/02/14

  08/03/14

  Can I combine the sequence 'create' and 'select '? Or should I create a function?

  What is the best option please?

  It depends on what you're trying to reach.  What you use the sequence for?  Primary key?  Experiment?  fun?

  Best option can be answered only if you provide the object...

  BTW - the select query above works, but it does not mean that you should use...  The best thing to do (if you use it as a primary key) is to create a trigger like this:

  create or replace

  TRIGGER "insert name here".

  BEFORE INSERT ON table_name

  FOR EACH LINE

  BEGIN

  SELECT sequence_name. NEXTVAL INTO: DOUBLE NEW.pkcolumn_name;

  END;

• SQL - select Help - box When? Return value of the second Table?

  -Next to people on this forum I am probably somewhere between a beginner and an intermediate SQL user.

  Ive been using a case when stated in plsql to find "all who has status in any program was canceled during a specific time, but have become or are still active in another program"

  So, Im actually trying to return a value from another table in a case where, but this isn't anthing taste other than a text declared as 'Yes' or 'no '.

  This is the select statement - y at - it another way to do it where I can get the results I need?

  -case when pp.party_id in (select pp1.party_id - cancelled active clients in another program)

  of asa.program_participation pp1,.

  ASA.curr_prog_participation_status cpps1

  where pp1.program_participation_id = cpps1.program_participation_id

  and pp1.party_id = pp.party_id

  and cpps1.code_value = 'Act')

  So 'Yes' is still 'No' end as Active_in_Other_Prg

  So - instead of 'Yes', I want essentially the program they are active or pp1.program_id, another null

  It is possible that the client can be active in more than one program as well.

  Any help is greatly appreciated, I explored with if and decodes but I can't get anything to work.

  Ben

  Looks like an outer join. See doc ora: joins at

  Select p

  q.party_id

  q.program_id

  of table_with_party_id p

  , (select pp1.party_id - cancelled active clients in another program)

  pp1.program_id

  of asa.program_participation pp1,.

  ASA.curr_prog_participation_status cpps1

  where pp1.program_participation_id = cpps1.program_participation_id

  and pp1.party_id = pp.party_id

  and cpps1.code_value = 'ACT') q

  where p.party_id = q.party_id (+)

  Note: In the example above shoudn't it be a space between the (and +), but the forum software automatically converts to

  The outer join will connect display all records in the table p and q records only if fits the party_id, IE q.party_id and q.program_id will be null if there is no match.

  Edit: adding program_id

• Select help with sql

  Hello
  could you please help write select sql to retrieve the maximum number of concurrent users, something to check?
  
  user_id, rec_start, rec_end
  1, 01.10.2009 12:01, 01.10.2009 13:11
  2, 01.10.2009 13:12, 01.10.2009 14:04
  3, 01.10.2009 13:35, 01.10.2009 13:55
  1, 01.10.2009 14:35, 01.10.2009 14:50
  1, 01.10.2009 14:45, 01.10.2009 14:50
  
  I would like:
  hour, max_of_conc_users
  01.10.2009 12: 1 - no more then 1 user at the same time
  01.10.2009 13: 2 - user_id 2and 3 record at the same time
  01.10.2009 14: 2 - user_id 1 to 2 sessions
  
  Thank you
  D.

  Hello

  Interesting problem!

  We will change a bit, your sample data for the (total connections per hour) much simpler problem solved by Sven and Hoek has not coincidentally the same results as your problem (the high concurrent users per hour).
  I changed the data of Hoek, adding a line, which has been lgged in for the entire period covered by others:

  CREATE TABLE t as
    select 9 user_id, to_date('01.10.2009 12:01', 'dd.mm.yyyy hh24:mi') rec_start, to_date('01.10.2009 14:49', 'dd.mm.yyyy hh24:mi') rec_end from dual union all
    select 1 user_id, to_date('01.10.2009 12:01', 'dd.mm.yyyy hh24:mi') rec_start, to_date('01.10.2009 13:11', 'dd.mm.yyyy hh24:mi') rec_end from dual union all
    select 2, to_date('01.10.2009 13:12', 'dd.mm.yyyy hh24:mi'), to_date('01.10.2009 14:04', 'dd.mm.yyyy hh24:mi') from dual union all
    select 3, to_date('01.10.2009 13:35', 'dd.mm.yyyy hh24:mi'), to_date('01.10.2009 13:55', 'dd.mm.yyyy hh24:mi') from dual union all
    select 1, to_date('01.10.2009 14:35', 'dd.mm.yyyy hh24:mi'), to_date('01.10.2009 14:50', 'dd.mm.yyyy hh24:mi') from dual union all
    select 1, to_date('01.10.2009 14:45', 'dd.mm.yyyy hh24:mi'), to_date('01.10.2009 14:50', 'dd.mm.yyyy hh24:mi') from dual
  ;
  

  The query below unpivots these data in separate lines for rec_start and rec_end. We use the analytical SUM function to count each + 1 rec_start and each rec_end as -1 to get the number of concurrent users at any time. As soon as we have these data, we can use GROUP BY TRUNC (dt, 'HH')as Sven Hoek has suggested, to get the maximum by houir:

  WITH     cntr         AS
  (
       SELECT     1  AS cnt     FROM dual     UNION ALL
       SELECT     -1 AS cnt     FROM dual
  )
  ,     events     AS
  (
       SELECT     CASE     cntr.cnt
                 WHEN   1  THEN  t.rec_start
                 WHEN  -1  THEN     t.rec_end
            END     AS dt
       ,     cntr.cnt
       FROM          t
       CROSS JOIN     cntr
  )
  ,     concurrent_users     AS
  (
       SELECT     TRUNC (dt, 'HH')          AS hour
       ,     SUM (cnt) OVER (ORDER BY dt)     AS concurrent_users
       FROM     events
  )
  SELECT       hour
  ,       MAX (concurrent_users)     AS max_of_conc_users
  FROM       concurrent_users
  GROUP BY  hour
  ORDER BY  hour;
  

  Output:

  HOUR             MAX_OF_CONC_USERS
  ---------------- -----------------
  01.10.2009 12:00                 2
  01.10.2009 13:00                 3
  01.10.2009 14:00                 3
  

• Select help request - integrated

  Hello
  
  The following query will show me the catalog ID and Descriptions of all the outfits hired
  for each branch, with revenues generated in descending order...
  

  SELECT Members_Order.Catalogue_ID, Item.Item_Description, Item.Colour Orders.Branch_ID, Item.Hire_Charge, Members_Order.Number_of_Days, (Hire_Charge*Number_of_Days) AS Total
  From Members_Order, Item, Orders
  WHERE Members_Order.Item_ID = Item.Item_ID
  AND Members_Order.Order_ID = Orders.Order_ID
  ORDER BY Total DESC;

  What I want to do now is to create a query to display the details of the outfits, which are the same color as the suit that has generated the most revenue. I'm guessing that this will involve a choose embedded, using the base of the query above, but I'm not sure about what should go with the select embedded?
  
  I have the following to this day, could someone help me finish or point me to the right direction...?
  

  SELECT Members_Order.Catalogue_ID, Item.Item_Description, Item.Colour, Item.Hire_Charge, Members_Order.Number_of_Days, (Hire_Charge*Number_of_Days) AS Total
  From Members_Order, Item, Orders
  WHERE Members_Order.Item_ID = Item.Item_ID
  AND Colour = (SELECT Colour FROM Item WHERE 
  ;

  Published by: user10945931 on April 15, 2009 19:50

  Hello

  I'm surprised that ran at all.

  I made a mistake in my previous answer. The second line of SELECTION (right before ROW_NUMBER) shouldn't be there at all. My apologies.
  Here's what I meant:

  WITH  ranked_data  As
  (
       SELECT  Members_Order.Catalogue_ID
       ,     Item.Item_Description
       ,     Item.Colour
       ,     Orders.Branch_ID
       ,     Item.Hire_Charge
       ,     Members_Order.Number_of_Days
       ,     (Hire_Charge * Number_of_Days)     AS Total
       ,     RANK () OVER (ORDER BY Hire_Charge * Number_of_Days DESC)
                                                 AS rnk
       FROM     Members_Order
       ,     Item
       ,     Orders
       WHERE     Members_Order.Item_ID     = Item.Item_ID
       AND     Members_Order.Order_ID     = Orders.Order_ID
  )
  SELECT     *     -- or list all columns except rnk
  FROM     ranked_data
  WHERE     colour  = (
              SELECT  colour
              FROM       ranked_data
              WHERE       rnk     = 1
              );
  

• Select help request

  Oracle version 10.2.0.2.0

  Can I write in a single SQL aside the function instead of if... else. I tried with the case but not thru. Please advice

  FUNCTION mark_place

  (

  i_year in NUMBERS

  i_month in varchar2,

  i_school_code in varchar2,

  i_paper_code in varchar2,

  i_condition in varchar2)

  Return number

  IS

  number of mark_count;

  Start

  IF i_condition = "COMPLETE" THEN

  Select count (criteria_mark_status) in mark_count

  of ssn_yes

  where school_code = i_school_code

  and year = i_year

  and month = i_month

  and paper_code = i_paper_code

  and criteria_mark_status = "COMPLETE";

  on the other

  Select count (criteria_mark_status) in mark_count

  of ssn_yes

  where school_code = i_school_code

  and year = i_year

  and month = i_month

  and paper_code = i_paper_code

  and criteria_mark_status! = "FULL";

  END IF;

  Return mark_count;

  end mark_place;

  An option

   select count(criteria_mark_status) into mark_count
      from ssn_yes
      where   school_code = i_school_code
      and year = i_year
      and month = i_month
      and paper_code = i_paper_code
      and (case
              when i_condition = 'COMPLETE' and criteria_mark_status  = 'COMPLETE' then 'VALID'
              when i_condition != 'COMPLETE'and criteria_mark_status  != 'COMPLETE' then 'VALID'
        end) = 'VALID';
  

  See you soon

  AJ

• Why by selecting 'help' in Premiere Elements give me a message forbidden http403?

  Why choose 'Help' in the first elements 11 "give me a 403 Forbidden message?

  DonOma

  Thanks for the follow-up.

  All the links I posted were the links that you should be able to click on open in the Help Menu of first Elements 11.

  You have another browser besides Internet Explorer - Firefox or Chrome?

  We will follow to your results.

  RTA

• sum sql select help

  Hello.
  In a table, I keep product_id, sale_date, amount order_id
  
  How is possible to select the County (order_id) and flat per day in a month
  but visible every day in a month
  
  Concerning
  ARIS DC

  To view all the days of March, even if no sale is present for a few days:

  select to_char(sale_date,'dd-mm-yyyy') day, count(order_id), sum(amount)
  from yourtable,
       (select to_date('20100301','yyyymmdd')+level-1 mydate
          from dual
        connect by level <= to_date('20100331','yyyymmdd')-to_date('20100301','yyyymmdd')+1) dates
  where sale_date(+) = mydate
  group by to_char(sale_date,'dd-mm-yyyy')
  

  Max
  http://oracleitalia.WordPress.com

• selecting help

  I have the query like this
  
  SELECT DISTINCT
  BILL OF RIGHTS. ROUTING_SEQUENCE_ID,
  MSI. Segment1 ITEM_NUMBER,
  NVL (BILL OF RIGHTS. ASSEMBLY_ITEM_ID, msi.inventory_item_id) ASSEMBLY_ITEM_ID,.
  BILL OF RIGHTS. ALTERNATE_ROUTING_DESIGNATOR,
  DECODE (Bill of Rights. Status_route ALTERNATE_ROUTING_DESIGNATOR, null, 'primary', 'other'),
  BOM. ALTERNATE_BOM_DESIGNATOR,
  DECODE (bom. Status_bom ALTERNATE_BOM_DESIGNATOR, null, 'primary', 'other')
  OF BOM_OPERATIONAL_ROUTINGS BOR,.
  MSI mtl_system_items,
  mtl_item_categories mic,
  MC mtl_categories,
  bom_bill_of_materials bom
  where msi.item_type = "FG".
  and msi.organization_id = 84
  and msi.inventory_item_id = mic.inventory_item_id
  and mic.category_set_id = 1100000043
  and mic.category_id = mc.category_id
  and mic.organization_id = msi.organization_id
  and msi.inventory_item_id = bom.assembly_item_id (+)
  and msi.inventory_item_id = bor.assembly_item_id (+)
  and IN msi.inventory_item_id (12832, 10894,12835)
  order of msi.segment1
  
  and the result is
  
  ITEM_NUMBER ASSEMBLY_ITEM_ID ALTERNATE_ROUTING_DESIGNATOR STATUS_ROUTE ALTERNATE_BOM_DESIGNATOR STATUS_BOM ROUTING_SEQUENCE_ID
  
  2028 380M. CMXXX.02.0160.0 20091009 primary 12832 replacing
  2028 380M. 12832 primary primary CMXXX.02.0160.0
  7419 380M. CMXXX.02.0160.0 20091009 12832 alternate replacement 20091009
  7419 380M. CMXXX.02.0160.0 20091009 12832 alternate primary
  2029 380M. CMXXX.02.0781.0 20091009 primary 12835 replacing
  2029 380M. 12835 primary primary CMXXX.02.0781.0
  7430 380M. CMXXX.02.0781.0 20091009 12835 alternate replacement 20091009
  7430 380M. CMXXX.02.0781.0 20091009 12835 alternate primary
  700 M. RPDXX.50.0044.0 10894 primary primary
  
  
  I want the query will return the result like this
  
  ITEM_NUMBER SEGMENT3 ASSEMBLY_ITEM_ID ALTERNATE_ROUTING_DESIGNATOR STATUS_ROUTE ALTERNATE_BOM_DESIGNATOR STATUS_BOM
  
  
  380. M CMXXX.02.0160.0 A 20091009 12832 alternate replacement 20091009
  380. M CMXXX.02.0781.0 A 20091009 12835 alternate replacement 20091009
  700 M. RPDXX.50.0044.0 10894 primary primary
  
  I can afford is in ALTERNATE_ROUTING_DESIGNATOR, there is another primary n then priority to select's replacement, n its same with ALTERNATE_BOM_DESIGNATOR must choose replacing if don't have no Deputy then select primary as the output...
  
  for the item id 10894, because this element is not ALTERNATE_ROUTING_DESIGNATOR or ALTERNATE_BOM_DESIGNATORthen turn primary or if you can't turn to ' ' (space)
  
  THX in advance
  
  Kind regards
  Elbert

  with tab as(
  SELECT DISTINCT BOR.ROUTING_SEQUENCE_ID                                           ,
    msi.segment1 ITEM_NUMBER                                                        ,
    NVL(BOR.ASSEMBLY_ITEM_ID,msi.inventory_item_id) ASSEMBLY_ITEM_ID                ,
    BOR.ALTERNATE_ROUTING_DESIGNATOR                                                ,
    DECODE(bor.ALTERNATE_ROUTING_DESIGNATOR,NULL,'Primary','Alternate') status_route,
    bom.ALTERNATE_BOM_DESIGNATOR                                                    ,
    DECODE(bom.ALTERNATE_BOM_DESIGNATOR,NULL,'Primary','Alternate') status_bom
     FROM BOM_OPERATIONAL_ROUTINGS BOR,
    mtl_system_items msi              ,
    mtl_item_categories mic           ,
    mtl_categories mc                 ,
    bom_bill_of_materials bom
    WHERE msi.item_type      = 'FG'
  AND msi.organization_id    = 84
  AND msi.inventory_item_id  = mic.inventory_item_id
  AND mic.category_set_id    = 1100000043
  AND mic.category_id        = mc.category_id
  AND mic.organization_id    = msi.organization_id
  AND msi.inventory_item_id  = bom.assembly_item_id(+)
  AND msi.inventory_item_id  = bor.assembly_item_id(+)
  AND msi.inventory_item_id IN (12832, 10894,12835)
  ORDER BY msi.segment1
  )
  SELECT ITEM_NUMBER,
    ASSEMBLY_ITEM_ID ,
    CASE
      WHEN MAX(DECODE(STATUS_ROUTE,'Alternate',STATUS_ROUTE)) = 'Alternate'
      THEN 'Alternate'
      ELSE MAX(STATUS_ROUTE)
    END STATUS_ROUTE                                      ,
    MAX(ALTERNATE_BOM_DESIGNATOR) ALTERNATE_BOM_DESIGNATOR,
    CASE
      WHEN MAX(DECODE(STATUS_BOM,'Alternate',STATUS_BOM)) = 'Alternate'
      THEN 'Alternate'
      ELSE MAX(STATUS_BOM)
    END STATUS_BOM
     FROM tab
  GROUP BY ITEM_NUMBER,
    ASSEMBLY_ITEM_ID
  

  not tested...

  Ravi Kumar

• Camera selection help

  I'm looking into getting a new camera for me.  Occasional photos of the family and others.

  I'm wanting to get a camera that is about the size of a smartphone and take better pictures than one (my wife, for example, has one of those Amazon Fire phones).

  I was watching the ELPH cameras and cameras in the series.  Any recommendations?

  In the same sense, what makes a camera like the better/more expensive s 340 ELPH Powershot Powershot 150 IS?  Looking at the specs for individuals and others, they look for the most part; more big difference I noticed is the ability of Wi - Fi, I have no interest in.

  Thank you.

  The PowerShot A series and the series ELPH cameras are only slightly better than newer than sensors mobile phone cameras are only slightly larger A and ELPH. A beautiful compact camera that would be higher than the cell phone would be 120 in my opinion. It is a camera very pocketable which has the same sensor size as the much larger G16 amateur camera and all full manual controls and the scene modes you could want. The lens is much brighter than the A series cameras and ELPH, with a much better ability to low light that cell phones are usually able to. The S120 can shoot in RAW and JPEG format and has a decent zoom range. I know the price is probably more you want to spend, but it would be a real advance upwards from a cell phone camera that you would really notice. The S110 is the old model and is much less expensive and would still be a big improvement over cell phones.

  As far as the cost of the differences on the 340 s and 150 IS, the 340 a longer zoom range, for movies HD is a high definition, has a larger screen at the back of the camera and wifi. The 340 also has a range of ISO superior to work with.

  Steve M.

• Pls select help more scores

  Hi Experts
  I have data like this.
  
  < pre class = "jive-pre" > < class ID = "java jive jive-code" >
  OrderNo OrderQTY OnhandQTY OnhandSubInvCode
  311000014 50 50 FC_AREA
  311000014 50 119 ST - FG
  311000015 50 70 FC_AREA
  311000015 50 120 ST - FG
  
  < / code > < / pre >
  But I'm looking for an output like below...
  < pre class = "jive-pre" > < class ID = "java jive jive-code" >
  OrderNo OrderQTY OnhandQTY OnhandSubInvCode
  311000014 50 50 FC_AREA
  119 M - FG
  311000015 70 70 FC_AREA
  120 ST - FG
  < / code > < / pre >
  I try to used function < = font color 'marine' > more (partition by...) < / police > but is not successful.
  
  Pls suggest me which works how can I applied for her.
  
  We thank in advance.

  mosaq wrote:
  If you are on oracle sql prompt... sql parameters following who will do for you...

  SQL > break on OrderNo, OrderQty

  Sajid

  It works, but only in SQL * more.
  If the information is necessary in order to be displayed via other means such as output to a file using UTL_FILE or another front end interface, then you can not use this way.

• Select icon workstation: so, 'aid', so: "Help and Support Center" - &#62; does not work.

  When I select "Help and Support Center" with Microsoft, I get the error message: "Windows cannot find helpctr.exe.

  Can I reinstall anything from Application or system recovery disks - or download the Microsoft HELP?  -
  Or can only be re-established by dong RESTORATION?   Thanks for you help... ~!

  Do you mean you see a message like this:

  Windows cannot find 'helpctr.exe.  Make sure you typed the name correctly and then try again.  To search for a file, click the Start button, and then click search.

  The Center help and Support sometimes get broken with overzealous cleaning and there are a lot of things to 'try' who sometimes work and sometimes they are not. Sometimes people drop everything simply and never reuse Help and Support Center, but it can still be repaired.

  Do you now or nave already used third-party applications on your system where the product description includes descriptive as sentences:

  cleaner, mechanic, detective, doctor, heal, optimize, clean up, tune up, speed up, set towards the top, compact, compress, faster, power, boost, boost, gum, muncher. guaranteed or all that has an icon that looks like a key, the key or the screwdriver?

  We will restore some things in the registry who sometimes kill himself by malicious software or, sometimes, these cleaning programs.

  Before making any changes to your registry (although I hope that this update), make a copy of your registry with this free and popular tool:

  http://www.SnapFiles.com/get/ERUNT.html

  Then go to this page WWW of Riou (thanks, Ramesh).

  http://WindowsXP.MVPs.org/startmenuhelp.htm

  When you click the file startmenuhelp.reg on this page with your browser, you will see a bunch of text which is information of record that you want to apply to your system.  It seems daunting, but it's not so bad.

  Press Ctrl + A to select all the text, then press Ctrl-C to copy the text to the Windows Clipboard.

  Click Start, run, and then in the box, type:

  notebook

  Click OK to open a new Notepad file.

  Press Ctrl + V to paste the information that you copied into the Windows Clipboard in the Notepad file.  Save the new file in Notepad on your desktop and name the new file something he can hold, as:

  startmenuhelp.reg

  Quit Notepad and double click the file startmenuhelp.reg on your desktop and respond in the affirmative to the question about adding information to your registry.

  Test your help and your support now, then restart and test again to make sure that the changes 'stick' with a reboot.

  You can delete the file startmenuhelp.reg to your desktop.

  If that does not do so, you can reinstall the whole (not reinstall XP - just the help and Support Center)

• TB38.3.0, the Lightning disappeared between extensions. Relocation of lightning and update to 38.4.0 did not help. [was: my calendar disappeared]

  I have Thunderbird 38.3.0 on a Windows 7 PC. For some reason any today my calendar with all my appointments simply disappeared. When I went to the Add-ons Manager, lightning was missing in my extensions. I didn't remove it myself.

  I tried to reinstall it. After you restart Thunderbird, Lightning was back to the list of extensions (version 4.0.4.1) but I still have no schedule and no toggle button "today Pane.

  I tried to remove and install again. Still no joy. Help!

  That's what I'll try:
  Determine the folder of your profile through the troubleshooting information.

  In the top right of the Thunderbird window, click the menu button , then select help > troubleshooting information > profile folder > open folder.

  Profile opens in Windows Explorer.

  Close Thunderbird.

  Antivirus real-time scanner snoozes.

  Navigate to the subfolder of extensions and search for a folder {e2fda1a4-762b-4020-b5ad-a41df1933103}. This is the Lightning extension. Delete this folder, if there is.

  If there is a folder "staged" delete it as well.

  Launch Thunderbird and install again the lightning. For Thunderbird 38.4.0 the corresponding version of lightning is 4.0.4.1.

  If it worked this time, turn anti-virus back on.

• I need to reset Firefox, but the help icon (first stage) does not appear in the Menu.

  I try to reset Firefox (for Linux/Ubuntu 12.04 LTS), who has gone a bit wobbly... but following the procedure, the first thing is to select 'Help' ('question mark icon) and proceed from there. Unfortunately, there is no aid icon displayed in the choice as indicated on the Firefox Web site.
  It's like trying to find a corner in a round room.
  By the way, one of the problems I am experiencing, is the appearance of green, gray and black rectangular boxes in the browser window. Visually, it's like the text appears that usually it is has currently "hidden" or something.
  (Maybe) About nothing... This seems to have occurred in the wake of a regular update of Ubuntu.
  Thanks for advice and guidance.
  Jaguar
  PS - I wanted to you / l a screen shot, but was unable to do so.

  Thanks a lot for the presentation of reports.