use to insert the last day of each month

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• First day/last day of each month

  Hello
  y at - it sql/script to get the first day/last day of each month.new to bi do not know the syntax
  
  If a point on the link to get these things will be highly appreciated

  Hello
  I suggest that you go through the following link

  (1) http://oracle.ittoolbox.com/groups/technical-functional/oracle-bi-l/obiee-date-comparison-1726677#M1729534

  Toget first/last day of the month

  (2) http://www.obinotes.com/2010/02/tip-to-get-firstday-lastday.html

  New to OBIEE---> http://obiee101.blogspot.com/2009/07/obiee-how-to-get-started.html

  Thank you
  Saichand.V

• Select the last record of each month

  Hello

  to select the last docnumber and qty of every month

  Structure

  Name Null?    Type

  ------------------------------- -------- ----

  PRODUCTCODE NUMBER

  NUMBER NUMBER

  DATE OF PLANFORMONTH

  NUMBER OF CLEXPECTEDQTY

  NUMBER OF CLCONFIRMQTY

  NUMBER OF CLFGBUFFERQTY

  NUMBER OF CLTOTPRINTBUFFER

  in this select query if I take the sum he required all records where, as I want the last record of each month

  SELECT productcode docnumber MAX (Number), planformonth, SUM (clexpectedqty) clexpectedqty (planformonth) MAX.

  SUM (clconfirmqty) clconfirmqty, SUM (clfgbufferqty) clfgbufferqty, cltotprintbuffer OF FGSALESPLAN of the SUM (cltotprintbuffer)

  GROUP BY productcode, (planformonth)

  Sandy

  Hello

  Thanks its working now the code is written as below:

  SELECT * FROM

  (SELECT

  e.*,

  ROW_NUMBER() OVER (partition by PRODUCTCODE by DOCNUMBER DESC order) r

  Of

  E FGSALESPLAN)

  WHERE r = 1 AND

  entryvalid = 'Y '.

  order by Number

  Sandy

• for the 25th day of each month in Date function

  Dear all,
  
  I want to want to get the 25th day of each month
  as.
  Select sysdate from dua.
  
  
  
  Concerning

  SQL> select trunc(sysdate,'MM')+24 "Day" from dual;
  
  Day
  ---------
  25-MAY-13
  

• How to get the last day of a month for every 2 months for a given period?

  Hello

  Can is it some please let me know how to get the last day, last day of the week, the weekend last day, last Monday, one month for every 2 months for a given period?

  Thanks in advance.

  Try the below

  SELECT LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))) lastday.

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'SAT '.

  SO LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-1

  WHERE TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'Sun '.

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-2

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  END as lastweekday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') IN ('Sam', 'SUN')

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  -(TO_NUMBER (TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))),' from)) - 1).

  END as lastweekendday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'MY

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER NEXT_DAY (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), "LUN")-7

  END AS lastmonday

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• How can I program a list of Interfaces that will run on the last Sunday of each month...

  Hi can someone help me to achieve this scenario...

  Thanks in advance...

  Hello

  Make the scenario for each interface and expand when the script option is planning.

  Scheduling---> option execution---> select month (day of week)---> monthly date = last & Sunday and schedule accordingly.

  Let me know

  Thank you

• repeat_interval in DBMS_SCHEDULER.create_job - for the 2nd day of each month

  Hi all
  
  I want to clarify in the repeat_interval the Scheduler for this task must be run on the second of each month at 20:00.
  I've been racking my brains out but nothings coming out.
  
  Any suggestions?

  You probably want a range like this:

  FREQ=MONTHLY;BYMONTHDAY=2;BYHOUR=20;BYMINUTE=0;BYSECOND=0;
  

  You can use the DBMS_SCHEDULER. EVALUATE_CALENDAR_STRING function to test, as follows:

  SQL > DECLARE
    2  start_date        TIMESTAMP;
    3  return_date_after TIMESTAMP;
    4  next_run_date     TIMESTAMP;
    5  BEGIN
    6  start_date :=
    7    to_timestamp_tz('01-JAN-2003 10:00:00','DD-MON-YYYY HH24:MI:SS');
    8  return_date_after := start_date;
    9  FOR i IN 1..5 LOOP
   10    DBMS_SCHEDULER.EVALUATE_CALENDAR_STRING(
   11      'FREQ=MONTHLY;BYMONTHDAY=2;BYHOUR=20;BYMINUTE=0;BYSECOND=0;',
   12      start_date, return_date_after, next_run_date);
   13  DBMS_OUTPUT.PUT_LINE('next_run_date: ' || next_run_date);
   14  return_date_after := next_run_date;
   15  END LOOP;
   16  END;
   17  /
  next_run_date: 01/02/2003 08:00:00.000000 PM
  next_run_date: 02/02/2003 08:00:00.000000 PM
  next_run_date: 03/02/2003 08:00:00.000000 PM
  next_run_date: 04/02/2003 08:00:00.000000 PM
  next_run_date: 05/02/2003 08:00:00.000000 PM
  

• These last days on each screen by clicking on sparkles and top rollers at the bottom makes it difficult to work.

  * Original title: screen flickers

  These last days on each screen by clicking on sparkles and top rollers at the bottom makes it difficult to work. What could be the reason? Windows 7 Professional operating systems.

  I have since uninstalled Adobe Flash as Java and I find twinkle and has stopped rolling top screen downstairs. In case the problem recurs, I'll follow the advice given by you. Thanks for your quick response.

• Select the last value for each day of the table

  Hello!
  
  I have a table that contains several measures for each day. I need two queries on this table, and I'm not sure how to write them.
  
  The table stores the rows (sample data)
  

  *DateCol1                 Value       Database*
  27.09.2009 12:00:00       100           DB1
  27.09.2009 20:00:00       150           DB1
  27.09.2009 12:00:00       1000          DB2
  27.09.2009 20:00:00       1100          DB2
  28.09.2009 12:00:00       200           DB1
  28.09.2009 20:00:00       220           DB1
  28.09.2009 12:00:00       1500          DB2
  28.09.2009 20:00:00       2000          DB2

  Explanation of the data in the sample table:
  We measure the size of the data files belonging to each database to one or more times a day. The value column indicates the size of the files of database for each database at some point (date in DateCol1 European model).
  
  
  What I need:
  Query 1:
  The query must return to the last action for each day and the database. Like this:

  *DateCol1       Value      Database*
  27.09.2009        150          DB1
  27.09.2009       1100          DB2
  28.09.2009        220          DB1
  28.09.2009       2000          DB2

  Query 2:
  The query should return the average measurement for each day and the database. Like this:

  *DateCol1       Value      Database*
  27.09.2009       125          DB1
  27.09.2009      1050          DB2
  28.09.2009       210          DB1
  28.09.2009      1750          DB2

  Could someone please help me to write these two queries?
  
  Please let me know if you need further information.
  
  Published by: user7066552 on September 29, 2009 10:17
  
  Published by: user7066552 on September 29, 2009 10:17

  Why two queries when it suffice ;)

  SQL> select dt
    2       , db
    3       , val
    4       , avg_val
    5    from (
    6  select dt
    7       , val
    8       , db
    9       , row_number () over (partition by db, trunc (dt)
   10                                 order by dt desc
   11                            ) rn
   12       , avg (val) over (partition by db, trunc (dt)) avg_val
   13    from test)
   14   where rn = 1
   15  order by dt
   16  /
  
  DT        DB           VAL    AVG_VAL
  --------- ----- ---------- ----------
  27-SEP-09 DB2         1100       1050
  27-SEP-09 DB1          150        125
  28-SEP-09 DB2         2000       1750
  28-SEP-09 DB1          220        210
  

• How to get the same day of a month each year in the DB (update a flag)

  Hello
  
  I'm trying to make a update for a table of flag request in our database that contains the dates and the Pavilion columns. Currently the system have dates for the next ten years. The flags are updated with the values 0 or 1, if a particular date falls under the criteria required.
  
  I need to update the column flag for the same day of the month of each year. for example, 2nd Sunday of October. The value must be updated in all the years in the table. Currently I use the following query to update of the current year.
  
  UPDATE FILTERCALENDAR SET YEAR_WINDOW = 1 WHERE c_date = NEXT_DAY (TO_DATE('OCT-2013','MON-YYYY'), 'SUNDAY') + (2-1) * 7;
  
  and for the next year as
  
  UPDATE FILTERCALENDAR SET YEAR_WINDOW = 1 WHERE c_date = add_months (NEXT_DAY (TO_DATE('OCT-2013','MON-YYYY'), 'SUNDAY') + (2-1) * 7, + 12)-1;
  
  This isn't a great way to do it because he does not take care of leap years, and it does not scan and update values across the table for all the years correctly.
  
  Can someone help me fix this please.

  Welcome to the forum!

  Whenever you provide post your Oracle version 4-digit (result of SELECT * FROM V$ VERSION)
  >
  and for the next year as

  UPDATE FILTERCALENDAR SET YEAR_WINDOW = 1 WHERE c_date = add_months (NEXT_DAY (TO_DATE('OCT-2013','MON-YYYY'), 'SUNDAY') + (2-1) * 7, + 12)-1;
  >
  Why do you use "2013" in the TO_DATE for the year next rather than use simply '2014 '?

  You said it works
  >
  UPDATE FILTERCALENDAR SET YEAR_WINDOW = 1 WHERE c_date = NEXT_DAY (TO_DATE('OCT-2013','MON-YYYY'), 'SUNDAY') + (2-1) * 7;
  >
  Just interview the years from your table (list of the separate years) and use the query above on them.

  SELECT DISTINCT TO_CHAR(c_date, 'yyyy') FROM FILTERCALENDAR
  

  Or use this predicate

  WHERE c_date = next_day(last_day(add_months (c_date, -1)), 'SUNDAY') + 7
     AND TO_CHAR(c_date, 'mm') = '10'
  

  1 TO_CHAR ensures that the line has a month to October.
  2 ADD_MONTHS goes to Sept. 1.
  3 LAST_DAY going until the last day of September.
  4 NEXT_DAY goes to the first Sunday in October
  5 + 7 is going to the second Sunday in October

• ORA-01847: day of the month must be between 1 and the last day of the month

  Hi all
  
  
  
  
  
  
  Select
  To_date(mDate||) e '|| mtime, "YYYY-MM-DD HH24MISS") meddate
  of PR_MOCTEST_TEMP
  
  mDate IS OF TYPE of DATA VARCHAR2 AND mtime OF VARCHAR2
  
  mDate: 07-09-2009
  mtime: 131241
  
  mDate IS IN FORMAT DD-MONTH-YYYY
  mtime: HHMMS
  
  mtimeOF IS OF TYPE of DATA VARCHAR2 AND VARCHAR2 mDate
  
  mDate: 07-09-2009
  mTIME: 131241
  
  mDATE IS IN FORMAT DD-MONTH-YYYY
  mTIME: HHMMS
  
  I NEED TO COMBINE THE 2 COLUMNS TO GET THE OUTPUT AS DD-MM-YYYY HH24MISS
  AND I AM GETTING THE ERROR;
  
  
  ORA-01847: day of the month must be between 1 and the last day of the month
  
  where mistaken?
  
  Please notify
  
  
  Kai

  You will find the bad dates using a table of logging of errors:

  --we'll try to insert into here, invalid dates will be thrown out
  create table dst(d date);
  
  -- create an error log table dst_err
  exec dbms_errlog.create_error_log('dst', 'dst_err');
  
  -- try the insert. Will fail with your ORA-01847
  insert into dst select TO_DATE(mdate||' '||mtime,'DD-MM-YYYY HH24MISS') from PR_MOCTEST_TEMP log errors into dst_err('comment'); 
  
  -- view the errors
  select * from dst_err;
  

• Stop/Fix "Please insert the last disk of all selfextracting and click OK to continue.

  (With the help of Win 7 32 - bit update)

  I have not used a disk of 3.5 inches for many years.  In addition, I have not used any device (USB, CD or DVD) that has / had problems of "whole selfextracting.

  Also, AutoPlay was disabled on my system for years.

  That said, whenever I do a search of file/folder I get "Please insert the last disk of all selfextracting and click OK to continue.

  How can I be to determine:

  1. What causes the error message and/or
  2. How to stop it forever!

  Thanks for any thoughts or ideas!

  DennisCPA

  Don't know if you've discovered this done yet for you, but I would say it is your usb flash drive. It happens when he is out BEFORE you used the 'Safely remove' icon on the taskbar.

  If it is, then you must copy any information on the USB key to another location and format the USB. Then you can copy the info on it and you're right to go!

  This will continue to happen sometimes even though you have the properties/policies defined in a quick deletion. I got mine the value of the radio button performance and ALWAYS use the icon REMOVE safe in your taskbar. Once you find that your data will be corrupted if is not removed properly, even if the ssd is supposed to be "hot." If you have a usb key that has a light on it, wait for the light to STOP BLINKING before removing it. If you do not have a light on this issue, it is always advisable to wait a second or two after the popup window say you that it is save to remove your USB.

  See you soon

  Glenn

• Get the last day of the month

  Hello

  How can I get the (day number of the) last day of a given month and year?

  So, if

  year 2015 = and month = 1, the output should be 31

  year = 2012 and month = 2 while production is expected to be 29

  year 2013 = and month = 2 while production is expected to be 28

  etc.

  Y at - it no OBIEE to achieve? If not, then a command SQL Oracle is very good too (I prefer OBIEE however)

  Thanks in advance,

  Erik

  You start from the first day of the month, you add 1 month [TIMESTAMPADD (SQL_TSI_MONTH, 1, 'your date')], you must subtract 1 day [TIMESTAMPADD (SQL_TSI_DAY,-1, 'your date')] and use the DAYOFMONTH function to get the number of the last day of the month [DAYOFMONTH ('your ' date')].

  All these calls nesting together and you're there.

• How to get the last day of the weekend rather than a month

  Hi all

  Is the request appropriate and preferable to use to get the last business day of the month below?

  SELECT to_date('13.08.2014','dd.mm.yyyy') + MAX(RNUM) LastDay(nonweekend)
     FROM   (SELECT ROWNUM RNUM
            FROM   ALL_OBJECTS where rownum <=31)
    WHERE   ROWNUM <= 31 ANd
       TO_CHAR(to_date('13.08.2014','dd.mm.yyyy') + RNUM, 'DY','NLS_DATE_LANGUAGE=ENGLISH' ) NOT IN ('SAT' , 'SUN')
       and to_date('13.08.2014','dd.mm.yyyy') + RNUM <= last_day(to_date('13.08.2014','dd.mm.yyyy'))
  

  I have to use this motion for production.

  East - recommended to use?

  You can change your query this way:

  WITH t AS (SELECT trunc (to_date ('& calc_date', 'dd.mm.yyyy'), 'mm') + level - 1 calc_date)

  OF THE DOUBLE

  CONNECT BY LEVEL<= last_day(to_date('&calc_date',="" 'dd.mm.yyyy'))="" -="" trunc(to_date('&calc_date',="" 'dd.mm.yyyy'),="" 'mm')="" +="">

  )

  Select max (calc_date)

  t

  where to_char (calc_date, 'DY', 'NLS_DATE_LANGUAGE = ENGLISH') NOT IN ("SAT", "Sun");

• How to get the last day of the week?

  HII
  
  I can get the week number of calendar for a given date using
  
  SELECT to_char (to_date('04/04/2011','MM/DD/YYYY'), 'WW') FROM dual
  
  can any body tell me, how to get the last day of the week?
  
  and the answer should be: 04/08/2011(8th april)
  Thank you
  San
  
  Published by: sandeep9 on April 4, 2011 03:50

  Perhaps this...

  SQL> select trunc(sysdate,'WW')+6 from dual;
  
  TRUNC(SYSDATE,'WW')+
  --------------------
  08-APR-2011 00:00:00
  
  SQL>