By selecting the rope between some special characters
Dear SeniorPlease guide me how to select the string from - channel selection - behind the edge-
I mean I want to select the channel of the first indent of before the second indent
example of
1-OS MARKING-1072
2 BONE POCKET TIE-1288
3-OS ATTACH A-1073
4-OS CUP-1128
5-OS ATTACH B-1075
POCKET 6 OS O/L-976
7 REGULUS SLEEVE O/L-1221
8-ARMHOLE F/L-804
9-CARD MAKING-819
10-BADGE TIE-820
Result
BONE MARKING
OS LOCK TIE
BONE JOIN
CUTTING OF THE BONE
BONE TIE B
POCKET OS O/L
REGULUS SLEEVE O/L
ARM HOLE F/L
BADGE MANUFACTURING
BADGE TIE
Hello
Use INSTR and SUBSTR, like this:
WITH got_pos AS
(
SELECT str
, INSTR (str, '-', 1, 1) + 1 AS start_pos
, INSTR (str, '-', 1, 2) AS end_pos
FROM table_x
)
SELECT SUBSTR ( str
, start_pos
, end_pos - start_pos
) AS between_hyphens
FROM got_pos
;
You can also use regulat expressions, but they will be slower.
In Oracle 10.1 (and), for example:
SELECT REGEXP_REPLACE ( str
, '^[^-]*-([^-]*)-.*'
, '\1'
) AS between_hyphens
FROM table_x
;
From Oracle 11.1, you can also use REGEXP_SUBSTR.
Again, it will be less effective than using SUBSTR and INSTR.
I hope that answers your question.
If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.
Explain, using specific examples, how you get these results from these data.
What do you do if the string does not contain 2 hyphens? If thiis is a problem, then include examples in your sample data and results.
Always say what version of Oracle you are using (for example, 11.2.0.2.0).
See the FAQ forum {message identifier: = 9360002}
Tags: Database
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Hello
msinn wrote:
Hello Forum,a value is accumulated more a day and over a period of time. The next day, the value is reset and starts to build up again:
Thanks for posting the sample data and results. Be sure to explain how you get these results from these data. For example "for each day, I just want to show the lines after the daily low was reached. For example, on September 9, the lowest val was 23, which occurred at 6:12, so I don't want to show all lines earier to 06:12 September 9. In addition, when a val is the same as or more than the previous same day val (in order by ts), then I don't want to display the line later. For example, on 9 September, there are several consecutive lines, starting at 14:21 which all have the same val, 142. I want to only display the ealiest of this group, the line of 14:21. »
Here's a way to do it, using analytical functions:
WITH got_analytics AS ( SELECT ts, val , MIN (val) OVER ( PARTITION BY TRUNC (ts) ORDER BY ts DESC ) AS min_val_after , CASE WHEN val = MIN (val) OVER (PARTITION BY TRUNC (ts)) THEN -1 -- Impossibly low val. See note below ELSE LAG (val) OVER ( PARTITION BY TRUNC (ts) ORDER BY ts ) END AS prev_val FROM sampledata ) SELECT ts , val FROM got_analytics WHERE val <= min_val_after AND val > prev_val ORDER BY ts ;
This requires that val > = 0. If you don't know a lower bound for val, and then the same basic approach still works, but it's a bit messier.
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