Select to partition interval

Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production

I have a partitioned table of interval on a range of numbers and to select the data of a partition for a specific value is

CREATE TABLE part_test(part_key       NUMBER
                      ,part_data      VARCHAR2(10)
                      )
PARTITION BY RANGE (part_key)
  INTERVAL ( 1 )
  (PARTITION p_base VALUES LESS THAN (0));

INSERT INTO part_test(part_key, part_data)
VALUES      (-1, '-1');
INSERT INTO part_test(part_key, part_data)
VALUES      (0, '0');
INSERT INTO part_test(part_key, part_data)
VALUES      (1, '1');
INSERT INTO part_test(part_key, part_data)
VALUES      (2, '2');
COMMIT;

SELECT *
FROM   part_test PARTITION FOR(1);

What I really want to select the partition is based on a value in another table to be

CREATE TABLE part_value (part_key NUMBER);

INSERT INTO part_value(part_key)
VALUES      (1);
COMMIT;

SELECT *
FROM   part_test PARTITION FOR(select part_key from part_value);

It gives ORA-00936: lack of expression.  I could use dynamic sql statements to create the query (or generate a view), but it would save instead.  Any ideas if this can be achieved by a simple sql statement?

Thank you.

You try something like:

SELECT *.

OF part_test pt, part_value pv

where pt.part_key = pv.part_key

In most cases a particular partition will be only accessible, no full table scans (not true in all scenarios, however)

Tags: Database

Similar Questions

  • modify an existing table to selectively the partition interval range

    I'm using Oracle 11.2.0.3.

    I have an existing table that has parition interval range.

    example:
     
create table Log( ts date, level  varchar2(20), scr varchar2(2000))PARTITION BY RANGE (TS)
INTERVAL( NUMTODSINTERVAL(1,'DAY'))
    Currently, we have the log of the table that is the partition of the range by day and we drop old parition to a week. However, we want to change this to persist the records in the table of WHICH = LEVEL "IMPORTANT."

    What is the best way to achieve this?

    >
    Is it possible to modify the existing interval partition table to add partition in the list?
    >
    Only using the DBMS_REDEFINITION to do online. And that always involves the creation of a "provisional" table

    If you have a window of failure just to create a new partitioned table the way you want to and INSERT the data into it. You should be able to use a DEC to do if you want. You may not use swap partition since all data must be physically moved.
    >
    Can we do list-interval partition table i.e. (with partition interval as partition sup)?
    >
    No - subpartitioning of interval is not currently supported.

    Here is the code example of a partitioned table by using the RANGE-interval LIST. It uses a VIRTUAL column, but you can ignore it for your use case

    DROP TABLE mytable;

CREATE TABLE mytable
(
CREATION_DATE TIMESTAMP(6),
LAST_MODIFIED_DATE TIMESTAMP(6),
CREATION_DAY NUMBER(2) GENERATED ALWAYS AS (TO_NUMBER(TO_CHAR(CREATION_DATE, 'DD'))) VIRTUAL
)
PARTITION BY RANGE (LAST_MODIFIED_DATE) INTERVAL(NUMTOYMINTERVAL(1, 'MONTH'))
SUBPARTITION BY LIST (CREATION_DAY)
   SUBPARTITION TEMPLATE
   ( SUBPARTITION days_1_5 VALUES (1,2,3,4,5)
   , SUBPARTITION days_6_10 VALUES (6,7,8,9,10)
   , SUBPARTITION days_11_15 VALUES (11,12,13,14,15)
   , SUBPARTITION days_16_20 VALUES (16,17,18,19,20)
   , SUBPARTITION days_21_25 VALUES (21,22,23,24,25)
   , SUBPARTITION days_26_31 VALUES (26,27,28,29,30,31)
   )
(
   PARTITION prior_to_2013 VALUES LESS THAN (TO_DATE('2013-01-01', 'YYYY-MM-DD'))
)

  • Partitioning interval. How to choose the name of the partition

    Hi all

    Is there a wat to choose the name of the partition when new partitions are created?
    Instead of "SYS_P101", I mean something like CUSTOMRES_P_256, where 256 is the new value that caused the creation of the partition.

    The reason is that, before you launch a long process I need to collect statistics on the partition based on this number

    Thanks in advance,

    You can rename a partition with your preferred naming convention:

    alter table CUSTOMER rename partition SYS_P101 to CUSTOMRES_P_256;

    But you first need to know the name of the partition. One thing I have used in cases when a partition interval has not created yet is to insert a record with the new partition key value so that the partition interval is created, then get the name of the partition and then push the insert. In this way, you know the name of partition before any data is loaded.

    Of course, you can query dba_tab_partitions and examine the high_value column to select the correct partition. However, I prefer the method of obtaining the name of the next partition. It gives you the name of the partition for a row in a table. This is also useful for existing data (not only new partitions) If you need to find the partition where a certain rank.

    select subobject_name
into v_partition
from ALL_OBJECTS
where OWNER = 'SCHEMA_OWNER'
AND data_object_id in (select dbms_rowid.rowid_object(rowid)
                                 from FACT_TABLE
                                 where PARTITION_KEY_COL = MY_VALUE
                                 and rownum = 1);

    You can then use the name of the partition to load your facts, statistics or rename the partition.

  • slow queries with high_value inappropriate for partition interval

    Hello

    yesterday, I defined a partitioned table with a single initial partition interval. The partition key was an id of value with a (generated sequence) run around, the interval was 1 - and since I didn't know the value of the id, I put the high value of initial partition 1. Then I inserted a few lines, started a query simple - and waited a long time for the result. 10046 trace showed, that the query was using a lot of cpu - but I had no idea what he was doing.

    Today, I created a simple test case (in 11.1.0.7 on a Centos 5-server; but I got similar results on my Windows 11.2.0.1 database):
    -- test_interval.sql

set verify off
undefine high_value

drop table test_interval_p1_&&high_value;

create table test_interval_p1_&high_value
  partition by range (id)
  interval (1)
  (partition test_p1 values less than (&high_value))
as
select 100000 id
     , t.*
  from all_objects t
 where 1 = 0;

insert into test_interval_p1_&high_value
select 100000 id
     , t.*
  from all_objects t;

commit;

-- pause
  
select id, count(*)
  from test_interval_p1_&high_value
 group by id;
    When I choose a high_value > 100000 grouping query runs < 1 sec.
    With high_value = 100000: 1 < s
    With high_value = 90000: 1 sec
    With high_value = 80000: 3 sec
    With high_value = 70000: 9 dry
    With high_value = 60000: 17 dry
    With high_value = 50000: 28 dry
    With high_value = 40000: 34 dry
    With high_value = 30000: 47 dry
    With high_value = s 20000: 61
    With high_value = 10000: 76 s
    With high_value = s 1: 102

    When I take pictures of the v$ sesstat before and after execution of the statement, I see that the slow queries show signifikant higher values for "CPU used when calling has begun", "CPU used by this session,"DB time","uga session in memory","pga session in memory.

    But I have still no idea what the query does with all CPUS (maybe browse the possible - but non-existent partitions? "(Mais cela semble un peu ridicule)." In documentation (http://download.oracle.com/docs/cd/E11882_01/server.112/e16541/part_admin001.htm#VLDBG1088), I couldn't find any explanation (and I have no MOS access at the moment).

    Can someone explain to me what is happening here?

    Thanks and greetings

    Martin

    Edited by: mpreiss may 25, 2011 20:05

    Edited by: mpreiss may 25, 2011 20:45

    >

    >

    But I have still no idea what the query does with all CPUS (maybe browse the possible - but non-existent partitions? "(Mais cela semble un peu ridicule)." In documentation (http://download.oracle.com/docs/cd/E11882_01/server.112/e16541/part_admin001.htm#VLDBG1088), I couldn't find any explanation (and I have no MOS access at the moment).

    Can someone explain to me what is happening here?

    It looks like a bug - call him in to Oracle with a SR.

    I repeated your test but only to insert a row into the table, and it took 15 seconds to run the query on my laptop when I put & high_value 25000.

    Check the activity of rowcache $ v - this is where the CPU is going. You will see '100 000 - high_value' Gets the dc_tablespaces and dc_users rank of the cache entries when you run the query (and it's two hits on rowcache latch latch for each get).

    Concerning
    Jonathan Lewis

  • partition interval on the data type TIMESTAMP PrimaryKey

    question:
    Need example of Oracle Interval partitioning on the TIMESTAMP data type of primary key, including the LOCAL INDEX generated by partitioned interval key functional

    Published by: oracletune on April 17, 2013 07:51

    >
    * It seems that interval of time STAMP partitioning is not supported:
    >
    This is not correct.
    >
    Partitioning interval is limited to a partition key unique to a numeric or date range.
    >
    The above is YOUR text and is NOT what the doc.

    The VLDB and partitioning Guide
    http://docs.Oracle.com/CD/E18283_01/server.112/e16541/part_admin001.htm#BAJHFFBE
    >
    For the partitioning of the interval, the partitioning key can be a single column of the table name, and it must be the number or DATE type.
    >
    Which must be read carefully. It is said should be "NUMBER or DATE type. Note that 'DATE type' does NOT mean 'Type of DATE data. A TIMESTAMP (but not TIMESTAMP WITH TIMEZONE) are a type of DATE. It's confusing and the doc must could be formulated differently.

    This code is very well:

    drop table test_part_timestamp

CREATE TABLE TEST_PART_TIMESTAMP
(
PRODUCT_ID NUMBER,
DESCRIPTION VARCHAR2(20 BYTE),
CREATE_DATE TIMESTAMP(6)
)
PARTITION BY RANGE (CREATE_DATE)
INTERVAL(NUMTOYMINTERVAL(1, 'MONTH'))
(
PARTITION OLD_DATA VALUES LESS THAN (TIMESTAMP' 2013-01-01 00:00:00'),
PARTITION P_2013_JAN VALUES LESS THAN (TIMESTAMP' 2013-02-01 00:00:00')
)

  • How to get details of partition interval value. In what its stored dictionary.

    I have create table statement below. I want details on interval value. Where it is stored in the oracle Table.

    Please let me know one.

    CREATE TABLE PARTITION_T1 (ID NUMBER, VARCHAR2 ADDRESS (1000))

    PARTITION OF RANGE (ID)

    INTERVAL (10)

    SUBPARTITION BY LIST (ADDRESS)

    (PARTITION P1 VALUES LESS THAN (30))

    (SUBPARTITION S_P1 VALUES ('BDM', 'DEL'))) ;

    What dictionary its INTERVAL (10) stored value retail.

    Select the INTERVAL from dba_part_tables where table_name = 'PARTITION_T2 ';

    I got the result.

  • How to store a LOB in separate tablespace if we use partition interval

    I have a table that has a LOB column, is it possible interval partiioning the table on a date column and at the same time stores LOB in a separate tablespace

    create table TEST_TABLE
    (date of time_enter
    payload CLOB
    )
    tablespace TEST_TBSP
    partition by range (time_enter)
    store of partition (numtoyminterval(1,'MONTH')) interval (TBSP1, TBSP2)
    LOB (PAYLOAD) STORE AS
    (tablespace TBSP_LOB)



    ---

    the generated scores of repressive will keep the lob data in separate tablespace?

    Thank you

    Yes:

    SQL> select * from v$version;

BANNER
--------------------------------------------------------------------------------
Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
PL/SQL Release 11.2.0.1.0 - Production
CORE    11.2.0.1.0      Production
TNS for Linux: Version 11.2.0.1.0 - Production
NLSRTL Version 11.2.0.1.0 - Production

SQL> column segment_name format a30
SQL> column tablespace_name format a10
SQL> set linesize 100
SQL> --
SQL> drop table test_table purge;

Table dropped.

SQL> drop tablespace ts0 including contents and datafiles;

Tablespace dropped.

SQL> drop tablespace ts1 including contents and datafiles;

Tablespace dropped.

SQL> drop tablespace ts2 including contents and datafiles;

Tablespace dropped.

SQL> drop tablespace tl0 including contents and datafiles;

Tablespace dropped.

SQL> create tablespace ts0 datafile '/u02/oradata/DB112/ts0_01.dbf' size 100m;

Tablespace created.

SQL> create tablespace ts1 datafile '/u02/oradata/DB112/ts1_01.dbf' size 100m;

Tablespace created.

SQL> create tablespace ts2 datafile '/u02/oradata/DB112/ts2_01.dbf' size 100m;

Tablespace created.

SQL> create tablespace tl0 datafile '/u02/oradata/DB112/tl0_01.dbf' size 100m;

Tablespace created.

SQL> select segment_name
  2  from dba_segments
  3  where tablespace_name like 'T%';

no rows selected

SQL> --
SQL> create table test_table
  2  (
  3  time_enter date,
  4  payload clob
  5  )
  6  tablespace ts0
  7  lob (payload) store as (tablespace tl0)
  8  partition by range (time_enter)
  9  interval (numtoyminterval(1,'MONTH'))
 10  store in (ts1,ts2)
 11  (partition p0 values less than (to_date('01-01-2012','DD-MM-YYYY')))
 12  ;

Table created.

SQL> --
SQL> select segment_name, segment_type, partition_name, tablespace_name
  2  from dba_segments
  3  where tablespace_name like 'T%';

SEGMENT_NAME                   SEGMENT_TYPE       PARTITION_NAME                 TABLESPACE
------------------------------ ------------------ ------------------------------ ----------
TEST_TABLE                     TABLE PARTITION    P0                             TS0
SYS_IL0000073922C00002$$       INDEX PARTITION    SYS_IL_P180                    TL0
SYS_LOB0000073922C00002$$      LOB PARTITION      SYS_LOB_P179                   TL0

SQL> --
SQL> insert into test_table values(sysdate,'Jan');

1 row created.

SQL> insert into test_table values(sysdate+20,'Feb');

1 row created.

SQL> insert into test_table values(sysdate+40,'Mar');

1 row created.

SQL> commit;

Commit complete.

SQL> select segment_name, segment_type, partition_name, tablespace_name
  2  from dba_segments
  3  where tablespace_name like 'T%';

SEGMENT_NAME                   SEGMENT_TYPE       PARTITION_NAME                 TABLESPACE
------------------------------ ------------------ ------------------------------ ----------
TEST_TABLE                     TABLE PARTITION    SYS_P184                       TS1
TEST_TABLE                     TABLE PARTITION    SYS_P187                       TS2
TEST_TABLE                     TABLE PARTITION    P0                             TS0
TEST_TABLE                     TABLE PARTITION    SYS_P181                       TS2
SYS_IL0000073922C00002$$       INDEX PARTITION    SYS_IL_P186                    TL0
SYS_IL0000073922C00002$$       INDEX PARTITION    SYS_IL_P189                    TL0
SYS_IL0000073922C00002$$       INDEX PARTITION    SYS_IL_P180                    TL0
SYS_IL0000073922C00002$$       INDEX PARTITION    SYS_IL_P183                    TL0
SYS_LOB0000073922C00002$$      LOB PARTITION      SYS_LOB_P185                   TL0
SYS_LOB0000073922C00002$$      LOB PARTITION      SYS_LOB_P188                   TL0
SYS_LOB0000073922C00002$$      LOB PARTITION      SYS_LOB_P179                   TL0

SEGMENT_NAME                   SEGMENT_TYPE       PARTITION_NAME                 TABLESPACE
------------------------------ ------------------ ------------------------------ ----------
SYS_LOB0000073922C00002$$      LOB PARTITION      SYS_LOB_P182                   TL0

12 rows selected.

    Edited by: P. Forstmann on 29 Jan. 2012 11:40

  • Select the partition to format RT?

    I currently use a NI PXI machine for my LabView code.  I would also like to be able to use it as a real-time target.  Hoping to do this, I created another partition on the hard disk to install the software in real time.  However, when I boot from the disc USB Utility and select "marker hard disk" I get three options: "1 reformat the first RT-compatible partition on the disk", "2 clear all Acha partitions a single partition. ' and '3. Cancel the Format.  Seem to be how to choose my partition created for these purposes.  If I select '1' I run the risk of losing my c:\ drive, or maybe the "Acronis" partition supplied with the computer.  Is there a way around this, or what I have to re-partition of my drive hard so that the new partition is 'before' the c:\ drive?

    Incidentally, most of the other options of the menu "1. Boot using software installed on the hard disk","2. Start in safe mode"etc. seem to prevent the computer to crash.  Each fixed for this?

    My disk USB Utility has been created with LabView 8.6 use MAX 4.5.0.

    Thank you

    Doug

    Hi Doug,.

    I'm happy to help you with your question! Start with, I would not recommend using the Desktop PC utility USB player with most of the PXI systems. Several recent of National Instruments PXI controllers are provided with the opportunity to start in the Mode of LabVIEW Real-time safe via an EEPROM (with any necessary USB external drive), and so it is generally a better option.

    What PXI controller do you use? If you enter the BIOS at startup of the system and see the real LabVIEW Real-time boot options, then you use one of the controllers with built-in LabVIEW of safe in real-time mode. A cautionary note: you need a LabVIEW Real-time Deployment license for run LabVIEW Real-time on your PXI controller. If you bought the controller and it delivered without LabVIEW Real-time installed, he probably didn't understand this license.

    Assuming you are using one of these controllers, you have two basic options:

    (1) install the files in time real LabVIEW and Windows on the same partition (FAT32). When you start your system, you can use the BIOS options to specify Windows or LabVIEW Real-time. The first time you start the system before loading files in time real LabVIEW, you start in safe mode and then install software of MAX. After this point, you will be able to run LabVIEW Real-time and your application at startup using the options in the BIOS.

    (2) install the files in time real LabVIEW and windows on different partitions. To do this, you can install Windows on the FAT32 partition of second or later on your system, or (more commonly) to install Windows on an NTFS partition. LabVIEW Real-time will use the first partition FAT32 or remedy available. Once more, you can use the BIOS options to specify Windows or LabVIEW Real-time to start.

    At the end of the day, you can use the USB of PC Desktop Utility player to install LabVIEW Real-time on any PC with supported hardware (assuming that you bought a LabVIEW Real-time Deployment license). However, this will cause the real-time system appears under MAX as a PC, and if you format using the command of the utility, you will need to replace the system boot record. It is possible to configure a system to dual-boot with bootloader like GRUB utilities, etc., but I highly recommend using the built-in OS BIOS selection if possible.

    Please let me know if you have any additional questions, and I'm happy to help you further. Have a great day of Doug!

    Kind regards

    Casey Weltzin

    Product Manager, LabVIEW Real-time

    National Instruments

  • Select the partition, it will work?

    Hi, I have a TT_table partiotined:

    CREATE THE TABLE RYBATEMP. T_STAT
    (DATE OF THE ACTDATE,
    COL_LIST, FORMAT_LIST...
    .....)
    TABLESPACE "RYBA_DATA" PARTITION BY RANGE
    ("ACTDATE")
    (PARTITION 'D_20100901' VALUES LESS THAN (TO_DATE (' 2010-09-02 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN '))...)

    I just somehow check that the statement select refer directly wanted partition as expected is not browsing through all the table:

    SELECT COL_LIST FROM T_STAT WHERE
    ACTDATE > = to_date ('01 - SEPT.-10 00:00:00 "," DD-MON-YY HH24:MI:SS') AND
    ACTDATE < = to_date ('01 - SEPT.-10 21:01:16 ',' DD-MON-YY HH24:MI:SS')


    This time the date setting confuses me, even after reading through defintionis where format partition involves with hh. Is there way of anay follow in Plan or something, he never did on Oracle.
    It will take more/less/signs?


    Thank you
    Trent

    Hi Trent,
    Yes you can how things work with partitions in the plans of the explain command.
    I don't know your version, but some explanations in example 9.2:
    http://download.Oracle.com/docs/CD/B10500_01/server.920/a96533/ex_plan.htm#7211
    If you want to know how to have the complete trace etc (for example in point 10.2):
    http://download.Oracle.com/docs/CD/B19306_01/server.102/b14211/SQLTrace.htm
    (Notice the partitioning does not avoid the need to index)
    Best regards
    Phil

  • Re: How to get Max (all values of columns) records on a partition interval

    Hello
    Hours      Days            Name     used_size
1     01-09-012     R1     1100
10     01-09-012     R1     1150
15     01-09-012     R1     1160
23     01-09-012     R1     1200

1     01-08-012     R1     1600
10     01-08-012     R1     1700
15     01-08-012     R1     1800
23     01-08-012     R1     1500

1     01-09-012     J1     10
10     01-09-012     J1     20
15     01-09-012     J1     30
23     01-09-012     J1     60

1     01-08-012     J1     70
10     01-08-012     J1     5
15     01-08-012     J1     17
23     01-08-012     J1     22


Needed o/p:

23     01-09-012     R1     1200
23     01-08-012     R1     1500
23     01-09-012     J1     60
23     01-08-012     J1     22
    We have table as above, IE. everyday, there are records at regular intervals of hours for different users.

    I want to get a single record of every day for one hour on this day for all users.


    Please let me know if my question was unclear?

    -Thank you

    Another way, maybe more simple here, here could be just group by user, day.

    SELECT user, day, Max(hours) max_hours, Max (used_size) KEEP (DENSE_RANK LAST ORDER BY hours) mh_used_size
  FROM (table)
 GROUP BY user, day
 ORDER BY user, day

  • How to make a list of dynamic selection with time interval of 15 minutes

    Hi all

    I have a question. I need a selection list containing the time with 15 minute intervals from 08:00 until 16:00.
    example 08:00
    08:15
    08:30
    08:45
    09:00
    09:15
    and so on until 16:00
    Or values stored in a column of varchar type.
    Can someone help me with this one please?

    Best regards
    Caroline

    You can generate the entries in a dynamic way, as:

    select  to_char(trunc(sysdate)+8/24+(level-1)*1/96,'HH24:MI') period
from    dual
connect by level <= 33

    or if you want/need to use your stored values:

    select display_column, return_value from table where
 display_column in (
               select  to_char(trunc(sysdate)+8/24+(level-1)*1/96,'HH24:MI') period
               from    dual
               connect by level <= 33 )

  • Try to convert the partitioned Table of interval in the range... Swap partition...

    Requirement:

    Interval of replacement partitioned Table by range partitioned Table
    DROP TABLE A;

CREATE TABLE A
(
   a              NUMBER,
   CreationDate   DATE
)
PARTITION BY RANGE (CreationDate)
   INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
   (PARTITION P_FIRST
       VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));


INSERT INTO A
     VALUES (1, SYSDATE);

INSERT INTO A
     VALUES (1, SYSDATE - 30);

INSERT INTO A
     VALUES (1, SYSDATE - 60);
    I need to change this partitioned Table apart to a partitioned range Table. I can do using the EXCHANGE PARTITION. Like if I use the classic method to create another table range partitioned, then:

    DROP TABLE A_Range
CREATE TABLE A_Range
(
a NUMBER,
CreationDate DATE
)
PARTITION BY RANGE (CreationDate)
   (partition MAX values less than (MAXVALUE));

Insert  /*+ append */  into A_Range Select * from A; --This Step takes very very long..Trying to cut it short using Exchange Partition.
    Problems:

    I can't do
     ALTER TABLE A_Range
  EXCHANGE PARTITION MAX
  WITH TABLE A
  WITHOUT VALIDATION;
    ORA-14095: ALTER TABLE CHANGE requires a not partitioned table nonclustered
    This is because the tables are partitioned. So it does not allow me.

    If I instead:


    Create a table that is not partitioned for exchanging data by partition.
      Create Table A_Temp as Select * from A;
  
   ALTER TABLE A_Range
  EXCHANGE PARTITION MAX
  WITH TABLE A_TEMP
  WITHOUT VALIDATION;
   
  select count(*) from A_Range partition(MAX);
    -The problem is that all the data is in MAX Partition.
    Even after the creation of a large number of partitions by walls of separation, the data is still in MAX Partition only.

    So:

    -What we cannot replace a partitioned Table to the Table partitioned using the EXCHANGE PARTITION range interval. that is, we have to insert in...
    -We can do it, but I'm missing something here.
    -If all the data is in MAX Partition due to "WITHOUT VALIDATION", can say us be redistributed in the right type of range partitions.

    You must pre-create the partitions in a_range and then swap one for one for a tmp, and then to arange. With the help of your sample (thanks to proviing code, incidentally).

    SQL> CREATE TABLE A
  2  (
  3     a              NUMBER,
  4     CreationDate   DATE
  5  )
  6  PARTITION BY RANGE (CreationDate)
  7     INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
  8     (PARTITION P_FIRST
  9         VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));

Table created.

SQL> INSERT INTO A VALUES (1, SYSDATE);

1 row created.

SQL> INSERT INTO A VALUES (1, SYSDATE - 30);

1 row created.

SQL> INSERT INTO A VALUES (1, SYSDATE - 60);

1 row created.

SQL> commit;

Commit complete.

    You can find the form of existing partitions assistance:

    SQL> select table_name, partition_name, high_value
  2  from user_tab_partitions
  3  where table_name = 'A';

TABLE_NAME PARTITION_NAME HIGH_VALUE
---------- -------------- --------------------------------------------------------------------------------
A          P_FIRST        TO_DATE(' 2001-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
A          SYS_P44        TO_DATE(' 2013-01-28 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
A          SYS_P45        TO_DATE(' 2012-12-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
A          SYS_P46        TO_DATE(' 2012-11-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA

    You can then create the table a_range with apporopriate partitions. Note that you may need to create additional in a_range partitions because the partitioning interval does not create the partitions has no data for, even if that leaves 'holes' in the partitioning scheme. So, on that basis:

    SQL> CREATE TABLE A_Range (
  2     a NUMBER,
  3     CreationDate DATE)
  4  PARTITION BY RANGE (CreationDate)
  5     (partition Nov_2012 values less than (to_date('30-nov-2012', 'dd-mon-yyyy')),
  6      partition Dec_2012 values less than (to_date('31-dec-2012', 'dd-mon-yyyy')),
  7      partition Jan_2013 values less than (to_date('31-jan-2013', 'dd-mon-yyyy')),
  8      partition MAX values less than (MAXVALUE));

Table created.

    Now, create a regular table to use in the constituencies:

    SQL> CREATE TABLE A_tmp (
  2     a              NUMBER,
  3     CreationDate   DATE);

Table created.

    and all partitions in Exchange:

    SQL> ALTER TABLE A
  2    EXCHANGE PARTITION sys_p44
  3    WITH TABLE A_tmp;

Table altered.

SQL> ALTER TABLE A_Range
  2    EXCHANGE PARTITION jan_2013
  3    WITH TABLE A_tmp;

Table altered.

SQL> ALTER TABLE A
  2    EXCHANGE PARTITION sys_p45
  3    WITH TABLE A_tmp;

Table altered.

SQL> ALTER TABLE A_Range
  2    EXCHANGE PARTITION dec_2012
  3    WITH TABLE A_tmp;

Table altered.

SQL> ALTER TABLE A
  2    EXCHANGE PARTITION sys_p46
  3    WITH TABLE A_tmp;

Table altered.

SQL> ALTER TABLE A_Range
  2    EXCHANGE PARTITION nov_2012
  3    WITH TABLE A_tmp;

Table altered.

SQL> select * from a;

no rows selected

SQL> select * from a_range;

         A CREATIOND
---------- ---------
         1 23-NOV-12
         1 23-DEC-12
         1 22-JAN-13

    John

  • importing into a partitioned table of interval 11g

    as I took export utility simple partition table 8i exp not rained so 100 k lines in there.

    and imported with the import utility in the interval of 11g partitioned based on the date column.

    There were imported, but did not what I expected...

    If we execute the simple insert for partition interval 11g command, it create new partition automatically according to the strategy of partition.

    Here's the demo...

    created range partitioned table on the date with shift interval column...

    CREATE TABLE TEST.xxx_HIST
    (
    xxx_DATE DATE NOT NULL,
    P_ROLL_CONVENTION CHAR (2),
    R_ROLL_CONVENTION CHAR (2),
    P_COMPOUNDING_IND CHAR (2),
    R_COMPOUNDING_IND CHAR (2),
    P_CALC_METHOD CHAR (2),
    R_CALC_METHOD CHAR (2),
    P_SPREAD_AMT NUMBER (28,12).
    R_SPREAD_AMT NUMBER (28,12).

    )
    partition by range (xxx_DATE)
    interval (numtoyminterval(3,'MONTH'))
    store (security)
    (
    values of pQ1 lower partition (to_date('2010-01-01','yyyy-mm-dd'))
    ) IN PARALLEL.


    -IMPORTED FROM ROWS IN THE TABLE...

    ======================================================================
    Connected to: Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production
    With partitioning, OLAP, Data Mining and Real Application Testing options

    Export file created by EXPORT: V08.01.07 direct

    CAUTION: objects have been exported by SYSTEM, not by you

    . import of xx_ARCH in TEST objects
    . . import of 141749 lines imported from the table 'xxx_HIST '.
    Import completed successfully without warnings.
    ========================================================================



    -HE HAS A LOT OF DATES OF DIFF IN THERE...



    SQL > SELECT COUNT (DISTINCT xxx_DATE) TEST.xxx_HIST;

    COUNT (DISTINCT xxx_DATE)
    -----------------------------
    1371


    28-MARCH 06
    10 FEBRUARY 06
    9 FEBRUARY 05
    20 FEBRUARY 02
    3 JUNE 02
    10 MAY 04
    26 DECEMBER 03
    31 JANUARY 03

    xxx
    ---------
    21 JULY 08
    31 OCTOBER 05
    25 APRIL 08
    28 APRIL 08
    12 OCTOBER 06
    DECEMBER 21 07
    28 DECEMBER 04


    -BUT STILL ALL DUMPED INTO A PARTITION


    SQL > SELECT nom_partition FROM DBA_TAB_PARTITIONS WHERE TABLE_OWNER = 'TEST ';

    NOM_PARTITION
    ------------------------------
    PQ1

    It all dumped in a partition...

    fact partition interval 11g creates the partition automatically in function whose lines if imported... when we import lines in there...? or am I missing something?

    any idea guys?

    Seems to be a poor strategy for me because if I am not mistaken, there is no way to specify the order of the imported lines. If you import a line with the date max as your first row... bang, you get a range partition created for you and the rest falling.

    I think you'd be better import these data into a table in step and then by a

    insert into new_fancy_partition_table
select *
from old_8_temporary_imported_table
order by date_column asc

    Or create the partitions manually.

    I just realized that you specify a partition in your create table statement (missed that on cursory inspection). And I think you misunderstand how the interval works... it's for values LARGER than the existing partitions ONLY...

    http://download.Oracle.com/docs/CD/E11882_01/server.112/e10592/statements_7002.htm#SQLRF01402

    "
    INTERVAL clause

    Use this clause to set the interval of partitioning the table. Range partitions are partitions based on a digital range interval or datetime. * They extend from range partitioning by commanding the database to automatically create partitions of the specified range or interval when the data inserted in the table exceed all the partitions.* range
    "

    Published by: Tubby on August 16, 2010 18:32

    Additional document link.

  • 531 E - select partition recovery disks

    Hi, I would like to have two OS on my Thinkpad E531. I have all the recovery discs four (2 App and drivers + 2 OS Recovery). Is it possible to install Windows 8 with selection of partition. Because if I start to recover, it is automatically used all of my hard drive.

    And is it possible to install only the operating system without other programs such as the Antivirus Northon and so on?

    Thank you!

    Good day and welcome to the community.

    From my experience using recovery media factory, process, other than the disks when you are prompted, switch is completely automatic. No picking partitions or installs selective component. The aim of the game is to restore the computer to its out-of-box state.

    Hope this helps to clarify.

    Kind regards.

  • Select the system partition to reinstall

    I have Dell latitude D610 and try to reinstall Windows XP Professional using the dell operating system reinstall disk.

    During the installation process, he asked which partition to delete.  Select the partition system (C:\windows)?  It is the only partition shown.

    Thanks for any advice.

    Yes

Maybe you are looking for

  • Fonts change more content.

    Today I found that nothing I do changes in the police. I changed the police before, but now I can't.

  • Satellite U400: Various uncomfortable questions - rundll, programs etc. of closing.

    I have a laptop Toshiba U400 brand new which started to play up. When I try to open a document using a program for whichI navigate on the computer - and not one assigned to the document, if I click on 'Browse' the white on the box and I get the messa

  • How to remove the keyboard on Satellite L850?

    Nobody here knows how to remove the keyboard on a L850 or can point me in the direction of the repair?Older models had a band at the top that does this is very simple, but this model seems to be sealed in.

  • Motorcycle shipping 360

    I had an order a couple of days for a 360 of motorcycle, and the expected delivery date, said happen on 18-12-14. Problem is that I'm leaving the country in 6 days. What were the popular experience on the shipping time? Do you have your watch arrive

  • New wireless adapter

    Hello I have a HP Envy 15-j010us I have problems with my improved wireless card. I bought a 7260.HMWG AC Intel WiFi card in replacement of the RAlink card came with the laptop.  The RaLink card did not work well.  He drops the internet connection con