selecting the top folder of each student

Hello

I have a table named the school where I have a list of students, the table looks like this.

score of the student to school
A 14 1 AB
A 7 2 AC
A 17 1 AA
B 1 2 BA
BB 4 2 B

I need the output as follows
score of the student to school
A 14 1 AB
B 1 2 BA

Regardless of the values of the student, mark and I need the first record of each school.

Something like that-

select school,
       student,
       score,
       in
from (
        select school,
               student,
               score,
               in,
               row_number() over(partition by school order by t_tmstmp) rn
        from t
     )
where rn = 1

N.B.: Not tested...

Kind regards.

LOULOU.

Tags: Database

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How to find the rank lowest for each student using a Select query?
Hey I'm having a little trouble here

I have this table

Student - Grade

John - 8
Richard - 9
Louis - 9
Francis - 5
John - 13
Richard - 10
Peter - 12

Shades may vary from 0 to 20.

Name - varchar (50)
Grade - wide

I'm trying to generate a SQL search to search for each rank lowest for each student.

So far, I did:

Select s.name, s.grade
s student
where s.grade = (select min (grade) of student)

The result of this search returns me only the rank lowest of all ranks posted above, which is Francis - 5.

I want to find the lowest rank, but not only for Francis, but for all students in the table.

How do I do that?

Thank you in advance.
Ok

Now we head into analytical SQL:
```
with student as (select 'John' name, 8 grade, 'fail' result from dual union all
                 select 'John' name, 13 grade, 'pass' result from dual union all
                 select 'Francis',     5 grade,  'fail' from dual union all
                 select 'Peter', 12, 'pass' from dual)
-- End of your test data
SELECT   name,
         MAX (result) KEEP (DENSE_RANK FIRST ORDER BY grade) result,
         MIN (grade) min_grade
FROM     student
GROUP BY name
```
Please note that I passed ;)

Concerning
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To learn more:
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Remove duplicates by selecting the first line of each subgroup in a Recordset

Oracle: 11 GR 2
Client Windows 7
I have a set of data (the result of a query) which is similar to:
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1 112233 prod1-iphone phone 200 500 100
1 112233 prod1-iphone4 phone 200 500 100
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:                    :               :                                   :               :             :              :
:                    :               :                                   :               :             :              :
:                    :               :                                   :               :             :              :
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2 223344 prod2-300 1000 400 windows7 OS
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:                    :               :                                   :               :             :              :
:                    :               :                                   :               :             :              :
:                    :               :                                   :               :             :              :
You will enjoy the little help.

Hello

user13667036 wrote:

Oracle: 11 GR 2

Client Windows 7

I have a set of data (the result of a query) which is similar to:

D_rank product_id product_desc category income price cost

1 112233 prod1-iphone phone 200 500 100

1 112233 prod1-iphone4 phone 200 500 100

2 223344 prod2-300 1000 400 windows7 OS

2 223344 prod2-300 1000 400 software windows7

3 334455 prod3-Mac 1000 computer 1500-1000

4 445566 prod4-xyz 2000 800 1200 misc

:                    :               :                                   :               :             :              :

:                    :               :                                   :               :             :              :

:                    :               :                                   :               :             :              :

As you can see the first 4 rows, these rows are repeated due to the product_desc and category material. I have need of these fields but the first value of each subgroup...

...

What does "first" here? What "subgroup"?

Depending on your needs, maybe you want to Request Top - N, something like this:

WITH got_r_num AS

(

SELECT d_rank, product_id, product_desc, category, price, income, cost

ROW_NUMBER () OVER (PARTITION BY d_rank

ORDER BY product_desc, category

) AS r_num

OF data_set

)

SELECT d_rank, product_id, product_desc, category, price, income, cost

OF got_r_num

WHERE r_num = 1

;

I hope that answers your question.

If this isn't the case, please post a small example of data (CREATE TABLE and INSERT statements) and the results desired from these data. (I know you said this is a game of results from a query, and not an array, but the solution is the same as the entry is a single table, or a query, perhaps involvoing several tables.)

Report when the request above is erroneous results and explain, using specific examples, how find you the correct results from these data.

As said ground, see the FAQ in the forum: Re: 2. How can I ask a question on the forums?

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RowKeySet ch = this.roleTable.getSelectedRowKeys ();

PS. Clear();

PS. Add (this.roleTable.getRowKey ());

AdfFacesContext.getCurrentInstance () .addPartialTarget (this.roleTable);

Make sure the displayRow selected = is defined in the table property

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------------------------------- -------- ----
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Hello

I have a table that contains all the contacts that we have with our customers.
We consider a file active file from the moment where there was 2 contacts for this customer.
Today someone asked me "can you tell me how many new customers with an active file, we have this year."

So what I really want to do now is make a view that contains the DATE of the SECOND CONTACT for each CLIENT_ID.

the table looks like this:
CONTACT_ID
CLIENT_ID
DATE
CONTACT_FORM (any in this story)
REMARKS (any in this story)

Can someone help me with this please?

Thanks in advance for your answers.

L

change I don't know how to make an opinion, which is not the problem :) in this case only the query select to make the problem there.

Edit 2 I made a small example

If I start with the data in this table:
```
CLIENT_ID || DATE           .... other columns here...
436     || 01-02-2011
328     || 05-04-2011
319     || 13-01-2011
220     || 03-09-2011
319     || 17-12-2011
220     || 25-11-2011
436     || 01-04-2011
436     || 01-04-2011
```
that vision must end up with:
```
CLIENT_ID  || DATE_OF_SECOND_CONTACT
436     || 01-04-2011
220     || 25-11-2011
319     || 17-12-2011
```
(works with version 11.2.0.1.0)

Published by: 901981 on 13-dec-2011 02:16
If you do something like
```
SELECT CLIENT_ID, date_column
FROM (
SELECT client_id, date_column, row_number() over (partition by client_id order by date_column asc) AS CONTACT
FROM YOUR_TABLE)
where contact = 2
/
```
HTH

Roger

Published by: Roger on December 13, 2011 02:19

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Hello!

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27.09.2009 20:00:00       150           DB1
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Please let me know if you need further information.

Published by: user7066552 on September 29, 2009 10:17

Published by: user7066552 on September 29, 2009 10:17

Why two queries when it suffice ;)

SQL> select dt
  2       , db
  3       , val
  4       , avg_val
  5    from (
  6  select dt
  7       , val
  8       , db
  9       , row_number () over (partition by db, trunc (dt)
 10                                 order by dt desc
 11                            ) rn
 12       , avg (val) over (partition by db, trunc (dt)) avg_val
 13    from test)
 14   where rn = 1
 15  order by dt
 16  /

DT        DB           VAL    AVG_VAL
--------- ----- ---------- ----------
27-SEP-09 DB2         1100       1050
27-SEP-09 DB1          150        125
28-SEP-09 DB2         2000       1750
28-SEP-09 DB1          220        210

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selecting the top folder of each student

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