Showing and hiding of multiple tables with a drop-down list

I'm doing a drop-down list so that users can select the number of tables that are shown/generated when they specify the tables how they need to complete (there is 1 table for each day of a multi = day, maximum of 5).

I thought I would use a similar javascript than I used in another place on the form that has been applied to radio buttons to show or hide a specific table. When I applied that to the drop down and added more than lines that the scipt was ineffective, with some play that I managed to do the work, but now it seems thre is a question with which value is selected in the list. When a user selects a certain value, it shows the previous value (so when I chose 4 days, which has a hairy '3', the message box for the test proposed, I added told me I selected the value '2').

I wonder if there is an easier way to do the function, what I'm doing, or if the drop down menu is the best solution? The maximum number of tables that can be filled is 5, then the drop down menu appears as a way ideal for resticting than for the person filling out the form.

This is an example of writing, that I joined the drop-down list, as an action of "change." It is repeated 4 times for each value.

Form1. Page2.DropDownList1::change - (JavaScript, client)

If (this.value == '2') {}

Form1. Page2.TableDay1.presence = "visible";

Form1. Page2.TableDay2.presence = "visible";

Form1. Page2.TableDay3.presence = 'hidden ';

Form1. Page3.TableDay4.presence = 'hidden ';

Form1. Page3.TableDay5.presence = 'hidden ';

}

else {}

Form1. Page2.TableDay1.presence = 'hidden ';

Form1. Page2.TableDay2.presence = 'hidden ';

Form1. Page2.TableDay3.presence = 'hidden ';

Form1. Page3.TableDay4.presence = 'hidden ';

Form1. Page3.TableDay5.presence = 'hidden ';

}

If (this.value == '3') {}

Form1. Page2.TableDay1.presence = "visible";

Form1. Page2.TableDay2.presence = "visible";

Form1. Page2.TableDay3.presence = "visible";

Form1. Page3.TableDay4.presence = 'hidden ';

Form1. Page3.TableDay5.presence = 'hidden ';

}

else {}

Form1. Page2.TableDay1.presence = 'hidden ';

Form1. Page2.TableDay2.presence = 'hidden ';

Form1. Page2.TableDay3.presence = 'hidden ';

Form1. Page3.TableDay4.presence = 'hidden ';

Form1. Page3.TableDay5.presence = 'hidden ';

}

I looked at it and tried a few different things and my colleague who is much better than me with sciprting is also at a loss for now - he is unfamiliar with LiveCycle, unless I have so any help is appreciated. Thanks a lot once again as my last number (the script for radio buttons) has been resolved here. Thanks again.

The question that you see with the value being off is due to the fact that you use the change event. The change event is triggered * before * the new value is assigned to the field. This event is commonly used for intercpet changes. If you wish to continue using the change event, you can get the new value with:

xfa.event.newText;

This, however, will get the text that is displayed instead of the value behind. No doubt, you can consult the nodes in the drop-down list to see what value, but I think you should just avoid all of this by adding your code to the layout event: each subform hideable... loan for example, for the first, in the case of TableDay2 layout_ready (as the day1 should never be hidden, as I understand it) put :

This.Presence = (DropDownList1.rawValue > = 1)? "visible": "hidden";

TableDay3 would be:

This.Presence = (DropDownList1.rawValue > = 2)? "visible": "hidden";

etc.

Let me know if it helps.

-Scott

Tags: Adobe LiveCycle

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