SQL Count helps

Similar Questions

• SQL query - help with join

  Dear friends,

  Version of DB - 11.1.0.7... , I'm stuck with SQL basics today... need your help...

  The slot SQL tells me "cache them locks library" in the database that I will put up as a proactive measure.

  I'll be it works via shell script and include the table gv instance_name $ instance ... I'm a little confused as to how a 3rd table "gv$ instance ' can be introduced into the query in order to make the instance_name in the result set...

  SELECT * FROM)

  SELECT / * + LEADING (a) USE_HASH (u) * /.

  instance_name, INST_ID select, blocking_inst_id, blocking_session, username, session_id, sql_id, current_obj #,.

  DECODE (sql_opcode, 1, 'CREATE TABLE', 2, 'INSERT') as "order."

  Event, mod(P1,16) p1, p2, p3

  COUNT (*) totalseconds

  , SUM (CASE WHEN wait_class = 'Application' THEN 1 ELSE 0 END) 'Application '.

  Of

  (SELECT

  a.*

  , TO_CHAR (CASE WHEN session_state = 'WAITING' THEN ELSE null END p1, '0XXXXXXXXXXXXXXX') p1hex

  , TO_CHAR (CASE WHEN session_state = "PENDING" THEN p2 ELSE null END, '0XXXXXXXXXXXXXXX') p2hex

  , TO_CHAR (CASE WHEN session_state = "PENDING" THEN ELSE null END p3, '0XXXXXXXXXXXXXXX') p3hex

  SGS $ active_session_history one) a

  u dba_users

  WHERE

  a.user_id = u.user_id

  AND sample_time BETWEEN sysdate-90 /(24*60) AND sysdate

  - AND a test of ('library cache lock', 'library cache pin")

  AND event like '% library '.

  GROUP BY

  INST_ID select, blocking_inst_id, blocking_session, username, session_id, sql_id, current_obj #,.

  DECODE (sql_opcode, 1, 'CREATE TABLE', 'INSERT', 2),

  event, mod (p1, 16), p2, p3

  Having count (*) > 5

  ORDER BY

  TotalSeconds DESC

  , INST_ID select, blocking_session, username, session_id, sql_id, current_obj #, 'Order', event

  )

  WHERE

  ROWNUM < = 20

  /

  replace

  instance_name

  by

  (select instance_name gv$ instance where INST_ID select = a.inst_id) instance_name

  or select... in... a, u, gv$ instance where... and gv$ instance.inst_id (+) = a.inst_id...

• GROUP OF + SQL COUNT + SUM

  Hello
  
  I have a table, it has 2 colunms, (name, number)
  
  name number
  B1 7
  B1 7
  B1 28
  B1 28
  B1 28
  B2 7
  B2 28
  B3 7
  . .
  . .
  .
  .
  
  
  I want to see below
  
  number
  name sum 7sum 28sum
  
  5 2 3 B1
  2 1 1 B2
  B3...
  .
  .
  .
  .
  .
  
  
  Can you help me
  
  THANK YOU VERY MUCH FOR HELP

  Like this?

  SQL> ed
  Wrote file afiedt.buf
  
    1  with t as (select 'B1' as name, 7 as num from dual union all
    2             select 'B1', 7 from dual union all
    3             select 'B1', 28 from dual union all
    4             select 'B1', 28 from dual union all
    5             select 'B1', 28 from dual union all
    6             select 'B2', 7 from dual union all
    7             select 'B2', 28 from dual union all
    8             select 'B3', 7 from dual)
    9  --
   10  -- end of test data - use query below
   11  --
   12  select name
   13        ,count(*)
   14        ,sum(decode(num,7,1,0)) as sum7
   15        ,sum(decode(num,28,1,0)) as sum28
   16  from t
   17  group by name
   18* order by 1
  SQL> /
  
  NA   COUNT(*)       SUM7      SUM28
  -- ---------- ---------- ----------
  B1          5          2          3
  B2          2          1          1
  B3          1          1          0
  

• error of dynamics of the associative array (pl/sql), please help

  Function down I can hard-coded but not able to go to dynamically can u please friends
  
  CREATE OR REPLACE FUNCTION FN_SUBSCRIPTION_BEHAVIOUR(P_YYMM IN VARCHAR2) RETURN VARCHAR2
  AS
  ARR_LIST APEX_APPLICATION_GLOBAL. VC_ARR2;
  Typ_array. ARRAY TYPE IS VARCHAR2 (16);
  array_final typ_array;
  V_ARRAY VARCHAR2 (2000);
  v_out VARCHAR2 (2000);
  v_result VARCHAR2 (2000);
  BEGIN
  ARR_LIST: = APEX_UTIL. STRING_TO_TABLE (P_YYMM, ',');
  Select LISTAGG (fid_value, ',') IN GROUP (ORDER BY fid_value) BY v_array
  of filter_detail, filter_master
  where fil_id = fid_fil_id
  and fil_position = 15
  AND NVL (fid_ACTIVE, 'Y') = 'Y ';
  array_final: = typ_array (v_array); Commented (1102,1101,1012,1011,1010,1009,1008,1007,1006,1005,1004,1003,1002,1001);
  I'm looping 1.array_final.count
  If array_final (i) in (arr_list (I)) then v_result: = '1';--Commented--(1002,1003,1007)
  Another v_result: = '0';
  end if;
  v_out: = v_out | v_result;
  end loop;
  Return v_out;
  END;
  
  
  my output is
  
  00000001000110
  
  Published by: V on March 23, 2011 21:42
  
  Published by: V on March 23, 2011 22:24
  
  Published by: V on March 23, 2011 23:00
  
  Published by: V on March 24, 2011 12:57 AM

  Hello

  Please check below, hope this helps.

  SQL>
  SQL> DROP TABLE tmp
    2  /
  
  Table dropped
  SQL> CREATE TABLE tmp ( col1 NUMBER)
    2  /
  
  Table created
  SQL> INSERT INTO tmp
    2      SELECT 1001 FROM DUAL UNION
    3      SELECT 1002 FROM DUAL UNION
    4      SELECT 1003 FROM DUAL UNION
    5      SELECT 1004 FROM DUAL UNION
    6      SELECT 1005 FROM DUAL UNION
    7      SELECT 1006 FROM DUAL UNION
    8      SELECT 1007 FROM DUAL UNION
    9      SELECT 1008 FROM DUAL UNION
   10      SELECT 1009 FROM DUAL UNION
   11      SELECT 1010 FROM DUAL UNION
   12      SELECT 1011 FROM DUAL UNION
   13      SELECT 1012 FROM DUAL UNION
   14      SELECT 1101 FROM DUAL UNION
   15      SELECT 1102 FROM DUAL
   16  /
  
  14 rows inserted
  SQL> COMMIT
    2  /
  
  Commit complete
  SQL> CREATE OR REPLACE FUNCTION FN_SUBSCRIPTION_BEHAVIOUR(P_YYMM IN VARCHAR2)
    2    RETURN VARCHAR2 AS
    3    ARR_LIST APEX_APPLICATION_GLOBAL.VC_ARR2;
    4    TYPE typ_array IS TABLE OF VARCHAR2(16);
    5    array_final typ_array;
    6    V_ARRAY     VARCHAR2(2000);
    7    v_out       VARCHAR2(2000);
    8    v_result    VARCHAR2(2000);
    9  BEGIN
   10    select LISTAGG(col1, ',') WITHIN
   11     GROUP(
   12     ORDER BY col1)
   13      INTO v_array
   14      from tmp;
   15    ARR_LIST := APEX_UTIL.STRING_TO_TABLE(v_array, ',');
   16    for i in 1 .. ARR_LIST.count loop
   17      if (INSTR(P_YYMM, ARR_LIST(i)) > 0) then
   18        v_result := '1';
   19      else
   20        v_result := '0';
   21      end if;
   22      v_out := v_out || v_result;
   23    end loop;
   24    return v_out;
   25  END;
   26  /
  
  Function created
  SQL> DECLARE
    2     l_out   VARCHAR2(2000);
    3  BEGIN
    4     l_out := FN_SUBSCRIPTION_BEHAVIOUR('1002,1003,1004');
    5     dbms_output.put_line(l_out);
    6  END;
    7  /
  
  01110000000000
  
  PL/SQL procedure successfully completed
  
  SQL> 
  

  Ameya

• SQL count (*) with Group of

  Hello
  
  I need help to fix this SQL.
  
  Fields in the table are like that.
  

  ID(PK)
  user_id
  user_name
  login_time(timestamp)

  Basically I want the values of user_id, user_name, last time the logged-in user and total number of times the user
  

  select  distinct user_id , user_name, login_date from USER_LOGIN
  where login_date in (select max(login_date) from USER_LOGIN group by user_id) 

  the above query is to give the result set with user_id, user_name, last time that the user logged on, but how can I include count (*) Group of user_id in the sql above
  

  select  distinct user_id , user_name, login_date, count(*) from USER_LOGIN
  where login_date in (select max(login_date) from USER_LOGIN group by user_id)  group by user_id 

  the sql above does not work.
  
  can you help me to get the number of records by user_id group.
  
  Thank you
  SK

  Hello

  Looks like you want something like this:

  SELECT       user_id
  ,       user_name
  ,       MAX (login_time)     AS last_login_time
  ,       COUNT (*)          AS total_rows
  FROM       user_login
  GROUP BY  user_id
  ,            user_name
  ;
  

  This assumes that user_login is off standard (like him are often seen), such that every row of the same user_id will also have the same user_name.

  I hope that this answers your question.
  If not, post a small example of data (CREATE TABLE and INSERT statements) and the results desired from these data.

• SQL query help

  Hello

  I have the table and professorid, studentid, classid.

  Please provide the sql code to find professor_id which hosts up to students.

  with t as)

  Select professor_id,

  ROW_NUMBER() over (order by count (distinct student_id) desc) rn

  from your_table

  Professor_id group

  )

  Select professor_id

  t

  where rn = 1

  /

  However, if there is a tie and a teacher number max of students has more meanings will select one of them. If you want that all teachers use:

  with t as)

  Select professor_id,

  DENSE_RANK() over (order by count (distinct student_id) desc) rn

  from your_table

  Professor_id group

  )

  Select professor_id

  t

  where rn = 1

  /

  SY.

• SQL Query help find albums from sale

  Hi Experts,

  I have the following data and the need to find the book Top sold in each type.

  Book Type QTY

  20	Help the	3
  10	Kitchen	1
  5	Navigation	2
  30	Help the	4

  Please let me how can know we get this simple SQL help?

  Thank you

  Bharat

  Hello

  Bharat Hegde wrote:

  Hi all

  I tried to use Dense_rank as below. But it gives me the top selling books. I need high library in each type...

  This looks like a job for 'PARTITION BY type

  For example:

  WITH got_rnk AS

  (

  SELECT b.bid, b.type

  SUM (o.quantity) AS total_quantity

  DENSE_RANK () OVER ( PARTITION BY b.type

  ORDER OF SUM (o.quantity) / / DESC

  ) AS rnk

  B BOOK

  o order1

  WHERE b.bid = o.bid

  GROUP BY b.bid, b.type

  )

  SELECT total_quantity, type submission

  OF got_rnk

  WHERE rnk = 1

  ;

  . Aggregate functions (such as the SUM, above) are calculated before analytical functions, so an analytic function (such as DENSE_RANK above) may depend on an aggregate function; you don't need a separate subquery for that.

• SQL Count query - Assistance needed

  Hello

  Hoping someone can point me in the right direction. Here's the query I have so far. What I'm trying to do is to compare and add the names of the skills of individuals. My current query will count them, however, I need to take a step further where if the person has a name of "Spanish" skills can only which is counted and not their names other skills.

  Current query:

  WITH AS TBL1

  (SELECT

  TRIM (A.NWIE_ID) AS NWIE_ID,

  A.AGENT_NM,

  B.BUSINESS

  Of

  LIGHTHOUSE. IEX_AGENTS A JOIN

  LIGHTHOUSE. TBL_GEN_MU_BUSINESS B

  ON A.MU_ID = B.MU_ID

  WHERE B.BUSINESS IN ('PL_LEGACY'));

  TBL2 ACE

  (SELECT

  TRIM (C.USER_ID) AS USER_ID,

  TRUNC (ASOF_DT, 'IW') AS WEEKBEGINNING,

  CASE

  WHERE (SKILL_NM = 'PLSCLegacy' AND SKILL_LEVEL < = 2) THEN "basic".

  WHERE (SKILL_NM = 'PLSCLegacy' AND SKILL_LEVEL < = 7) THEN "moderate."

  WHERE (SKILL_NM = 'PLSCLegacy' AND SKILL_LEVEL < = 10) THEN 'complex '.

  WHERE (SKILL_NM = "PLSCLegacySpanish") THEN 'Spanish '.

  Another null

  END AS SKILL_NM

  THE LIGHTHOUSE. C CFG_PERSON_SKILL_HIST

  )

  SELECT

  WEEKBEGINNING,

  SKILL_NM,

  COUNT (DISTINCT NWIE_ID) TOTAL_SKILLED

  Of

  TBL1,

  TBL2

  WHERE TBL1. NWIE_ID = TBL2. USER_ID

  AND SKILL_NM NOT IN ('NULL %')

  SKILL_NM GROUP, WEEKBEGINNING

  ORDER OF WEEKBEGINNING, SKILL_NM

  Create the Table data:

  CREATE TABLE IEX_AGENTS

  (

  AGENT_NM VARCHAR2 (20).

  NWIE_ID CHAR (8),

  NUMBER OF MU_ID (5)

  )

  CREATE TABLE TBL_GEN_MU_BUSINESS

  (

  BUSINESS VARCHAR2 (100),

  NUMBER OF MU_ID (5)

  )

  CREATE TABLE CFG_PERSON_SKILL_HIST

  (

  USER_ID VARCHAR2 (8).

  DATE OF ASOF_DT,

  SKILL_NM VARCHAR2 (64).

  NUMBER OF SKILL_LEVEL (10)

  )

  INSERT INTO IEX_AGENTS (AGENT_NM, NWIE_ID, MU_ID) VALUES ("Marcelle, Athalie", "MARCELA1", 5)

  INSERT INTO IEX_AGENTS (AGENT_NM, NWIE_ID, MU_ID) VALUES ('Lister, Laura", 'LISTERL3', 6)

  INSERT INTO IEX_AGENTS (AGENT_NM, NWIE_ID, MU_ID) VALUES ("Purvis, Bradley", 'PURVIB1', 4)

  INSERT INTO IEX_AGENTS (AGENT_NM, NWIE_ID, MU_ID) VALUES ("Cannon, Mark", "CANNON1", 4)

  INSERT INTO TBL_GEN_MU_BUSINESS (BUSINESS, MU_ID) VALUES ('PL_LEGACY', 5)

  INSERT INTO TBL_GEN_MU_BUSINESS (BUSINESS, MU_ID) VALUES ('PL_LEGACY', 6)

  INSERT INTO TBL_GEN_MU_BUSINESS (BUSINESS, MU_ID) VALUES ('PL_LEGACY', 4)

  INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('PURVIB1', 3/9/2014 12:00 ',' PLSCLegacy', 1).

  INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('MARCELIA1', 3/9/2014 12:00 ',' PLSCLegacy', 10)

  INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('LISTERL3', 3/9/2014 12:00 ',' PLSCLegacy', 7)

  INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('CANNON1', 3/9/2014 12:00 ',' PLSCLegacy', 7)

  INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('MARCELIA1', 3/9/2014 12:00 ',' PLSCLegacySpanish', 3)

  INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('LISTERL3', 3/9/2014 12:00 ',' PLSCLegacySpanish', 6)

  INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('PURVIB1', 3/9/2014 12:00 ',' PLSCLegacySpanish', 2)

  INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('PURVIB1', 3/19/2014 12:00 ',' PLSCLegacy', 10)

  INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('LISTERL3', 3/19/2014 12:00 ',' PLSCLegacy', 2)

  INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('MARCELIA1', 3/9/2014 12:00 ',' PLSCLegacy', 10)

  INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('CANNON1', 3/19/2014 12:00 ',' PLSCLegacy', 7)

  INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('CANNON1', 3/19/2014 12:00 ',' PLSCLegacySpanish', 7)

  Results of the current query:

  WEEKBEGINNING	SKILL_NM	TOTAL_SKILLED
  07/03/2014 12:00:00 AM	Foundational	1
  07/03/2014 12:00:00 AM	Complex	1
  07/03/2014 12:00:00 AM	Moderate	2
  07/03/2014 12:00:00 AM	Spanish	3
  14/03/2014 12:00:00 AM	Foundational	1
  14/03/2014 12:00:00 AM	Complex	2
  14/03/2014 12:00:00 AM	Moderate	1
  14/03/2014 12:00:00 AM	Spanish	1

  Desired results:

  WEEKBEGINNING	SKILL_NM	TOTAL_SKILLED
  07/03/2014 12:00:00 AM	Foundational	0
  07/03/2014 12:00:00 AM	Complex	0
  07/03/2014 12:00:00 AM	Moderate	1
  07/03/2014 12:00:00 AM	Spanish	3
  14/03/2014 12:00:00 AM	Foundational	1
  14/03/2014 12:00:00 AM	Complex	2
  14/03/2014 12:00:00 AM	Moderate	0
  14/03/2014 12:00:00 AM	Spanish	1

  WITH ACE TBL1)

  SELECT TRIM (A.NWIE_ID) AS NWIE_ID,

  A.AGENT_NM,

  B.BUSINESS

  OF IEX_AGENTS HAS

  JOIN THE

  TBL_GEN_MU_BUSINESS B

  ON A.MU_ID = B.MU_ID

  WHERE B.BUSINESS IN ("PL_LEGACY")

  ),

  (ACE TBL2)

  SELECT USER_ID, TRIM (C.USER_ID)

  TRUNC (ASOF_DT, 'IW') AS WEEKBEGINNING,

  CASE

  WHERE (SKILL_NM = 'PLSCLegacy' AND SKILL_LEVEL<= 2)="" then="">

  WHERE (SKILL_NM = 'PLSCLegacy' AND SKILL_LEVEL<= 7)="" then ="">

  WHERE (SKILL_NM = 'PLSCLegacy' AND SKILL_LEVEL<= 10)="" then ="">

  WHERE (SKILL_NM = "PLSCLegacySpanish") THEN 'Spanish '.

  END AS SKILL_NM

  OF CFG_PERSON_SKILL_HIST C

  ),

  (AS TBL3)

  SELECT USER_ID,

  WEEKBEGINNING,

  SKILL_NM,

  COUNT)

  SKILL_NM SEPARATE CASE

  WHEN 'Spanish', 1

  END

  ) HAS_SPANISH OVER (PARTITION BY USER_ID, WEEKBEGINNING)

  FOR TBL2

  )

  SELECT WEEKBEGINNING,

  SKILL_NM,

  COUNT)

  SEPARATE CASE

  WHEN HAS_SPANISH = 0 THEN NWIE_ID

  WHEN SKILL_NM = "Spanish" THEN NWIE_ID

  END

  ) TOTAL_SKILLED

  FROM TBL1;

  TBL3

  WHERE TBL1. NWIE_ID = TBL3. USER_ID

  AND SKILL_NM NOT IN ('NULL %')

  SKILL_NM GROUP,

  WEEKBEGINNING

  ORDER OF WEEKBEGINNING,

  SKILL_NM

  /

  WEEKBEGINNING SKILL_NM TOTAL_SKILLED
  ---------------------- ------------ -------------
  03/03/2014 12:00:00 am founders 0
  03/03/2014 moderate from 12:00:00 am 0
  03/03/2014 12:00:00 am 2 Spanish
  17/03/2014 12:00:00 am complex 1
  17/03/2014 12:00:00 am basic 1
  17/03/2014 12:00:00 am Spanish 1

  6 selected lines.

  SQL >

  SY.

• SQL - select Help - box When? Return value of the second Table?

  -Next to people on this forum I am probably somewhere between a beginner and an intermediate SQL user.

  Ive been using a case when stated in plsql to find "all who has status in any program was canceled during a specific time, but have become or are still active in another program"

  So, Im actually trying to return a value from another table in a case where, but this isn't anthing taste other than a text declared as 'Yes' or 'no '.

  This is the select statement - y at - it another way to do it where I can get the results I need?

  -case when pp.party_id in (select pp1.party_id - cancelled active clients in another program)

  of asa.program_participation pp1,.

  ASA.curr_prog_participation_status cpps1

  where pp1.program_participation_id = cpps1.program_participation_id

  and pp1.party_id = pp.party_id

  and cpps1.code_value = 'Act')

  So 'Yes' is still 'No' end as Active_in_Other_Prg

  So - instead of 'Yes', I want essentially the program they are active or pp1.program_id, another null

  It is possible that the client can be active in more than one program as well.

  Any help is greatly appreciated, I explored with if and decodes but I can't get anything to work.

  Ben

  Looks like an outer join. See doc ora: joins at

  Select p

  q.party_id

  q.program_id

  of table_with_party_id p

  , (select pp1.party_id - cancelled active clients in another program)

  pp1.program_id

  of asa.program_participation pp1,.

  ASA.curr_prog_participation_status cpps1

  where pp1.program_participation_id = cpps1.program_participation_id

  and pp1.party_id = pp.party_id

  and cpps1.code_value = 'ACT') q

  where p.party_id = q.party_id (+)

  Note: In the example above shoudn't it be a space between the (and +), but the forum software automatically converts to

  The outer join will connect display all records in the table p and q records only if fits the party_id, IE q.party_id and q.program_id will be null if there is no match.

  Edit: adding program_id

• PL/SQL code help

  Morning all,

  I need assistance with regard to the PL/SQL code.

  Question: How many cases was activated from Direct treatment information/advice within 8 weeks?

  Sample data:

  MEMBER_ID	CASE_ID	SP_CODE	SP_NAME	SP_SUBTYPE_CODE	SP_SUBTYPE_NAME	REFERRAL_DATE	SERVICE_DATE
  000000001	2013858	1001	Info & advice	1001	Information	-	25/09/2012
  000000001	2013858	1005	Direct treatment	1022	Seamless	10/01/2012	10/01/2012

  I need to count the number of the place where CASE_ID SP_CODE = '1001 ' and then a SP_CODE = '1005' as the program installation, then the difference between SERVICE_DATE for ' 1001' and for '1005' REFERRAL_DATE is within 8 weeks? I hope this makes sense?

  Hello

  One way is to use a Sun-query EXISTS, like this:

  SELECT COUNT (case_id) AS cnt - or COUNT (DISTINCT case_id)

  FROM table_x m

  WHERE sp_code = 1005

  AND THERE ARE)

  SELECT 1

  FROM table_x

  WHERE sp_code = 1001

  AND case_id = m.case_id

  AND service_date > = m.service_date - (8 * 7)

  AND service_date< >

  )

  ;

  I hope that answers your question.

  If not, post a small example of data (CREATE TABLE and INSERT statements) and the results desired from these data.  Point where the query above will not and explain how to get good results in these places.

  See the FAQ forum: https://forums.oracle.com/message/9362002#9362002

  The combination (case_id, sp_code) is unique?  What happens if a case_id has, say, 1001 multiple s all less than 8 weeks before the same 1005?

  Member_id (or one of the other columns not in the above query) plays no role in this problem?

• SQL statement Help Find County

  I have an Oracle table with lot of columns and I want to check if 3 of my columns contain all values (I don't like the real value, there, I just want to know how many of them have a value). Allows so say for example:
  
  Table columns: ID, A, B, C
  
  These conditions would be true... value exists in both A AND B, A AND C or B AND C columns. If a value exists in A and not B or C, then it should not be counted. Similarly, if a value exists in B and not A or C, or there is a value C and not A or B, then he shouldn't have counted.
  
  ----------------------
  | ID | A | B | C |
  ----------------------
  | 1. X | X | | <-true
  | 1. X | X | X | <-true
  | 1. X | | X | <-true
  | 1 | | X | X | <-true
  | 1. X | | | <-false
  | 1 | | X | | <-false
  | 1 | | | X | <-false
  | 1 | | | | <-false
  | 2. X | X | | <-true
  | 2. X | X | X | <-true
  | 2. X | | X | <-true
  | 2 | | X | X | <-true
  | 2. X | | | <-false
  | 2 | | X | | <-false
  | 2 | | | X | <-false
  | 2 | | | | <-false
  ----------------------
  
  Static values will be my ID. I want to check against 2 ID who I know will always be the case. I tried to write, but I'm sure I'm doing something wrong because my count was very high (about 1.7 million records over 2 million).
  
  That's what I wrote:
  
  Select count (*)
  FROM table1
  where (ID = "1" or ID = "2")
  (A is not null and B is not null)
  or (A is not null and is not null)
  or (B is not null and is not null);
  
  Thanks for your help!
  
  Published by: 973560 on March 14, 2013 12:03

  Hello

  One way to see how many rows have values in at least 2 of the following columns:

  SELECT  COUNT (*)     AS cnt
  FROM     table1
  WHERE     id     IN ('1', '2')     -- is id really a string?
  AND     NVL2 (a, 1, 0)
        + NVL2 (b, 1, 0)
        + NVL2 (c, 1, 0) >= 2
  ;
  

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
  Point where the above query is to produce erroneous results, and explain, using specific examples, how you get the right results from data provided in the palces.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).
  See the FAQ forum {message identifier: = 9360002}

• PL/SQL cursor help

  Dear Experts,
  
  I need help, writing / editing PL/SQL procedure below. My task is to rebuild indexes on tables that were not rebuilt during the last 24 hours. The "select" statement of down gives me the list of all the names of tables whose indexes are not rebuilt in last 24 hours (maint.index_rebuild is a custom table, we built to capture the rebuild index timings).
  
  maint.online_reorg procedure done index rebuild. I need this procedure to run on all tables (returned by the select statement). How can I get the modified procedure to get what I'm looking for below. Enjoy your entries.
  
  

  declare cursor c1 is
  select distinct table_name from maint.index_rebuild where start_time <= SYSDATE-1;
  begin
  for i in c1 loop
  maint.online_reorg('OWNER','table name from cursor result set');
  end loop;
  end;
  /

  declare
    cursor c1 is
      select distinct table_name from maint.index_rebuild where start_time <= SYSDATE-1;
  begin
    for i in c1 loop
      maint.online_reorg('OWNER',i.table_name);
    end loop;
  end;
  

  will do what you ask. As others have pointed out, however, what you're trying to do is strongly discouraged. Reconstruction of each index everyday is going to generate a huge amount of load on your database for no benefit and creates a number of opportunities to introduce errors.

  Justin

• The join SQL query help

  I'm just having a bit of troubel get a correct join query - I thought it was an Inner Join, but I don't get the results I expect.

  My table structure is:

  Table: lodges

  LodgeID (PK)

  Lodge

  etc.

  Table: implemented application

  NominationID (PK)

  Category

  LodgeID

  Year

  So I try to use this structure to replicate this page:

  http://www.safariawards.com/nominees12/

  That is to say a list of boxes for each category, they are appointed on.

  The query I've tried looks like this:

  SELECT appointments. LodgeID, lodges. Lodge, applications. NominationID, applications. Lodges INNER JOIN applications category IT lodges. LodgeID = nominated. NominationID WHERE category = "Best property of Safari in southern Africa" ORDER BY Lodge

  But this product:

  http://www.safariawards.com/nominees12/southernafrica.php

  Its the right number of results, but not the list on the right of the boxes - for example British Airwways is not LodgeID 786

  If anyone could help with the SQL right for what would be well appreciated.

  That you join on the wrong column. Try this:

  SELECT appointments. LodgeID, lodges. Lodge, applications. NominationID, applications. Lodges INNER JOIN applications category IT lodges. LodgeID = nominated. LodgeID WHERE category = "Best property of Safari in southern Africa" ORDER BY Lodge

• Oracle 11G install on Win 7 with PL/SQL Developer Help Needed

  Today is my first day with Oracle. I tried to install Ora11g since our network drive. I think that the installation went well. I also have installated PL/SQL Developer when I try to log in I got the following error see below.
  
  ---------------------------
  PL/SQL Developer - (not connected)
  ---------------------------
  Initialization error
  
  SQL * Net not properly installed
  
  
  
  OracleHomeKey: SOFTWARE\ORACLE
  
  OracleHomeDir:
  ---------------------------
  Ok
  
  After I did some research on the Internet I found this solution "go to tools > Preferences > options manually set 'Oracle Home" in the folder "Library OIC" and ORACLE_HOME to file oci.dll is located in ORACLE_HOME/bin/oci.dll.
  
  C:\app\user\product\11.2.0\Client_1\bin.dll < = I think it's my Oracle_Home
  C:\app\user\product\11.2.0\client_1\bin\oci.dll < = is my OCI library.
  
  When I apply a thse 2 ways I get the following error.
  
  Initialization error
  
  Could not load C:\app\user\product\11.2.0\client_1\bin.dll «»
  
  OCIDLL to C:\app\user\product\11.2.0\client_1\bin.dll
  LoadLibrary (C:\app\user\product\11.2.0\client_1\bin\.dll) returned 0
  
  Can someone help me with this? /

  PL indicate which version of Win 7 - you need professional or superior - home versions are not taken in charge/certified, then things may or may not work as expected.

  http://download.Oracle.com/docs/CD/E11882_01/install.112/e16773/reqs.htm#CHDHGGFE

  HTH
  Srini

• SQL Newbie help

  The following query works fine but I need to do the same thing but this time by using a join explicitly.
  
  Select Departments.Deptnumber, Departments.name,
  sum (quantity)
  from SalesOrderItems, departments
  where Departments.Deptnumber = SalesOrderItems.DeptNumber
  Departments.Deptnumber group, Departments.name;
  
  
  
  I tried
  
  Select Departments.Deptnumber, Departments.name,
  sum (quantity)
  INNER JOIN SalesOrderItems ministries
  ON Departments.Deptnumber = SalesOrderItems.DeptNumber
  order of Departments.Deptnumber, Departments.name;
  
  but get the error
  ERROR at line 3:
  ORA-00933: SQL not correctly completed command.
  
  any help will be great thank you.

  What version of Oracle are you using?

  SELECT * FROM v$version
  

  ANSI style joins are available with version 9. ? and at the top

  John