start a virtual machine at startup of windows 7 via issue of short boot cut

Hi Experts

I am running Win7 with 10 Workstation. I'm trying to start a VM at startup as its suppose to host my server cloud. Then I don't have to manually start the virtual machine each time.

I put a shortcut to vmware workstation in the startup folder in the start menu. And followed the guide of the user of the WS10, excerpts below:

Incorporate the workstation Startup Options in a Windows shortcut

1 right click on the shortcut of the workstation and select Properties.

2 in the target text box, add all the options to use after the vmware.exe and place the entire order

quoted string.

For example:

«C:\Program VMware Workstation\vmware.exe x»

C:\Documents and utilisateur\Mes Documents\My Me\Windows Machines\Windows Settings\nom virtual

Me.vmx ".

So I did the same thing, but when I put in the path to my vmx file I get an error how the target path is invalid. That's what I put:

"C:\Program Files (x 86) \VMware\VMware Workstation\vmware.exe x - D:\My Documents\Virtual Machines\OwnCloud_2nd\OwnCloud_2nd.vmx.

But when I run it as a command such as file below, it works:

CD "C:\Program Files (x 86) \VMware\VMware Workstation\.

VMware.exe - x "D:\My Documents\Virtual Machines\OwnCloud_2nd\OwnCloud_2nd.vmx"

output

can someone point out to me what am I doing wrong?

Form the command as follows: "C:\Program Files (x 86) \VMware\VMware"-x "D:\My Documents\Virtual Machines\OwnCloud_2nd\OwnCloud_2nd.vmx.

Or you can configure the virtual machine to run as a Virtual Machine shared.  Check out the VMware Workstation Documentation and or the help file.

Tags: VMware

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