Store XML data in tables

Similar Questions

• Store decimal data in table

  I have a set of data

  lets say

  "3.45, 1.21, 3.67, 1.23, 4.78.

  I want to store these data in a table. So, how would I be able to store them in table form and yet be able to view the data?

  
  

• How update the relational table with XML data?

  I get XML messages that include a bunch of data items to be updated in a table. An arbitrary subset of rows is updated for each message received.
  
  The output of the following example is correct, but the use of the intermediate table that bothers me. The temporary table can be eliminated somehow? Or is the most reasonable way to loop just explicitly and parse the XML message and then update each row separately?
  
  I'm under 11.2.0.1.0.
  

  create table otn9test (
    id number not null primary key,
    data xmltype
  );
  
  insert into otn9test values (1, xmltype('<data>default for 1</data>'));
  insert into otn9test values (2, xmltype('<data>default for 2</data>'));
  insert into otn9test values (3, xmltype('<data>default for 3</data>'));
  
  create table otn9input (
    id number,
    data xmltype
  );
  
  column data format a30
  
  declare
    updata constant xmltype := xmltype('<root>
    <item>
      <id>1</id>
      <data>Id 1 updated.</data>
    </item>
    <item>
      <id>3</id>
      <data>Id 3 updated.</data>
    </item>
    <item>
      <id>4</id>
      <data>Id 4 updated.</data>
    </item>
  </root>');
  
  begin
    insert into otn9input
      select * from
      xmltable('/root/item' passing updata
            columns
            id number path 'id',
            data xmltype path 'data');
  
    update otn9test t set data = (
      select data from otn9input i
      where t.id = i.id
    ) where t.id in (select id from otn9input);
  
    commit;
  end;
  /
  
  select * from otn9input;
  
  /*
       ID DATA
  ---------- ------------------------------
        1 <data>Id 1 updated.</data>
        3 <data>Id 3 updated.</data>
        4 <data>Id 4 updated.</data>
  */
  
  select * from otn9test;
  
  /*
       ID DATA
  ---------- ------------------------------
        1 <data>Id 1 updated.</data>
        2 <data>default for 2</data>
        3 <data>Id 3 updated.</data>
  */
  
  drop table otn9input;
  drop table otn9test;

  The temporary table can be eliminated somehow?

  You can do it with the MERGER:

  merge into otn9test t
  using (
    select id, data
    from xmltable('/root/item' passing updata
          columns
            id   number  path 'id',
            data xmltype path 'data'
         )
  ) x
  on ( t.id = x.id )
  when matched then update
   set t.data = x.data
  ;
  

  However, if you are looking for performance on large data sets, I think that the best is to use an intermediate table of XMLType (binary storage) to maintain the XML instance.

  create table otn9input of xmltype
  xmltype store as securefile binary xml;
  
  insert into otn9input values(
  xmltype('
    
      1
      Id 1 updated.
    
    
      3
      Id 3 updated.
    
    
      4
      Id 4 updated.
    
  ')
  );
  
  merge into otn9test t
  using (
  select id, data
  from otn9input,
       xmltable('/root/item' passing object_value
            columns
              id number path 'id',
              data xmltype path 'data'
       )
  ) x
  on ( t.id = x.id )
  when matched then update
   set t.data = x.data
  ;
  

  A structured XMLIndex could also help.

• Store XML files in a table

  DB version: 11 GR 2
  
  If you were asked to store XML files in an oracle table, what kind of column would you use? BLOB or some other associated XML type?

  Balaji k wrote:
  You can use SQL * Loader to load large amounts of XML data in the Oracle database.

  Personally, (and), I would use the XML DB instead. Just copy/ftp the file XML in the XML DB and hey presto, the XML in the database as an XMLTYPE.
  And it can even load into patterns and shred the XML as well.

  SQL * Loader is today so clumsy, I think that was pretty well that day as other technologies have improved.

  XML DB FAQ Forum:

  DB XML FAQ

• Load xml data into the table

  Hi all
  
  I have an XML (emp.xml) with data below:
  
  -< root >
  -< row >
  < name > steve < / lastname >
  < 30 > < / Age >
  < / row >
  -< row >
  < name > Paul < / lastname >
  <>26 < / Age >
  < / row >
  < / root >
  
  I would like to create a stored procedure to store the xml data into the EMP table.
  
  EMP
  LastName age
  Steve 30
  Paul 26
  
  I tried to watch all threads related to this forum, but cannot find the right wire. Any help is greatly appreciated. Thank you

  With

  SQL>  select * from xmltable('root/row' passing xmltype('
  
  steve
  30
  
  
  Paul
  26
  
  ') columns lastname path 'lastname',
                     Age path 'Age')
  /
  LASTNAME   AGE
  ---------- ----------
  steve      30
  Paul       26   
  

  You can now just make a

  Insert into emp as select...

• Table design for the newspaper error due to a xml data type

  Hello

  I am trying to create a table of error log, but I get the below error

  ORA-20069: unsupported column or the types found:

  Table on which I am trying to create a column with the xml data type.

  Is there a way to create the error table for tables with the XML data type.

  Thank you

  PAL

  http://docs.Oracle.com/CD/E11882_01/server.112/e41084/statements_9014.htm#SQLRF55101

  Concerning

  Etbin

  http://docs.Oracle.com/CD/E11882_01/AppDev.112/e40758/d_errlog.htm#ARPLS680

  Look at the skip_unsupported setting

• including return transport with the XML data in the table

  I am inserting data using XML in a table in a context of InDesign.
  As part of the text, I would put a few carriage returns, so that the text has a line break where I like it rather than that InDesign can do its best estimate as to how to split the lines.

  I tried to put & #8629; and < br / > in the text, but has not been what I hoped, he might.

  Any suggestions?

  Thank you!

  Hello Urban, try this:

  Roland

• Update of a column of table from xml data

  Hello

  I have an obligation to update a particular table from xml data column. to do this, I wrote the code below but I am not able to insert. could you please a peek into that.

  create table emp3
  as
  select *From emp
  where 1=1;
  
  alter table emp3
  add (fax_response varchar2(50));
  
  /*create sequence EmailRecords_XMLFILE_SEQ
    minvalue 1
    maxvalue 999999999999999999999999999
    start with 1
    increment by 1
    nocache;*/
  
  /* create global temporary table EmailRecords_XMLFILE
    (
    ID NUMBER not null,
    xmlfile CLOB
    )
    on commit preserve rows;*/
  
  /* create global temporary table UPD_Email_Records_With_Xml
    (
    id NUMBER not null,
  
    response VARCHAR2(500)
  
    )
    on commit preserve rows; */
  
  
  

  the XML data is

  <FAX>
  <EMAILOG>
  <ID>7839</ID>
  <RESPONSE>FAX SENT</RESPONSE>
  </EMAILOG>
  <EMAILOG>
  <ID>7566</ID>
  <RESPONSE>FAX NOT SENT</RESPONSE>
  </EMAILOG>
  </FAX>
  
  
  

  CREATE OR REPLACE PROCEDURE proc_upd_email_records (
     loc_xml          IN       CLOB,
     p_err_code_out   OUT      NUMBER,
     p_err_mesg_out   OUT      VARCHAR2
  )
  IS
     loc_id   NUMBER;
  BEGIN
     loc_id := emailrecords_xmlfile_seq.NEXTVAL; --created sequence
  
  
  
     INSERT INTO emailrecords_xmlfile --created Global Temp table
                 (ID, xmlfile
                 )
          VALUES (loc_id, loc_xml
                 );
  
     COMMIT;
        insert into UPD_Email_Records_With_Xml --created Global Temp table
          (ID, RESPONSE)
          select x1.id,
  
                    x1.RESPONSE
            from EmailRecords_XMLFILE,
                 xmltable('/FAX/EMAILOGID' passing
                          xmltype.createxml(EmailRecords_XMLFILE.xmlfile)
                          columns header_no for ordinality,
                          id number path 'ID',
                          RESPONSE VARCHAR2(250) path 'RESPONSE'
  
                             ) x1
           where EmailRecords_XMLFILE.id = loc_id;
     COMMIT;
  
     UPDATE emp3 er
        SET er.fax_response = (SELECT response
                             FROM upd_email_records_with_xml pr
                            WHERE pr.ID = er.empno)
      WHERE er.empno IN (SELECT ID
                           FROM upd_email_records_with_xml);
  EXCEPTION
     WHEN NO_DATA_FOUND
     THEN
        raise_application_error
           (-20000,
            'Sorry ! The Xml File which is passed is empty. Please try with Valid Xml File. Thank you!!! '
           );
     WHEN OTHERS
     THEN
        p_err_code_out := 4;
        p_err_mesg_out := 'error in insertion=> ' || SQLERRM;
  END proc_upd_email_records;
  {code}{code}
  
  
  

  Someone suggest me a slightly easier way to insert data...

  Thank you...

  You're complicating things

  A simple MERGE statement will do.

  create or replace procedure (proc_upd_email_records)

  loc_xml in clob

  )

  is

  Start

  merge into e emp3

  a_l'_aide_de)

  Select id

  response

  from xmltable)

  "/ FAX/EMAILOG.

  by the way xmlparse (document loc_xml)

  the columns id number way "ID".

  , path of varchar2 (250) response 'RESPONSE '.

  )

  ) v

  on (e.empno = v.id)

  When matched then update

  Set e.fax_response = v.response

  ;

  end;

  /

  But there is no value added by using these temporary tables if you are not at least an intermediate XMLType column (storage preferably binary XML).

  -What is the input XML code?

  -What is the version of db?

• Select this OPTION to generate XML data from the table using XMLELEMENT, XMLAGG gives error ORA-19011 string buffer too small

  My select statement fails with the error:

  
  

  The ORA-19011 string buffer too small

  
  

  The select statement looks like:

  
  

  SELECT TO_CLOB)

  XMLELEMENT ("accounts",

  XMLELEMENT ("count",

  XMLATTRIBUTES)

  rownum AS "recordId."

  To_date('20130520','YYYYMMDD') AS "datestarted."

  123456 AS "previousBatchId."

  56789 AS 'previousRecordId '.

  ),

  ....

  .... .

  .....

  XMLFOREST)

  SIG_ROLE AS "SignatoryRole."

  To_char(TRANSFER_DATE,'YYYY-mm-DD') AS "TransferDate."

  NVL(Reason,0) AS 'reason '.

  ) AS the 'transfer '.

  )

  ()) AS CRDTRPT

  OF ANY_TABLE;

  • It looks like I can choose only 4000 characters using the SELECT statement (please, correct me if I'm wrong)

  I'd use the XMLGEN package. But the environment team says no mounted drives in the future with the arrival of the EXADATA.

  NO HARD DRIVE MOUNTED, NO ACCESS TO THE DATABASE DIRECTORIES

  No UTL_FILE

  I need to use the REEL spool the resulting XML data of the SELECT query.

  SQL is a standard in my org, but I can do with a PL/SQL solution also to load data into a table (cannot use a COIL with PL/SQL)

  What I do is:

  1. a column of type CLOB to a xml_report of the loading of the above SELECT query table
  2. Then using SELECT * FROM xml_report to SPOOL the data to a file report.xml

  No need of XMLTYPE data behind. Xml data stream is fine for me.

  In addition, I need to validate the XML file, also using XSD.

  Problem is that the resulting lines of the select query are supposed to be from 15000 to 20000 bytes long.

  Oracle database version: Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production

  A Suggestion or a solution to this problem would be appreciated.

  (Sorry for the use of "BOLD", just to make it more readable and highlight the imp points)

  Bravo!

  Rahul

  It looks like I can choose only 4000 characters using the SELECT statement (please, correct me if I'm wrong)

  You use the right method.

  There is an implicit conversion from XMLType to the data type VARCHAR2 as expected by the function TO_CLOB, where the limitation, and the error.

  To serialize XMLType to CLOB, use the XMLSerialize function:

  SELECT XMLSerialize (DOCUMENT

  XMLELEMENT ("accounts",

  ...

  )

  )

  OF ANY_TABLE;

  For the rest of the requirement, I wish you good luck trying to spool the XML correctly.

  You may need to play around with the SET LONG and SET LONGCHUNKSIZE commands to operate.

• Store XML in the schema issue generated tables and XML Validation against the schema.

  Hello friends,

  I am facing a problem where to store xml in a saved schema generated from tables.

  It's my diagram

  --

  <? XML version = "1.0" encoding = "UTF-8"? >

  " < xs: schema xmlns:ds = ' http://www.w3.org/2000/09/xmldsig# "" xmlns: XS = " " http://www.w3.org/2001/XMLSchema "xmlns =" " http://www.ABC.inf.in/test "targetNamespace =" " http://www.abc.inf.in/test" elementFormDefault = "qualified" attributeFormDefault = "unqualified" > "

  < xs: include schemaLocation = "abc.xsd" / >

  < xs: element name = "project" type = 'student' >

  < xs: annotation >

  < Intention > it is a Documentation < / intention >

  < / xs: annotation >

  < / xs: element >

  < / xs: Schema >

  -This is my xml document

  "< project versão ="2.00"xmlns ="http://www.abc.inf.in/test">."

  "< test xmlns ="http://www.abc.inf.in/test">."

  " < intest version ="2.00"Id ="testabc"xmlns: xsi =" http://www.w3.org/2001/XMLSchema-instance "  >

  < ide >

  < cUF > 35 < / cUF >

  < cNF > 59386422 < / cNF >

  < natOp > This is post < / natOp >

  < indPag > 1 < / indPag >

  < mod > 55 < / mod >

  < set > 1 < / series >

  < / ide >...

  .....................

  Giving not complete because it is too long.

  1. I registered successfully of the schemas in the database

  2. then I generate the saved schema table

  2. in my java code I have validated the document XML schema compared and it's valid successfully.

  3 but when I recorded this XML file in the generated table there me gives error

  As:

  INSERT INTO XMLTABLE

  VALUES

  (XMLTYPE (bfilename('MYDIR','testabc.xml'), NLS_CHARSET_ID ('AL32UTF8')))

  Error report:

  SQL error: ORA-31061: error XDB: XML error event

  ORA-19202: an error has occurred in the processing of XML

  LSX-00333: literal '94032000' is not valid with regard to the model

  And I have to store this xml in tables of this so what I have to do?

  Thanks for your reply odie_63.

  I got this my solution for the error. My XML document is not well structured based on my registered XML schema.

  Average in My XML Document is an invalid value and which do not match my schema model so it gives this error

  SQL error: ORA-31061: error XDB: XML error event

  ORA-19202: an error has occurred in the processing of XML

  LSX-00333: literal '94032000' is not valid with regard to the model

  For the Solution, we have two ways

  1. I changed this literal value "94032000" in my xml file, then save it.

  2.

  -To delete this schema can

  -We need to change the schema for the particular element model

  like: -.

  -then to store xml in the database, it works...

  Thank you.

• Way to know which table APEX stores the data of particular application?

  If, for example, I went to the shared-> components Templates-> change the Page template
  and I want to know what APEX table stores the data that is displayed on this page in the definition-> header section
  is it possible to do?
  
  In this particular case, I would like to ask all requests for one ' < link rel = "stylesheet" ' string
  
  Any guidance would be GREATLY appreciated

  You can find it in every application > utilities > APEX views > APEX_APPLICATION_TEMP_PAGE. You must connect this point of view the point of view of APEX_APPLICATION_PAGES in order to get this info.

  Denes Kubicek
  -------------------------------------------------------------------
  http://deneskubicek.blogspot.com/
  http://www.Apress.com/9781430235125
  http://Apex.Oracle.com/pls/Apex/f?p=31517:1
  http://www.Amazon.de/Oracle-Apex-XE-Praxis/DP/3826655494
  -------------------------------------------------------------------

• Insert XML data from the Table-&gt; back to null

  Dear Experts,
  
  -I have table xml as below:
  
  Example of CREATE TABLE (XML_spec XMLTYPE);
  
  Insert in the example
  Select ' < name of Message = "dataStaticInvestor" type = "IncomingMessage" >
  < name of field = "batchReference" > OPENINGBATCH000000 < / field > < List name = "data" >
  < = record name "data" >
  < name of field = "externalReference" > 01234567890aaaaaaa < / field >
  < name of field = "participantID" > OD001 < / field >
  < name of field = "participantName" > EQUITY SECURITIES INDONESIA, PT < / field >
  < / recording >
  < = record name "data" >
  < name of field = "externalReference" > 01234567890aaaaaaa < / field >
  < name of field = "participantID" > OD001 < / field >
  < name of field = "participantName" > EQUITY SECURITIES INDONESIA, PT < / field >
  < / recording >
  < = record name "data" >
  < name of field = "externalReference" > 01234567890aaaaaaa < / field >
  < name of field = "participantID" > OD001 < / field >
  < name of field = "participantName" > EQUITY SECURITIES INDONESIA, PT < / field >
  < / recording >
  < / list >
  < / message > ' double.
  
  Select * example;
  
  create table hasil1 (c1 varchar2 (500), c2 varchar2 (500), c3 varchar2 (500));
  
  -This step I create the procedure to insert xml data into the table as the batch.
  
  DECLARE
  x XmlType;
  BEGIN
  Select XML_SPEC in x for example;
  
  insert into hasil1
  SELECT
  p.Extract('/Record/Field/@externalReference').getstringval (C1),
  p.Extract('/Record/Field/@participantID').getstringval (C2),
  p.Extract('/Record/Field/@participantName').getstringval () as c3
  TABLE (XMLSequence (Extract(x,'Message/List/Record'))) p;
  commit;
  END;
  /
  
  -when the result of select hasil1, the output is back 3 rows and 3 columns, but all data is a null *.
  
  Best regards
  Sigcle

  You don't explain what output you need, but I guess something like this:

  SQL> insert into hasil1 (c1, c2, c3)
    2  select x.c1, x.c2, x.c3
    3  from example t
    4     , xmltable(
    5         'Message/List/Record'
    6         passing t.xml_spec
    7         columns c1 varchar2(500) path 'Field[@name="externalReference"]'
    8               , c2 varchar2(500) path 'Field[@name="participantID"]'
    9               , c3 varchar2(500) path 'Field[@name="participantName"]'
   10       ) x
   11  ;
  
  3 rows inserted
  
  SQL> select * from hasil1;
  
  C1                     C2        C3
  ---------------------- --------- --------------------------------
  01234567890aaaaaaa     OD001     EQUITY SECURITIES INDONESIA,PT
  01234567890aaaaaaa     OD001     EQUITY SECURITIES INDONESIA,PT
  01234567890aaaaaaa     OD001     EQUITY SECURITIES INDONESIA,PT
   
  

• Error when inserting XML Date in the Table

  Hi all
  
  I am working on Oracle 11 g and trying to insert a date XML in the table but get error - below
  
  Query - insert into TableName (ID, CREATION, CREATEDBY) VALUES (50, *'2010 - 12-15 T 12: 57:19'*, 'Name')
  
  Error - java.sql.SQLDataException: ORA-01861: literal does not match the format string
  
  CREATED column datatype is Date
  
  When I try to use sysdate instead of hard-coding XML date of obtaining inserted successfully into the table. Please let me know how to pass this XML format date.
  
  Thanks in advance.
  
  Concerning
  Nikhil

  I don't see any XML in what you posted. In any case:

  "2010 12-15 T 12: 57:19'.

  is a string, not a date. Use:

  to_date('2010-12-15T12:57:19','YYYY-mm-dd"T"HH24:mi:SS')

  For example:

  SQL> create table tbl(created date);
  
  Table created.
  
  SQL> insert into tbl values('2010-12-15T12:57:19');
  insert into tbl values('2010-12-15T12:57:19')
                         *
  ERROR at line 1:
  ORA-01861: literal does not match format string
  
  SQL> insert into tbl values(to_date('2010-12-15T12:57:19','YYYY-MM-DD"T"HH24:MI:SS'))
    2  /
  
  1 row created.
  
  SQL> 
  

  SY.

• Error occurred when the XML data is inserted in the table.

  Hello
  
  I'm trying to load the xml data into the table of following code.but get below error
  
  Error on line 1
  ORA-31011: XML parsing failed
  ORA-19202: an error has occurred in the processing of XML
  LPX-00222: error received from the SAX callback function
  ORA-06512: at "SYS." DBMS_XMLSTORE', line 78
  ORA-06512: at line 21
  
  

  DECLARE
   
    xmldoc   clob;
    insCtx   DBMS_XMLStore.ctxType;
    dname    varchar2(20) := 'MDIR';
    rows  number;
   
   BEGIN
   
      xmldoc := dbms_xslprocessor.read2clob(dname, 'try_xm3.xml');
      insCtx := DBMS_XMLStore.newContext('try1');
   dbms_output.put_line('1');
      DBMS_XMLStore.setRowTag(insCtx, 'cajas');
   rows := DBMS_XMLStore.insertXML(insCtx, xmlDoc);
   
   commit;
    dbms_output.put_line('INSERT DONE '||TO_CHAR(rows));
   
    DBMS_XMLStore.closeContext(insCtx);
   
   END;

  <?xml version="1.0" encoding="utf-8"?>
  <cajas xmlns="PBcion.Caja" fec="2011-03-02T14:20:14" codDeleg="093">
    <caj codPrev="80001223" fechaInicio="2011-03-02" fec="2011-09-02" couta="01" idPerio="1" caj="32"></caj>
   </cajas>

  can you please look at this?
  I m using oracle 10g

  insert
    into try1
    with t as (
               select xmltype('') x from dual
              )
    select  codPrev,
            fechaInicio,
            fec,
            couta,
            idPerio,
            caj
      from  t,
            xmltable(
                     '/'
                     passing x
                     columns
                       codPrev number path '@codPrev',
                       fechaInicio varchar2(25) path '@fechaInicio',
                       fec varchar2(25) path '@fec',
                       couta number path '@couta',
                       idPerio number path '@idPerio',
                       caj number path '@caj'
                    )
  /
  
  1 row created.
  
  SQL>  select  *
    2    from  try1
    3  /
  
     CODPREV FECHAINICIO               FEC                            COUTA    IDPERIO        CAJ
  ---------- ------------------------- ------------------------- ---------- ---------- ----------
    80001223 2011-03-02                2011-09-02                         1          1         32
  
  SQL> 
  

  SY.

• Update the XML data store

  Hello experts,
  
  I've created an interface when an xml file is reversed in the form of a source data store. Xml data are pumped into a target of oracle db. All this goes well.
  
  I'm creating a scenario where I get an xml file from a ftp server on a daily basis (with agent). This new xml file has the same structure as that already used in the interface. The question is: How can I update the data in the xml data store?
  
  I tried to replace the original xml file, but it does not work and cdc does not seem to apply here, I searched for quite a while now.
  
  Thank you very much!
  
  Yves

  Hello

  See if that helps
  XML for the interface Oracle even insert County regardless of input XML file

  Thank you
  Fati