strange symbol scaling, when the value of key in a Tween

Similar Questions

• Data affinity: Duplication of entities when the value of associatedKey?

  I'm trying to implement data affinity. I have a domain of the FootballClub and player model. A player is held by a FootballClub. Players and Clubs are cached in separate NamedCaches and I use serialization of java base.
  
  Affinity seems to work - I connect the partition using a BackingMapListener and you can see that a player is going to the same partition as the club owner. If I start a new data node, and the score moves to the new node, that the player and the Club move together.
  
  The problem I have is that if I change the owner of an existing player and put in my reader updated in the cache of the drive, I don't update the existing player entry in the cache - I get a brand new player. This is the expected behavior?
  
  If it is not planned, anyone have any suggestions as to where I could go wrong? I tried with a KeyAssociator and by setting up KeyAssociation on Player.Id.
  I also tried excluding the clubName (associatedKey), in the methods Player.Id.hashcode () and equals() and make the transitional clubName in this class.
  
  I connect MapEvents and you can see that the toString() of the binary version changes key player when the value of KeyAssociator.getAssociatedKey () changes slightly, but convert the key to original format using BackingMapManagerContext.getKeyFromInternalConverter () always returns the same value.
  
  I'm new on consistency so quite possible something basic wrong I.

  user6871200 wrote:
  I'm trying to implement data affinity. I have a domain of the FootballClub and player model. A player is held by a FootballClub. Players and Clubs are cached in separate NamedCaches and I use serialization of java base.

  Affinity seems to work - I connect the partition using a BackingMapListener and you can see that a player is going to the same partition as the club owner. If I start a new data node, and the score moves to the new node, that the player and the Club move together.

  The problem I have is that if I change the owner of an existing player and put in my reader updated in the cache of the drive, I don't update the existing player entry in the cache - I get a brand new player. This is the expected behavior?

  This is the expected behavior: If you have actually changed the key, it's a different key, and you put the same player with a different key in the cache. Why it would affect old Scripture?

  A key in the plan is considered as immutable and you violate this principle.

  The problem is that your modeling is defective: owner should not be part of the key, or must be immutable. In your case, it should not be part of the key (but then you can't affinity). Question is: why do you want to have an affinity between the owner and player, anyway?

  Best regards

  Robert

• replace some symbols and converts the value to a number

  Hi all. I've got bp_link table with 'avalue' column VARCHAR2 (200). If I can find a different version of p here:
  
  (a) 100%
  (b) 100
  (c) 100.00
  (d) 100.00
  (e) null
  (f) symbol of space
  (I hope that all versions are mentioned).
  
  So I try to replace some symbols and convert the value to a number using the following steps:
  
  NVL(Avalue,0) - removes the null value
  Replace (NVL(Avalue,0), '%', ")-removes the symbol '% '.
  Replace (Replace (NVL(Avalue,0), '%', "), ',','. ')-remove a symbol «,»
  Trim (Replace (Replace (NVL(Avalue,0),'%',''),',','.')) - removes the symbol space)))
  TO_CHAR (Trim (Replace (Replace (NVL(Avalue,0), '%', "), ', '.'")), "FM999999999999.90")-converts format "100.00".
  
  But it still does not, maybe I don't see anything else.
  
  When I just "select * from...". "it works:
  
  Select to_char (trim (replace (replace (nvl(avalue,0), '%', "), ', '.'")), "FM999999999999.90")
  as avalue of JJ bp_link where roletypeid = 9
  
  But when I try "order by avalue" ends with error - ORA-01722: invalid number
  
  Select to_char (trim (replace (replace (nvl(avalue,0), '%', "), ', '.'")), "FM999999999999.90")
  as avalue of JJ bp_link where roletypeid = 9
  order of dd.avalue
  
  What can I do else?

  Maybe this will help you
  http://nimishgarg.blogspot.com/2010/04/Oracle-SQL-extract-numbers-from-string.html

• How the LED lights up when a threshold is reached, then turns off only when the value does not reach the threshold for a while?

  Hi, I want to write a program that can turn on the LED when a range of value, this is the threshold and only when the value does not reach the threshold for a period of time, say 5 seconds, then the LED will turn off, otherwise it will remain. How can I achieve this in labview? Can someone help me? Really thanks!

  I assume that you use a while loop to keep the updated value.

  Add a record to offset to your looping it initialize with a U32 (time in ms)

  Add the registry to offset to your loop that keeps the previous value of your bool

  When your reaches the threshold value => the light and set the current time in your shift register.

  In the next iteration of the loop weather check value is still above threshold

  => Y-online previous set to true?

  => Y-online the next iteration

  -Online N => turn switch on and set the current time in your shift register.

  -Online N => subtract the time current less time shift record-online more then 5 seconds?

  => Is => keep turning on

  -Online N => turn given

• Is it possible a 0 is displayed after the decimal point when the value is rounded? (I get: 20-20, 1;) "I need 20, 0-20, 1).

  Using the effect of text "cursor", I am able to view replace "30 ° C" "35.5 ° C". My question is: is it possible a 0 is displayed after the decimal point when the value is rounded? (I get: 20-20, 1;) "I need 20, 0-20, 1). I use this code:

  Temp = effect ("Slider Control") ("Slider");

  sliderValue = Math.round(temp*10)/10;

  [sliderValue + ' ° C ' "']

  Here is the solution:

  numDecimals = 1;

  Temp = effect ("Slider Control") ("Slider");

  sliderValue = (Math.round(temp*10)/10).toFixed(numDecimals);

  sliderValue + "° C";

• How to disable Lov when the value of the attribute is NULL at the level line

  Hi all
  
  JDev 11.1.1.5.0
  
  I have a view as a table ADF jsff page object. Value of the attribute in a row may have null values.
  And I want that Lov must be disabled when the value of the attribute in the row is null or not.
  So please suggest me how can I implement this.
  
  Kind regards
  Marie-Claude

  Set to the disabled for LOV attribute property

  disabled="#{bindings.YourAttribute.inputValue eq null}
  {code}                                                                                                                                                                                                                                        
  

• Cell borders disappear when the value is null

  I'm now a PL/SQL report. When the value of a column is null, the cell borders disappear. I would have preferred that they do not disappear.
  
  Any suggestions?
  

• How to hide the div tags when the value inside is empty?

  I'm creating a tab bar using jQueryTabs.

  I want to hide a tab when the value inside is empty.

  It is perfectly feasible to hide the real on the ground when notting to show is, however, the tab is always in the tabs on top.

  Here is the code:

  as you can see in the tabs 4 and 5 I'm hidding values that are inside the field is it not there no. The tab is still there

   <script type="text/javascript">
  // BeginOAWidget_Instance_2140022: #jQueryTabs
  
  
  
  
            $(function() {
        $("#jQueryTabs").tabs({
                      event:"click",
                      collapsible: false,
                      selected:'0',
                      fx: { opacity: 'none', duration: 1 }
          }).tabs( "none" , 1 , false ); 
            });
  
  
  // EndOAWidget_Instance_2140022
         </script>
        <div id="jQueryTabs">
          <ul>
            <li><a href="#tabs-1">Description</a></li>
            <li><a href="#tabs-2">Specification</a></li>
            <li><a href="#tabs-3">Video</a></li>
            <li><a href="#tabs-4">Audio</a></li>
            <li><a href="#tabs-5">Downloads</a></li>
          </ul>
          <div id="tabs-1">
            <p><?php echo $row_Recordset1['Full_Description']; ?>
          </div>
          <div id="tabs-2">
            <p><?php echo $row_Recordset1['Specification']; ?></p>
          </div>
          <div id="tabs-3">
            <p><?php echo $row_Recordset1['Video']; ?></p>
          </div>
          <div id="tabs-4">
            <p><?php if (!is_null($row_Recordset1['Audio1'])) { ?><a href="<?php echo $file_wav.$row_Recordset1['Audio1']; ?>"><img src="files/Images/audio_image1.jpg" width="50" height="50" ></a><?php } ?></p>
          </div>
          <div id="tabs-5">
            <p><?php if (!is_null($row_Recordset1['Brochure'])) { ?>
            <a href="<?php echo $file_pdf.$row_Recordset1['Brochure']; ?>"><img src="files/Images/pdf_image1.jpg"></a>Brochure<?php } ?></p>
            <p><?php if (!is_null($row_Recordset1['User_Guide'])) { ?><a href="<?php echo $file_pdf.$row_Recordset1['User_Guide']; ?>"><img src="files/Images/pdf_image1.jpg"></a>User Guide<?php } ?></p>
          </div>
  
  

  RiaandSteve1 wrote:

  Thanks for your quick response,

  I tried this,

   
  
            
  ">
          
  
  
  
  

  I'm not able to click on the tab now, but he is always visible (in this case telling audio). I must be something to do with this code

  Audio
  

  above the actual div for the tab.  Do not know how to remove the tab

  Well Yes if you want to hide the tab too then you must surround the

tag in a similar way:
• Audio

• In the column of table when the values are grater that maximum linear axis it does not show the bar

  Hi guys,.

  In the column of table when the values are grater than there maximum linear axis it does not show the Bar.But I want to display the bar up to the maximum limit of the axis is linear without changing the limit max.

  Consider following the example:

  The values are 80 90 200 300

  and here is the result:

  Left: when I don't put maximum property of linear axis.

  Right: when I put in maximum property of linear axis to 200.

  

  Law 4th bar is not visible because the value of this bar is 300 which is excedding maxium. But I want the 4th bar to appear identical to 3 bar.

  How can I do this?

  Thanks in advance.

  Then you should change the value of Y to the maximum value.

  Another option, you should consider is changing the Render item column to reflect that the value is greater than the specified maximum value.

• Object that can be bound but not updated when the value changes

  I have an object that is declared as [Bindable], which is updated in a component that is also declared as [Bindable] However, when the value is changed the user interface shows the change but the linked object never gets updated.
  
  Are there cases where related objects do not updated?

  Yes, as I said, pass the name of the property and the value in the change manager.

  Support rating allows you to set the value, not a switch statement. Some examples of code.

  Tracy

• Language office (and all menus) are all in strange symbols, even if the language selected is English

  I have a Vista Home Premium computer laptop (Toshiba Satellite) which shows strange lines and brands for all of the words on the desktop and menus. I guess it could be a different language, although it looks more like mutilated. I managed to check the regional/language settings (was not easy) and English is selected. Anyone know what is happening and how to fix this without reloading the operating system?

  Hello toryander,.

  Thanks for posting on the Microsoft answers Community Forum.

  When the problem started happening with the display of strange symbols and marks in your Vista Home Premium?
  What has changed in your environment? Did you install a new program or install an update from Windows?

  Have you tried running Safe Mode to see if it'll happen here?

  If you know when the problem started, you can check and see if you have the system restore back to an earlier point in time. Note: System Restore does not save or delete your personal documents. This means that a document created and saved today is not deleted if you use the system restore. Only some system files and settings are changed when you perform a system restore.

  Click the URL below to review the steps on the system restore.
  936212 KB - how to repair the operating system and how to restore the configuration of the operating system to an earlier point in time in Windows Vista
  http://support.Microsoft.com/kb/936212 use system restore to undo changes
  To be sure, save the files before you restore to an earlier point. To restore your system to a previous restore point:

  1. Click Start
  2. Point to all programs
  3. Point to Accessories
  4. Point to System Tools
  5. Click on the system restore and click on the Next button
  6. Select "choose a different restore point" and click the Next button
  7. Select the time of the desired date and restore point description.
  8. Click the Next button.
  9. Click Next to start the restore process.
  10. Click Yes in the confirmation message box that appears.

  The computer shut down and on again automatically once the recovery is complete.

  Please try the suggestions and reply back with the results and let us know if you need help or if this solves your problem.

  Sincerely,

  Marilyn
  Microsoft Answers Support Engineer
  Visit our Microsoft answers feedback Forum and let us know what you think.

• Change the value of key Flexfield - job title Segment

  I understand that when a key flexfield structure is put in place, it is not advisable to change it and I don't mean to.

  What I want to do, however, is to change the columns value and reflected in the values of the segment. When I try to do, I get a message that field 40200 is protected against editing. It seems that I can do this with the other fields in flex, but not the title of the post. I know there are a number key behind it for relational purposes, so I don't know why it is locked from editing.

  Essentially, I need to change the verbiage associated with the value of the value and translated. I can't use the description column as it will be used for something else.

  "Do I need to create of new job titles whenever I needed to change 'Responsible' Executive, account", or when there is a spelling error? Is there an API that allows me to make these changes?

  Any thoughts are appreciated.

  Thank you!

  Wayne

  Sorry I couldn't give you the answer you wanted

  1. I expect that you would be able to change an existing job definition to use a new segment value - however, I have no access to a system to be able to prove or to disprove the statement, the only thing I can suggest you do is try on a job. It would be relatively good news if you could because your referential integrity would not be affected since the internal job_id argument would be unchanged.

  2. to load a large number of sets of value, I believe that there is an internal package, even if it is not a public API in the truest sense - package FND_FLEX_VALUES_PKG. A better way, perhaps, if you can, to use the charger in a development instance data, then do a DOWNLOAD of FNDLOAD to extract a file TDL for later download to other forums. Or, if the power to lend themselves, simply use data loader in each time only. Data on a simple screen like this loader is certainly likely to cause problems.

  Good luck with it!

  See you soon,.

  Clive

• Trigger to run the query when the value of LOV is selected

  HI guys,.
  
  I have a form in which I have 2 fields in Master and 4 fields in detail, showing all on the same canvas.
  I put a "execute_query" in when_new_form_instance trigger so that when I open the form it is pre - filled.
  The fields get the values LOVs. I want to run the master block query when the user selects a value in LOV, then in what trigger should I put it.
  I tried in 'when_validate_item' and 'when_list_changed' triggers, but it showed an error.
  So, what should I do?
  
  Concerning
  
  Ranjan

  user8664136 wrote:
  I want to run the master block query when the user selects a value of LOV

  If master block (header) is based on the table, using LOV without pressing enter_query firstly, update existing record.
  Here's my version (Andreas, sorry, I used your code :))

  TO KEY-LISTVAL:

  DECLARE
       tm TIMER:=FIND_TIMER('TM_QUERY');
  BEGIN
    IF ID_NULL(tm) THEN
      tm:=CREATE_TIMER('TM_QUERY', 1, NO_REPEAT);
    END IF;
    ENTER_QUERY;
  END;
  

  In WHEN-TIMER-EXPIRED:

  IF SHOW_LOV('LOV') THEN
   EXECUTE_QUERY;
  END IF;
  

• relaxation led when the value is greater than

  Hey everybody! I have to do a project and im stuck because I'm a noobler with regard to labview. I'm using labview 6 and got to watch the pressure and temperature of a reactor in time. I need to create a system in which if a value is greater than it triggers an alarm (perhaps led can show it) or is less than a certain limit. I mean it should trigger an alarm when the temperature or pressure is beyond 100 and less than 10. And after that to generate a text document in which it is specified the time and date at which these values were exceeded. I also use randomly generated values. Can I get help please? I'm not manage it by myself)

  Line and force. as Norbert said.

  You won't get much sympathy on overloaded around here.  Three things occurred to me that I read your messages:

  1. You will be in trouble when you get a job if you think that you will be not always charged.
  2. If I help you, you'll probably end up working for me and I still have to do your homework.
  3. You'll be fine.  Engineers outsource their work all the time.

  

• How to set the limit function, means I want defined logic that when the value is between 0 to 0.3 loop and then stops.

  Hello

  I'm looking for the logic as the way to define the logic of upper limit and lower limit.

  Means that there is only one indicator of entry in which a user can enter any value, I want that when the user gives value between 0 and 0.3 for example while then loop will stop other wise, it will work on an ongoing basis.

  Please guide me.

  Thank you very much.

  Please consider the VI below.