Strings and replacing their value

Similar Questions

• How can I change the registry values with a common search for the string and replace the function where I don't do all manually?

  Due to problems of space with my installation of XP Pro, (operating system has been installed on a 4 GB partition and I did have a copy of the OS to do a new installation) I am trying to move a number of files on a mounted drive.

  It is a way to search an entire record of [SPECIFY FOLDER] "C:\Program Files\" instances and replace each with "C:\Program Files\Overflow\ [SPECIFY FOLDER]" as a common discovery replace function?

  Also, I'll have to move several "Common Files" files in the mounted folder 'Overflow '. The method to make learning one should help me to do both. Manually, it will take most of thousand years that all the files in HKLM\SOFTWARE\Microsoft\Windows\CurrentVersion\Installer\UserData\S-1-5-18\Components
  the files seem to have a key value have changed.

  I have already uninstalled and reinstalled some programs at the desired location, but many still use the "Common files" folder despite my having already changed the default installation directory path in the registry. Any help would be appreciated.

  Thank you

  NORTH CAROLINA

  One way:

  1. Start Regedit (start-> Run-> 'Regedit')
  2. Select the branch of the registry, or you are interested in changing.
  3. The export of this branch of the registry (file-> export) in a ".reg" file
  4. Use a programming editor (for example, the freeware Notepad ++) and use the "Find and replace" function to make the changes you want.  Save the modified file.
  5. After making the changes, double-click the .reg file to fold changes in your registry.

  As always, keep a backup of your original registry in case things get really bad and know how to do to restore this backup your machine should not be able to start.

  Notepad ++: <> http://notepad-plus-plus.org/ >

  HTH,
  JW

• divide the string and replace the token

  Hi all
  
  I have a field called "FreeText" that contains data that is more or less according to the following format.
  
  "1 NEWTON/ISAACSIR WITHOUT DAIRY AND PEANUT PREFER ONE REGIME FRUITS"
  
  It contains the name of a text followed by someone. I want to this tokenized by using space as the delimiter and the first token can separate from the rest of it. The expected output would be two columns containing.
  
  "1 NEWTON/ISAACSIR" and the second column
  "NO DAIRY AND NO PEANUT PREFER ONE REGIME FRUITS."
  
  Thanks and greetings
  
  Crusoe

  Replace with your channel:
  It splits the string for 2 values separated by the character of the first found SPACE.

  WITH abc AS
    (SELECT '1NEWTON/ISAACSIR NO DAIRY PRODUCTS AND NO PEANUTS PREFERS A FRUIT ONLY DIET' A
     FROM dual)
  SELECT SUBSTR(A,1,INSTR(a,' ',1)-1) , SUBSTR(A,INSTR(a,' ',1)+1 , LENGTH(a))
  FROM abc
  

  Published by: AJ99 on July 1, 2009 11:09

• compare and replace the value

  Hello

  Just need a quick help. I have 3 tables. I have some data in Array1 table which has 10 columns.

  I take the value in the first column of the array Array1 and compare with the values in table 2. For example, in table 1, is it 133.38 between 30,00 and 230.00 (of arry, 2) then put 50.0 (from table 3) in the last column of the table Array1.

  It simply means, take each value of Column1 of array1, control the scope of this value, then exit in the last column of table 3 of the value of the index in table 3 corresponding to the lower bound index in table 2.

  Example 2. given 400.00 in array1 table Column1, compare its range with the value of array2. We can see that 400 is between 230 and 1000.00 (of array2), so you have to 70.0 in the last culomn of the array Array1.

  Thanks for this help.

  Use the threshold D 1 table to get the index where your first value will be compared to table 2, rounded down (towards - Infinity) and index in table 3.  Relplace the corresponding cell in the table 1.

  

• The extract number and String and replace with space

  Hello
  
  I need to extract number and string of a data table. I use Oracle 8i
  
  For example: 001FI025A, 001PDIT002, 001UXSV029AA
  I want to separate as follows
  001 025 A FI
  
  001 002 RESULTED
  
  USXV 029 A 001
  
  
  How can I achieve this? Any help is very useful.
  
  Thank you

  Hello

  Welcome to the forum!

  You must change "001FI025A" to the name of the column. Example:

  SELECT '001FI025A',
         SUBSTR(TRANSLATE('001FI025A',
                          '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ',
                          '0123456789                          '),
                1,
                INSTR(TRANSLATE('001FI025A',
                                '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ',
                                '0123456789                          '),
                      ' ')) AS ELEMENT_1,
         SUBSTR(LTRIM(TRANSLATE('001FI025A',
                                '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ',
                                '          ABCDEFGHIJKLMNOPQRSTUVWXYZ')),
                1,
                INSTR(LTRIM(TRANSLATE('001FI025A',
                                      '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ',
                                      '          ABCDEFGHIJKLMNOPQRSTUVWXYZ')),
                      ' ')) AS ELEMENT_2,
         LTRIM(SUBSTR(TRANSLATE('001FI025A',
                                '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ',
                                '0123456789                          '),
                      INSTR(TRANSLATE('001FI025A',
                                      '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ',
                                      '0123456789                          '),
                            ' '))) AS ELEMENT_3,
         LTRIM(SUBSTR(LTRIM(TRANSLATE('001FI025A',
                                '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ',
                                '          ABCDEFGHIJKLMNOPQRSTUVWXYZ')),
                INSTR(LTRIM(TRANSLATE('001FI025A',
                                      '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ',
                                      '          ABCDEFGHIJKLMNOPQRSTUVWXYZ')),
                      ' '))) AS ELEMENT_4
    FROM DUAL;
  

  Kind regards

• Replace negative values in multiple channels with "0'.

  Hello

  I'm calculating and then by creating a cumulative channel, multiple channels. Negative values in these channels aren't necessary, and I need a nice way to replace each negative value in these channels with a value of '0'.

  My current code is:

  Do
  Do
  If Data.Root.ChannelGroups (2). Channels (i). Values (II)< 0="" then="" data.root.channelgroups(2).channels(i).values(ii)="0    ">
  II = ii + 1
  Loop until the second > Data.Root.ChannelGroups (2). Channels (i). Properties ("length"). Value
  II = 1
  i = i + 1
  Loop until I > Data.Root.ChannelGroups (2). Channels.Count

  It works, but I don't like. He adds a few seconds when running my script, which was almost instantly. Is there a better way to do it?

  Thank you.

  Hello Kevin,

  The fastest way to go through a channel and check the values less than or equal to 0 is through the canal's calculator. The code below takes all the channel first channel group (with the exception of the first string that is be the weather channel in my example data set) and replaces the values<0 with="" 0="" through="" the="" iif="">

  Set Group = Data.Root.ChannelGroups (1)
  
  iMax = Group.Channels.Count
  
  FOR i = 2 to iMax
  
    Adjust the strings = Group.Channels (i)
  
    Formula = "= IIF (y '.<0, 0,="">
  
    Call to calculate (formula, Array("y"), Array (Channel))
  
  NEXT ' I

  In this example we overwrite the existing values of data channel with 0, but you can also copy the channels to make sure that your raw data is available.

  The calculator of channel is extremely fast for this type of operation because it does not create a loop to go if each line separately and check the values he...

  I hope this is useful,

  Otmar

• Case-sensitive option in find and replace the chain

  Hello!

  Attached is my problem.

  I'm looking 'toto' in the 'toto + tototi' input string and replace 'toto' by 'A0 '.

  I want to "respect" the input search in order to get a string result: A0 + tototi

  Are there options allowing for case-sensitive option?

  BR,
  Vincent

  You use search and replace with Regular Expressions selected (the little asterisk icon).  \b represents a word boundary, basically the imaginary space between the character is a letter, number or underscore, and the other is not.  In other words, it is an assertion of width zero, which means that \b does not capture anything.

  For example: toto is toto, toto1, toto_1 etc.  toto\b matches the string 'toto' when it is followed by something that is not alphanumeric or underline, is why it will not match toto1 but will match toto + or 'toto '.

  Go to pcre.org for more information or follow the assistance detailed in LV I assumed you knew because you need to turn on Regular Expressions in S & are so I assumed that you had done.  You've probably done without being aware of what you were doing.

• Find and replace the delimited string value by the

  Hi all

  I have a requirement where I need to find and replace the delimited string values.

  For example, the string is "GL ~ 1001 ~ 157747 ~FEB-13~ CREDIT ~ A ~ N ~ US ~ NULL ~". The 4th column gives the month and year. I need to replace it with the name of the previous month. For example: "GL ~ 1001 ~ 157747 ~JAN-13~ CREDIT ~ A ~ N ~ US ~ NULL ~". I need to do the same thing for the past 12 months.

  I thought initially divide the values and store it in a variable and then after him substituting the value required, join the return.

  I just wanted to know if there is a better way to do it?

  Like this:

  with a model like

  (select "GL ~ 1001 ~ 157747 ~ FEB-13 ~ CREDIT ~ A ~ N ~ $ ~ NULL ~' double UNION ALL data")

  Select ' GL ~ 1001 ~ 157747 ~ JAN-13 ~ CREDIT ~ A ~ N ~ US ~ NULL ~' double data)

  Select

  REPLACE (DATA, TO_CHAR (to_date (substr (data, 16.6), "MON-RRRR"), 'MON - RR'), TO_CHAR (to_date (substr (data, 16.6), "MON-RRRR")-1, 'MON - RR'))

  modeling;

  GL ~ 1001 ~ 157747 ~ JAN-13 ~ CREDITS ~ HAS ~ N ~ US ~ NOTHING ~

  GL ~ 1001 ~ 157747 ~ DEC-12 ~ CREDITS ~ HAS ~ N ~ US ~ NOTHING ~

  Ishan

• How to search and replace only tag values XML and tag not the columns?

  Hello
  
  I'm new to xml db, and I have a scenario where I need to find and replace the xml content. The search is based on a clear text and not on any column.
  
  I have a table as follows:
  
  ID VARCHAR2 (32 BYTE),
  MESSAGE_TYPE, VARCHAR2 (64 BYTE),
  XMLTYPE OF the MESSAGE_CONTENT,
  REJECTED_REASON VARCHAR2 (256 BYTE)
  
  And XML in the form of the sample:
  
  <? XML version = "1.0" encoding = "US-ASCII"? >
  < MessageEnvelope >
  < header >
  Renault < partner > < / partners >
  < MessageType > release < / MessageType >
  S74 < PartnerMessageType > < / PartnerMessageType >
  < MessageTime > 2001-12-17T 09: 30:47.0Z < / MessageTime >
  String of < LinkToRawMessage > < / LinkToRawMessage >
  < / header >
  < body >
  < version >
  < address >
  < DealerDestAddr > ABCD < / DealerDestAddr >
  < DestAddr > ABCD < / DestAddr >
  < NextDestAddr / >
  < StartAddr / >
  < / book >
  < assignment / >
  < ClientStatus / >
  < dates / >
  < HoldInfo >
  < HoldCode > HoldTest < / HoldCode >
  < / HoldInfo >
  < message / >
  < partner >
  < OrderGiverCode > CMR00BCV < / OrderGiverCode >
  < / partners >
  < ToDo / >
  < transport / >
  < vehicle >
  W0LGDM9A_Ran11115 < WINE > < / WINE >
  < / vehicle >
  < / Statement >
  < / body >
  < / MessageEnvelope >
  
  
  I'm running the query of foll:
  
  UPDATE t_xml D SET D.MESSAGE_CONTENT = replace (D.MESSAGE_CONTENT, "ABCD", "Chennai")
  (WHERE d.MESSAGE_CONTENT.existsNode('//*[*="ABCD"]') = 1;
  
  This works very well and replaces the two ABCD < DealerDestAddr > < / DealerDestAddr > and < DestAddr > ABCD < / DestAddr > tag values in Chennai. But the problem I encounter is if there is that a node with the name of the < ABCD > tag is also changed to < Chennai >. Please help me to fix this problem.
  
  Kind regards
  Sprightee

  What happens if I need to select and update a node that has the value null. Who doesn't have any value to it.

  You can test if the partner has a child text() node:

  existsNode(
    d.message_content
  , '/MessageEnvelope/Header[not(Partner/text())]'
  , 'xmlns="http://www.groupecat.com/CLV2/MessageEnvelope/20120501"'
  ) = 1
  

• replace some symbols and converts the value to a number

  Hi all. I've got bp_link table with 'avalue' column VARCHAR2 (200). If I can find a different version of p here:
  
  (a) 100%
  (b) 100
  (c) 100.00
  (d) 100.00
  (e) null
  (f) symbol of space
  (I hope that all versions are mentioned).
  
  So I try to replace some symbols and convert the value to a number using the following steps:
  
  NVL(Avalue,0) - removes the null value
  Replace (NVL(Avalue,0), '%', ")-removes the symbol '% '.
  Replace (Replace (NVL(Avalue,0), '%', "), ',','. ')-remove a symbol «,»
  Trim (Replace (Replace (NVL(Avalue,0),'%',''),',','.')) - removes the symbol space)))
  TO_CHAR (Trim (Replace (Replace (NVL(Avalue,0), '%', "), ', '.'")), "FM999999999999.90")-converts format "100.00".
  
  But it still does not, maybe I don't see anything else.
  
  When I just "select * from...". "it works:
  
  Select to_char (trim (replace (replace (nvl(avalue,0), '%', "), ', '.'")), "FM999999999999.90")
  as avalue of JJ bp_link where roletypeid = 9
  
  But when I try "order by avalue" ends with error - ORA-01722: invalid number
  
  Select to_char (trim (replace (replace (nvl(avalue,0), '%', "), ', '.'")), "FM999999999999.90")
  as avalue of JJ bp_link where roletypeid = 9
  order of dd.avalue
  
  What can I do else?

  Maybe this will help you
  http://nimishgarg.blogspot.com/2010/04/Oracle-SQL-extract-numbers-from-string.html

• I have different bookmarks I want to keep on each computer, synchronization will delete the bookmarks on a single computer and replace the bookmarks from another computer in their place

  I have not yet used sync, but I sense it's going to be a problem if I do. I have different bookmarks I want to keep it on each computer. Sync will delete the bookmarks on a single computer and replace the bookmarks from another computer in their place? So I think that will erase the bookmarks on the second computer you configured to synchronize. Is there a way to merge bookmarks on every computer in the library of a bookmark that contains all bookmarks on both computers, so I'm not all bookmarks in sync?

  Just to be clear, this is something that we have commented several times in the forum, Firefox Sync adds everything that is already in the device for the account and pushes this info for the rest of the devices.

  So if you have 2 computers with data X and the other with the data from there, once you set up synchronization in both computers you will have X + Y at the same time.

  I hope that clarifies the doubts...

• The filter string and value some strin

  Hello!!! Alls

  I have a string code and I have messages and numbers, I want to filter in the chain, because I need graphic values

  Please help me!

  Thank you

  Hello

  If you have a string which you want digital data, you can use certain features of the range of the chain. For example, if you know the exact location of the numerica data in the string, you can use the String subset function (just specify the character in which we will start the research and the amount of characters to be read). Once you have the string, you can use the analysis of string function, which allows you to format the string to a numeric value that you can graph. I have attached the image of functions.

  

  You can find them in the channel Palette in the block diagram. If you want to know how they work, you can use help, by pressing Ctrl + H and by moving the mouse on the functions.

  I hope this is useful,

  Kind regards

• I can't seem to make the "search and replace string" works as expected.

  I tried to replace "^ []] +---+ ([^] +).» "$*" with $1 in "create table leq_octave_5min (recorded_time DATETIME CONSTRAINT pk1 PRIMARY KEY, leq5m leq5m of FLOAT CONSTRAINT NOT NULL, min min FLOAT CONSTRAINT NOT NULL, max max FLOAT CONSTRAINT NOT NULL, CONSTRAINT of FLOAT L05 05 NOT NULL, CONSTRAINT of FLOAT L10 10 NOT NULL, L50 FLOAT CONSTRAINT 50 NOT NULL, L90 FLOAT 90 CONSTRAINT NOT NULL. L95 FLOTTER CONSTRAINT 95 NON NULL, us01 us01 FLOAT CONSTRAINT NOT NULL, EN02 EN02 FLOTTER CONSTRAINT NOT NULL, fr03 FR03 FLOTTER CONSTRAINT NOT NULL, fr04 FR04 FLOTTER CONSTRAINT NOT NULL, fr05 FR05 FLOTTER CONSTRAINT NOT NULL, fr06 FR06 FLOTTER CONSTRAINT NOT NULL, fr07 FR07 FLOTTER CONSTRAINT NOT NULL, fr08 FR08 FLOTTER CONSTRAINT NOT NULL, fr09 FR09 FLOTTER CONSTRAINT NOT NULL, fr10 FR10 FLOTTER CONSTRAINT NOT NULL Fr11 FR11 FLOTTER CONSTRAINT NOT NULL, FR12 FLOTTER CONSTRAINT NOT NULL fr12, fr13 FR13 FLOTTER CONSTRAINT NOT NULL, fr14 FR14 FLOTTER CONSTRAINT NOT NULL, fr15 FR15 FLOTTER CONSTRAINT NOT NULL, fr16 FR16 FLOTTER CONSTRAINT NOT NULL, fr17 FR17 FLOTTER CONSTRAINT NOT NULL, fr18 FR18 FLOTTER CONSTRAINT NOT NULL, fr19 FR19 FLOTTER CONSTRAINT NOT NULL, fr20 FR20 FLOTTER CONSTRAINT NOT NULL, fr21 FR21 FLOTTER CONSTRAINT NOT NULL Fr22 FR22 FLOTTER CONSTRAINT NOT NULL "(, e23, e23 FLOTTER CONSTRAINT NOT NULL, fr24 FR24 FLOAT CONSTRAINT NOT NULL, fr25 FR25 FLOTTER CONSTRAINT NOT NULL, fr26 FR26 FLOTTENT CONSTRAINT NOT NULL, fr27 FR27 FLOTTER CONSTRAINT NOT NULL, fr28 FR28 FLOTTER CONSTRAINT NOT NULL, fr29 FR29 FLOTTER CONSTRAINT NOT NULL, fr30 FR30 FLOTTER CONSTRAINT NOT NULL, status TEXT (2) st NOT NULL CONSTRAINT).

  The goal was to get the third token, 'leq_octave_5min '.

  The result string is "leq_octave_5min", but the real result string is the input string itself.

  What is the problem with my method?

  I'm sorry.

  I forgot to turn on 'regular expressions' in "Search and replace the String" VI.

  After having turned it on, it works as expected.

• Search and replace the string formatting

  Hello

  I try to do a search and replace the formatting of a string.

  In the example, I'm looking for the string 'SUCCESSFUL', but it must also begin by usbflash and some number + PASSED.

  I can't get the format to have a number between 1 and 99. The number of replacements should add up to 6 in this case. I tried with \d for any number, and I also tried [1-99].

  Make a right-click on the function search and replace the string.  There is an option to use regular Expressions.  Then give it a try.

  

  EDIT: You need to set the entry replace all to TRUE.

• Find and replace the string function replaces line breaks when I only replaced spaces?

  I need to replace all instances of a space or a series of spaces to a line with commas (or tabs) multi string so I can throw in a worksheet.

  I use the regular expression [\s]+ and it works, but it is also to replace the end of lines (\r\n) too.

  How can I replace the spaces but leave the end of the lines intact?

  Right-click on the search string and to take '-' code display. Enter the space character (\s) correctly - you \\s right now.