SUM IS INCORRECT
I have a worksheet and the SUM function gives the wrong number. It's really dangerous because I need precision.
I deduced that there is a single cell, that it fails to include in the sum, even if the cell is selected.
I click on the cell, I want to add to the column, then press = and then select the column. The sum is incorrect and fails to add one of the cells
Why?
It is so irritating and so dangerous that I need clarification on this sheet of numbers. Never had this with excel.
Help, please!
Thank you
without details, it is difficult to guess.
Often, the cell is not the same as the other somehow. Maybe it's in text format, or there's a funny character in the cell. Try to copy the data to a new table in a new document to check the results.
If you can validate the data, then we can try too.
Tags: iWork
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Hi guys,.
I do the query like this:
Select
SPH. PERIOD,
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Best regards
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Hi Linda
You made the UNION between a statement select 9 columns to return with a second return 12 columns. Please unify the number of columns selected at a time.
I hope that solves your problem
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using two sum() in multiple join query
Hello
I'm stuck with the help of two sum() functions in a single query. Are columns of different tables that are joined.
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chris227 wrote:
I seem to be a bug to me.
The result is 11.2.0.3
SUM(PAY_AMT) SUM(USG_AMT) 700 200 What is your version?
What looks like the plan to explain it with predicates?
BTW, why do you think that both are incorrect, for me, only the second is incorrect, should be 200 instead of 100.
Post edited by: chris227 Question added
No Chris, the po said they want the o/p 100, and they were getting an invalid value (for example, the 200 is incorrect).
It's because of the joining of the usg_amt of duplication:
SQL > ed
A written file afiedt.buf1 refill as (select date "'2013-07-01 as dt, 500 as pay_amt, 1 as cust_id of union double all the")
2 select dates "2013-07-01', 200, 1 double)
3, use as (select date "'2013-07-01 as dt, 100 in usg_amt, 1 as cust_id of union double all the")
4 Select the dates "2013-07-02', 300, 2 double)
5 --
6 select DT, pay_amt, usg_amt - sum (pay_amt), r.id_client, sum (usg_amt)
7 recharge r
8 join use u on u.cust_id = r.ID_client
9 and you.dt = DT
10 where u.cust_id = 1
11 * and u.dt = date ' 01-07-2013'
SQL > /.CUST_ID DT PAY_AMT USG_AMT
---------- -------------------- ---------- ----------
1 1 JULY 2013 00:00:00 200 100
1 1 JULY 2013 00:00:00 500 100If the sum is of course to sum up 100 twice because of two lines to pay.
So why I have indicated that the aggregation (sum) should usually before the join is made, so it is only made the cust_id amount and date for each table and then joined the results.
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Hi all
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giveswith t as (select org_id, lv, parent_org_id, 'ORG' who_type, 0 timee from thierarch connect by parent_org_id = prior org_id start with parent_org_id = 0 -- union all -- select p.person_id, 0, o.org_id, 'PER', p.TIMEE from (select * from thierarch where lv = 1 connect by parent_org_id = prior org_id start with parent_org_id = 0) o, (select * from tdata) p where o.org_id = p.org_id) -- select rownum, org_id, who_type, parent_org_id, t.lv, TIMEE, (select sum(tt.TIMEE) from t tt start with tt.org_id = t.org_id connect by prior tt.org_id = tt.parent_org_id) as TIMEE from t connect by parent_org_id = prior org_id start with parent_org_id = 0;
but I want toROWNUM ORG_ID WHO_TYPE PARENT_ORG_ID LV TIMEE TIMEE ---------- ---------- -------- ------------- ---------- ---------- ---------- 1 167 ORG 0 3 0 40 2 1489 ORG 167 2 0 40 3 905 ORG 1489 1 0 40 4 4730 PER 905 0 20 20 5 597 PER 905 0 20 40 6 168 ORG 167 2 0 0 7 1892 ORG 168 1 0 0 8 363 PER 1892 0 0 0 9 1529 ORG 168 1 0 0 10 363 PER 1529 0 0 0 11 172 ORG 0 3 0 20 12 176 ORG 172 2 0 20 13 309 ORG 176 1 0 20 14 597 PER 309 0 20 40 14 rows selected SQL>
so for anyone 597 must be 20 because salvation works in two different orgROWNUM ORG_ID WHO_TYPE PARENT_ORG_ID LV TIMEE TIMEE ---------- ---------- -------- ------------- ---------- ---------- ---------- 1 167 ORG 0 3 0 40 2 1489 ORG 167 2 0 40 3 905 ORG 1489 1 0 40 4 4730 PER 905 0 20 20 5 597 PER 905 0 20 20 6 168 ORG 167 2 0 0 7 1892 ORG 168 1 0 0 8 363 PER 1892 0 0 0 9 1529 ORG 168 1 0 0 10 363 PER 1529 0 0 0 11 172 ORG 0 3 0 20 12 176 ORG 172 2 0 20 13 309 ORG 176 1 0 20 14 597 PER 309 0 20 20 14 rows selected SQL>
What did I miss?Hello
The scalar subquery that calculates an incorrect value is looking for a specific org_id in result set t, but org_id is not unique. It looks like the combination of org_id and parent_org_id is unique, so if you want to identify the lines, you must compare the two values.
with t as (select org_id, lv, parent_org_id, 'ORG' who_type, 0 timee from thierarch connect by parent_org_id = prior org_id start with parent_org_id = 0 -- union all -- select p.person_id, 0, o.org_id, 'PER', p.TIMEE from (select * from thierarch where lv = 1 connect by parent_org_id = prior org_id start with parent_org_id = 0) o, (select * from tdata) p where o.org_id = p.org_id) -- select rownum, org_id, who_type, parent_org_id, t.lv, TIMEE, (select sum(tt.TIMEE) from t tt start with tt.org_id = t.org_id AND tt.parent_org_id = t.parent_org_id -- ***** NEW ***** connect by prior tt.org_id = tt.parent_org_id) as TIMEE from t connect by parent_org_id = prior org_id start with parent_org_id = 0;I added only 1, line 5 from the end.
Depending on your data and your needs, you may need to do the same kind of change elsewhere in the query, where org_id is used.This whole request seems unnecessarily complicated. I don't know what you're trying to do, but it is difficult to imagine anyting you are trying maybe that we can't do with 1 or 2 possible, CONNECT BY query, and not 4 as you use.
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4 GB of ram
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Hello
I get incorrect results in a DISTINCT COUNT measure column GRAND TOTAL.
I have 5 separate in Paris and 10 separate clients in New York, I want the grand total for the sum of the two, it is 15.
But OBIEE calculates separate customers for all cities, so if there are customers in Paris and New York, the result is false.
This is the result I get:
City Number_Distinct_Customers
----------------------------------------------------------------------------
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The correct GRANT TOTAL is expected to be 5 + 10 = 15
Thank you
ConcerningI guess that COUNT(DISTINCT...) is regarded as the default aggregation in the Oracle replies.
To come in this, change the State of aggregation of fx (formula column in the criteria of answers tab) to 'SUM '...Let me know if that solves your problem.
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The line view alias role_tab returns exactly the same results using UNION or UNION ALL, ie. 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rol_type, cpy_name, cpy_cty_code HAVING SUM(ftrn_mamount_gbp) > 225000;
What is expected as the return values are logically unique.
So I decided to go with UNION ALL to the performance. However, the returned results are different when used in the context of the entire query - with UNION 122 096 rows are returned, UNION ALL returns 137 904...
This could be the cause, I may be missing something, but it seems to me that one or both sets of results must by incorrect?
Any ideas or help would be greatly appreciated.
See you soon
BenI think that your problem lies here:
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AND rol_cpy = 'HIL'So presumably you will get HEL so much HIL rows in the subquery, but you also get the lines of HEL in an another subquery. UNION will remove the duplicate set.
I think you could do this in a more easy way, by collapsing your subqueries in one (or maybe two) - looks that you single out a TRANSFEREE line if you have a line of TRUSTEE, which you could do this by adding a pivot.
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trigger for update field in a table with the sum of the fields to another table
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Create a trigger failed, for the following reason:
ORA-06552: PL/SQL: ORA-06553 finished Compilation unit analysis: PLS-320: the declaration of the type of the expression is incomplete or incorrect
Here is my attempt to create the trigger on my own.
create or replace trigger "ASSIGNMENT_TIME_TRACK_T1".
AFTER
INSERT or update or delete on 'ASSIGNMENT_TIME_TRACK '.
for each line
Start
update assignments
Set time_spent = (select sum (time_spent)
of assignment_time_track
where assignment_time_track.name = assignments.name);
end;
/
If what I posted is not clear or more detail is needed, let me know and I will respond with a full description of tables and my goals for each table. Thanks in advance for any help. I also gladly accepts links to tutorials or lessons that explain how to do this kind of thing.
Published by: bobonthenet on March 9, 2009 14:01I think I understand what you mean :)
Rather than use a trigger to keep the master table (assignments) in sync with the time spent on the details, it would be much easier to use a query to do this, maybe creating a view.
Something along the lines of
SQL> create table assignments 2 (id number primary key 3 ,name varchar2(10) 4 ); Table created. SQL> SQL> create table assignment_time_tbl 2 (id number primary key 3 ,assid number references assignments 4 ,time_spent number 5 ); Table created. SQL> SQL> insert into assignments 2 select rownum 3 , 'a' 4 from all_objects 5 where rownum < 5 6 / 4 rows created. SQL> SQL> insert into assignment_time_tbl 2 select rownum 3 , rownum 4 , rownum * 3 5 from all_objects 6 where rownum < 5 7 / 4 rows created. SQL> SQL> commit; Commit complete. SQL> SQL> SQL> select a.id 2 , a.name 3 , (select sum (time_spent) 4 from assignment_time_tbl 5 where assid = a.id 6 ) 7 from assignments a 8 / ID NAME (SELECTSUM(TIME_SPENT)FROMASSIGNMENT_TIME_TBLWHEREASSID=A.ID) ---------- ---------- ------------------------------------------------------------- 1 a 3 2 a 6 3 a 9 4 a 12 -
Hello
I need help with something with that I'm struggling
When I wrote <? xdoxslt:IfElse ((CF_OP_BAL > 0), (CF_OP_BAL + xdoxslt:sum(DEBIT)),xdoxslt:sum(DEBIT))?) > it works fine...
but now I need to manage xdoxslt:sum (DEBIT) null...
so, I tried...
<? xdoxslt:IfElse ((CF_OP_BAL > 0), (CF_OP_BAL + decode(xdoxslt:sum(DEBIT),",0,xdoxslt:sum(DEBIT)),decode(xdoxslt:sum(DEBIT),",0,xdoxslt:sum(DEBIT)))? >))
This gives XPATH Incorrect error...
Concerning
RigotHello
Try:
0),(CF_OP_BAL+sum(DEBIT[.!=''])),(sum(DEBIT[.!=''])))?>{code}Regards, Colectionaru Edited by: Colectionaru on Dec 15, 2008 7:36 AM -
6 iOS10 incorrect percentage battery iPhone
On my 6 running latest iOS iPhone 10 (10.0.1) my battery indicator in percentage is incorrect most of the time. I can't tell if the percentage indicator is stuck or something. This happened 9 w/IOS, but seems aggravated with iOS 10. Here are two typical scenarios:
1. indicator indicates the value > 50%, but then stops
2. indicator indicates the value ~ 10%, but then when it is plugged in charge indicator of cable past at 30%.
I see that when people are complaining about this preliminary response was to "upgrade to iOS 9.3 +'-well, which obviously does not work for me." I would like to have an indicator that represents the amount of battery life I have left.
Bart Taylor wrote:
On my 6 running latest iOS iPhone 10 (10.0.1) my battery indicator in percentage is incorrect most of the time. I can't tell if the percentage indicator is stuck or something. This happened 9 w/IOS, but seems aggravated with iOS 10. Here are two typical scenarios:
1. indicator indicates the value > 50%, but then stops
2. indicator indicates the value ~ 10%, but then when it is plugged in charge indicator of cable past at 30%.
I see that when people are complaining about this preliminary response was to "upgrade to iOS 9.3 +'-well, which obviously does not work for me." I would like to have an indicator that represents the amount of battery life I have left.
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The address of the map and driving directions in IOS devices 3/4 Ave., Almena, WI 54805 continues to be incorrect in Apple Maps to 369 12. We have presented more than 15 applications over the past 4 years to this fixed and submitted two photos geocoded with delivery address and Barron County, WI property and survey records of SIG showing the right address but this remains unclear. On an IOS device, if you enter the address 369 12 3/4 Ave., Almena, WI 54805 map will take you to the correct location on the map, but the map shows an address of 369 12 3/4 Ave., Turtle Lake, WI 54889. And if you have driving directions to 369 12 3/4 Ave., Almena, WI 54805 that will correctly identify the map take you somewhere 369 S 4th Ave, Alpena, MI 49707, 500 miles.
Apple is not regularly monitor the discussions. These are mostly a user in discussions.
Send feedback to Apple. They will not respond, but at least know that there is a problem or a suggestion for change. If enough people send feedback, it can get change / suggested the problem solved as soon as possible.
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My iphone 5 c (IOS 9.3) sent my incorrect position.
My iphone 5 c (IOS 9.3) sent my incorrect position. I have 'share my location' with my husband and this day there, he checked my position and it showed that I was about 1 to 1 1/2 miles away at a park (I've never been to). I was home at the time and wifi may have been down, but I can't understand why it was closed so far.
If there is no wifi, cellular service (I have Verizon) would not in the correct location? I even checked the location history on my phone and it me House shows during this period and shows the whole story to that area of the Park? Which would be so far off the coast?
Thank you.
If the phone can't get a current location due to the Internet being down, or in the case that the reception is not good enough to triangulate your location using nearby cell towers, the nearest known position will be displayed. If there is a cell tower near this park, it could also be stated as your position until your appliance again to a new location or the quality of the signal is still improving.
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