Table keeps assigning a defined size which I can't edit, please help!

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  version 11g
  
  Please help me in new id of person assiging for dirrerent so people it's middle name is different
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    /* Scenario3 NULL can be equal to any value if there is only one value to equate with 
      In the below case we have ONE VALUE  that can equate with null so DONT ASSIGN ANY IDS*/
   SELECT 17540300 ID , 'AMARONE' LAST_NAME , 'JOSEPH' FIRST_NAME , 'J' MIDDLE_NAME FROM DUAL UNION ALL   
   SELECT 17540300 ID , 'AMARONE' LAST_NAME , 'JOSEPH' FIRST_NAME , NULL MIDDLE_NAME FROM DUAL
  
   )
   Select * from names
   
   o/P Required
   ID    LAST_NAME    FIRST_NAME    MIDDLE_NAME
  
  47540310    WO      ROBERT          C
  99999990    WO      ROBERT          W                   -- New Sequence Number
  99999991     WO      ROBERT         X                   -- New Sequence Number
  47540300    AMATUZIO    ALBERT    J
  99999992    AMATUZIO    ALBERT                          -- New Sequence Number
  99999993    AMATUZIO    ALBERT    L                     -- New Sequence Number
  17540300    AMARONE    JOSEPH    J
  17540300    AMARONE    JOSEPH    

  Thank you
  
  Published by: new learning June 7, 2012 14:12

  I do not understand what does this line:

  FIRST_VALUE (fn_get_person_id) - sequence to function

  I feel that the only difference with my query is to select distinct values, do not consider duplicates. Correct me if I'm wrong.

  For me, this should give the same result as your query:

  WITH NAMES AS ( /* Scenario1 -- Three dirrerent people so assign Three diffrrent ID, keeping 1 id as is and assign two
  new ids from sequence*/
                 SELECT   47540310 ID,
                          'WO' LAST_NAME,
                          'ROBERT' FIRST_NAME,
                          'C' MIDDLE_NAME
                   FROM   DUAL
                 UNION ALL
                 SELECT   47540310 ID,
                          'WO' LAST_NAME,
                          'ROBERT' FIRST_NAME,
                          'C' MIDDLE_NAME
                   FROM   DUAL
                 UNION ALL
                 SELECT   47540310 ID,
                          'WO' LAST_NAME,
                          'ROBERT' FIRST_NAME,
                          'W' MIDDLE_NAME
                   FROM   DUAL
                 UNION ALL
                 SELECT   47540310 ID,
                          'WO' LAST_NAME,
                          'ROBERT' FIRST_NAME,
                          'X' MIDDLE_NAME
                   FROM   DUAL
                 UNION ALL
                 /* Scenario2 NULL can be equal to any value if there is only one value to equate with
                   In the below case we have two values that can equate with null so assign three diffrent ids */
                 SELECT   47540300 ID,
                          'AMATUZIO' LAST_NAME,
                          'ALBERT' FIRST_NAME,
                          'J' MIDDLE_NAME
                   FROM   DUAL
                 UNION ALL
                 SELECT   47540300 ID,
                          'AMATUZIO' LAST_NAME,
                          'ALBERT' FIRST_NAME,
                          NULL MIDDLE_NAME
                   FROM   DUAL
                 UNION ALL
                 SELECT   47540300 ID,
                          'AMATUZIO' LAST_NAME,
                          'ALBERT' FIRST_NAME,
                          'L' MIDDLE_NAME
                   FROM   DUAL
                 UNION ALL
                 /* Scenario3 NULL can be equal to any value if there is only one value to equate with
                   In the below case we have ONE VALUE  that can equate with null so DONT ASSIGN ANY IDS*/
                 SELECT   17540300 ID,
                          'AMARONE' LAST_NAME,
                          'JOSEPH' FIRST_NAME,
                          'K' MIDDLE_NAME
                   FROM   DUAL
                 UNION ALL
                 SELECT   17540300 ID,
                          'AMARONE' LAST_NAME,
                          'JOSEPH' FIRST_NAME,
                          'Y' MIDDLE_NAME
                   FROM   DUAL
                 UNION ALL
                 SELECT   17540300 ID,
                          'AMARONE' LAST_NAME,
                          'JOSEPH' FIRST_NAME,
                          NULL MIDDLE_NAME
                   FROM   DUAL
                 UNION ALL
                 SELECT   17540300 ID,
                          'AMARONE' LAST_NAME,
                          'JOSEPH' FIRST_NAME,
                          'M' MIDDLE_NAME
                   FROM   DUAL
                 UNION ALL
                 SELECT   17540300 ID,
                          'AMARONE' LAST_NAME,
                          'JOSEPH' FIRST_NAME,
                          'M' MIDDLE_NAME
                   FROM   DUAL
                 UNION ALL
                 SELECT   99999999 ID,
                          'LO' LAST_NAME,
                          'CHRISTY' FIRST_NAME,
                          NULL MIDDLE_NAME
                   FROM   DUAL
                 UNION ALL
                 SELECT   99999999 ID,
                          'LO' LAST_NAME,
                          'CHRISTY' FIRST_NAME,
                          'M' MIDDLE_NAME
                   FROM   DUAL
                 UNION ALL
                 SELECT   99999999 ID,
                          'LO' LAST_NAME,
                          'CHRISTY' FIRST_NAME,
                          'M' MIDDLE_NAME
                   FROM   DUAL),
   sel_names AS (  SELECT id
                            , last_name
                            , first_name
                            , middle_name
                            , COUNT (middle_name) OVER (PARTITION BY id ORDER BY middle_name) cnt
                            , ROW_NUMBER () OVER (PARTITION BY id  ORDER BY middle_name) rown
                         FROM (SELECT DISTINCT * FROM names) -- use SELECT DISTINCT here to remove duplicates
                     ORDER BY 1, 2, 3, 4
                     )
  SELECT 8888888 new_id, id, last_name, first_name
       , middle_name
    FROM sel_names
   WHERE cnt > 1 AND rown > 1;
  

  As you can see I have just replace the table with a view of inline using SELECT DISTINCT *.

                         FROM (SELECT DISTINCT * FROM names) -- use SELECT DISTINCT here to remove duplicates
  

  For the new id I put a dummy value 888888, you can use a function or sequence according to your needs.

  Kind regards.
  Al

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