Please help me to assign a new Id for different people
version 11gPlease help me in new id of person assiging for dirrerent so people it's middle name is different
I've listed on three scenarios in the example below. Please help me
WITH NAMES AS(
/* Scenario1 -- Three dirrerent people so assign Three diffrrent ID,
keeping 1 id as is and assign two new ids from sequence*/
SELECT 47540310 ID , 'WO' LAST_NAME , 'ROBERT' FIRST_NAME , 'C' MIDDLE_NAME FROM DUAL UNION ALL
SELECT 47540310 ID , 'WO' LAST_NAME , 'ROBERT' FIRST_NAME , 'W' MIDDLE_NAME FROM DUAL UNION ALL
SELECT 47540310 ID , 'WO' LAST_NAME , 'ROBERT' FIRST_NAME , 'X' MIDDLE_NAME FROM DUAL UNION ALL
/* Scenario2 NULL can be equal to any value if there is only one value to equate with
In the below case we have two values that can equate with null so assign three diffrent ids */
SELECT 47540300 ID , 'AMATUZIO' LAST_NAME , 'ALBERT' FIRST_NAME , 'J' MIDDLE_NAME FROM DUAL UNION ALL
SELECT 47540300 ID , 'AMATUZIO' LAST_NAME , 'ALBERT' FIRST_NAME , NULL MIDDLE_NAME FROM DUAL UNION ALL
SELECT 47540300 ID , 'AMATUZIO' LAST_NAME , 'ALBERT' FIRST_NAME , 'L' MIDDLE_NAME FROM DUAL UNION ALL
/* Scenario3 NULL can be equal to any value if there is only one value to equate with
In the below case we have ONE VALUE that can equate with null so DONT ASSIGN ANY IDS*/
SELECT 17540300 ID , 'AMARONE' LAST_NAME , 'JOSEPH' FIRST_NAME , 'J' MIDDLE_NAME FROM DUAL UNION ALL
SELECT 17540300 ID , 'AMARONE' LAST_NAME , 'JOSEPH' FIRST_NAME , NULL MIDDLE_NAME FROM DUAL
)
Select * from names
o/P Required
ID LAST_NAME FIRST_NAME MIDDLE_NAME
47540310 WO ROBERT C
99999990 WO ROBERT W -- New Sequence Number
99999991 WO ROBERT X -- New Sequence Number
47540300 AMATUZIO ALBERT J
99999992 AMATUZIO ALBERT -- New Sequence Number
99999993 AMATUZIO ALBERT L -- New Sequence Number
17540300 AMARONE JOSEPH J
17540300 AMARONE JOSEPH Published by: new learning June 7, 2012 14:12
I do not understand what does this line:
FIRST_VALUE (fn_get_person_id) - sequence to function
I feel that the only difference with my query is to select distinct values, do not consider duplicates. Correct me if I'm wrong.
For me, this should give the same result as your query:
WITH NAMES AS ( /* Scenario1 -- Three dirrerent people so assign Three diffrrent ID, keeping 1 id as is and assign two
new ids from sequence*/
SELECT 47540310 ID,
'WO' LAST_NAME,
'ROBERT' FIRST_NAME,
'C' MIDDLE_NAME
FROM DUAL
UNION ALL
SELECT 47540310 ID,
'WO' LAST_NAME,
'ROBERT' FIRST_NAME,
'C' MIDDLE_NAME
FROM DUAL
UNION ALL
SELECT 47540310 ID,
'WO' LAST_NAME,
'ROBERT' FIRST_NAME,
'W' MIDDLE_NAME
FROM DUAL
UNION ALL
SELECT 47540310 ID,
'WO' LAST_NAME,
'ROBERT' FIRST_NAME,
'X' MIDDLE_NAME
FROM DUAL
UNION ALL
/* Scenario2 NULL can be equal to any value if there is only one value to equate with
In the below case we have two values that can equate with null so assign three diffrent ids */
SELECT 47540300 ID,
'AMATUZIO' LAST_NAME,
'ALBERT' FIRST_NAME,
'J' MIDDLE_NAME
FROM DUAL
UNION ALL
SELECT 47540300 ID,
'AMATUZIO' LAST_NAME,
'ALBERT' FIRST_NAME,
NULL MIDDLE_NAME
FROM DUAL
UNION ALL
SELECT 47540300 ID,
'AMATUZIO' LAST_NAME,
'ALBERT' FIRST_NAME,
'L' MIDDLE_NAME
FROM DUAL
UNION ALL
/* Scenario3 NULL can be equal to any value if there is only one value to equate with
In the below case we have ONE VALUE that can equate with null so DONT ASSIGN ANY IDS*/
SELECT 17540300 ID,
'AMARONE' LAST_NAME,
'JOSEPH' FIRST_NAME,
'K' MIDDLE_NAME
FROM DUAL
UNION ALL
SELECT 17540300 ID,
'AMARONE' LAST_NAME,
'JOSEPH' FIRST_NAME,
'Y' MIDDLE_NAME
FROM DUAL
UNION ALL
SELECT 17540300 ID,
'AMARONE' LAST_NAME,
'JOSEPH' FIRST_NAME,
NULL MIDDLE_NAME
FROM DUAL
UNION ALL
SELECT 17540300 ID,
'AMARONE' LAST_NAME,
'JOSEPH' FIRST_NAME,
'M' MIDDLE_NAME
FROM DUAL
UNION ALL
SELECT 17540300 ID,
'AMARONE' LAST_NAME,
'JOSEPH' FIRST_NAME,
'M' MIDDLE_NAME
FROM DUAL
UNION ALL
SELECT 99999999 ID,
'LO' LAST_NAME,
'CHRISTY' FIRST_NAME,
NULL MIDDLE_NAME
FROM DUAL
UNION ALL
SELECT 99999999 ID,
'LO' LAST_NAME,
'CHRISTY' FIRST_NAME,
'M' MIDDLE_NAME
FROM DUAL
UNION ALL
SELECT 99999999 ID,
'LO' LAST_NAME,
'CHRISTY' FIRST_NAME,
'M' MIDDLE_NAME
FROM DUAL),
sel_names AS ( SELECT id
, last_name
, first_name
, middle_name
, COUNT (middle_name) OVER (PARTITION BY id ORDER BY middle_name) cnt
, ROW_NUMBER () OVER (PARTITION BY id ORDER BY middle_name) rown
FROM (SELECT DISTINCT * FROM names) -- use SELECT DISTINCT here to remove duplicates
ORDER BY 1, 2, 3, 4
)
SELECT 8888888 new_id, id, last_name, first_name
, middle_name
FROM sel_names
WHERE cnt > 1 AND rown > 1;
As you can see I have just replace the table with a view of inline using SELECT DISTINCT *.
FROM (SELECT DISTINCT * FROM names) -- use SELECT DISTINCT here to remove duplicates
For the new id I put a dummy value 888888, you can use a function or sequence according to your needs.
Kind regards.
Al
Tags: Database
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Please, help me to by merging the same id assining people
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Please help me
We_addr_id defines the Address. We_pid Defines the Person. i am planning to merge the same person together by assigining the same we_pid.WITH merge_names AS (SELECT 1000 We_pid, 999898989 We_addr_id, 'DONALD' first_name, 'BOATRIGHT' last_name, 'L' middle_name, NULL Suffix FROM DUAL UNION ALL SELECT 1001 We_pid, 999898989 We_addr_id, 'DONALD' first_name, 'BOATRIGHT' last_name, 'LARRY' middle_name, NULL Suffix FROM DUAL UNION ALL SELECT 1002 We_pid, 999898989 We_addr_id, 'DONALD' first_name, 'BOATRIGHT' last_name, NULL middle_name, NULL Suffix FROM DUAL UNION ALL SELECT 33065 WE_PID, 99000000 We_addr_id, 'LUNA' First_name, 'JOSE' last_name, NULL middle_name, NULL suffix FROM DUAL UNION ALL SELECT 8450527 WE_PID_LINK, 99000000 We_addr_id, 'LUNA' First_name, 'JOSE' last_name, 'A' middle_name, NULL suffix FROM DUAL UNION ALL SELECT 373453429 WE_PID_LINK, 99000000 We_addr_id, 'LUNA' First_name, 'JOSE' last_name, NULL middle_name, NULL suffix FROM DUAL UNION ALL SELECT 442303062 WE_PID, 99000000 We_addr_id, 'LUNA' First_name, 'JOSE' last_name, 'S' middle_name, NULL suffix FROM DUAL UNION ALL SELECT 30088775765 WE_PID, 990000878 We_addr_id, 'BILL' last_name, 'RAY' first_name, 'M' middle_name, NULL SUFFIX FROM DUAL UNION ALL SELECT 30088775766 WE_PID, 990000878 We_addr_id, 'RAY' first_name, 'BILL' last_name, NULL middle_name, NULL SUFFIX FROM DUAL UNION ALL SELECT 30088775767 WE_PID, 990000878 We_addr_id, 'RAY' first_name, 'BILL' last_name, 'MAX' middle_name, NULL SUFFIX FROM DUAL UNION ALL SELECT 30088775768 WE_PID, 990000878 We_addr_id, 'RAY' first_name, 'BILL' last_name, 'MICHEL' middle_name, NULL SUffix FROM DUAL UNION ALL SELECT 399998776 WE_PID, 9901111 We_addr_id, 'ELLISON' first_name, 'LAWRANCE' last_name, NULL middle_name, NULL SUFFIX FROM DUAL UNION ALL SELECT 399998777 WE_PID, 9901111 We_addr_id, 'ELLISON' first_name, 'LAWRANCE' last_name, 'J' middle_name, 'JR' SUFFIX FROM DUAL UNION ALL SELECT 399998778 WE_PID, 9901111 We_addr_id, 'ELLISON' first_name, 'LAWRANCE' last_name, 'JAMES' middle_name, 'SR' SUFFIX FROM DUAL UNION ALL SELECT 399998779 WE_PID, 9901111 We_addr_id, 'ELLISON' first_name, 'LAWRANCE' last_name, 'JACK' middle_name, 'JR' SUFFIX FROM DUAL) SELECT * FROM merge_names
Thank youo/p Required WE_PID WE_ADDR_ID FIRST_NAME LAST_NAME MIDDLE_NAME SUFFIX MERGE_WEPID 1000 999898989 DONALD BOATRIGHT L 1000 1001 999898989 DONALD BOATRIGHT LARRY 1000 1002 999898989 DONALD BOATRIGHT 1000 33065 99000000 LUNA JOSE 33065 8450527 99000000 LUNA JOSE A 8450527 373453429 99000000 LUNA JOSE 33065 442303062 99000000 LUNA JOSE S 442303062 30088775765 990000878 BILL RAY M 30088775765 30088775766 990000878 RAY BILL 30088775766 30088775767 990000878 RAY BILL MAX 30088775767 30088775768 990000878 RAY BILL MICHEL 30088775768 399998776 9901111 ELLISON LAWRANCE 399998776 399998777 9901111 ELLISON LAWRANCE J JR 399998777 399998778 9901111 ELLISON LAWRANCE JAMES SR 399998778 399998779 9901111 ELLISON LAWRANCE JACK JR 399998777Hello
Interesting problem!
That's what you asked for:
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