Table with multiple partitions
Hello
I've got a big look up postcodes dimension table:
create table zip (from_zip number(5), to_zip number(5));
It's almost 1 billion record table and the content of the table is:
from_zip: it has all postal codes in the United States, about 40,000 nationwide).
to_zip: it lists all zip codes to 400 miles of the zip code in the from_zip column.
I need to run a query such as:
select a.* from TRX_TABLE a, ZIP where a.ZIP = ZIP.TO_ZIP where from_zip = 10001;
I only provide a zip code in where clause above. Because the ZipCode table is so great, I thought that the best way to partition the table zip by list (from_zip) so that a single partition will contain a zip code of from_zip. This would create about 40 000 partitions since there are 40 000 postal codes in the United States. And since I only provide a zip code in the where clause, it would only be to access a zip. Is 40 000 partitions too? Exceeds the appropriate design? Would it be useful to have a local index on to_zip? the TRX_TABLE has about 10 million documents.
Y at - it an easy way to create a partition for each zip or do I have to list each of the zip codes in the partitions?
Help, please.
41004 projection in accordance with (the United States) is a coordinate system where the coordinates are projected on a plan, coordinates x, Y in meters. Sorry I didn't say that. The sdo_dim_array must therefore:
MDSYS. () SDO_DIM_ARRAY
MDSYS. SDO_DIM_ELEMENT ('X', - 20000000.0, 20000000.0, 1),
MDSYS. SDO_DIM_ELEMENT('Y',-20000000.0, 20000000.0, 1))
These ranges of X and there are enough to cover almost everyone and are what we use for in my work projected coordinate systems. A tolerance of 1 meter (a little more than a yard) seems fine for your application. 50 even would be OK for you.
Create the actual error of your index finger is hidden in the Middle "ORA-13375: the layer is of type [2002] while inserted geometry has type [2001]"-J' made a mistake and stuck in the bad example for the spatial index. "" I'm sorry. A few points of index
CREATE INDEX xxx_SPIND ON xxx (COORDINATES) INDEXTYPE IS MDSYS. SPATIAL_INDEX PARAMETERS ('layer_gtype =POINT');
To convert the long/lat 41004 use:
sdo_cs. Transform (SDO_GEOMETRY (2001, 8307, SDO_POINT (v_long, v_lat, NULL), NULL, NUll), 41004)
To use SDO_WITHIN_DISTANCE to 41004, you give a unit type or give the distance in meters. 1 mile = 1609.344 Mr. (we went metric in the 1970s here in Australia, so I'm comfortable in both).
Here is an example that I did to make sure I had not missed anything else.
create table t_point (name varchar2 (20) null, mdsys uncoordinated.) SDO_GEOMETRY);
insert into (TABLE_NAME, COLUMN_NAME, DIMINFO, SRID) user_sdo_geom_metadata
values ('T_POINT', 'Contact INFORMATION', MDSYS. SDO_DIM_ARRAY (MDSYS. SDO_DIM_ELEMENT ('X', - 20000000.0, 20000000.0, 1),
MDSYS. (SDO_DIM_ELEMENT('Y',-20000000.0, 20000000.0, 1)), 41004);
insert into t_point values ('HOME', sdo_cs.transform (SDO_GEOMETRY (2001, 8307, SDO_POINT (-96,23, NULL), NULL, NULL), 41004));
insert into t_point values ('1', sdo_cs.transform (SDO_GEOMETRY (2001, 8307, SDO_POINT (-96,24, NULL), NULL, NULL), 41004));
insert into t_point values ('Hemisphere.2', sdo_cs.transform (SDO_GEOMETRY (2001, 8307, SDO_POINT (-96,25, NULL), NULL, NULL), 41004));
insert into t_point values ('NORTH3', sdo_cs.transform (SDO_GEOMETRY (2001, 8307, SDO_POINT (-96,27, NULL), NULL, NULL), 41004));
create index t_point_spind on t_point (coordinates) INDEXTYPE IS MDSYS. SPATIAL_INDEX PARAMETERS ('layer_gtype = POINT');
-Request less than 100 miles - search 2 points
Select * from t_point
where sdo_within_distance (coordinates, sdo_cs.transform (SDO_GEOMETRY (2001, 8307, SDO_POINT (-96.1,22.9, NULL), NULL, NULL), 41004))
'unit = mile = 100 distance') = 'TRUE ';
- Or giving counters:
Select * from t_point
where sdo_within_distance (coordinates, sdo_cs.transform (SDO_GEOMETRY (2001, 8307, SDO_POINT (-96.1,22.9, NULL), NULL, NULL), 41004))
'distance =' | TO_CHAR (100 * 1609.344, '99999999')) = "TRUE";
-Interview to 200 miles
Select * from t_point
where sdo_within_distance (coordinates, sdo_cs.transform (SDO_GEOMETRY (2001, 8307, SDO_POINT (-96.1,22.9, NULL), NULL, NULL), 41004))
'unit = distance = 200 mile') = 'TRUE ';
Kind regards
David
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