Take the difference of two tables

Similar Questions

• The most elegant way to get the difference between two tables - not least!

  Hello
  
  
  Simplified example of what I'm trying to achieve - I have two tables ORIGINAL and REVISED.
  
  
  My aim is to compare the two, such as; -
  
  
  When there is data in the two tables I get the difference between the Budget column, and if there is no difference, so I don't want no lines.
  
  When data exists in the ORIGINAL, but not in review, I want to the inverse of the current value of the Budget column.
  
  Where the data exist in REVISED I want the REVISED value.
  
  I can see how I can do this, see below, but is there a more elegant solution?
  
  
  
  
  Data for the ORIGINAL table
  

  select '801040' entity, '2186' expense_type, 234000 budget
  from dual
  union all
  select '801040' entity, '3001' expense_type, 1000 budget
  from dual
  union all
  select '801040' entity, 'P132' expense_type, 34000 budget
  from dual
  union all
  select '801040' entity, 'P135' expense_type, 43000 budget
  from dual

  Data for the REVISED table
  

  select '801040' entity, '2186' expense_type, 235000 budget
  from dual
  union all
  select '801040' entity, 'P132' expense_type, 34000 budget
  from dual
  union all
  select '801040' entity, 'P139' expense_type, 56000 budget
  from dual

  Desired output
  
  
  
  ENTITY EXPENSE_TYPE DIFFERENCE
  ------ ------------ ----------
  801040 2186 1000
  801040 3001-1000
  801040 P135-43000
  801040 P139 56000
  
  5 selected lines.
  
  
  
  Code current to achieve this, is there a better way?
  

  select original.entity
  ,      original.expense_type
  ,       (nvl(revised.budget,0) - original.budget) as difference
  from   original
  ,      revised
  where  original.entity = revised.entity(+)
  and    original.expense_type = revised.expense_type(+)
  and   (nvl(revised.budget,0) - original.budget) != 0
  union all
  select  revised.entity
  ,       revised.expense_type
  ,       revised.budget as difference
  from   revised
  where  not exists
  (select 'x'
  from   original
  where  original.entity = revised.entity
  and    original.expense_type = revised.expense_type)
  and    revised.budget != 0

  Thanks a lot for your comments,.
  
  
  Robert.
  
  Published by: Robert Angel on January 17, 2012 03:31 to change is not equal to! = - Thanks for the heads up

  SQL> with original
    2  as
    3  (
    4    select '801040' entity, '2186' expense_type, 234000 budget
    5    from dual
    6    union all
    7    select '801040' entity, '3001' expense_type, 1000 budget
    8    from dual
    9    union all
   10    select '801040' entity, 'P132' expense_type, 34000 budget
   11    from dual
   12    union all
   13    select '801040' entity, 'P135' expense_type, 43000 budget
   14    from dual
   15  )
   16  , revised
   17  as
   18  (
   19    select '801040' entity, '2186' expense_type, 235000 budget
   20    from dual
   21    union all
   22    select '801040' entity, 'P132' expense_type, 34000 budget
   23    from dual
   24    union all
   25    select '801040' entity, 'P139' expense_type, 56000 budget
   26    from dual
   27  )
   28  select *
   29    from (
   30          select nvl(o.entity, r.entity) entity,
   31                 nvl(o.expense_type, r.expense_type) expense_type,
   32                 nvl(r.budget,0) - nvl(o.budget,0) budget
   33            from original o
   34            full join revised r
   35              on o.entity = r.entity
   36             and o.expense_type = r.expense_type
   37         )
   38   where budget <> 0
   39  /
  
  ENTITY EXPE     BUDGET
  ------ ---- ----------
  801040 2186       1000
  801040 P135     -43000
  801040 3001      -1000
  801040 P139      56000
  
  SQL>
  

• Difference between two tables (ORA-01722)

  I am trying to get the difference of two tables on two databases.
  
  Walker I run the script below, it gives me a result that is not accurate.
  

  Select name, creation_time of v$datafile@REMOTE_database.com
  2 LESS THAN
  3 select name, creation_time from v$ datafile;
  
  I get 14 ranks of foregoing.

  However, when I run this script, I get an accurate count of the difference. How can I list the exact number instead of only to count the difference? Want lists all five name missing on table 2.
  

  SQL > SELECT a.cnt - b.cnt

  > count 2 (name) select cnt (of v$datafile@REMOTE_database.com) a, b

  3 (select count (name) NTC v$ datafile);
  
  A.CNT - B. CNT
  -----------
  5

  edited by: Albert Zaza on July 19, 2010 11:19

  have you tried:

  select trim(upper(name)) from v$datafile@REMOTE_database.com
   MINUS
   select trim(upper(name)) from v$datafile;
  

• Take the time between two values

  Hi people,

  I have a problem and I know idea how to solve... I need help.

  The problem is I want to take the time between two values max as you can see in the chart.

  For example, in the image that I have add

  4.5 - 1 840 = 2.66

  And enter this value in the 'time between mostra '.

  It's that I want...

  But what I think is very complicated, because I don't know how to take the time correctly and does remove...

  Thank you very much

  Any solution?

  Hi jocuma,

  I tried something and hope that helps u.

  Just create two arrays of temperature and voltage. First of all, I'll get the value of the voltage when it is more of a certain value and that same index to get the value of time and store in the shift register.

  When I get the second higher than the limit value, I'll get time and subtract the previous value.

• Take the minimum value for table data

  I'm storing test data in a table, with the hope that I can output the minimum value of the data. So far, I have used the table of max/min but can't make it work how I want. The test runs continuously in a loop of the holder. I get the minimum values in the table, but I would like to change the number of samples that the table contains, before it generates a minimum. The other option is that I run the test for a period of time (e.g. 3 seconds) and the table stores the data for this time then output 1 minimum value for the entire period.

  My current configuration VI is attached.

  Very appreciated

  Chris

  The size of the array in your VI is determined by the number of samples that you collect in your DAQ assistant, who is now 100 samples.  Never more, never less.

  How many samples do you want before you determine the minimum?

  Maybe what you really want to do is to build the table in the while loop and store it in a shift register, and when the loop has repeated enough times, then you take the minimum of built table.

• How to quickly find the difference of two version of RPD?

  Hi all
  
  Someone has a good idea to quickly find the difference of two versions of the RPD in the project?
  
  
  Kind regards
  Anne

  This could be a help for you
  http://varanasisaichand.blogspot.com/2010/03/how-to-merge-two-repositories.html
  http://www.rittmanmead.com/2010/07/OBIEE-11gr1-incremental-patches-to-the-RPD/

  See you soon,.
  KK

  Published by: Kranthi.K on December 7, 2011 21:41

• What is the difference between a table and a subform?

  What is the difference between a table and a subform in LC forms? Please post your answers about the merits and demerits of using subforms instead of tables.

  Hello

  a table is simply a set of subforms with a particular role.

  It is easier to handle the tables if they must be dynamic (add or remove lines, show or hide lines when page breaks appear etc..).

  And Designers UI has some dialogue prepared in the object palette to simplify the settings of the tables.

  For subforms, dialog boxes are more frequent, so you have yourself a little more script.

  But at least you can do everything with subforms as you can do with tables.

  The only one who is not very good with tables we work when you wrap arrays in other tables.

• How to find the difference between two dates in the presentation layer

  Hi gurus,
  
  Hello to everyone. Today, I came with the new requirement.
  
  
  I need to know the difference between a date and the current date in the formula column application presentation layer.by.
  
  
  
  Thank you and best regards,
  Prates

  Hi Navin,

  TIMESTAMPDIFF function first determines the timestamp component that corresponds to the specified interval setting. For example, SQL_TSI_DAY corresponds to the day component and SQL_TSI_MONTH corresponds to the component "month".

  If you want to display the difference between two dates in days using SQL_TSI_DAY, unlike butterflies SQL_TSI_MONTH and so on...

  hope you understand...

  Award points and to close the debate, if your question is answered.

  See you soon,.
  Aravind

• Kindly help me with the request to find the data in two tables

  Hello Guru
  
  Kindly help me to recover the data from two tables-
  
  BASEBALL
  LEGAL_ENT_ID (PK)
  GAME_ID (FK)
  LEGAL_ENT_NM
  INACTIVE_DT
  DATE OF INS_TS
  INS_LOGIN
  DATE OF UPD_TS
  UPD_LOGIN
  
  
  FOOTBALL
  GAME_ID (PK)
  BRKR_NM,
  BRKR_ISR_ID
  BROKER_SYMBOL
  INACTIVE_DT
  BRKR_SWIFT_FLG
  BRKR_INTERNAL_FLG
  BRKR_CATEGORY
  UPD_TS
  MINORITY_FLG
  BROKER_TYP
  STATUS
  INS_TS
  INS_LOGIN
  UPD_LOGIN
  APP_USER
  ACTIVE_FLG
  
  and if I want fecth data from these two tables according to the following condition then it is fine with the suite of applications.
  
  1 select distinct values only table of BASEBALL by using the following query.
  
  SELECT DISTINCT B.GAME_ID as 'CLEARING GAME ID', B.BRKR_NM "NAME of THE GAME of COMPENSATION" OF BASEBALL A, FOOTBALL B WHERE A.BROKER_RELATION_CD IN ('FUTBRKR1', 'FUTBRKR2') AND A.GAME_ID = B.GAME_ID
  
  2 Select all the table BRKR_NM OF FOOTBALL as well by using the query - next
  
  SELECT GAME_ID "RUNNING GAME ID", 'NAME OF THE GAME OF EXECUTION' BRKR_NM SOCCER
  
  Now, my query is that--
  
  I want a query that gives me a combination of above mentioned queries... and if I tried to use Union or Union All, then she is not giving me the result as expected.
  
  I like the result to look like who has a few conditions such as -
  1 - the records in the table Football are high vs Baseball table because there is no condition to filter the records of the Football.
  2 - football is a superset of records and Baseball is a subset.
  3 - COMPENSATION NOM_JEU and RUNNING NOM_JEU may return the same values as well.
  
  I want the result to be in the following form-
  
  EXECUTION ID GAME | NAME OF THE GAME TO RUN. COMPENSATION ID GAME | DELETE THE NAME OF THE GAME.
  2123 test1 2345 test5
  2456 test10 2456 test10
  
  
  Thanks in advance. Kindly help me.
  
  Published by: user555994 on January 4, 2011 23:48

  In the output you want.
  All the values of baseball;
  Values of football that are matched;
  But on what condition you want to match?

• Find the difference between two date and time

  Hi friends,
  
  I wanted to find the difference between two date and time, but my qury is slightest error "invalid number."
  
  

  select sql_step_num,proc_name,run_seqno,start_date,end_date,(to_char(start_date,'HH24-MI-SS') - to_char(end_date,'HH24-MI-SS') ) as ed  
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate) 
  order by sql_step_num;

  You try to get the feel between two char strings.
  And more difference between two dates gives a NUMBER of days.
  Try this:

  select sql_step_num,proc_name,run_seqno,start_date,end_date,numtodsinterval(end_date-start_date,'DAY') as ed
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate)
  order by sql_step_num;
  

• How it warns Oracle to use an index for the join of two tables...

  How to prevent the Oracle to use an index for the join of two tables to get a view online that is used in an update statement?
  
  O.K. I think I should explain what I mean:
  
  When you join two tables that have many entries sometimes there're better is not to use an index on the column that is used as a criterion to join.
  
  I have two tables: table A and table B.
  
  Table A has 4,000,000 entries and table B has 700,000 entries.
  
  I have a join of two tables with a numeric column as join criteria.
  
  There is an index on this column in A table.
  
  So I instead of
  

    where (A.col = B.col)

  I want to use
  

    where (A.col+0 = B.col)

  in order to avoid Oracle using the index.
  
  When I use the join in a select query, it works.
  
  But when I use the join as inline in an update statement I get the error ORA-01779.
  
  When I remove the '+ 0' the update statement works. (The column is unique in table B).
  
  Any ideas why this happens?
  
  Thank you very much in advance for any help.
  
  Hartmut cordially

  You plan to use a NO_INDEX hint as shown here: http://www.psoug.org/reference/hints.html

• display the data in two tables.

  Hi considers the following data

  WITH table1 AS
  (
    SELECT 111 userid,  To_Date('7/31/2010','mm/dd/yyyy') dt  FROM dual UNION ALL
    SELECT 111 userid,  To_Date('8/1/2010','mm/dd/yyyy') dt  FROM dual UNION all
    SELECT 111 userid,  To_Date('8/2/2010','mm/dd/yyyy') dt FROM dual UNION ALL
    SELECT 111 userid,  To_Date('8/3/2010','mm/dd/yyyy') dt  FROM dual UNION ALL
    SELECT 111 userid,  To_Date('8/4/2010','mm/dd/yyyy') dt FROM dual UNION ALL
    SELECT 111 userid,  To_Date('8/5/2010','mm/dd/yyyy') dt  FROM dual UNION ALL
  
    SELECT 222 userid,  To_Date('2/28/2010','mm/dd/yyyy') dt  FROM dual UNION all
    SELECT 222 userid,  To_Date('3/5/2010','mm/dd/yyyy') dt  FROM dual UNION all
  
  ),
   mydates AS
  (
   SELECT To_Date('7/31/2010','mm/dd/yyyy') dt1, To_Date('8/4/2010','mm/dd/yyyy') dt2 FROM dual  UNION ALL 
   SELECT To_Date('2/28/2010','mm/dd/yyyy') dt1, To_Date('3/5/2010','mm/dd/yyyy') dt2 FROM dual 
  )

  I want to join these two tables and result the following
  

  DT        DT2
  7/31/2010 8/04/2010
  8/01/2010  8/01/2010
  8/02/2010  8/02/2010
  8/03/2010  8/03/2010
  8/04/2010  8/04/2010
  8/05/2010  8/05/2010
  
  2/28/2010  3/5/2010
  3/5/2010   3/5/2010

  Basically, I join two tables, take dt from table1 and look into mydates. If the data match then display dt and DM2.
  If the date in table1 does not match date in t1d in mydates, then display the data but dt and DM2 there same date.
  
  for example,.
  
  7/31 in table1 is 7/31 in mydates so I show 7/31 dt and DM2 as 8/4(from mydates).
  now 8/01 does not match all lines in my dates so dt should be 8/01 and T2D should be 8/01. same logic applies to the other lines
  
  can someone write a query that gives the above result? Thank you

  Hello

  If you want all lines of table1 (attached to mydates when this is possible, but even when there is no match) then use an outer join:

  SELECT     t.dt
  ,     NVL (m.dt2, t.dt)     AS dt2
  FROM          table1     t
  LEFT OUTER JOIN     mydates     m     ON     t.dt     = m.dt1
  ORDER BY     t.dt
  ;
  

• How to calculate the difference between two times by the NUMBERS

  I'm so bothered by the fact that I can't understand that.

  Cell B2 - 08:00

  Cell C2 - 10:50

  (How can cell D2 - I get this cell to calculate the difference and say 02:50?)

  I know it's probably one of the most basic operations, but for the life of me I can't understand it. The cells B2 and C2 are formatted for a 24-hour clock. But if I tell the system to just subtract the two, I get "0,118. Everything I find on the forum search goes beyond what I need. Can someone help me?

  Thank you

  Hi sapirs,

  Departure and arrival of the cells are in Date and time with Date format: no and time: 24-hour clock.

  

  Formula in D2 (fill down)

  = C2−B2

  

  The results become a duration format, but under automatic (numbers automatically worth this format)

  

  If you wish, you can change the cells of lasting results.

  What Data Format have your result cells?

  Kind regards

  Ian.

• Find the difference between two numbers (DBL)

  Hi all

  Is there a function in labview other than the subtraction function that can find the difference between the two numbers given?

  Thank you

  Davidson

  
  

• Delete rows in a table when the columns from two tables match

  Hello

  I have following two tables.

  ===========================================

  create the table empbooth as

  (

  Select 1 empid, 1 double cabin Union all the

  Select option 2, Union 1 double all the

  Select 3, Union 1 double all the

  Select option 4, Union 2 double all the

  Select option 5, 2 double

  );

  create the table attsht as

  (

  Select 1 empid, 240 reg, 0 unpaid all double union

  Select option 2, reg 200, 0 unpaid of all the double union

  Select 3, 240 reg, 0 unpaid all double them union

  Select 4 480 reg, 0 unpaid all double union

  Select 5 240 reg, unpaid double 0

  );

  =================================================

  I want to remove rows from attsht where corresponding booth (which is stored in the empbooth table) is 1.

  The condition is 'where attsht.empid = empbooth.empid and empbooth.booth = 1 '.

  I use oracle 10g.

  Help, please

  delete from attsht where a.empid in (select b.empid from empbooth b where b.booth = 1)

  or

  remove from attsht a

  where exists (select null

  of empbooth b

  where b.booth = 1

  and b.empid = a.empid)