The addition of '\n' to a specific position in the LONG Variable
Hello
I have a requirement where I will read the file and it will contain a field with a data LENGTH. I'm assigning this value in a long Variable. I know that LONG is outdated, but I need to live with it now that there are a lot of changes in multiple procedures.
Requirement is
1. the value will be length approximately 8000 characters.
2. I need to read the value and add a '\n' in every 79th position
For example, in the 79th, 158th, 237th positions and so on for each 79th position.
Please help with a solution to achieve this.
Please let me know for any question about the requirement.
As mentioned Blu, SQL LONG is obsolete, but it looks like you are using a long Variable. Therefore, specify here. If I understand right, read you file in PL/SQL in the LONG PL/SQL variable (which is nothing but VARCHAR2(32760)
) and then insert into the column. There is no direct relationship between the LONG SQL and PL/SQL LONG, so you can use the VARCHAR2 variable. In addition, you must specify \n. You literally mean \n or \n say CRLF? I'll assume that CRLF:
SQL > create table tbl (long l);
Table created.
SQL > declare
v_str 2 varchar2 (32760);
3. start
4 v_str: = ' I have a requirement where I'll read the file and it will contain a field with a data LENGTH. I'm assigning this value in a long Variable. I know that LONG is outdated, but I need to live with it now that there are a lot of changes in multiple procedures. » ;
5. Insert
6 in tbl
7 values)
8 regexp_replace (v_str,'(.{78}) ',' \1' |) Chr (13) | 10
9 );
10 end;
11.
PL/SQL procedure successfully completed.
SQL > set 1000 long
SQL > select *.
2 tbl
3.
L
--------------------------------------------------------------------------------
I have a requirement where I will read the file and it will contain a field ha
ving a BIG data. I'm assigning this value in a long Variable. I know that
LONG is outdated, but I need to live with it now that there are a lot of cha
NGES in several procedures.
SQL >
SY.
Tags: Database
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