the deleting of the output XML tag beginning with LIST_
HelloI have a requirement to generate a report with the XML output. This output will be used for downloading information to another application. I know the names of all the tags and I can't have other tags.
I have a file xml for bi publisher and work very well but the group element added a tag more beginning with LIST_.
for example
< LIST_mygroup_name >
< mygroup_name >
....
< / mygroup_name >
< / LIST_mygroup_name >
I want to remove all the tags that begin with LIST_.
Any suggestion?
Thank you
Kale.
Reports6i, I can click on the properties of the report of the group to remove the label from the list.
Model data it is sufficient to add the property
Don't forget to give me points!
IKE Wiggins
http://bipublisher.blogspot.com
Tags: Business Intelligence
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Hi the Indesign Experts,
I am confused many in the sub question. I have an indesign document. In the xml structure, if I select an item and when trying to rename the selected item markupTag.name, is changing all elements with the name of the selected elements.
I use the code to execute after selecting an element of xml below.
App.Selection [0].markupTag.Name = "test";
But the look of the output like below.
But I want onlu to rename the selected xmlelement.
Any idea to do?
Thank you and best regards,
Vel.
You change the name of the tag applied rather than assigning another tag. Try this:
var testTag = app.activeDocument.xmlTags.item("test").isValid ? app.activeDocument.xmlTags.item("test") : app.activeDocument.xmlTags.add({name: "test"}); app.selection[0].markupTag = testTag;
Jeff
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Concatenate the nested XML tags
Hello
I am looking for a solution concatenate duplicate in an xml tags.
I need only the tags 'tag' 'type = keyword' in a field in a table.
The sql statement that I use, I get six records and I just need a registration.
Hope that my written English is not hard to understand what I mean.
It is a part of the XML data.
<? XML version = "1.0" encoding = "UTF - 8"? >
< list >
< article id = "25230245" title = "st" publish = "true" sender =">
< categories >
< naam category = "Staking" externalid = "Economy/staking" / >
< / categories >
< geoinfo latitude =' 52,3936' longitude' 6,142065 =' zoom = "15" / >
< tags >
< tag name = 'Overijssel, Raalte, Raalte' type = 'rental' / >
< tag name = 'Overijssel, Deventer, Deventer' type = 'rental' / >
< tag name = 'Overijssel Olst-Wijhe Wijhe' type = 'rental' / >
< tag name = "CAD" type = "keyword" / >
< name of tag = "vleeswarensector" type = "keyword" / >
< name of tag = "seniorenregeling" type = "keyword" / >
< tag name = "fnv bondgenoten" type = "Keyword" / >
< name of tag = "werkonderbreking" type = "keyword" / >
< tag name = 'Zwanenburg' type = "Keyword" / >
< tag name = "staking" type = "Keyword" / >
< tag name = "Scott" type = "Keyword" / >
< name of tag = "La¼pack" type = "keyword" / >
< tag name = "cnv vakmensen" type = "Keyword" / >
< / tags >
< publicatiedatum datum = '1400663902374' datumstr ='2014 - 05-21T 11: 18:00 + 0200 "/ >"
< wijzigingsdatum datum = '1400663902374' datumstr ='2014 - 05-21T 11: 18:00 + 0200 "/ >"
< printdatum datumstr = May 22, 2014 "/ >"
< bestemming >
< bestemming channel = 'web' site = 'ST' page =' Regio/Deventer /' primary = "false" / >
< bestemming channel = 'web' site = 'ST' page =' Regio/Olst-Wijhe /' primary = "false" / >
< bestemming channel = 'web' site = 'ST' page =' Regio/Raalte /' primary = "true" / >
< / bestemming >
< bron naam = "Benny Koerhuis" / >
< figurines / >
< / product >
< / list >
And it's my sql (part of a plsql procedure) statement.
SELECT decode (upper (t1.publish), 'TRUE', 'Y', 'n')
, trunc (to_date (substr (replace (t1.pdate, 't',' '), 1, 19), "YYYY-MM-DD HH24:MI:SS")) update
, to_date (substr (replace (t1.flitstijd, 't',' '), 1, 19), "YYYY-MM-DD HH24:MI:SS") flitstijd
t1.naam_flitser
t1.sectie
t1.titel
t1.soort
t2.trefwoorden
OF flits_berichten_clob t1
, XMLTABLE ("' / / test/artikel")
By the WAY of XMLTYPE (t1.xml_file)
COLUMNS publish VARCHAR2 (10) path '@publish '.
update the PATH in VARCHAR2 (25) "publicatiedatum/@datumstr".
, flitstijd PATH VARCHAR2 (25) "wijzigingsdatum/@datumstr".
, naam_flitser PATH VARCHAR2 (25) "bron/@naam".
, books VARCHAR2 (255) PATH 'bestemmingen/bestemming[@primary="true"]/@page '.
, titel VARCHAR2 (10) path 'bestemmingen/bestemming[@primary="true"]/@site '.
, soort PATH VARCHAR2 (10) 'bestemmingen/bestemming[@primary="true"]/@channel '.
tags XMLTYPE PATH 'tags') t1
, XMLTABLE ('/ tags/tag [@type = "keyword"] ")
PASSAGE t1.tags
T2 of COLUMNS trefwoorden VARCHAR2 (255) PATH "@name")
ID WHERE = 15;
This is the result.
THERE 21/05/2014 21/05/2014-11:18 Benny Koerhuis Regio/Raalte. ST Web werkonderbreking THERE 21/05/2014 21/05/2014-11:18 Benny Koerhuis Regio/Raalte. ST Web Zwanenburg THERE 21/05/2014 21/05/2014-11:18 Benny Koerhuis Regio/Raalte. ST Web staking THERE 21/05/2014 21/05/2014-11:18 Benny Koerhuis Regio/Raalte. ST Web Stegeman THERE 21/05/2014 21/05/2014-11:18 Benny Koerhuis Regio/Raalte. ST Web La¼Pack THERE 21/05/2014 21/05/2014-11:18 Benny Koerhuis Regio/Raalte. ST Web CNV vakmensen Is it possible to concatenate the results of the last column?
It should be "werkonderbreking, Zwanenburg, staking, Stegeman, la¼pack, cnv vakmensen" so, I get a recording instead of six.
Thanks in advance.
Is it possible to concatenate the results of the last column?
Yes, use string-join function:
...
titel PATH of VARCHAR2 (10) 'bestemmingen/bestemming[@primary="true"]/@site '. soort PATH of VARCHAR2 (10) 'bestemmingen/bestemming[@primary="true"]/@channel '. trefwoorden PATH of VARCHAR2 (4000) 'string-join(tags/tag[@type="keyword"]/@name, ","). ) t1
In this way, that you need more of the second XMLTABLE.
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Hello
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Published by: user340 on July 28, 2009 12:51
Published by: user340 on July 28, 2009 12:57the plu sql is not come away with a mistake. I mean sql is not treat this case like a sqlerror.
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Column name DataType ID Number Record BLOB OBJECT This is the XML code that is stored in the file inside the BLOB field format. XML below, I need go get AMC1234 there is after < itemName > text < / itemName > I thought to use XMLTYPE, but unfortunately my DBA team does not XML database, I now use UTL_RAW. CAST_TO_VARCHAR2 and recovery entire string, but I am not able to read actual result it takes. Can someone help me remove AMC1234.
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<! DOCTYPE importFile SYSTEM "xyz.dtd" >
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Without
Without - try something like...
with t as (select"
-
"the double pass."-
General failure 1 component and invalid vacation list -
PRQ ABC -
LMP ABC -
KEY 9999 -
Text AMC1234, FIXED_ALL, RED )
Select Replace (regexp_substr (col,'
([^<> ']) itemName)) , replace (regexp_substr (col,'
([^<> ""]) Valeurelement)) t
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Output XML code directly will open in the browser
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