The table can be outer joined to a single other table

Similar Questions

• Need to create the form that the user can fill out and SAVE Reader

  Hello

  My form, of course, works fine in Adobe Acrobat 4 CS4, is sunk when typed in with Acrobat Reader. It says at the top:

  "Please complete the following form. You cannot save data typed into the form. Please print your form if you would like a copy for your records. »

  * I know it's possible * to make it writable / recordable for users of readers, because I have a form that someone else created and in Reader the message says: "Please complete the following form. You can save the data entered in the form. »

  What setting do I change in Acrobat to make recordable in Reader? Document attached.

  Thank you in advance!

  Open the PDF in Acro 8 or 9 and in the Advanced menu, choose extend features in Adobe Reader.

• You can force BI outer join in w/o logical SQL Anwser in the Advanced tab

  In the repository of BI, we Protocol, region, Site of Protocol, Dimension of the object and a table of facts containing the physical tables Protocol, region, site and subject as a source in MDB.
  
  The relationship is that a protocol can have 0, n regions, region 0, n sites and a site 0, n subject, with the fact table of the region contains Protocol WID and done Site contains the Protocol and Feds region, subject is contains the Protocol, the region and Site Feds.
  
  In reporting on the Protocol and the region, BI users would like to have all the protocols appear in the report, without worrying if a protocol contains regions or not. Even as the Protocol-region-Site reports, etc. I can create these reports with SQL logic in the Advanced tab to force BI joins external Protocol, region or Site, etc.. However, users of BI would be difficult to write these SQLs.
  
  It seems to me that BI server always uses an inner join in the SQLs generated when the user selects the attributes of Protocol, region and Sites, etc. I played with constant implicit approach.
  
  I know that I can use outer join to define the logic Table Source in the layer of MDB. Would this tangle Protocol, region and site, tables etc. in MDB? What is the best practice to the MDB template when you want compatible outer join?
  
  Is there a way to force the BI server to generate outer join in the answers?
  
  Thanks in advance,
  
  Shi-ning

  Joins using external in the layer MDB is not recommended because it brings in the tables in the query and also impact performance. The right way to handle this scenario is the ETL.

  Add a record to the dimension tables with 0 for the ROW_WID and NULL values for the rest of the columns
  All of fact records without valid WID values for the dimension of research must have a value of 0 instead
  Now when we try to do an INTERNAL JOIN between the fact and any dimension, even those made documents that donot have a valid WID value will also be part of the result. It is essentially an OUTER JOIN operation.

• Why left outer join with a table gives me more lines?

  Hi gurus,

  I can see "view_a" and a table 'table_a '.

  view_a a county of 100 lines. Now, when I left outer join that discovers with a 'table_a', I expect all 100 lines.

  However, I'm more than 100 lines. Is it still possible?

  Also even to analyze these situations, how can I move forward?

  Because it is very high volumn of sight and takes longer to run.

  Select count (*) view_a, view_b

  where view_a.col1 = view_b.col1 (+)

  and view_a.col2 = view_b.col2 (+);

  Thank you

  I can see "view_a" and a table 'table_a '.

  view_a a county of 100 lines. Now, when I left outer join that discovers with a 'table_a', I expect all 100 lines.

  However, I'm more than 100 lines. Is it still possible?

  Also even to analyze these situations, how can I move forward?

  Because it is very high volumn of sight and takes longer to run.

  Select count (*) view_a, view_b

  where view_a.col1 = view_b.col1 (+)

  and view_a.col2 = view_b.col2 (+);

  Which is not necessarily related to the use of an outer join.

  Just join of two tables in general will give you more rows of one table has.

  Scott DEPT table contains ONE row for deptno = 10

  The EMP table has THREE rows of deptno = 10

  The number of rows you plan if you join two tables using an equi-join?

  Three - what is MORE lines the DEPT table has for deptno = 10

  Select * from Department where deptno = 10

  DEPTNO, DNAME, LOC
  10, ACCOUNTING, NEW YORK

  Select * from emp where deptno = 10

  MGR, EMPLOYMENT ENAME, EMPNO, HIREDATE, SAL, COMM, DEPTNO
  7782, CLARK, MANAGER, 7839, 6/9/1981,2450, 10
  7839, KING, PRESIDENT, 17 NOVEMBER 00, 10
  7934, MILLER, CLERK, 7782, 23 JANUARY 00: 10

  Select dept.*, emp.*
  Department, emp
  where dept.deptno = 10
  and dept.deptno = emp.deptno

  DEPTNO, DNAME, LOC, EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO_1
  10, ACCOUNTING, NEW YORK, 7782, CLARK, MANAGER, 7839, 6/9/1981,2450, 10
  10, ACCOUNTING, NEW YORK, 7839, KING, PRESIDENT, 17 NOVEMBER 00, 10
  10, ACCOUNTING, NEW YORK, 7934, MILLER, CLERK, 7782, 23 JANUARY 00: 10

  So if these are the lines ONLY in the table EMP and DEPT the query would give you THREE lines despite the DEPT table only ONE line.

  No do you expect? You get ALL the child rows that belong to the parent company. Otherwise, how could it possibly work?

  The OUTER join includes lines where the parent row exists but there is NO child line as others have shown.

  Outer joins

  Outer join extends the result of a simple join. Outer join returns all rows that satisfy the join condition and also returns some or all rows in a table for which no line of the other meet the join condition.

  Get more lines to exist in one of the paintings is a basic necessity. It usually has NOTHING to with the question of whether you have an outside to join or not.

  See the section on the JOINTS in the Oracle documentation

  http://docs.Oracle.com/CD/B28359_01/server.111/b28286/queries006.htm

• Problem with the implementation of Outer JOIN

  Hello Guru,
  
  Here's my scenario. I know that this can be achieved in several ways. But I need this in a single in aid Of JOINS EXTERNALrequest.
  
  I have two tables namely masters and transactions table. I need to join two columns (trx_name, trx_type) of the two tables and the need for all transactions. Part the trickiest is off 2 join columns, one column can be NULL in the main table.
  
  Script TABLES:
  
  create master table (mstr_no number, trx_name varchar2 (100), trx_type varchar2 (100), trx_module varchar2 (100));
  
  insert into masters values (1, 'yyyy', 'simple', 'cont');
  insert into masters values (2, 'bbbb', < NULL >, "cust");
  insert into masters values (3, 'yyyy', 'triple', "cont1");
  
  create table transaction (trx_no number, trx_name varchar2 (100), trx_type varchar2 (100));
  
  Insert in transaction values (1, 'yyyy', 'simple');
  Insert the transaction values (2, 'bbbb', 'double');
  Insert in transaction values (3, 'yyyy', 'triple');
  Insert in transaction values (4, 'cccc', 'purple');
  commit;
  
  I need output like below.
  
  1, 'yyyy', 'simple', 'cont '.
  2, 'bbbb', < NULL >, * "cust."
  3, 'yyyy', 'triple', "cont1".
  4, 'cccc', 'purple', < NULL >
  
  I need to join trx_name & trx_type in the two tables. Even if one of the column is null in the main table (mstr_no = 2), I have need of the corresponding value of trx_module since trx_name made match.
  
  
  My query:
  Select a.*, b.trx_module of transaction a, master b
  where a.trx_name = b.trx_name (+)
  and a.trx_type = NVL (b.trx_type (+), 'NULL')
  order of a.trx_no
  
  Appreciate your help.
  
  
  Concerning
  MN

  Maybe I'm wrong, but I don't think you can do this with a single outer join:

  with
  full_matches as (
  select *
    from master
   where trx_type is not null)
  ,
  partial_matches as (
  select *
    from master
   where trx_type is null)
  select a.*
       , coalesce(b.trx_module, c.trx_module) trx_module
    from transaction a
    left outer join full_matches b
      on (a.trx_name = b.trx_name and a.trx_type = b.trx_type)
    left outer join partial_matches c
      on (a.trx_name = c.trx_name)
   ;
  
  TRX_NO TRX_NAME             TRX_TYPE             TRX_MODULE
  ------ -------------------- -------------------- ------------
       1 aaaa                 single               cont
       3 aaaa                 triple               cont1
       2 bbbb                 double               cust
       4 cccc                 purple
  

  Re-reading my answer, I see that a short explanation might be useful: the query uses two outer joins: first masters lines with the name and type are joined, and then type the lines with missing. Him coalesce work to choose the most relevant information of module.

  Published by: Martin Preiss on June 7, 2013 20:24

• Outer join on the Filter Condition

  Hello

  I would like to show all rows in a query for two conditions to filter on the 'status '. I used an outer join on the outer query to return the values inside the inline query, but it returns not to return all rows.

  create table (test)
  ID number,
  start_date date,
  status varchar2 (1).
  number of amount,
  number of cust_type
  );

  
  Insert test values (001, June 1, 2014 ", am ', 189, 78");
  Insert test values (001, March 26, 2014 ", 'R', 175, 4");
  Insert test values (001, December 1, 2014 ", 'R', 89, 91");
  Insert test values ("001, 13 August 2014 ', 'J', 19, 2);
  Insert test values (001, 12 August 2014 ', 'E', 19, 2);

  Insert test values (002, January 1, 2014 ', 'R', 17, 4);
  Insert test values (002, 26 June 2014 ", 'R', 175, 4");
  Insert test values (' 002, February 1, 2014 ', 'J', 9, 8);
  Insert test values (002, 13 October 2014 ', ', 190, 2);

  Insert test values (' 003, June 1, 2014 ', 'J', 189, 78);
  Insert test values (003, March 26, 2014 ", 'R', 175, 4");
  Insert test values (003, December 1, 2014 ", 'R', 89, 91");
  Insert test values (' 003, 13 August 2014 ', 'J', 19, 2);
  Insert test values (' 003, 12 August 2014 ', 'J', 19, 2);

  commit;

  Select i.ids, i.start_date, i.cust_type, i.amount as gross_amount, i.amount + ii.amount as net_amount
  test I have,
  (select id, amount)
  of the test
  where (status = status or 'R' = 'J')) ii
  where i.cust_type in (4, 78, 91, 2, 4, 8)
  and i.ids (+) = ii.ids
  and i.status (+) to (', 'E')
  "and i.start_date between 1 January 14 ' and 31-dec-2014."

  The query above exclude ID 003 because there is that no status (M / E) butI want always display all codes, even if the condition is not consistent

  Hello

  Want results from an inner join to match identifiers, but the results of an outer join for identifiers that are not?  In other words, you want to include the rows of the table I only when one of the following is true:

  The line of table I have ticked all the boxes, or

  No line in not table i with the same ID meets all conditions

  ?

  If so, here's a way to do it:

  WITH got_rnk AS

  (

  Select i.ids, i.start_date, i.cust_type

  , nvl2 (ii.ids, i.amount, 0) as gross_amount

  , i.amount + nvl (ii.amount, 0) as net_amount

  dense_rank () over (partition of i.ids

  order of nvl2 (ii.ids, 'A', 'B')

  ) as rnk

  I have test

  (in left outer join

  SELECT ID, amount

  of the test

  where status ('R', 'J')

  ) ii on i.ids = ii.ids

  and i.cust_type in (4, 78, 91, 2, 4, 8)

  and i.start_date between to_date (January 1, 2014 ", 'dd-mon-yyyy')

  and to_date (31-dec-2014', 'dd-mon-yyyy')

  and i.status in (', 'E')

  )

  SELECT ID, start_date, cust_type

  gross_amount, net_amount

  of got_rnk

  where rnk = 1

  ;

  Results of your sample data:

  ID START_DATE GROSS_AMOUNT NET_AMOUNT CUST_TYPE

  --------- ----------- ---------- ------------ ----------

  1 1 June 2014 78 189 364

  1 1 June 2014 78 189 278

  1 1 June 2014 78 189 208

  1 12 August 2014 2 19 38

  1 12 August 2014 2 19 108

  1 12 August 2014 2 19 194

  2 13 October 2014 2 190 207

  2 13 October 2014 2 190 365

  2 13 October 2014 2 190 199

  3 March 26, 2014 4 0 175

  3 1 June 2014 78 0 189

  3 12 August 2014 2 0 19

  3 August 13, 2014 2 0 19

  3 1 December 2014 91 0 89

• ORA-01719: outer join operator (+) not allowed in operand of GOLD or IN

  I'm migrating a stored procedure (package) in Oracle 11 g.  The SQL has an outer join, combined with a "GOLD":

  Select a.row1, a.row2, b.row3, b.row4, c.row5, c.row6

  schema1.table1 a, schema1.table2 b, schema2.table3 c

  where

  ((c.orgunit = a.org (+) and b.newaccount (+) and TO_CHAR(c.createdatetime,'MM/DD/YYYY = c.account and c.feed = 'FOO' ') = TO_CHAR (SYSDATE, ' DD/MM/YYYY'))

  or

  ((c.feed = 'BAR' and c.orgunit = a.org (+) and c.account b.newaccount (+) and TO_CHAR(c.createdatetime,'MM/DD/YYYY =') = TO_CHAR (SYSDATE, ' DD/MM/YYYY'));

  The error is:

  ORA-01719: outer join operator not allowed in operand of GOLD or IN

  * Cause: Outer join appears in a clause or.

  * Action: If A and B are predicates, to achieve the effect of (has or B).

  I do not understand how to apply the suggested action to my query above.  Can anyone provide a solution or a workaround?

  Thank you.

  your base table is c, a and b must be attached to the left

  Select a.row1, a.row2, b.row3, b.row4, c.row5, c.row6

  of schema2.table3 c

  Join schema1.table1 left a c.orgunit on = a.org

  c.account left join schema1.table2 b = b.newaccount

  where c.createdatetime > = trunc (sysdate)

  and c.createdatetime<>

  and (c.feed = 'FOO' or c.feed = 'BAR');

• Former Outer Join syntax on constants

  Hello

  Can someone please tell me why the below two queries are performing differently. How to join a constant by using the old syntax used.

  Also, how is 3 different query of query 2?

  CREATE TABLE T1 (X VARCHAR2 (10), B INTEGER);

  CREATE TABLE T2 (Y VARCHAR2 (10), B INTEGER);

  INSERT INTO T1 VALUES('XXX',10);
  INSERT INTO T1 VALUES('XXX',10);
  INSERT INTO T1 VALUES('XXX',10);
  INSERT INTO T1 VALUES('YYY',20);
  INSERT INTO T1 VALUES('YYY',20);
  INSERT INTO T1 VALUES('YYY',20);

  INSERT INTO T2 VALUES('AAA',10);
  INSERT INTO T2 VALUES('BBB',20);

  Query 1

  SELECT T1.*, T2.* FROM T1 LEFT JOIN T2

  ON T1. B = T2. B

  AND T1. B = 20

  -OUTPUT

  =========

  BBB YYY 20 20

  BBB YYY 20 20

  BBB YYY 20 20

  NULL NULL 10 XXX

  NULL NULL 10 XXX

  NULL NULL 10 XXX

  Query 2

  SELECT T1.*, T2.* FROM T1, T2

  ON T1. B (+) = T2. B

  AND T1. B ( + ) = 20;

  OUTPUT

  =======

  BBB YYY 20 20

  BBB YYY 20 20

  BBB YYY 20 20

  Request 3

  SELECT T1.*, T2.* FROM T1, T2

  ON T1. B (+) = T2. B

  ET T2. B ( + ) = 20;

  -OUTPUT

  =========

  BBB YYY 20 20

  BBB YYY 20 20

  BBB YYY 20 20

  NULL NULL 10 XXX

  NULL NULL 10 XXX

  NULL NULL 10 XXX

  Thank you and best regards,

  Mathieu

  Hi, nada.

  967250 wrote:

  Hello

  My apologies for errors in queries.

  Please find the three queries

  QUERY1

  SELECT T1.*, T2.*
  T1 LEFT JOIN T2
  ON T1. B = T2. B
  AND T1. B = 20;

  QUERY2

  SELECT T1.*, T2.*
  FROM T1, T2
  WHERE T1. B = T2. B ( + )
  AND T1. B (+) = 20;

  QUERY3
  SELECT T1.*, T2.*
  FROM T1, T2
  WHERE T1. B = T2. B ( + )
  AND T2. B (+) = 20;

  Query 1 and 3 produce the same results. I want to know is what is the difference between Q2 and (T1 or T3)

  Thank you

  Mathieu

  In the query above 1, t1 is the required table (LEFT OUTER JOIN means the table on the LEFT is needed, and the other table is optional).

  Query 3 is the way to do the same in the old notation.

  If you use the old notation of outer join, the + sign is used by reference to the table as an option.  It should always apply for t1 or t2, not sometimes one and sometimes the other, which is what you do in the application 2.  In the State:

  T1. B = T2. B ( + )

  you say that t2 is optional; in the other condition

  T1. B (+) = 20

  you say that t1 is optional.  I don't know why that does not raise an error.  Apparently, it is just to ignore the sign in this last condition.

• Outer joins are equijoins and?

  Manual says Yes, but I think their only equijoins, insofar as the matched data and include other data as well. so technically should not fall outside the category of the equijoins?

  Hello

  Outer joins can be are equijoins.  In other words, some outer joins are of equijoins, others are not.

• Conditional outer join

  I have question while doing a conditional outer join... Suggestion help will be most appreciated
  
  I have three tables say x, y, emp.
  Table x and have a foreign key for emp say name empid column.
  
  condition should now be like that...
  If x.empid is not null
  then
  x.EmpID = emp.empid
  If x.empid is null
  then
  If y.empid is not null
  then
  y.EmpID = emp.empid
  on the other
  y.EmpID = emp.empid (+)
  
  To solve this problem, I pulled following gives the error "ORA-01719: outer join operator (+) not allowed in GOLD or IN the operand.
  Select *.
  x qm, o q, stdqs of the emp
  where)
  (qm.empid is not null and qm.empid = stdqs.empid)
  or
  (qm.empid is null and q.empid = stdqs.empid (+))
  )
  
  Published by: 870965 on July 9, 2012 12:36
  
  Published by: 870965 on July 9, 2012 12:37 AM

  a possible solution:

  WITH y AS
       (SELECT 10 AS y_pk, NULL AS empid FROM DUAL
        UNION ALL
        SELECT 20, 60 FROM DUAL
        UNION ALL
        SELECT 30, NULL FROM DUAL
       ),
       x AS
       (SELECT 1 AS x_pk, 10 AS y_fk, 50 AS empid FROM DUAL
        UNION ALL
        SELECT 2, 20, NULL FROM DUAL
       ),
       emp AS
       (SELECT 50 empid, 'Tom' empname FROM DUAL
        UNION ALL
        SELECT 60 empid, 'Smith' empname FROM DUAL
       )
  SELECT
       *
  FROM
       (SELECT
             x.x_pk
            ,y.y_pk
            ,nvl(x.empid, y.empid) empid
        FROM
            x, y
        WHERE x.y_fk(+) = y.y_pk
       ) z
       ,emp
  WHERE
       z.empid = emp.empid(+);
  

  Published by: kedruwsky on July 9, 2012 02:44

• Different Outer Join query result

  Hi all
  
  Under query gives the expected result
  
  
  Select DECODE (FPOVR. PROFILE_OPTION_VALUE,
  NULL, FPOVS. PROFILE_OPTION_VALUE, FPOVR. ZZ PROFILE_OPTION_VALUE)
  OPS FND_PROFILE_OPTIONS, FND_PROFILE_OPTION_VALUES FPOVR,.
  FND_PROFILE_OPTION_VALUES FPOVS where 1 = 1 and FPOVS. LEVEL_ID (+) = 10001
  and FPOVS. LEVEL_VALUE (+) = 0
  and FPOVS. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and FPOVR. (+) LEVEL_ID = 10003 and FPOVR. LEVEL_VALUE (+) = 21533
  and FPOVR. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and fpo.profile_option_name = 'GL_SET_OF_BKS_ID. '
  
  
  But the following query does not give the expected result.
  
  
  Select DECODE (FPOVR. PROFILE_OPTION_VALUE,
  NULL, FPOVS. PROFILE_OPTION_VALUE, FPOVR. ZZ PROFILE_OPTION_VALUE)
  OPS FND_PROFILE_OPTIONS, FND_PROFILE_OPTION_VALUES FPOVR,.
  FND_PROFILE_OPTION_VALUES FPOVS where 1 = 1 and FPOVS. LEVEL_ID (+) = 10001
  and FPOVS. LEVEL_VALUE (+) = 0
  and FPOVS. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and FPOVR. (+) LEVEL_ID = 10003 and FPOVR. LEVEL_VALUE = 21533
  and FPOVR. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and fpo.profile_option_name = 'GL_SET_OF_BKS_ID. '
  
  Difference between them is a join with external FPOVR. LEVEL_VALUE and hard coded value. Why these query above return different results even if the outer join is made with hard coded in value?
  
  Thank you
  SK

  SK says:
  Hi all

  Under query gives the expected result

  Select DECODE (FPOVR. PROFILE_OPTION_VALUE,
  NULL, FPOVS. PROFILE_OPTION_VALUE, FPOVR. ZZ PROFILE_OPTION_VALUE)
  OPS FND_PROFILE_OPTIONS, FND_PROFILE_OPTION_VALUES FPOVR,.
  FND_PROFILE_OPTION_VALUES FPOVS where 1 = 1 and FPOVS. LEVEL_ID (+) = 10001
  and FPOVS. LEVEL_VALUE (+) = 0
  and FPOVS. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and FPOVR. (+) LEVEL_ID = 10003 and FPOVR. LEVEL_VALUE (+) = 21533
  and FPOVR. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and fpo.profile_option_name = 'GL_SET_OF_BKS_ID. '

  But the following query does not give the expected result.

  Select DECODE (FPOVR. PROFILE_OPTION_VALUE,
  NULL, FPOVS. PROFILE_OPTION_VALUE, FPOVR. ZZ PROFILE_OPTION_VALUE)
  OPS FND_PROFILE_OPTIONS, FND_PROFILE_OPTION_VALUES FPOVR,.
  FND_PROFILE_OPTION_VALUES FPOVS where 1 = 1 and FPOVS. LEVEL_ID (+) = 10001
  and FPOVS. LEVEL_VALUE (+) = 0
  and FPOVS. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and FPOVR. (+) LEVEL_ID = 10003 and FPOVR. LEVEL_VALUE = 21533
  and FPOVR. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and fpo.profile_option_name = 'GL_SET_OF_BKS_ID. '

  Difference between them is a join with external FPOVR. LEVEL_VALUE and hard coded value.

  In fact, the difference is that the condition relating to FPOVR. LEVEL_VALUE to 21533 is part of the outer join condition in the first query, but it is not in the second query.

  Why these query above return different results even if the outer join is made with hard coded in value?

  When you say

  FPOVR.LEVEL_VALUE(+) = 21533
  

  (with a sign +) only the lines of fpovr with level_value = 21533 will join the other table. If there is no such line in fpovr, then a row of output will be generatedd for each row in the other table anyway.
  When you say

  FPOVR.LEVEL_VALUE = 21533
  

  (without a sign +) then the outer join is made using the other conditions, which may result in some lines of the other table who appear in the result set with NULL in places where the values of fpovr would normally appear. Then when the join is complete, the condition is applied, and all these lines with the NULL value instead of fpovr.level_value are deleted because they do not meet the condition "FPOVR. LEVEL_VALUE = 21533 ". The effect is identical to an inner join.

  When you use the old rating of outer join (i.e. with signs +), if any condition involving the fpovr table has a + sign, and then all of the conditions involving table fpovr must have a + sign, otherwise the result will be the same if none of the conditions were a sign +.

• The merged clips appear out-of-sync indicators while in sync

  So I have this weird problem with merged clips showing out-of-sync indicators while in fact, the audio is synchronized.

  Let me explain first the workflow for this feature;

  -Set of 6 K RED footage gets converted to 1080 p Prores Proxy

  -All the proxies and separate audio files are imported into a project file 'Master and Sync' (I use it to synchronize and merge clips as well as rename them)

  -When everything is synchronized, merged and renamed, they are placed in their corresponding scene number folder

  -J' I then open my project file 'Edit' and in the media browser, browse to the file "Master and Sync" project.

  -J' have drag and drop clips/merged records newly created the 'Master Sync' in the mediabrowser, in my project 'change '.

  -J' I change with them and everything works as expected.

  The issue comes in when I try to import a sequence edited of my Deputy Editor-in-Chief.

  -We work with the latest version of first

  -We are working on our own systems at home, but both have local access to all the images that we work with.

  -We have a record of sharing creative cloud where our editing projects are located and saved as well as the project "Master and Sync.

  -When my assistant has completed a first Assembly of a scene I navigate to his project to change the media browser when changing my own project is open.

  -J' I find the finished sequence and drag and drop it into my own project to change .

  And at that time there almost every single clip shows the out-of-sync indicator, but when I play the sequence everything is synchronized. I checked with my assistend maybe if its sequence shows also these indicators, but it is not. So it only seems to happen when I import its sequences. I tried ' display indicator out of sync clips unrelated " in the preferences, but without success.

  

  To add a comment to the audio to video synchronization. I had to make up for a lot of audio clips by a 1 or a couple of images manually because they turned with timecode jamming and not gen-lock. It is so true that technically the audio can be out of sync before their merger all but as you can see on the screenshot the indicators show a shift much larger than 1 or two images (I think the max lag that I got was 9 frames).

  All suggestions are welcome and I really hope I'm overlooking something rather than finding a bug!

  Thank you!

  So, I just got a phone call from Adobe. Technology Adobe told me that he had tested this configuration to confirm that it is seeing the same thing I am. Unfortunately, it has been. He also told me that it is a limitation instead of bug. Is because my assistant and I are working on two different systems and no access don't not on the same physical hard disk and so do not have access to the "exact" same media.

  It would be no problem if we worked on different systems, but to access media on the shared storage.

  The shame if this is considered to be a limitation rather than a bug. Seems to me it is repairable but, Hey! I'm just a simple editor and no programmer so it might be more difficult.

• OUTER JOIN not of Formate ansi

  SELECT A.DEPTNO, B.DEPTNO, A.EMPNO, B.EMPNO FROM EMP A, B EMP1
  WHERE = B.DEPTNO A.DEPTNO (+)
  
  
  I question as above
  I want to recover the data by FULL OUTER join
  
  No standard ansi formats
  
  ???

  select a.deptno, b.deptno, a.empno, b.empno
  from emp a, emp1 b
  where a.deptno     (+)     =     b.deptno
  union all
  select a.deptno, b.deptno, a.empno, b.empno
  from emp a, emp1 b
  where a.deptno          =     b.deptno (+)
  

• Outer join does not

  Hello
  
  Pls help me my request. I tried the following, but it does not give the expected results.
  
  Tab1
  EmplId, RepDt, Code, Hrs
  1/100,1/2009,199,8
  1/100,1/2009,200,4
  1/100,1/2009,255,3
  200,1/1/2009,200,4
  100.5/1/2009,199,8
  
  
  Tab2
  EmplId, RepDt, Code, Hrs
  1/100,1/2009,200,6
  200,1/1/2009,200,3
  
  I need output like this - 4 rows - need of all the rows from TAB1 when EMPLID, REPDT match TAB2, field values: need at a time when Code is also, when emlid, correspondence of the date, the Code missing so need A hrs, display ZERO as Tab2 hours.
  
  1/100,1/2009,199,8,0 - did not exist is not in tab2, so hrs Tab2 is ZERO
  1/100,1/2009,200,4,6 - Emplid, RepDt, Code match existence in Tab2, Tab1 Hrs 8, 6 Hrs Tab2
  1/100,1/2009,255,3,0 - did not exist is not in Tab2, so Tab2 hrs is equal to ZERO
  200,1/1/2009,200,4,3 - Emplid, Repdt, Code Match existed in Tab2, 4 Hrs of Tab1, Tab2 3 Hrs
  
  We are in 10g, Oracle.
  
  I tried the following
  T1. EmplId = T2.emplid AND T1.repdt = T2.repdt AND T1.code, T2.code = (+) - returns the unique corresponding lines, 2 rows.
  
  Pls help.
  
  Thanks in advance.
  
  Published by: NL 23 February 2009 09:20

  Hello

  See the Boneist first message in this thread:

  select t1.emplid, t1.repdt, t1.code, t1.hrs, nvl(t2.hrs, 0)
  from   tab1 t1,
         tab2 t2
  where  t1.emplid = t2.emplid (+)
  and    t1.repdt = t2.repdt (+)
  and    t1.code = t2.code (+)
  and    (t1.emplid, t1.repdt) in (select emplid, repdt
                                   from   tab2)
  order by repdt, emplid, code;
  

  As Boneist said, this fact corresponds to option (b)
  "(b) do just an outer join, with a condition EXISTS (or IN) in the WHERE clause to find corresponding repdts.
  The

  (+)
  

  an outer join are signs.

• Configure the network management grayed out in DCUI

  Configure the network management grayed out in DCUI and some other options are grayed out and network management IP is 0.0.0.0

  Seems that you have not any management VMkernel port or they may have been removed. You may need to check the same.

  Run esxcli list of network ip interface to check if there is no VMKernels.

  It does not generate re no output if NO vmkernel port is available.

  If no. VMkernel ports then follow the below to re-create the management VMkernel port group.

  esxcli network ip interface add-i = vmk0 Pei = "network management - M = 'MAC address' ' to create a VMKernel for management." Make sure the right to MAC address of the uplink is mentioned.

  And make sure that it is a unique vmk, does not correspond to a vmk existing (vmk0, vmk1, vmk2).

  Once the Port is created, you should be able to configure networking on the DCUI

  Hope it will be useful.