The Thread "thanks motorcycle.
Yes, you read that right.
I must be one of the users apparently little that is happy with my Droid X like this. No glitches or errors I've noticed yet. The integration of the social network was well done as well. Images from the camera with this phone are really good, even for a phone. It's everything I thought I would be with him. I'll patiently wait for Froyo out and enjoy that too.
I thought I'd post this thread, because in this type of industry 'Thank you' is something rare to hear an end user.
PS. for all users who complain about the apps included with the phone. I don't know if you noticed or not, but Need for Speed: Shift can be uninstalled, so at least you have this ability and not stuck with a set of installable demo 100 meg. I've included a screenshot to prove my point. Also, to add to this, that I'm not rooted, screenshot was taken with the Dalvik debugger which is located in the Android SDK.
Tags: Motorola Phones
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About a month ago I posted a question about iMovie and not being able to "share". I solved the problem thanks, so no more emails!
Hi Michael,
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Take care.
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How to manage the threads for TCP communication?
Hello
I have a project to control two separate applications (C++ and LabView) and two of them are implemented as server. Another client program (C++) is used to control applications. Communication between them are implemented using TCP socket. The client program sends the message to start or stop tasks on servers. The client program also sends time (HH) with the message start and end to determine when to start or stop.
Application in C++ (server): Listening to the request for the connection and when gets one, it creates a thread of communication allowing to manage this and listen again to another connection. Communication wire crossing of handles and messages when it receives a start or a stop message, it creates a thread of timer with the received time to trigger a task at the time specified. And after that he expects the client message. So, here, when the thread (communication, timer) is necessary, it is created.
In LabView (server): I tried to create the same as the C++ server. But, in manual of LabView and other discussions of the forum, I got that LabView is multithreaded and it can be done with the help of the loop independent. So, I had to create four loops in a diagram:
1. wait the new connection
2 manage the communication for the already received connection
3. start the timer
4 stop the timer
and they are executed at the beginning of execution and communication between them are managed using local variables. But, 2, 3 and 4th loop can handle only one connection and it can handle another if the current is closed. The C++ application can handle multiple connections by creating the thread when it is necessary, but not at the beginning of the application.
Is there a better way to implement this in LabView?
Is it possible to manage multiple connections and create the diagram node/block (such as a wire) dynamically as C++?
Thank you.
There are several ways to do so in modern LabVIEW and you should probably seek the Finder example for TCP examples. The classic is to transfer the refnum of connecting the listening loop in a communications loop that adds to an array of login credentials and then constantly iterates through this array to make the communication. He works on LabVIEW 4.0 perfectly for me even for applications with basic HTTP communication protocol. But you must make sure that the communication for a connection is not delaying his work for reasons that would delay the handling of other connections too, because they are really of course worked on sequentially. If you encounter an error, the connection ID is closed and removed from the table.
The other is that create you a VI that makes your entire communication and ends on an error or when the order quite. Make this reentrant VI and then launch it through VI server as the instance home, passing the refnum of newly received connection form the listening loop. Then use the method to Run let start and operate as an independent thread.
For all these, you should be able to find an example in the example Finder when searching for TCP.
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How to determine the Thread of execution for PostUIMessage,
Greetings:
I'm trying to develop an application TestStand with two Interfaces (in addition to the sequence editor) user, and I need to be able to view messages from interface user back and forth between two user interfaces.
So far I managed to create a user interface, and I can post messages for the user interface of a TestStand sequence to my user interface. large. I spent the reference Application Manager in the constructor of the UI object.
Now, I want a button on my first UI to cause a user interface message to send to my second UI... The PostUIMessage options I have are Engine.PostUIMessage or Thread.PostUIMessage... in both cases that I need the thread, I don't think I have unless I pass it explicitly in the constructor. Ideally, I would like to pass only a single object in the constructor (to keep things simple).
I tried to create versions of my first UI that pass the engine reference, or reference to the SequenceContext, but I seem to be impossible to extract the info that I need these. For example, the SeqContext, in theory I can get the engine and the Thread, but when I try to get the reference of the AppMgr of engine
TsEngine = seqContext.Engine;
AppMgr = TsEngine.GetInternalOption (InternalOptions.InternalOption_ApplicationManager) (ApplicationMgrClass);I get the following exception:
The instance of the .NET class could not be found.
Impossible to object cast COM type 'System.__ComObject' to the class type 'NationalInstruments.TestStand.Interop.UI.ApplicationMgrClass '. COM components that enter the CLR and do not support IProvideClassInfo or who have not any registered assembly are wound in the __ComObject type. Instances of this type cannot be cast to any other class; However they can be cast to interfaces as long as the underlying COM component supports calls QueryInterface for the IID of the interface.
Source: SidecarLib toWhat I really need to move the app Manager frame of reference and sequence and the thread as separate arguments my constructor, or I missed something that causes the exception above?
Thank you very much
Tom MacLean
It seems I've found the problem.
The code sample that I created on my user interface is from the article "launch of a floating .NET form in TestStand. In this example, the reference of the Application Manager is in a member of the class defined as:
Class AppMgr ApplicationMgr;
If you try to get the referral of Application of the motor as this handler:
AppMgr = seqContext.Engine.GetInternalOption (InternalOptions.InternalOption_ApplicationManager) (ApplicationMgrClass);
It is then the exception mentioned above is generated. If, however, the reference to Application Manager is defined as:
ApplicationMgr AppMgr.
and it is extracted in the context of the sequence as follows:
AppMgr = seqContext.Engine.GetInternalOption (InternalOptions.InternalOption_ApplicationManager) (ApplicationMgr);
everything works as I had planned (without exception).
I hope that it can save someone else some grief.
See you soon,.
Tom MacLean
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the response has been directly on the spot thank you!
My problem was with scams and virus people telling me that my computer was dated and full of infections in the registry after windows up date of the it and the help I got in my email was right! I voted for her too! but I realized my computer is not what it was. It takes forever to bring up some web pages like msn windows live something I think he might be my wireless connection, poor but my comp. said diagnost it or get the files from a cd that I have not have.that is why I posted that other saying question it was slow and I think someone should check there windows? THANK YOU very much Michael ps
Hello
You can be sure that the ball, Kosh, and Steve will be very happy that they were able to help you
the malicious software aspects of your questions.Here's the thread:
BTW, if you need to reach a longer question just click on your name above your Avatar on the right of
any page of thread OR on the top right corner (when Signed-in) of any page of answers that will take you to
your profile.=========================================================================
Please post any questions of performance, as you have in the answers – Windows Forums for your version
Windows. And don't forget to include all the information we need to help us help you.Answers - Windows Forums
http://answers.Microsoft.com/en-us/WindowsHow to ask a question
http://support.Microsoft.com/kb/555375Let's Illustrazione trying to help.
Rob Brown - Microsoft MVP<- profile="" -="" windows="" expert="" -="" consumer="" :="" bicycle="" -="" mark="" twain="" said="" it="">->
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HELLO developers,
ublic class Timer extends Thread { static boolean isMsgSentMode =true; static int timerCount; static int count=0; int i = 10; public void run(){ try{ while(isMsgSentMode){ if(i==-1) { //TODO // Add the code here // implement the operation needed when the counter reaches to 0 // sending the query status command only once if(count==0) { BluetoothSerialPortScreen.queryStatusCmd(); } safeSetLabelText(MsgCenter.SOS_MESSAGE_SEND); isMsgSentMode=true; // when count greater than 2 it will come out of the loop if(count>2) { isMsgSentMode=false; } count ++; //i=10; // resetting it to -1 } else { isMsgSentMode=false; } } else { // for testing purpose if(!(QueryStatusEntity.getmCurrentModeOfOperation()==3)) { System.out.println("Thread is working "+i); safeSetLabelText("SOS Will be send in"+ " "+ i+" "+"seconds"); Thread.sleep(1000); } else { isMsgSentMode=false; } i--; } } } catch(Exception e){ System.out.println("Exception has been occured "+e.getMessage()); } } /** * Used to Modify the sosmessagesendLabelField called from the Thread * * @param text * @return LabelField */ public final void safeSetLabelText( String text) { synchronized (UiApplication.getApplication().getEventLock()) { SosModeScreen._sosmessagesendLabelField.setText(text); // based on the text type the setpadding is being changed if(text.equalsIgnoreCase(MsgCenter.SOS_MESSAGE_SEND)) { SosModeScreen._sosmessagesendLabelField.setPadding(20, 0, 0, SpotConstants.WIDTH_BY_FOUR); } else { SosModeScreen._sosmessagesendLabelField.setPadding(20, 0, 0, SpotConstants.WIDTH_BY_SIX ); } } } /** * For stoping the thread programtically */ public synchronized static void stop() { isMsgSentMode=false; } /** * For starting the thread programtically */ public synchronized static void starts() { isMsgSentMode=true; }
I've set up a thread. that works very well for me, but the problem is that I can't stop this inorder to stop the current thread form execeuting I created a
public synchronized static void stop() { isMsgSentMode=false; }
Timer.stop using (), I call it but is still the thread is running in the background, need help for this
Thank you
sujithRavindran
There is no sure method to end a thread.
usually you put into a Boolean variable that you can change from the outside.
If (! stop)-> stop process set to true and the termination of the thread.
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Hello, is it possible to set the time-out for the thread? Or kill the thread if it runs longer than expected? If so, how? Thank you
"Is it possible to set the time-out for the thread?
Not that I know of.
"Or kill the thread if it runs longer than expected? If so, how? »
Start another Thread or a timer, which gives a reference to the Thread to be killed. When the time expires to check to see if the Thread has finished (isAlive()) and if so try to kill him. How do you kill, this will depend on what he does, you can try Thread.interrupt () but I'm not sure that this will break the connection http for example.
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Impact on the Thread.sleep processor
Hi all
Someone knows what this impact of the Thread.sleep on cpu perfemance BB?
Thank you
UDI
Thread.Sleep simply takes the current thread on the Scheduler to send for a certain period of time.
I guess my best answer is that there no direct impact on the performance CPU - CPU runs all the time, at the same speed than it was before.
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AssertionException poll() blocking call can only be called on the thread of the Service
Hello
When we do the getCache, we get the above error. Need suggestions how to solve this problem.
The requirement:
We have a feature that happens in the coherence, which should do a search on a map. This map is stored in another cache.
When we try to access this card, we get the above error.
The easiest way to resolve this would be to set up a poll thread for your service (put a positive thread count in your operational config or - Dtangosol.coherence.distributed.threads = N) this way that your initial request will be processed within the pool rather than on the thread dedicated services. Even in this case the reentrantly using consistency model is sure that if you access a cache belongs to another service and that you do not create a dependency of service cycles, i.e. A service shouts to service B, which calls to the C service which calls for A service. These cycles of any risk of deadlock, but if you avoid the cycle and use a pool of threads then you should be good.
Otherwise if you can ensure that the other elements of the cache you want to access may reside in the same partition that the main entrance, then you can avoid the communication in the service, and the network important expensive hops and access just the partition co-located entered directly. If for example you are in an EntryProcessor, you can mount the InvocableMap.Entry to a BinaryEntry and then call BinaryEntry.getContext () .getManager ().getBackingMapContext("otherCacheName").getBackignMapEntry (binOtherKey). This approach later is much higher but you will need to ensure that you will only interact with the items in the same partition, i.e. associate things related by using the KeyAssociation interface.
Thank you
Mark
The Oracle coherence
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How to report the thread in the wrong space?
Hello, where can I report that a thread is in the wrong space or subspace?
Is this the correct subspace or do I have to write to any host?
Thanks to advice.
On the wire, use the "report abuse" in the Actions panel and indicate that the thread is in the wrong place (and if you know where to go it would be useful that the moderators cannot know everything).
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Reopening the thread - fusion even people per ID adding another scenario
ORACLE VERSION: Oracle Database 11 g Enterprise Edition Release 11.2.0.2.0 - 64 bit ProductionSame Question is Solved By Frank in Here -- Thank you for helping me
When Testing With real data i came Across another Scenario, which i think the persons should me merged together. i tried ti figure this my self , but this logic seems to be more complex. also sorry for posting this multiple times
/* Formatted on 7/25/2012 8:41:48 AM (QP5 v5.115.810.9015) */ WITH merge_names AS ( /*SELECT 9000 We_pid, 99980000 We_addr_id, 'ROBERT' first_name, 'JOHN' last_name, NULL middle_name, NULL Suffix FROM DUAL UNION ALL SELECT 9001 We_pid, 99980000 We_addr_id, 'ROBERT' first_name, 'JOHN' last_name, NULL middle_name, NULL Suffix FROM DUAL UNION ALL SELECT 9002 We_pid, 99980000 We_addr_id, 'ROBERT' first_name, 'JOHN' last_name, 'H' middle_name, NULL Suffix FROM DUAL UNION ALL SELECT 9003 We_pid, 99980000 We_addr_id, 'ROBERT' first_name, 'JOHN' last_name, 'H' middle_name, NULL Suffix FROM DUAL UNION ALL SELECT 1000 We_pid, 999898989 We_addr_id, 'DONALD' first_name, 'BOATRIGHT' last_name, 'L' middle_name, NULL Suffix FROM DUAL UNION ALL SELECT 1001 We_pid, 999898989 We_addr_id, 'DONALD' first_name, 'BOATRIGHT' last_name, 'LARRY' middle_name, NULL Suffix FROM DUAL UNION ALL SELECT 1002 We_pid, 999898989 We_addr_id, 'DONALD' first_name, 'BOATRIGHT' last_name, NULL middle_name, NULL Suffix FROM DUAL UNION ALL SELECT 33065 WE_PID, 99000000 We_addr_id, 'LUNA' First_name, 'JOSE' last_name, NULL middle_name, NULL suffix FROM DUAL UNION ALL SELECT 8450527 WE_PID_LINK, 99000000 We_addr_id, 'LUNA' First_name, 'JOSE' last_name, 'A' middle_name, NULL suffix FROM DUAL UNION ALL SELECT 373453429 WE_PID_LINK, 99000000 We_addr_id, 'LUNA' First_name, 'JOSE' last_name, NULL middle_name, NULL suffix FROM DUAL UNION ALL SELECT 442303062 WE_PID, 99000000 We_addr_id, 'LUNA' First_name, 'JOSE' last_name, 'S' middle_name, NULL suffix FROM DUAL UNION ALL SELECT 30088775765 WE_PID, 990000878 We_addr_id, 'BILL' last_name, 'RAY' first_name, 'M' middle_name, NULL SUFFIX FROM DUAL UNION ALL SELECT 30088775766 WE_PID, 990000878 We_addr_id, 'RAY' first_name, 'BILL' last_name, NULL middle_name, NULL SUFFIX FROM DUAL UNION ALL SELECT 30088775767 WE_PID, 990000878 We_addr_id, 'RAY' first_name, 'BILL' last_name, 'MAX' middle_name, NULL SUFFIX FROM DUAL UNION ALL SELECT 30088775768 WE_PID, 990000878 We_addr_id, 'RAY' first_name, 'BILL' last_name, 'MICHEL' middle_name, NULL SUffix FROM DUAL UNION ALL SELECT 399998776 WE_PID, 9901111 We_addr_id, 'ELLISON' first_name, 'LAWRANCE' last_name, NULL middle_name, NULL SUFFIX FROM DUAL UNION ALL SELECT 399998777 WE_PID, 9901111 We_addr_id, 'ELLISON' first_name, 'LAWRANCE' last_name, 'J' middle_name, 'JR' SUFFIX FROM DUAL UNION ALL SELECT 399998778 WE_PID, 9901111 We_addr_id, 'ELLISON' first_name, 'LAWRANCE' last_name, 'JAMES' middle_name, 'SR' SUFFIX FROM DUAL UNION ALL SELECT 399998779 WE_PID, 9901111 We_addr_id, 'ELLISON' first_name, 'LAWRANCE' last_name, 'JACK' middle_name, 'JR' SUFFIX FROM DUAL UNION ALL */ SELECT 4498 WE_PID, 77127945 We_addr_id, 'PIGGEE' first_name, 'AARON' last_name, NULL middle_name, NULL SUFFIX FROM DUAL UNION ALL SELECT 4499 WE_PID, 77127945 We_addr_id, 'PIGGEE' first_name, 'AARON' last_name, NULL middle_name, 'JR' SUFFIX FROM DUAL UNION ALL SELECT 4450 WE_PID, 77127945 We_addr_id, 'PIGGEE' first_name, 'AARON' last_name, NULL middle_name, 'JR' SUFFIX FROM DUAL UNION ALL SELECT 4451 WE_PID, 77127945 We_addr_id, 'PIGGEE' first_name, 'AARON' last_name, NULL middle_name, 'JR' SUFFIX FROM DUAL UNION ALL SELECT 250 WE_PID, 77127950 We_addr_id, 'RODNEY' first_name, 'MONTGOMERY' last_name, NULL middle_name, NULL SUFFIX FROM DUAL UNION ALL SELECT 251 WE_PID, 77127950 We_addr_id, 'RODNEY' first_name, 'MONTGOMERY' last_name, NULL middle_name, NULL SUFFIX FROM DUAL UNION ALL SELECT 252 WE_PID, 77127950 We_addr_id, 'RODNEY' first_name, 'MONTGOMERY' last_name, NULL middle_name, 'SR' SUFFIX FROM DUAL UNION ALL SELECT 253 WE_PID, 77127950 We_addr_id, 'RODNEY' first_name, 'MONTGOMERY' last_name, NULL middle_name, 'III' SUFFIX FROM DUAL), got_min_we_pid AS (SELECT b.we_pid, b.we_addr_id, b.last_name, b.first_name, b.middle_name, b.suffix, MIN(b.we_pid) OVER ( PARTITION BY b.first_name, b.last_name, b.middle_name, b.suffix ) AS min_we_pid FROM merge_names b), possible_matches AS ( SELECT CONNECT_BY_ROOT min_we_pid AS min_we_pid, min_we_pid AS leaf_we_pid FROM got_min_we_pid WHERE CONNECT_BY_ISLEAF = 1 START WITH we_pid = min_we_pid CONNECT BY first_name = PRIOR first_name AND we_addr_id = PRIOR we_addr_id AND last_name = PRIOR last_name AND SUBSTR ('x' || middle_name, 1, LENGTH ('x' || PRIOR middle_name)) = 'x' || PRIOR middle_name AND 'x' || middle_name > 'x' || PRIOR middle_name AND 'x' || suffix = 'x' || PRIOR suffix), got_match_cnt AS (SELECT DISTINCT min_we_pid, leaf_we_pid, COUNT (DISTINCT leaf_we_pid) OVER (PARTITION BY min_we_pid) AS match_cnt FROM possible_matches) SELECT DISTINCT we_pid, we_addr_id, first_name, last_name, middle_name, suffix -- ***** CHANGED ***** , MIN (we_pid) OVER (PARTITION BY NVL (p.leaf_we_pid, c.min_we_pid)) AS merge_wepid -- ***** CHANGED ***** FROM GOT_MIN_we_pid c LEFT OUTER JOIN got_match_cnt p ON p.min_we_pid = c.min_we_pid AND p.match_cnt = 1 ORDER BY c.we_pid, c.last_name, c.first_name, c.middle_name;
Published by: new learning on July 25, 2012 05:50o/p required for the person PIGGEE AARON JR and RODNEY MONTGOMERY ALl other Person Mergings Are working Great. WE_PID WE_ADDR_ID FIRST_NAME LAST_NAME MIDDLE_NAME SUFFIX MERGE_WEPID 4450 77127945 PIGGEE AARON JR 4498 4451 77127945 PIGGEE AARON JR 4498 4498 77127945 PIGGEE AARON 4498 4499 77127945 PIGGEE AARON JR 4498 250 77127950 RODNEY MONTGOMERY 250 251 77127950 RODNEY MONTGOMERY 250 252 77127950 RODNEY MONTGOMERY SR 252 253 77127950 RODNEY MONTGOMERY III 253
Published by: new learning on July 25, 2012 06:49
Published by: new learning on July 25, 2012 06:51Hello
This example gets the results you requested on the sample data you posted:
WITH got_min_we_pid AS ( SELECT merge_names.* , MIN (we_pid) OVER ( PARTITION BY first_name , last_name , middle_name , suffix ) AS min_we_pid FROM merge_names ) , possible_matches AS ( SELECT CONNECT_BY_ROOT min_we_pid AS min_we_pid , min_we_pid AS leaf_we_pid FROM got_min_we_pid WHERE CONNECT_BY_ISLEAF = 1 START WITH we_pid = min_we_pid CONNECT BY first_name = PRIOR first_name AND last_name = PRIOR last_name AND SUBSTR ( 'x' || middle_name , 1 , LENGTH ('x' || PRIOR middle_name) ) = 'x' || PRIOR middle_name AND 'x' || middle_name >= 'x' || PRIOR middle_name -- ***** CHANGED ***** AND ( 'x' || suffix = 'x' || PRIOR suffix -- ***** CHANGED ***** OR PRIOR suffix IS NULL -- ***** NEW ***** ) -- ***** NEW ***** AND ( 'x' || middle_name != 'x' || PRIOR middle_name -- ***** NEW ***** OR 'x' || suffix != 'x' || PRIOR suffix -- ***** NEW ***** ) -- ***** NEW ***** ) , got_match_cnt AS ( SELECT DISTINCT min_we_pid , leaf_we_pid , COUNT (DISTINCT leaf_we_pid) OVER (PARTITION BY min_we_pid) AS match_cnt FROM possible_matches ) SELECT we_pid, we_addr_id, first_name, last_name, middle_name, suffix , MIN (we_pid) OVER (PARTITION BY NVL (p.leaf_we_pid, c.min_we_pid)) AS merge_wepid FROM GOT_MIN_we_pid c LEFT OUTER JOIN got_match_cnt p ON p.min_we_pid = c.min_we_pid AND p.match_cnt = 1 ORDER BY c.last_name , c.first_name , c.middle_name ;
It will give the results you want in view of all the data of your table, or data that can be added to your table in the future? It depends on what you want. It is impossible to everything that publish you current data, and it is impossible to display all of the data that you can obtain in the future. The best is you specify exactly what you want. For example:
"I want to group the lines and assign the we_pid lowest in the group like the merge_we_pid for all members of the group. Every row belongs to a group exaclty. The following rules define what a group is:
(a) last_name, first_name, middle_name and suffix identical lines are always in the same group.
(b) the lines with different name or last_name are never in the same group.
(c) two lines with different middle_names and/or suffixes can be in the same group, subject to the following conditions
(c1) One of the lines must be 'more complete' than the other
(c2) If row is "less complete" that line B, then A must not be "less complete" any line C less than B or C is "less complete" than the other, whereby all 3 ranks fall in the same group.
Line A is considered to be "less full" line B if and only if
(1) A middle_name matches the beginning of B middle_name (first name of B can be longer), and
(2) if A suffix is not NULL, then B has the same suffix. »I think that the example above describes what you want now. I guess that a suffix simply cannot be less than a complete suffix; that would deal with "II" as a less complete form of 'III'
What you asked for in your previous thread differs only in the role of suffix. The query I posted yesterday treated suffix such as first and last name: it had to be exactly the same for all rows in the group, and suffix played no role in the condition (c) or the definition of the "complete".
In the above query, if CONNECT BY condition tests a child line is more comprehensive than its parent. In the version I posted today, I changed the CONNECT BY clause to match the new definition of the "complete". Obviously, there are requirement suffix had to change. Yesterday, the B line could be more complete that the line has only if its middle_name took longer; now, they can be the same. But we cannot tolerate a situation where a line is it's own parent: to avoid to connect BY loops, add a condition that the middle_name or the suffix must be different.Published by: Frank Kulash, July 25, 2012 10:07
Added explanation. -
Hello
I read the following sentences in the FAQ:
But I n ' knows where I can find the forum: id, the: the ID of the thread and the message id:{forum:id=123} - Displays link to forum 123 {thread:id=12345} - Displays link to thread 12345 {message:id=1234567} - Displays link to message 1234567 {user:id=1234} - Displays link to user 1234 (numeric ID)
Thanks for your help
hqt200475hqt200475 wrote:
HelloI read the following sentences in the FAQ:
{forum:id=123} - Displays link to forum 123 {thread:id=12345} - Displays link to thread 12345 {message:id=1234567} - Displays link to message 1234567 {user:id=1234} - Displays link to user 1234 (numeric ID)
But I n ' knows where I can find the forum: id, the: the ID of the thread and the message id:
Thanks for your help
hqt200475
If you move your pointer over "reply" and "Reply to thread" link, you will see a URL like:
How can I find the Thread ID
If you copy one spent in your messages as (it is very sensitive to the case, must be lower}):
{thread:id=2234623}
Then you get a link as follows: -.
{: identifier of the thread = 2234623}
In the same way but on a forum link gives the id of the forum
... Hope it makes sense:
PS: Note that you reply to this message, using the icon toolbar of the quotes to get my answer... and alternating between text and tabs Preview are also useful.
Published by: bigdelboy on June 7, 2011 23:18: the id of the forum for this forum is determinable under the community your comments and Suggestions (Do Not Post Product - Related Questions here hyperlink)
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Hi all
Had a doubt while implementing threads, so I thought to do it erased before that I make progress. I have a method from where the new thread is called, and in the next line, I return statement.
Method() {}
Thread call ();
return the declaration;
}
What happens here? I want to say is that the parent process ends before the child process?
Thank you
Simiuser11138361 wrote:
I have exactly the same meaningint foo() {}
Runnable r = new MyRunnable();
Thread t = new Thread (r);
t.Start ();
Return 1;
}My question was if the child process runs then how will end the process (Px) parent?
There is no child process. You create a thread, not a process.
This point aside, I do not understand your question. The current thread and the new thread are totally independent of each other. Why wait we can't finish while the other is still ongoing?
Note also that the parent thread is NOT the same as this method foo(). The thread doesn't necessarily stop when the foo() method only. It can, however, and I don't know why you would think otherwise.
EDIT: My guess is that what you're really confused about is, ' how can end when foo() method one of its 'no' (in other words, the new thread) is running? The answer is that all its steps are made, even if the other thread is still ongoing.
stage of foo () of appeal t.start () is finished. This does not mean that the new thread has finished, however. The start() method says: "create a new, + independent + execution thread and turn it on." As soon as he does that, start() is done, and now the new thread is allowed to run (or run) regardless of the current thread.
Imagine that I have a list of chores: taking out the trash. Washing dishes; Show empty. This list is the foo() method. You are a new Thread object. After I wash the dishes, I tell you ' go to the store and buy some apples, milk, eggs, chicken and bread. " Let you do your work, and as soon as I told what to do, I continue with my duties. We do our work independently from each other, and I can't finish the chore on my list without waiting for you to come back on the store.
Edited by: jverd March 21, 2011 11:27
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If you ask the question and then choose a solution, the thread will be closed or still can you ask more details?
(sometimes, someone answers my question, and I want to mark it as the solution and am not yet quite ready for the thread be closed...)If you still experience this issue, you can return to this thread.
But, you must clear the flag solved . -
that fact view Reader in firefox? I can't wait to hear the Forum thank you.
that fact view Reader in firefox? I can't wait to hear the Forum thank you.
Hello
You can read all about Firefox reader discovers in this article.
I hope that this helps, but please come back here if you have any questions.
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Western Digital My Book Home Edition WD5000HICS-00 500 GB External Hard Drive
I am on a PC running Microsoft Windows XP and have had the MYBOOK for at least 2 years and have had no problems so far. We moved ouir PC hook-OUs from one room in our House to another and now when I turn on my system it's not fix the my BOOK device.
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Hello I'm looking for laptops with built-in WWAN. However, I don't see this option when I'm shopping at the official site. In the wireless section, the only choice is related to the Wifi / bluetooth, WWLAN No. Is it possible to eliminate all the Thi
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OEM Windows 7 installation on another computer after the first dead
I recently bought a laptop computer without an operating system, and the seller I sold separately an OEM Windows 7 Professional version. I installed and activated this version of Windows. I must return this laptop because I was not satisfied with it.
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Yesterday (June 10) to day LR and Psalm this morning can import photos into LR. Spin the ball of death (iMac - latest OS) immediately by clicking < import >. Uninstalled and reinstalled LR; same question. Would appreciate any suggestions.