Timestamp format must be yyyy-mm-dd hh: mm: [.fffffffff]

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• SQL * Loader: load data in the format MM/DD/YYYY HH: mi: SS PM

  Please advice how to load data in the format MM/DD/YYYY HH: mi: SS PM in an Oracle Table using SQL * Loader.
  
  -Should what format I give in the control file?
  -What would be the type of column to create the table to load data.
  
  Examples of data below;
  
  MM/DD/YYYY HH: MI: SS PM
  
  14:40:20 09/12/2012
  29/11/2011 11:23:12
  
  Thanks in advance
  Avinash

  Astr0 wrote:
  Hello Srini,

  I tried with the date of creation as DATE data type, but I had an error like

  ORA-01830: date format picture ends before converting entire input string
  CREATION_DATE               "TO_CHAR(TO_DATE(:CREATION_DATE,'MM/DD/YYYY HH:MI:SS AM'),'DD-MON-YYYY HH:MI:SS AM')",
  

  Try

  CREATION_DATE "to_Date(:CREATION_DATE,'yyyy-mm-dd hh:mi:ss AM')",
  

  Does that help? It is charging correctly in the timestamp column

  REDA

• Convert date format timestamp format

  Hello, I have the following code in * impl.java in the doDML method. I'm getting "invalid column type" at run time, but when I click on insert. I think that the problem is because I do not convert the timestamp format format date correctly. Any help please?

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  / * Some code here * /.

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  java.sql.Date d1 = new java.sql.Date (this.getRbcDtTo () .getTime ());

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  CS1. SetString(4,"RBCS");

  CS1. SetString (5, this.getRbcCode ());

  CS1.setInt (6, getRbcCounter ());

  CS1. ExecuteUpdate();

  Boolean ValeurRet = cs1.getBoolean (1);

  If (retvalue)

  {

  super.doDML (operation, e);

  }

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  System.out.println ("no Commit!");

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  } catch (SQLException f) {}

  throw new Aexception.getLocalizedMessage (f);

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  You did not created wrapper fucntion.

  Take a look at:

  Troubleshooting

  Use the same principle for the registered function...

• We had to find the date in the format "DD-MM-YYYY" and "DD/MM/YYYY '.

  Hello world
  
  I need to find the hire_date in the format "dd-mm-yyyy" and "dd/mm/yyyy '. This shows also some errors, I can't found. pls help to solve this problem...

  Hello

  Christine Schnittker says:
  ... It works as well:

  SQL> select to_date('22-02-2012','dd/mm/yyyy') dt from dual;
  
  DT
  ----------
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  (Does anyone know anything that actually says?)

  The Manual of the SQL language , after listing the format items allowed in TO_DATE, says the following:

  Any nonalphanumeric character is allowed to match punctuation characters in the format model. For example, the following statement returns no error:
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  TO_CH
  -----
  02/07

• convert date format dd.mm.yyyy jj.mm.AA

  Hi all
  
  My need is to convert date format dd.mm.yyyy jj.mm.AA. All years are 1999 or less. My first assumption is to use the combination of substr with concatination of '19', but maybe someone can suggest another decision.
  

  select '18.03.97' as dt from dual

  You can do this:

  SQL> select to_char(to_date('18.03.97','dd.mm.rrrr'),'dd.mm.rrrr') Result from dual;
  
  RESULT
  ----------
  18.03.1997
  

• How to get the date in the format dd/mm/yyyy?

  Hello
  for this query:
  > select to_date (to_char (sysdate), ' dd/mm/yyyy') of double;
  I wanted to get a date in the format dd/mm/yyyy, but this query is not in the right format to date.
  How to get it?

  Why you are converting a date (it's a date in your table, right) tank and back to a date. When you want to display a date a certain way, you use to_char and specify the mask format to display the date as to_char (sysdate, 'dd-mm-yyyy'). Internally, dates are stored as bytes 7, you use to_char only for display purposes.

• How to convert JAVA. SQL. Date the DATE in the format DD/MM/YYYY to DD/MM/YYYY

  I use an informix database that accepts the value of date as a DATE format...
  the other part of my app takes date from the field in the format DD/MM/YYYY... so I have to convert my java.sql.date in marker AAAA/MM/JJ JJ/MM/AAAA marker of the same type before inserting into db...
  but by using the parse method in SimpleDateFormat class can get the result format java.util.date...
  and also using method format may result in the conversion of strings...

  public class Dbop {
      static final java.text.SimpleDateFormat fmt = new java.text.SimpleDateFormat("dd/MM/yyyy");
      public static void main(String[] args) throws Exception {
          java.util.Date ud = fmt.parse("31/12/2010");
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• How do I get the date in the format dd/mm/yyyy hh: mm IS

  Hi all
  I want to display the sysdate in the format mm/dd/yyyy hh: mm IS. Please help if anyone knows.

  select to_char(systimestamp at time zone 'EST','mm/dd/yyyy hh:mi tzr') from dual
  

  do you think that... ??

  Ravi Kumar

• What is the best way to obtain a string that represents a date in the format mm/dd/yyyy

  What is the best way to obtain a string that represents a date in the format mm/dd/yyyy
  
  It would be good if I could generate this string using the static methods of a class.
  
  
  
  
  
  
  

  You can use date formatter:

  Import mx.formatters.DateFormatter;
  ...

  var trainer: DateFormatter = new DateFormatter();
  formatter.formatString = "YYYY/MM/DD JJ:NN:SS;
  var today: Date = new Date();
  trace (formatter.format (now));

• Timestamp format

  How can I convert under query timestamp? Is the difficult part a 't' in the string.
  

  SELECT '20080101T07:32:39.785', to_timestamp(SUBSTR('20080101T07:32:39.785',0,17),'YYYY-MM-DD HH24:MI:SS,FF') FROM DUAL; 

  Maybe not the best, but here's a way... first step is make your format string to match your string input and using the right index for SUBSTR. Second step is to detach the T via REPLACE()

  SELECT '20080101T07:32:39.785',
  to_timestamp(SUBSTR(replace('20080101T07:32:39.785','T',''),1,16),'YYYYMMDDHH24:MI:SS,FF')
  FROM DUAL;
  
  '20080101T07:32:39.785'          TO_TIMESTAMP(SUBSTR(REPLACE('2
  -------------------------------- -------------------------
  20080101T07:32:39.785            01-JAN-2008 07.32.39.000000000 AM 
  

• Change the timestamp format in mysql

  I've created a field date_posted in Recordset1 in my database named my_db now by default is set to the current timestamp, now the problem is the value that is generated is in this format

  yyyy-mm-dd hh: mm:

  but I want it to appear in this format it

  month date; year to hh: mm am/pm

  lets make it simple by this example, say that the month is June date is 15 and the time is 10:24

  the default format is like this

  2009-06-15 10:24

  but I want it to be like that

  June 15, 2009 at 10:24

  Please help and thanks in advance.

  Use the function DATE_FORMAT()) MySQL in your SQL query and assign the result to an alias.

  SELECT col1, col2, DATE_FORMAT(datecol, '%M %D, %Y at %k:%i %p') AS formatted_date
  FROM mytable
  

  "datecol" is the name of the column that is stored in your date. The date formatting will be available in your recordset as formatted_date.

  Moreover, this question was asked repeatedly in this forum. You should be able to find the answer using the search function.

• MySQL timestamp formatting errors

  I continue to have strange formatting errors when pulling data from a MySQL database.  I'm having now is with time values.

  

  The screenshot shows that the error is generated in the variant to Data.vi the real time stored in the database is from 08:30, but the conversion of timestamp, I get 8:29:59.999 unfortunately, there doesn't seem to be an easy way to 'around' this value to what I want either.

  I might go back to output string, because this particular error does not appear to spread in a chain.  But that mess with the rest of my application.  Return to the output chain cancels a couple of working days and leaves me with the problem of having to convert the string 'time' again in timestamp that LabVIEW can understand.

  The really weird thing is that 12:30 comes as 12:30 very well.  I don't know why that would be.  Any ideas?

  You can do this with the format string "% I: % h: %s %p %<%m/%d/%Y > T '

  

• convert Date format MMM DD YYYY to DD/MMMM yyyy

  Hello

  I'm in the studio EN 11.1.2.1... We have an obligation to display the date in the format yyyy MMMM dd is lets say 10 January 2015 should display as 10 January 2015

  Members exist in Essbase outline: creation Date

  The Member is used in the grid and the value of the cell is displayed in a block of text as < < GetCell("Grid1",1,A,1) > >

  I don't see the preference option to set as DD/MMMM YYYY format that is available for System Date function < < Date (jj/aaaa "MMMM") > >

  
  

  I also tried with true measures typed and activate the date format, but it does not work in EN report and it seems that the preferred default setting takes precedence.
  

  

  any suggestion will help...

  Thank you

  KP

  It resolved, post the answer might help someone in the future...

  good to know that the file-> preferably in the workspace can be changed... DD MMMM YYYY gives me the date to January 10, 2015 according to my expectations.

  I changed the Date in the file format-> preference for the financial report

• How to prevent the Automatic Conversion of TIMESTAMP Format column (0) WITH ZONE VARCHAR2

  Hello

  I created a view of my table and columns with the date format is automatically converted to varchar type...

  How can I avoid this?

  Create view V_T2 as

  Select

  MAX (DECODE (RESULT_TYPE, THE FROM ', DECODE (BACKUP_LEVEL_ID, 'F', LAST_START, NULL), NULL)) LAST_SUCCESS_FULL_START,.

  MAX LAST_SUCCESS_INC_START (DECODE (RESULT_TYPE,' TO DECODE (BACKUP_LEVEL_ID, 'F', NULL, LAST_START), NULL))

  of backup_log;

  the first 'LAST_SUCCESS_FULL_START' column format remains TIMESTAMP (0) WITH ZONE SCHEDULE, but the other changes to VARCHAR.

  the LAST_START column in my table in the source format is also TIMESTAMP (0) WITH ZONE SCHEDULE.

  Thank you for helping me.

  user649075 wrote:

  Create view V_T2 as

  Select

  MAX (DECODE (RESULT_TYPE, THE FROM ', DECODE (BACKUP_LEVEL_ID, 'F', LAST_START, NULL), NULL)) LAST_SUCCESS_FULL_START,.

  MAX LAST_SUCCESS_INC_START (DECODE (RESULT_TYPE,' TO DECODE (BACKUP_LEVEL_ID, 'F', NULL, LAST_START), NULL))

  of backup_log;

  The NULL value is treated as a VARCHAR2 since she does not have a real data type.

  Try to CAST as the appropriate data type.

  cast( null as timestamp(0) with time zone)
  

  MK

• Convert it to the format DD-MON-YYYY/MM/DD/YYYY

  I have an input variable date L_DATE as 11-Aug-2013(DD-MON-YYYY).
  In my home, I am to convert the date in MM/DD/YYYY format.

  The logic that I used the same thing in my stored Proc - COMPARE2 is:
  R_DATE: = to_char (to_date(L_DATE,'DD-MON-YYYY'), ' MM/DD/YYYY');

  But this is the error I get when operating the SP:
  ORA-01843: not one month valid
  ORA-06512: at "COMPARE2", line 51
  ORA-06512: at line 2

  Can anyone suggest how to fix this?

  Hello

  Apparently, you have an invalid value to l_date, such as 21-2013-Aug'.  Correcct of entry and the error occur.

  You may have good reasons to need to accept the date information in a VARCHAR2 column, but you have every reason to keep the date information in a VARCHAR2 column?  Why not let r_date a date?