To find the child sheet most to the hierarchical query

Similar Questions

• How to convert the hierarchical query of SQL Server (CTE) to Oracle?

  How to convert the hierarchical query of SQL Server (CTE) to Oracle?
  
  WITH cte (col1, col2) AS
  (
  SELECT col1, col2
  FROM dbo. [tb1]
  WHERE col1 = 12
  UNION ALL
  SELECT c.col1, c.col2
  FROM dbo. [tb1] AS c INNER JOIN cte AS p ON c.col2 = p.col1
  )
  DELETE one
  FROM dbo. [tb1] AS an INNER JOIN b cte
  ON a.col1 = b.col1

  Hello
  Something like this maybe:

  DELETE FROM dbo.tb1 a
   WHERE EXISTS (
    SELECT 1
      FROM dbo.tb1 b
    WHERE a.co11 = b.col1
        AND a.col2 = b.col2
     START WITH b.col1 = 12
    CONNECT BY b.col2 = PRIOR b.col1)
  

  Although you need to do here is to check that CONNECT it BY SELECT, returns records you wait first, then the DELETION should work too.

• How to find the sql query

  four months back someone updated my table of billing through sql developer.
  
  How can I find the details of the request or the original data.
  
  now the problem is that we rebooted the server, if it's not rest with time stamp.
  
  log mode is Archieve record only.
  Please help me

  I don't know why you're getting this error, I tried and it works:

  SQL> exec dbms_logmnr.add_logfile( logfilename=> 'C:\oracle\product\11.2.0\dbhome_1\RDBMS\ARC0000000736_0765299251.0001', options=> dbms_logmnr.new);
  
  PL/SQL procedure successfully completed.
  
  SQL> EXECUTE DBMS_LOGMNR.START_LOGMNR(OPTIONS => DBMS_LOGMNR.DICT_FROM_ONLINE_CATALOG);
  
  PL/SQL procedure successfully completed.
  
  SQL> exec dbms_logmnr.start_logmnr
  
  PL/SQL procedure successfully completed.
  
  SQL> select seg_owner,seg_name,sql_redo,sql_undo from v$logmnr_contents;
  
  .....
  
  35 rows selected.
  
  SQL> exec dbms_logmnr.end_logmnr
  
  PL/SQL procedure successfully completed.
  

  @Boris - you don't have to have an additional connection to the database. The thing is that if you don't have additional logging, Oracle will give you only the ROWID of the records and if it is not the same database or something has changed (as "alter table... move"), ROWID is not relevant. If you enable additional logging, you will get more information on the line (like the other columns or PK) which will help you a lot to identify RELEVANT changes. As I said, it is not mandatory, but as you say, if you want extra logging, it must be turned on BEFORE the changes in the database.

  Hope that's clear,
  Liron

• Find the sql query in statspack report

  Salvation;
  I have 11.5.10.2 and db version 9iR2... I took a statspack report, and I should find a sql query... But admin, is kill session and I can't see complite sorted SQL query by gets for DB...
  
  so the question is find this query which is kiiled by admin?
  
  Thank you

  Hello

  Its bad news to can not find this sql... So normally it istn killed by admin, I could find it from stats$ sql_summary or v$ sql_text?

  It is possible.

  Note: 153507.1 - Applications Oracle StatsPack
  https://metalink2.Oracle.com/MetaLink/PLSQL/ml2_documents.showDocument?p_database_id=not&P_ID=153507.1

  And another question... If I have a sql printing is eating my cpu or my server resource, how do I find this sql? Under what title I can find in the statspack report

  Refer to:

  Note: 232443.1 - how to identify the resource intensive SQL for Tuning
  https://metalink2.Oracle.com/MetaLink/PLSQL/ml2_documents.showDocument?p_database_id=not&P_ID=232443.1

  Kind regards
  Hussein

• Find the next query only job n

  Hello
  
  I need single query return the next workday after n days go on a date.
  Working day is every day (too much vacation) with the exception of satudarday and Sunday
  
  
  I found a few working days of request County betweeen two dates, but I can't
  to create a single query (without use of function) to add n working days, for example:
  
  Today is 18/04/2013, I would like to add 5 business days then
  
  the next working day is 25/04/2013
  
  If add 8 working days will be 30/04/2013
  
  How can he do?
  
  With the help of 9.2.08

  Something like...

  SQL> with t as
    2  (
    3  select to_date('18042013','ddmmyyyy') dt,
    4      8 no_of_days
    5  from dual
    6  ), t2 as
    7  (
    8  select dt,
    9     case to_char(dt,'fmday')
   10       when 'monday' then 4
   11       when 'tuesday' then 3
   12       when 'wednesday' then 2
   13       when 'thursday' then 1
   14       when 'friday' then 0
   15       when 'saturday' then -1
   16       when 'sunday' then -2
   17     end dif,no_of_days
   18  from t
   19  )
   20  select dt,no_of_days,
   21     case when no_of_days <= dif then dt+no_of_days
   22         else dt+dif+(no_of_days-greatest(dif,0))+
   23             (ceil((no_of_days-greatest(dif,0))/5)*2)
   24     end next_dt
   25  from t2;
  
  DT        NO_OF_DAYS NEXT_DT
  --------- ---------- ---------
  18-APR-13          8 30-APR-13
  

  Published by: JAC on April 18, 2013 19:17
  Not tested... It will give you a starting point, if you do not want to row generation...

• How to find the sql query by using the hash value

  Hello
  
  DBVERSION: 9.2.0.8
  
  I generated the statspack report and I want to see total request and I hash_value here.
  
  in v$ sql can't see all querys... .pls suggest me other ways...
  
  Thank you
  Srini...

  Have you seen Peter's response? There is no installation other than that would be to store the history of the IMO. Another reason that you must pass to 10g or 11g better, now.

  Aman...

• How to find the sql query generated by BI Publisher

  I'm looking for the physical sql query generated by BEEP when I send parameters as part of the data model.
  
  Of course, this can be noted in newspapers...
  
  Can anyone tell me the location of newspapers?
  
  Thanks in advance

  Have a look here http://gerardnico.com/wiki/dat/bip/log
  I explain a bit how you can get the newspaper.

  See you soon
  Nico

• Identify the hierarchical query paths

  Hi all
  
  11 GR 2 DB
  
  

  create table test_h(parent varchar2(1),child varchar2(1));
  
  insert into test_h values(null,'A');
  insert into test_h values('A','B');
  insert into test_h values('B','C');
  insert into test_h values('C','D');
  insert into test_h values('B','E');
  insert into test_h values('E','F');
  insert into test_h values('','1');
  insert into test_h values('1','2');
  insert into test_h values('2','3');
  commit;
  
  SQL> select *
    2  from test_h;
  
  P C
  - -
    A
  A B
  B C
  C D
  B E
  E F
    1
  1 2
  2 3
  
  9 rows selected.
  
  SQL> select connect_by_root child root_val,child,level lvl
    2  from test_h
    3  start with parent is null
    4  connect by prior child = parent;
  
  R C        LVL
  - - ----------
  1 1          1
  1 2          2
  1 3          3
  A A          1
  A B          2
  A C          3
  A D          4
  A E          3
  A F          4
  
  9 rows selected.
  
  Expected output: An identifier for each different path
  
  R C        LVL  PATH
  - - ----------  ----
  1 1          1  PATH1
  1 2          2  PATH1  
  1 3          3  PATH1
  A A          1  PATH2
  A B          2  PATH2
  A C          3  PATH2
  A D          4  PATH2
  A E          3  PATH3
  A F          4  PATH3

  Thanks in advance

  One-way ticket (not tested... Based on the fact that hierarchical queries will produce output orderly)

  SQL> with relation as
    2  (
    3   select connect_by_root child root_val,child,level lvl,rownum rn
    4   from test_h
    5   start with parent is null
    6   connect by prior child = parent
    7  ),
    8  flag as
    9  (
   10   select root_val,child,lvl,rn,
   11          case when lvl = lag(lvl) over(order by rn)+1
   12             then 0
   13              else 1
   14          end flg
   15   from relation
   16  )
   17  select root_val,child,lvl,
   18         'PATH'||sum(flg) over(order by rn) path
   19  from flag;
  
  R C        LVL PATH
  - - ---------- --------------------------------------------------
  1 1          1 PATH1
  1 2          2 PATH1
  1 3          3 PATH1
  A A          1 PATH2
  A B          2 PATH2
  A C          3 PATH2
  A D          4 PATH2
  A E          3 PATH3
  A F          4 PATH3
  
  9 rows selected.
  

• result of the hierarchical query in xml format

  Pls find below the example script table and the desired output format. Output XML must keep the information of hierarchy that is the requirement. Also is it possible to do it in single sql.
  Thank you.
  CREATE TABLE MAIN
  (
  IDENTIFICATION NUMBER,
  NAME VARCHAR2 (20 BYTE)
  );
  
  INSERT INTO THE HAND (ID, NAME) VALUES)
  1, "OS");
  INSERT INTO THE HAND (ID, NAME) VALUES)
  2, 'Windows');
  INSERT INTO THE HAND (ID, NAME) VALUES)
  3, 'BACK');
  INSERT INTO THE HAND (ID, NAME) VALUES)
  4, "1.x");
  INSERT INTO THE HAND (ID, NAME) VALUES)
  5, "1.1.x");
  INSERT INTO THE HAND (ID, NAME) VALUES)
  7, "1.1.1.1");
  INSERT INTO THE HAND (ID, NAME) VALUES)
  8, ' (1.2');
  INSERT INTO THE HAND (ID, NAME) VALUES)
  9, '2.x');
  INSERT INTO THE HAND (ID, NAME) VALUES)
  10, ' (2.1');
  INSERT INTO THE HAND (ID, NAME) VALUES)
  11, "2.2");
  INSERT INTO THE HAND (ID, NAME) VALUES)
  12, ' 2.2.1');
  INSERT INTO THE HAND (ID, NAME) VALUES)
  13, ' 2.2.2');
  COMMIT;
  
  CREATE TABLE RELA
  (
  NUMBER OF REL_ID
  IDENTIFICATION NUMBER,
  NUMBER OF PARENT_REL_ID
  );
  
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  1, 1, NULL);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  2, 2, 1);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  3, 4, 2);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  4, 5, 3);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  5, 7, 4);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  6, 8, 4);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  7, 9, 2);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  8, 10, 7);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  12, 7, 11);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  14, 9, 9);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  15, 10, 14);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  9, 3, 1);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  10, 4, 9);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  11, 5, 10);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  16, 11, 14);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  13, 8, 10);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  17, 12, 16);
  INSERT INTO RELA (REL_ID, ID, PARENT_REL_ID) VALUES)
  18, 13, 16);
  COMMIT;
  
  Example query
  Select rel_id, level, lpad (' ', 5 * level) | name,
  XmlElement ("rel_id", XMLAttributes (name as "name", rel_id as "rel_id")) as val
  principal, rela
  where main.id = rela.id
  Start with parent_rel_id is null
  Connect prior rel_id = parent_rel_id;
  
  Required xml output
  Required xml output
  
  < 1 name = "OS" >
  < name 2 = "Windows" >
  < 3 name = "1.x" 3 > ""
  < name 4 = "1.1.x" >
  < name 5 = "1.1.1.1" > < / 5 >
  < name 6 = "1.2" > < / 6 >
  < / 4 >
  < / 3 >
  < name = "" 2.x 7 ">"
  < name 8 = "2.1" > < / 8 >
  < / 7 >
  < / 2 >
  < name 9 'BACK' = >
  < name = "2.x 14" > "
  < name 15 = "2.1" > < / 15 >
  < name 16 = "2.2" >
  < name 17 = '2.2.1' > < / 17 >
  < name 18 = '2.2.2' > < / 18 >
  < / 16 >
  < / 14 >
  < 10 name = "1.x" > "
  < name 11 = "1.1.x" >
  < name 12 = "1.1.1.1" > < / 12 >
  < / 11 >
  < name 13 = "1.2" >
  < / 13 >
  < / 10 >
  < / 9 >
  < 1 >
  
  Published by: delights on September 18, 2009 16:47
  
  Published by: delights Sep 19, 2009 09:53

  No string function helps eliminate r because the xml output is great (in a real scenario) which gives "buffer too small" error.

  Try sth like

  SQL>select replace(x.column_value.getclobval(), 'XXX') xml
    2    from xmltable ('.' passing dbms_xmlgen.getxmltype (dbms_xmlgen.
    3                   newcontextfromhierarchy (
    4                   'select level, xmlelement (evalname ''XXX'' || rel_id, xmlattributes(name "name")) name
    5        from main, rela
    6       where main.id = rela.id
    7  start with parent_rel_id is null
    8  connect by prior rel_id = parent_rel_id'
    9                   ))) x
   10  /
  
  XML
  --------------------------------------------------------------------------------
  
  <1 name="OS">
    <2 name="Windows">
      <3 name="1.x">
        <4 name="1.1.x">
          <5 name="1.1.1.1"/>
          <6 name="1.2"/>
        
      
      <7 name="2.x">
        <8 name="2.1"/>
      
    
    <9 name="DOS">
      <10 name="1.x">
        <11 name="1.1.x">
          <12 name="1.1.1.1"/>
        
        <13 name="1.2"/>
      
      <14 name="2.x">
        <15 name="2.1"/>
        <16 name="2.2">
          <17 name="2.2.1"/>
          <18 name="2.2.2"/>
        
      
    
  
  
  SQL>
  

  Newcontextfromhierarchy is not a documented feature do not know if it will issue in releated support this in production code.

  Oracle's recommeds to use newcontextfromhierarchy in Metalink Note 882887.1 ;)

• To find the Top most parent SQL

  How to find the top most parent SQL. I want to avoid the hierarchical query that shows a high cost to run. Please suggest alternative options to find the parent

  Maybe (when having multiple hierarchy trees) to be adapted to your needs

  Select empno, I

  from (select empno, I

  WCP

  where empno = 7876

  model

  hierarchy of reference on (select employee empno,

  Manager Mgr

  WCP

  )

  dimension (employee)

  measures (Manager)

  main main_model

  size of (0 I)

  measures (empno)

  rules iterate (100) until (empno [iteration_number + 1] is null)

  (

  EmpNo [iteration_number + 1] = hierarchy.manager [empno [iteration_number]]

  )

  )

  where empno is not null

  order by I desc

  EMPNO	I
  7839	3
  7566	2
  7788	1
  7876	0

  Concerning

  Etbin

• Where to find the request resolved, sent to the database?

  Version 4.1.1.00.23

  Hello

  Where and how can I find the actual query that is sent to the database?  I enabled debugging in the Dev toolbar, but I still don't see where is the query that is sent to the database? I'm hoping to see a view with the elements of page not resolved not what's actually in the page.

  I have a query on a collection and I get an error "command not properly ended SQL" and I do not see why it is not "properly completed".

  Hope this is clear.

  Let me know if not.

  Thank you

  Joe

  Mike,

  I got it to work!

  In the query for the Collection, I went back to using the function replace to replace the colon with a comma and where clause of the query for the page I used the get_list function.

  So in the Collection query, she went from:

  AND (tbs_team_id IN (SELECT tbs_team_id FROM tbs_forecast_year get_list('|| :F189_TEAM_ID ||')) OR 0 IN (SELECT tbs_team_id FROM tbs_forecast_year get_list('|| :F189_TEAM_ID ||')))
  

  To do this:

  AND (tbs_team_id IN ('||replace(:F189_TEAM_ID,':', ',')||') OR 0 IN ('||replace(:F189_TEAM_ID,':', ',')||'))
  

  And in the query to create the page, I put this:

  AND (c002 IN (SELECT * FROM TABLE(get_list(:P11_TEAM))) OR 0 IN (SELECT * FROM TABLE(get_list(:P11_TEAM))))
  

  And fixed it.

  Thanks Tony and Ingenio VERY much for your help!

  Thank you

  Joe

• generations of months using the sql query

  Hello

  Based on the input of date parameter, I need display every month in the current year and last year.

  For example, suppose that my setting date is December 5, 14 ', I need the output below.

  JANUARY

  FEBRUARY

  MARCH

  APRIL

  MAY

  JUNE

  JULY

  AUGUST

  SEPTEMBER

  OCTOBER

  NOVEMBER

  DECEMBER

  JANUARY

  FEBRUARY

  MARCH

  APRIL

  PEUT

  Until the month of May and the month last year. I came with the request. Please find the following query.

  Select to_char (add_months (trunc(sysdate,'year'), level-1), 'MONTH') mth

  of the double

  connect by level < = 12

  Union of all the

  Select to_char (to_date (ddate, 'MM'), 'MONTH') month

  (select 1 + rownum - 1 ddate

  from user_objects

  where (1 + rownum - 1) < = to_number (to_char (to_date ('12-05-14', ' dd-mm-yy'), 'mm')));

  But I don't want to use the data user_objects dictionary. Can you please guide how to achieve this output, or can u give me some other request too if possible.

  Thank you

  Siva

  Try the below

  SELECT TO_CHAR (ADD_MONTHS (ADD_MONTHS (TRUNC (TO_DATE(:date1,'DD-MM-YY'), 'MM'),

  ((- MONTHS_BETWEEN (trunc (to_date(:date1,'DD-mm-YY'), 'MM'), trunc (to_date(:date1,'DD-mm-YY'), 'YY')) + 12)).

  (LEVEL-1))

  , 'MONTHS '.

  'NLS_DATE_LANGUAGE = ENGLISH') FROM dual months_between

  CONNECT BY LEVEL<=>

• Need to rotate the sub query using 11 g

  Hello
  
  Please find the below query
  
  SELECT AGING_BUCKET_ID, DAYS_START, DAYS_TO, AR_AGING_BUCKET_LINES TYPE
  WHERE AGING_BUCKET_ID = 3
  
  It displays the data as below
  
  AGING_BUCKET_ID DAYS_START DAYS_TO TYPE
  
  3-9999 0 CURRENT
  3 1 30 LAST
  3 31 60 LAST
  3 61 90 LAST
  3 91 9999999 PAST
  
  
  I tried to rotate the data, tried to make use of the PIVOT of the 11 g used the following query function
  
  WITH AGBUCK AS
  (
  SELECT AGING_BUCKET_ID, DAYS_START, DAYS_TO, AR_AGING_BUCKET_LINES TYPE
  WHERE AGING_BUCKET_ID = 3
  ) SELECT * FROM AGBUCK
  PIVOT)
  DAYS_START s1, s2 DAYS_TO, type
  FOR AGING_BUCKET_ID
  (3)
  );
  
  finished in the msg below:-ora-56902: wait for the aggregate within the operation of pivot function
  
  can you please help me to fix it.
  
  Concerning
  Yram

  Hi, Yram,

  Whenever you have a problem, after a few sample data and outcomes from these data.
  Sorry, I can't make a good guess at what you want, and I'm not an Oracle 11 database now to test. I think you want something like this:

  WITH      AGBUCK      AS
  (
       SELECT      AGING_BUCKET_ID
       ,     DAYS_START
       ,     DAYS_TO || TYPE      AS label
       FROM      AR_AGING_BUCKET_LINES
       WHERE      AGING_BUCKET_ID     = 3
  )
  SELECT     *
  FROM     agbuck
  PIVOT     (     MIN (days_start)
       FOR     label
       IN     (     '0 CURRENT'     AS current_0
            ,     '30 PAST'     AS past_30
            ,     '60 PAST'     AS past_60
            ,     '90 PAST'     AS past_90
            ,     '9999999 PAST'     AS past_9999999
            )
       )
  ;
  

  The first thing inside the parentheses after the PIVOT keyword must be an aggregate function. If there is a one-to-one correspondence between the lines in the "input" table and cells in the output, so no matter if you use the MIN or MAX (or, in the case of numbers, AVG or SUM).

• hierarchical query of VO in the ofa page

  Hello

  I try to use the hierarchical query in VO for the display of all levels of supervisors for employee and want to display in populist:

  This is the query

  REPLACE SELECT distinct (mgx.full_name, "',' ') supervisor_full_name;

  XPP. Employee_number

  OF per_assignments_x pax,.

  per_people_x ppx,

  per_people_x mgx,

  per_positions pp,

  per_jobs pj,

  per_position_definitions ppd

  WHERE ppx.person_id = pax.person_id

  AND ppx.current_employee_flag = 'Y '.

  AND mgx.person_id = pax.supervisor_id

  AND pp.position_id = pax.position_id

  AND pj.job_id = pax.job_id

  AND ppd.position_definition_id = pp.position_definition_id

  START WITH ppx.employee_number =: 1

  CONNECT BY PRIOR MGX.employee_number = ppx.employee_number AND LEVEL < 6

  I'm trying to get this VO implemented PR when I run the page in jdeveloper with parameter binding, it's getting error.

  oracle.apps.fnd.framework.OAException: oracle.jbo.SQLStmtException: 27122 Houston: SQL error in the preparation of the statement.

  I would like to delete the parameter binding and executing CO VO past these two statements may be:

  START WITH ppx.employee_number =: 1

  CONNECT BY PRIOR MGX.employee_number = ppx.employee_number AND LEVEL < 6

  How can I do?

  Thank you

  MK

  has worked?

• Find the parent of a child

  Hi all
  
  I have the following problem, I have a table with the following data
  
  Parent child
  101 201
  102 202
  201 301
  202 302
  301 401
  301 403
  
  Now I need to write a select query to find the top most parent of the given child, that is to say that I gave my input like 201 302 and 403 so my output should be
  
  Parent child
  101 201-> (201 is the son of 101)
  102 302-> (302 is the child of 202, 202 is the child of 102)
  101 403-> (403 is the child of 301, 301 - > 201, 201-> 101)
  
  Thanks for your help,
  REDA

  Hi, Raj,

  Welcome to the forum!

  Whenever you have any questions, post your examples of data in a form that people can use to recreate the problem and test their solutions.
  For example:

  CREATE TABLE     table_x
  (       parent     NUMBER (4)
  ,     child     NUMBER (4)     PRIMARY KEY
  );
  
  INSERT INTO table_x (parent, child) VALUES (101, 201);
  INSERT INTO table_x (parent, child) VALUES (102, 202);
  INSERT INTO table_x (parent, child) VALUES (201, 301);
  INSERT INTO table_x (parent, child) VALUES (202, 302);
  INSERT INTO table_x (parent, child) VALUES (301, 401);
  INSERT INTO table_x (parent, child) VALUES (301, 403);
  COMMIT;
  

  A WITH clause that, as Whithat posted, is also good.

  Always tell what version of Oracle you are using. This is particularly important with parent-child problems, because each version since Oracle 7 has had significant changes in this area. The following query will work in Oracle 10 (and more).

  SELECT      parent
  ,      CONNECT_BY_ROOT child     AS child
  FROM      table_x
  WHERE      CONNECT_BY_ISLEAF     = 1
  START WITH     child     IN (201, 302, 403)
  CONNECT BY     child     = PRIOR parent
  ;
  

  If you have Oracle 9, then you cannot use CONNECT_BY_ROOT, but you can get the same information from SYS_CONNECT_BY_PATH.

  The output of this product, in light of the data from the example above, is:

  `   PARENT      CHILD
  ---------- ----------
         101        201
         102        302
         101        403
  

  I guess that's what you wanted, and that the other things you posted your results (such as "---> (201 is the son of 101)"), just explained.
  The explanation is very useful, but clearly what you want really to the exit, and what is just your comments.