To get the last date of the year
Can someone tell me how to get the date of the year from the first date of last year:My query below gives the last date of the month
SELECT LAST_DAY (ADD_MONTHS (TO_DATE (JANUARY 1, 2012 "," DD/MM/YYYY '), 12-))
TO_NUMBER (to_char (sysdate, 'mm'))) OF the DOUBLE
Thnx in advance
SELECT LAST_DAY (ADD_MONTHS (TO_DATE ('01/01/2012', 'DD/MM/YYYY'), 11))
FROM DUAL
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I agree with Marcus Pivot is the way to go on this subject... But on the other hand you almost solved yourself... it was just a max function for your results:
---------
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select max(case when rownum=1 then last_day(to_date(to_char(rownum),'MM')) end) as Jan_month, max(case when rownum=2 then last_day(to_date(to_char(rownum),'MM')) end) as Feb_month, max(case when rownum=3 then last_day(to_date(to_char(rownum),'MM')) end) as mar_month, max(case when rownum=4 then last_day(to_date(to_char(rownum),'MM')) end) as apr_month, max(case when rownum=5 then last_day(to_date(to_char(rownum),'MM')) end) as may_month, max(case when rownum=6 then last_day(to_date(to_char(rownum),'MM')) end) as jun_month, max(case when rownum=7 then last_day(to_date(to_char(rownum),'MM')) end) as jul_month, max(case when rownum=8 then last_day(to_date(to_char(rownum),'MM')) end) as aug_month, max(case when rownum=9 then last_day(to_date(to_char(rownum),'MM')) end) as sep_month, max(case when rownum=10 then last_day(to_date(to_char(rownum),'MM')) end) as oct_month, max(case when rownum=11 then last_day(to_date(to_char(rownum),'MM')) end) as nov_month, max(case when rownum=12 then last_day(to_date(to_char(rownum),'MM')) end) as dec_month from dual connect by level <= 12 order by rownum;
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