Similar Questions

• How to upgrade all the record for a particular column in a table based on search criteria.

  Hi all

  I'm new to ADF. I have a requirement where I have to perform the update of mass on a table.

  Scenario:

  Ex: I have a search region manual dept. where I search with deptId: 20. I get 20 records in my table. now I have another area where I have an inputchoice list that contains all the column names that exist in the dept table. Beside that, I have a text box and a button update

  The user now, first research with dept id: 20 and click on the button Search, where it shows 20 record in the table. He then select an input choicelist(ex: ManagerId) column, then enter the new value in the decision-making box(ex: abc) then click on the button update.

  Now, I want to, all the records in the ManagerId column with dept id: 20 update with the new value 'abc '.

  Can someone help me with the code.

  Thanks in advance...

  Hello

  If you go to your VO and generate the ViewObjectImpl, here you can create a method that contains two parameters, 1 the name attribute and 2 the value.

  Then you can follow something as explained in this post:

  ADF tutorial: how to apply actions in bulk to a view object lines

  The only difference is that you must create a method like this:

  ' Public Sub updateAttribute (attribute String, Integer value) {}

  RowSetIterator iter = createRowSetIterator (null);

  While (iter.hasNext ()) {}

  Line = iter.next ();

  row.setAttribute (attribute, value);

  }

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  Then execute you who expose a customer interface and then after you filter your table according to your criteria just this method passing the correct parameters.

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• I use LRM6 with Win7.  Cannot display all of the subfolders on external drive with photos.  Can't see most recent used folders.  How can I get all the records to display in the tree when the library module?

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• Need of all invalid records

  Hi all

  Oracle version: Oracle Database 11g Express Edition Release 11.2.0.2.0 - Production

  I have following sample data:

  Examples of data

  WITH DATA AS

  (

  SELECT '100' GRP 1 January 2012 'EFFECTIVE_DATE', 30 June 2012 TERMINATION_DATE of the DOUBLE

  UNION ALL

  SELECT '100' GRP 1 JULY 2012 ' EFFECTIVE_DATE, JULY 31, 2012 "OF THE DOUBLE

  UNION ALL

  ' SELECT '100' GRP, 31 JULY 2012 ' EFFECTIVE_DATE, AUGUST 5, 2012 ' DOUBLE

  UNION ALL

  ' SELECT '100' GRP, 1 AUGUST 2012 ' EFFECTIVE_DATE, AUGUST 15, 2012 ' DOUBLE

  UNION ALL

  ' SELECT '100' FIBERGLASS, 2 AUGUST 2012 ' EFFECTIVE_DATE, AUGUST 10, 2012 ' DOUBLE

  UNION ALL

  "SELECT GRP '100', ' 01-SEP-2012' EFFECTIVE_DATE, AUGUST 2, 2012 ' DOUBLE

  UNION ALL

  "SELECT GRP '100', ' 01-SEP-2012' EFFECTIVE_DATE, AUGUST 2, 2012 ' DOUBLE

  UNION ALL

  SELECT '100' GRP 1 OCTOBER 2012, ' EFFECTIVE_DATE, NULL FROM DUAL

  )

  SELECT * FROM DATA;

  The query result

  GRP Effective_date termination_date

  100. ON 1 JANUARY 2012 30 JUNE 2012

  100 1 JULY 2012 JULY 31, 2012

  100 31 JULY 2012 AUGUST 5, 2012

  100 1 AUGUST 2012 AUGUST 15, 2012

  100 2 AUGUST 2012 AUGUST 10, 2012

  100 01 - SEP - 2012 AUGUST 2, 2012

  100 01 - SEP - 2012 AUGUST 2, 2012

  100 null October 1, 2012

  Expected results

  GRP Effective_date termination_date

  100 31 JULY 2012 AUGUST 5, 2012

  100 2 AUGUST 2012 AUGUST 10, 2012

  100 01 - SEP - 2012 AUGUST 2, 2012

  Business rules

  I have to get all invalid records according to business rules below

  -------------------------------------

  -No 1 rank and 2 records valid because that line no 2 effective date will start after the termination date of line no 1

  -line no 3 is invalid record as date of entry to start with the termination date of line no 2

  -tier 4 is valid record being entry into force or after superior to the previous termination date valid record which is the rank not 2 (July 31, 2012).

  -tier 5 is invalid record date of effect is smaller that the previous expiry date

  -tier 6 is valid record because the effective date is greater than the previous valid expiration date which is the rank not 4.

  -line No 7 is invalid record that the same data exists already, online, no 6

  -tier 8 is valid because effective date is greater than previous valid record who is ranked No. 6 date of termination.

  ---------------

  Really appreciate your assistance in this matter. Thank you

  Line

  SolomonYakobson wrote:

  Solution I posted is, I believe, "as close as this." In general, the task you has no soultion. You must choose the first line from that we begin calculation.

  Lies!

  I had a few extra cycles and need the practice with the TYPE clause. Primitive, perhaps... but achievable:

  Remember, there are other 'rules' I put in which seemed logical (ie the termination date must come after the entry into force).

  * shrug *.

  WITH DATA AS

  (

  SELECT GRP '100', TO_DATE('01-JAN-2012','dd-mon-yyyy') EFFECTIVE_DATE, TO_DATE('30-JUN-2012','dd-Mon-yyyy') TERMINATION_DATE of all the DOUBLE union

  SELECT '100' GRP, TO_DATE('01-JUL-2012','dd-mon-yyyy') EFFECTIVE_DATE, TO_DATE('31-JUL-2012','dd-Mon-yyyy') FROM DUAL Union all the

  SELECT '100' GRP, TO_DATE('31-JUL-2012','dd-mon-yyyy') EFFECTIVE_DATE, TO_DATE('05-AUG-2012','dd-Mon-yyyy') FROM DUAL Union all the

  SELECT '100' GRP, TO_DATE('01-AUG-2012','dd-mon-yyyy') EFFECTIVE_DATE, TO_DATE('15-AUG-2012','dd-Mon-yyyy') FROM DUAL Union all the

  SELECT '100' GRP, TO_DATE('02-AUG-2012','dd-mon-yyyy') EFFECTIVE_DATE, TO_DATE('10-AUG-2012','dd-Mon-yyyy') FROM DUAL Union all the

  SELECT '100' GRP, TO_DATE('01-SEP-2012','dd-mon-yyyy') EFFECTIVE_DATE, TO_DATE('02-AUG-2012','dd-Mon-yyyy') FROM DUAL Union all the

  SELECT '100' GRP, TO_DATE('01-SEP-2012','dd-mon-yyyy') EFFECTIVE_DATE, TO_DATE('02-AUG-2012','dd-Mon-yyyy') FROM DUAL Union all the

  SELECT '200' GRP, TO_DATE('01-SEP-2012','dd-mon-yyyy') EFFECTIVE_DATE, TO_DATE('02-AUG-2012','dd-Mon-yyyy') FROM DUAL Union all the

  SELECT '100' GRP, TO_DATE('01-OCT-2012','dd-mon-yyyy'), EFFECTIVE_DATE, NULL FROM DUAL

  )

  SELECT the grp, effective_date, termination_date, isvalid, pterm

  FROM THE DATA

  model

  partition (grp)

  dimension (ROW_NUMBER() over (PARTITION BY grp ORDER BY effective_date) rn)

  measures (effective_date, termination_date, "xxxxxxxx" isvalid, pterm sysdate)

  (COMMAND AUTOMATIC rules

  IsValid [1] = "VALID."

  pTerm [1] = termination_date [1],

  IsValid [rn > 1] ORDER BY rn = CASE WHEN effective_date [CV ()] > pterm [CV () - 1]

  AND effective_date [CV ()]<>

  AND effective_date [CV ()] > effective_date [CV () - 1]

  THEN "VALID," ANOTHER 'INVALID' END

  pTerm [rn > 1] ORDER BY rn = CASE WHEN isvalid [CV ()] = 'VALID' THEN termination_date [CV ()] ELSE pterm [CV () - 1] END

  )

  order of grp, effective_date

  Results:

  GRP EFFECTIVE_DATE TERMINATION_DATE ISVALID PTERM

  --- -------------- ---------------- -------- ---------

  100 1 JANUARY 12 JUNE 30, 12 VALID JUNE 30, 12

  100 1ST JULY 12 JULY 31, 12 VALID 31 JULY 12

  100 JULY 31, 12 5 AUGUST 12 INVALID 31 JULY 12

  100 1ST AUGUST 12 15 AUGUST 12 VALID 15 AUG 12

  100 2 AUGUST 12 10 AUGUST 12 INVALID 15 AUGUST 12

  100 01 - SEP - 12 AUGUST 2, 12 INVALID 15 AUGUST 12

  100 01 - SEP - 12 AUGUST 2, 12 INVALID 15 AUGUST 12

  100 1 OCTOBER 12 VALID

  01 SEP-200 12 2 AUGUST 12 VALID AUGUST 2, 12

  9 selected lines.

  I've always liked what can be done in Oracle these days, with all these funky features, tools, provisions and other

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  This one will work.

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