Trigger: easier way of passing trigger columns in line of a procedure

Hello
I am using Oracle 11g and I want to know if there is better way to transmit all columns in the row of triggerring a procedure?

Consider the following:
Table: my_table-> it is a table with 200 columns
Trigger: my_trigger-> insert after trigger on my_table
Procedure: my_proc (p_date my_table % ROWTYPE);

The conventional path might pass the values as

CREATE OR REPLACE TRIGGER my_trigger
AFTER INSERT ON my_table FOR EACH ROW
DECLARE
v_data my_table % ROWTYPE;
BEGIN
-assign variables
V_DATE. Column1: =: new.column1;
V_DATE. Column2: =: new.column2;
V_DATE. Column3: =: new.column3;
...
...
V_DATE.column200: =: new.column200;

my_proc (v_data);
END;

Is there a smarter way to do this? I know that I can generate the code above on SQL * more... .but I want the final code are small and clean.

Thank you.

Published by: Sylvie Shearer on February 25, 2010 17:11

It would have been nice if Oracle had something like what you are asking. But here's the bad news, there is no such a thing. You must mention the name of column in the OLD and the NEW individually.

Check this link asktom for any future reference.

http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:482821541531 #3384221019810

Tags: Database

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