trigger for the insert statement
Hello.I have a table, say, with 3 columns: ID, NAME, NAME_LENGTH.
I am trying to create a trigger that fires when a record is inserted in the table.
I send values for the ID and NAME columns per INSERT statement. and I need the trigger to write the LENGTH OF THE NAME INSERTED in the 3rd column
CREATE OR REPLACE TRIGGER schema_name. GENERATE_length
AFTER INSERT ON table_name
FOR EACH LINE
DECLARE
F NVARCHAR2 (200);
L NUMBER (5);
NL NUMBER (5);
NUMBER OF ID_LENGTH (5): = 5;
BEGIN
F: =:New.Name;
L: = LENGTH (F);
UPDATE HR_ORG_TREE
SET name_length = NL;
END;
but does not work. error occurres as...
ORA-04091: table schema_name.table_name is changing, the function of triggering/can not see
ORA-06512: at the 'schema_name '. GENERATE_length', line 13
ORA-04088: error during execution of trigger ' schema_name. GENERATE_length'
Thank you.
Sara
CREATE OR REPLACE TRIGGER schema_name.GENERATE_length
-- is "table_name" real name of your table?
AFTER INSERT ON table_name
FOR EACH ROW
BEGIN
-- this update will change all rows in HR_ORG_TREE table
-- specify WHERE for this update
UPDATE HR_ORG_TREE
SET name_length = LENGTH(:NEW.name);
END;
Suppose your table_name is HR_ORG_TREE and you need to calculate the length of the name for just inserted row
After maybe the code will be useful (not tested)
CREATE OR REPLACE TRIGGER schema_name.GENERATE_length
BEFORE INSERT ON HR_ORG_TREE
FOR EACH ROW
BEGIN
:new.name_length := LENGTH(:NEW.name);
END;
Good luck
Tags: Database
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Is possible to write the INSERT statement that fills two columns: 'word' and 'sense' of the file text with multiple lines - in each line is followed word that is the meaning?
Of course, it is possible. According to what the text file looks like to, you can create an external table that treats the text file as if it were a table. Otherwise, you can always read the file in PL/SQL, using the utl_file package and INSERT of PL/SQL commands.
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need help to create the insert statement
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Thank youuser11984714 wrote:
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Question related to the INSERT statement
Imagine this scenario:
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Thus, at time t2, table_a has 5 003 000 records.
My question is, at time t2, the number of records will be in table_b? Will it 5,000,000 or
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I guess it will be 5,000,000 because that is the number when the insert statement
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Any comment is appreciated.Syed Ullah says:
Imagine this scenario:-table_a has 5 000 000 records at time t1
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http://docs.Oracle.com/CD/E11882_01/server.112/e25789/consist.htm#CNCPT121
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INSERT INTO
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Thank you for your time!I came here with my own assumptions with this
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Help with the insert statement
Hello
I was wondering if someone could help write me a sql statement.
Here is my table:
Here are the instructions for correct insertion. This time, I posted 2 examples with 2 numbers different otherwise.CREATE TABLE "TEMP_INVOICE" ("INVOICE" VARCHAR2(100 BYTE), "DATE_OF_DOCUMENT" DATE, "DATE_OF_PAY_DAY" DATE, "D" NUMBER, "K" NUMBER );
I want to do is make an insert allows you to table another call is MADE:insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (1000,to_date('01.02.2012','dd.mm.yyyy'),to_date('01.03.2012','dd.mm.yyyy'),5000,0); insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (1000,to_date('01.04.2012','dd.mm.yyyy'),'','',1000); insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (1000,to_date('01.05.2012','dd.mm.yyyy'),'','',3000); insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (1000,to_date('01.06.2012','dd.mm.yyyy'),'','',1000); insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (2000,to_date('01.07.2012','dd.mm.yyyy'),to_date('01.09.2012','dd.mm.yyyy'),8000,0); insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (2000,to_date('01.10.2012','dd.mm.yyyy'),'','',5000); insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (2000,to_date('01.11.2012','dd.mm.yyyy'),'','',2000); insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (2000,to_date('01.12.2012','dd.mm.yyyy'),'','',1000);
Statements in the INVOICE table should be like this:CREATE TABLE "INVOICE" ("INVOICE" VARCHAR2(100 BYTE), "DATE_OF_DOCUMENT" DATE, "DATE_OF_PAY_DAY" DATE, "DATE_OF_PAYMENT_REC" DATE, "VALUE" NUMBER, "VALUE_DEDUCT" NUMBER, "DATE_FROM" DATE, "DATE_TO" DATE );
........ The Bill... date_of_document... date_of_pay_day... date_of_payment_rec... value... value_deduct... Date_from... Date_to
1...... 1000...............1.1.2012.................1.3.2012................NULL............................ 5000... NULL... 1.3.2012...1.4.2012
2...... 1000...............1.4.2012.................NULL..................... 1.4.2012...1000... 4000... 2.4.2012... 1.5.2012
3...... 1000...............1.5.2012.................NULL..................... 1.5.2012...3000... 1000... 2.5.2012... 1.6.2012
4...... 1000...............1.6.2012.................NULL..................... 1.6.2012...1000
Can someone help me with the sql statement that would insert data from table to table Bill temp_invoice as in the example?
Thank you!
PS
I would try to explain.
(1) the first statement that is to be inserted is original imply that at which is different DATE_OF_PAY_DAY to NULL.
To this inserted negative of the original imply, we must add date_from that is exatly the same date_of_pay_day and date_to which is exactly the same as the date of the first payment. Payment which came first!
(2) we have now in the second insert statement. It will be the first payment of lease with date_of_document and date_pf_payment_rec, which is the same as date_fo_document. Value field will be populated with the amount of payment received and value_deduct field will be the value of the original imply - value of the first payment. Date is date_of_document + 1 and date_to is the date of the next payment.
(3) Insert us the next installment. Date_od_payment_rec is the same as date_of_document... value is the amount of the second payment and value_deduct's previous value_deduct which was of 4000 - value of this second payment. date_from date_of_payment_rec + 1 and date_to is the date of the next payment
So we continue this same pattern until we reached the final payment when we finish insert with the statement:
Date of the document (date of the last payment received) and even for date_of_payment_rec and field value with the amount of the payment receieved. The rest (value_deduct, date_from, date_to) is null.
I really hope you understand what I'm trying to do here.
If you have any other questions please.
Published by: user13071990 on November 22, 2012 04:16
Published by: user13071990 on November 22, 2012 04:16Hello
user13071990 wrote:
... Here are the instructions for correct insertion. This time, I posted 2 examples with 2 numbers different otherwise.Ok!
Be sure to post the results you want new data.You probably need to add "PARTITION BY the Bill" to all analytical clauses in my solution:
INSERT INTO invoice ( invoice, date_of_document, date_of_pay_day, date_of_payment_rec , value, value_deduct, date_from, date_to ) SELECT invoice , date_of_document , date_of_pay_day , CASE WHEN k > 0 THEN date_of_document END AS date_of_payment_rec , NVL (d, k) AS value , NVL2 ( date_of_pay_day , NULL , SUM (d) OVER ( PARTITION BY invoice ORDER BY date_of_document ) - SUM (k) OVER ( PARTITION BY invoice ORDER BY date_of_document ) ) AS value_deduct , NVL ( date_of_pay_day , date_of_document + 1 ) AS date_from , LEAD (date_of_document) OVER ( PARTITION BY invoice ORDER BY date_of_document ) AS date_to FROM temp_invoice ;
Because I'm not an English speaker nativ, that I just posted what it should look like after the insert is successful.
OK, so you can't explain as you want, but you still need to explain.
... @Frank Kulash: you are very close, but still not quite what I'm looking for.
Point out where my solution is the production of incorrect results, and explain (as you can) how to get good results in these places.
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Hi all
I need to insert rows into a table, all the columns are have same value except a column that is to say
insert into table values ('a', 'b', 'b', 'b');
insert into table values ('b', 'b', 'b', 'b');
Insert in the table values ('b', 'b', 'c', 'b');
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Help, please
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Incomplete example
NSERT INTO TABLE ( COL1, COL2, COL3, COL4 ) SELECT FROM OTHERTABLE WHERE..., 'b' 'b' 'b' ...
The doc show this as an example:
INSERT INTO AIRPORTS (AIRPORT, CITY, COUNTRY) SELECT AIRPORT, CITY_NAME, COUNTRY FROM CITIES ORDER BY AIRPORT;
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value of the check box in the insert statement
I'm hand-coding an insert from the insert record sb construction will do for this application. The values of several form elements are inserted into the fields in the table. The problem that occur is a checkbox value in the form. If the box is checked, all is well and the value is 'True' inserted in the appropriate database field. However, if the checkbox is not checked I get syntax error message. The reason being that, while are passed on to the fields with null null, the checkbox is not transmitted at all. This is evident when changing the method of the form to 'Get' for testing purposes. There is no reference to this field check box in the query string.
My assumption is that this would require an If statement changing the value of the 'False' check box when the box is blocked. How I would go to this topic. With my knowledge limited to the ASP, I wrote the following, but it doesn't seem to work:
< input name = "emailprob_mor" type = "checkbox" id = "emailprob_mor" value = "< % If Not (IsNull (Request.Form ("emailprob_cus")) then Response.Write"True") Else Response.Write ("False") End If % >" >When you use the boxes, it is better to separate your Request.Form statement and your insert statement:
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UngOnly 5 bound for first INSERTION and only 1 for the next INSERTION.
This is false.
"db block ' is ALSO to the e/s logic." This is gets them in CURRENT mode. Oracle reads the Index blocks in the current mode to update the index blocks.
Your last statement is in direct contradiction with the previous paragraph
As Tom mentioned, oracle must change the index as well when records are inserted in > (or updated or deleted from) the table. This means oracle must first read the index blocks (in > compatibility mode (LIO) as well as in current mode) in addition to the blocks of the turntable when inserting new > records. So this must explain why LIOs are more when inserting in an indexed table from > inserting into a table not indexed.
What is correct.
Hemant K Collette
http://hemantoracledba.blogspot.com
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