On the insert statement
Hi allI need to insert rows into a table, all the columns are have same value except a column that is to say
insert into table values ('a', 'b', 'b', 'b');
insert into table values ('b', 'b', 'b', 'b');
Insert in the table values ('b', 'b', 'c', 'b');
y at - there no shortcut for insert because there are thousands of records to insert
Help, please
Thank you
If data are available in another table, you can use a select statement inside your insert statement.
Incomplete example
NSERT INTO TABLE (
COL1,
COL2,
COL3,
COL4
)
SELECT FROM OTHERTABLE WHERE...,
'b'
'b'
'b'
...
The doc show this as an example:
INSERT INTO AIRPORTS (AIRPORT, CITY, COUNTRY)
SELECT AIRPORT, CITY_NAME, COUNTRY FROM CITIES
ORDER BY AIRPORT;
SELECT yourvalue, 'b', 'b', 'b' of...
Best regards
mseberg
Published by: mseberg on October 6, 2012 08:31
Tags: Database
Similar Questions
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Is possible to write the INSERT statement that fills two columns: 'word' and 'sense' of the file text with multiple lines - in each line is followed word that is the meaning?
Hello
2796614 wrote:
Is possible to write the INSERT statement that fills two columns: 'word' and 'sense' of the file text with multiple lines - in each line is followed word that is the meaning?
Of course, it is possible. According to what the text file looks like to, you can create an external table that treats the text file as if it were a table. Otherwise, you can always read the file in PL/SQL, using the utl_file package and INSERT of PL/SQL commands.
You have problems whatever you wantt? If so, your zip code and explain what the problem is.
Whenever you have any questions, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the exact results you want from these data, so that people who want to help you can recreate the problem and test their ideas. In this case, also post a small sample of the text involved file.
If you ask about a DML operation, such as INSERT, then INSERT statements, you post should show what looks like the tables before the DML, and the results will be the content of the table changed after the DML.
Explain, using specific examples, how you get these results from these data.
Always say what version of Oracle you are using (for example, 11.2.0.2.0).
See the FAQ forum: Re: 2. How can I ask a question on the forums?
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Question related to the INSERT statement
Imagine this scenario:
-table_a has 5 000 000 records at time t1
-table_b is empty at time t1
-At time t1, I execute the following statement:
-L' insert statement ends in time t2insert into table_b select * from table_a;
-Between t1 and t2, say 3 000 new records have been added to the table_a (by OLTP processes).
Thus, at time t2, table_a has 5 003 000 records.
My question is, at time t2, the number of records will be in table_b? Will it 5,000,000 or
5 003 000 or somewhere between these two counts?
I guess it will be 5,000,000 because that is the number when the insert statement
has started to run.
Any comment is appreciated.Syed Ullah says:
Imagine this scenario:-table_a has 5 000 000 records at time t1
-table_b is empty at time t1
-At time t1, I execute the following statement:
insert into table_b select * from table_a;
-L' insert statement ends in time t2
-Between t1 and t2, say 3 000 new records have been added to the table_a (by OLTP processes).
Thus, at time t2, table_a has 5 003 000 records.My question is, at time t2, the number of records will be in table_b? Will it 5,000,000 or
5 003 000 or somewhere between these two counts?I guess it will be 5,000,000 because that is the number when the insert statement
has started to run.Any comment is appreciated.
At time t2, it is possible that the answer is 0. Once the insert operation finishes (can be any time after t1 in your example, possibly before t2, possibly after) and assuming you checked in the same session where you run the insert, you would see 5 000 000. In other sessions you would continue to see 0 up to what the session who made the done insert one COMMIT.
http://docs.Oracle.com/CD/E11882_01/server.112/e25789/consist.htm#CNCPT121
Is something that you should read. He described these concepts much better than what you'll probably find in a few posts on the forum.
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need help to create the insert statement
I have customer_priv of table which has 4 columns (login, privilize_id, adate, added_by)
the stmt insert like "insert into customer_priv values('JDOE',951.sysdate,admin);
I have 100 users and for each user, I need to add to the 15 privilize_id
I have the list of connections and roles, what is the best way to create a massive insert for all those users statement and
any help is very appreciated
Thank youuser11984714 wrote:
Thanks FrankI get the below now.what Miss. Also is it possible to reel in a file insert rather directly the data.am I missing values?
Sorry, I don't understand what you want.
You say you want to write something in a HOLD file instead of insert? Of course, you can do it. Change the INSERT statement in a SELECT statement and add commands to the COIL.SQL > @c:\insert_many.sql
33 old: SELECT ' & 1' priv_id, 'admin', sysdate)
33 News: SELECT sysdate, "BNELSON", "admin", priv_id)Of all_priv_id
*
ERROR on line 34:
ORA-00923: THE KEYWORD not found where expected
Thank youPublished by: user11984714 on August 9, 2010 18:40
Sorry, there was a typing error in my previous post.
Remove the ')' the end of theSELECT '&1', privilze_id, SYSDATE, 'admin')
I hope that you have more problems, but if you do, post your code, even if you think that you just copied it from this site.
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Decode in the insert statement
Hi friends,
I use an insert select with decode function as below... I get the error Ora-01722 invalid number
insert into table (name, user...) tNom
Select col1, col2,...,.
Decode (tab2. COL4, 'AF','(susbstr (tab2. COL8, 1, 5). » -'|| substr (tab2. COL8, 6))', tab2. COL8) COL8,.
....
of tname2 tab2
The two tNom. COL8 and tab2.col8 are varchar fields... Please let me know if something escapes me in the DECODE statement...
Thank you very much
>,'(susbstr (tab2
You have single quotes around your substr function calls.
-
Honestly, I really looked everywhere for this.
The problem is that, while tinkering in SQL Developer and knowing that in the spreadsheet I can just execute individual instructions by placing the cursor on the SQL statement I want to run I tried to do an INSERT query that would allow me to run an INSERT statement for... Well many inserts.
I thought I could use a brand of continuation but nothing I've tried has worked.
INSERT INTO
HF_easy_drinks
VALUES
("Blackthorn", "tonic water", 1.5, 1.0, "pineapple juice", "mix with ice").
("Blue Moon", "soda", 1.5 "Blueberry Juice",. 75, "mix with ice, strain")
;
I ended up doing just individual INSERT statements, which was not as convenient.
INSERT INTO HF_easy_drinks
VALUES ('Blackthorn', 'tonic water', 1.5, 1.0, "pineapple juice", "mix with ice");
INSERT INTO HF_easy_drinks
VALUES ('Blue Moon', 'soda', 1.5, 'Blueberry Juice',. 75, "mix with ice");
Hello
Perhaps you might prefer "an" insert like this:
INSERT INTO hf_easy_drinks (x, y, z,...)
SELECT "Blackthorn", "tonic water", 1.5, 1.0, "pineapple juice", "mix with ice" OF THE double
UNION ALL SELECT 'Blue Moon', 'soda', 1.5, 'Blueberry Juice',. 75, "mix with ice, strain ' FROM dual
SELECT UNION ALL... OF the double
SELECT UNION ALL... OF the double
;Best regards
Bruno Vroman.
-
Need help with the insert statement
Hello
I have a question on how to write a SQL statement.
This is the table of "base":
and it comes to resoult in the target table. SQL statement must take care of the insert in a base of the target table table (example below is already provided with test data).CREATE TABLE TEMP_TBL ( id_nr NUMBER, DATE_DOK DATE, DATE_DUE DATE, DATE_DOK_PAY DATE, DEB NUMBER, KRD NUMBER ); insert into temp_tbl (ID_NR,DATE_DOK,DATE_DUE,DATE_DOK_PAY,DEB,KRD)values('1',TO_DATE('11.01.2011','DD.MM.YYYY'),TO_DATE('25.02.2011','DD.MM.YYYY'),NULL,'423,24','0'); insert into temp_tbl(ID_NR,DATE_DOK,DATE_DUE,DATE_DOK_PAY,DEB,KRD)values('2',TO_DATE('16.12.2011','DD.MM.YYYY'),TO_DATE('13.06.2011','DD.MM.YYYY'),NULL,'91270,15','0'); insert into temp_tbl(ID_NR,DATE_DOK,DATE_DUE,DATE_DOK_PAY,DEB,KRD)values('3',TO_DATE('27.09.2011','DD.MM.YYYY'),TO_DATE('27.09.2011','DD.MM.YYYY'),NULL,'0','2000');
If someone could give me a helping hand how write correct insert statement I would be really gratefull.create table table_sod ( id_nr number ,date_from date ,date_to date ,deb_krd number ); One thing to note here : values in column deb_krd under insert 1 and 4 must be summarized in insert 4. insert into table_sod (id_nr,date_from,date_to,deb_krd) values('1',null,to_date('25.02.2011','dd.mm.yyyy'),'423,24'); insert into table_sod(id_nr,date_from,date_to,deb_krd) values('2',to_date('26.02.2011','dd.mm.yyyy'),to_date('13.06.2011','dd.mm.yyyy'),'423,24'); insert into table_sod(id_nr,date_from,date_to,deb_krd)values('3',null,to_date('13.06.2011','dd.mm.yyyy'),'91270,15'); insert into table_sod(id_nr,date_from,date_to,deb_krd)values('4',to_date('14.06.2011','dd.mm.yyyy')to_date('27.09.2011','dd.mm.yyyy'),'91693,39'); insert into table_sod(id_nr,date_from,date_to,deb_krd)values('5',null,to_date('27.09.2011','dd.mm.yyyy'),'2000');
Thank you for your time!I came here with my own assumptions with this
SQL> select rownum id_nr 2 , date_from 3 , date_to 4 , case when date_from is null then deb 5 else sum(case when date_from is not null then deb else 0end) over(order by id_nr, no) 6 end deb_krd 7 from ( 8 select id_nr 9 , case when lg_dt is null or ld_dt = date_due then null else lg_dt+1 end date_from 10 , ld_dt date_to 11 , case when deb = 0 then krd else deb end deb 12 , no 13 from ( 14 select t1.* 15 , lead(t1.date_due) over(order by t1.id_nr, t2.no) ld_dt 16 , lag(t1.date_due) over(order by t1.id_nr, t2.no) lg_dt 17 , t2.no 18 from temp_tbl t1 19 cross 20 join (select 1 no from dual union all select 2 no from dual) t2 21 order by id_nr, no 22 ) 23 where ld_dt is not null 24 ) 25 / ID_NR DATE_FROM DATE_TO DEB_KRD ---------- --------- --------- ---------- 1 25-FEB-11 42324 2 26-FEB-11 13-JUN-11 42324 3 13-JUN-11 9127015 4 14-JUN-11 27-SEP-11 9169339 5 27-SEP-11 2000
-
Help with the insert statement
Hello
I was wondering if someone could help write me a sql statement.
Here is my table:
Here are the instructions for correct insertion. This time, I posted 2 examples with 2 numbers different otherwise.CREATE TABLE "TEMP_INVOICE" ("INVOICE" VARCHAR2(100 BYTE), "DATE_OF_DOCUMENT" DATE, "DATE_OF_PAY_DAY" DATE, "D" NUMBER, "K" NUMBER );
I want to do is make an insert allows you to table another call is MADE:insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (1000,to_date('01.02.2012','dd.mm.yyyy'),to_date('01.03.2012','dd.mm.yyyy'),5000,0); insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (1000,to_date('01.04.2012','dd.mm.yyyy'),'','',1000); insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (1000,to_date('01.05.2012','dd.mm.yyyy'),'','',3000); insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (1000,to_date('01.06.2012','dd.mm.yyyy'),'','',1000); insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (2000,to_date('01.07.2012','dd.mm.yyyy'),to_date('01.09.2012','dd.mm.yyyy'),8000,0); insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (2000,to_date('01.10.2012','dd.mm.yyyy'),'','',5000); insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (2000,to_date('01.11.2012','dd.mm.yyyy'),'','',2000); insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k) values (2000,to_date('01.12.2012','dd.mm.yyyy'),'','',1000);
Statements in the INVOICE table should be like this:CREATE TABLE "INVOICE" ("INVOICE" VARCHAR2(100 BYTE), "DATE_OF_DOCUMENT" DATE, "DATE_OF_PAY_DAY" DATE, "DATE_OF_PAYMENT_REC" DATE, "VALUE" NUMBER, "VALUE_DEDUCT" NUMBER, "DATE_FROM" DATE, "DATE_TO" DATE );
........ The Bill... date_of_document... date_of_pay_day... date_of_payment_rec... value... value_deduct... Date_from... Date_to
1...... 1000...............1.1.2012.................1.3.2012................NULL............................ 5000... NULL... 1.3.2012...1.4.2012
2...... 1000...............1.4.2012.................NULL..................... 1.4.2012...1000... 4000... 2.4.2012... 1.5.2012
3...... 1000...............1.5.2012.................NULL..................... 1.5.2012...3000... 1000... 2.5.2012... 1.6.2012
4...... 1000...............1.6.2012.................NULL..................... 1.6.2012...1000
Can someone help me with the sql statement that would insert data from table to table Bill temp_invoice as in the example?
Thank you!
PS
I would try to explain.
(1) the first statement that is to be inserted is original imply that at which is different DATE_OF_PAY_DAY to NULL.
To this inserted negative of the original imply, we must add date_from that is exatly the same date_of_pay_day and date_to which is exactly the same as the date of the first payment. Payment which came first!
(2) we have now in the second insert statement. It will be the first payment of lease with date_of_document and date_pf_payment_rec, which is the same as date_fo_document. Value field will be populated with the amount of payment received and value_deduct field will be the value of the original imply - value of the first payment. Date is date_of_document + 1 and date_to is the date of the next payment.
(3) Insert us the next installment. Date_od_payment_rec is the same as date_of_document... value is the amount of the second payment and value_deduct's previous value_deduct which was of 4000 - value of this second payment. date_from date_of_payment_rec + 1 and date_to is the date of the next payment
So we continue this same pattern until we reached the final payment when we finish insert with the statement:
Date of the document (date of the last payment received) and even for date_of_payment_rec and field value with the amount of the payment receieved. The rest (value_deduct, date_from, date_to) is null.
I really hope you understand what I'm trying to do here.
If you have any other questions please.
Published by: user13071990 on November 22, 2012 04:16
Published by: user13071990 on November 22, 2012 04:16Hello
user13071990 wrote:
... Here are the instructions for correct insertion. This time, I posted 2 examples with 2 numbers different otherwise.Ok!
Be sure to post the results you want new data.You probably need to add "PARTITION BY the Bill" to all analytical clauses in my solution:
INSERT INTO invoice ( invoice, date_of_document, date_of_pay_day, date_of_payment_rec , value, value_deduct, date_from, date_to ) SELECT invoice , date_of_document , date_of_pay_day , CASE WHEN k > 0 THEN date_of_document END AS date_of_payment_rec , NVL (d, k) AS value , NVL2 ( date_of_pay_day , NULL , SUM (d) OVER ( PARTITION BY invoice ORDER BY date_of_document ) - SUM (k) OVER ( PARTITION BY invoice ORDER BY date_of_document ) ) AS value_deduct , NVL ( date_of_pay_day , date_of_document + 1 ) AS date_from , LEAD (date_of_document) OVER ( PARTITION BY invoice ORDER BY date_of_document ) AS date_to FROM temp_invoice ;
Because I'm not an English speaker nativ, that I just posted what it should look like after the insert is successful.
OK, so you can't explain as you want, but you still need to explain.
... @Frank Kulash: you are very close, but still not quite what I'm looking for.
Point out where my solution is the production of incorrect results, and explain (as you can) how to get good results in these places.
-
trigger for the insert statement
Hello.
I have a table, say, with 3 columns: ID, NAME, NAME_LENGTH.
I am trying to create a trigger that fires when a record is inserted in the table.
I send values for the ID and NAME columns per INSERT statement. and I need the trigger to write the LENGTH OF THE NAME INSERTED in the 3rd column
CREATE OR REPLACE TRIGGER schema_name. GENERATE_length
AFTER INSERT ON table_name
FOR EACH LINE
DECLARE
F NVARCHAR2 (200);
L NUMBER (5);
NL NUMBER (5);
NUMBER OF ID_LENGTH (5): = 5;
BEGIN
F: =:New.Name;
L: = LENGTH (F);
UPDATE HR_ORG_TREE
SET name_length = NL;
END;
but does not work. error occurres as...
ORA-04091: table schema_name.table_name is changing, the function of triggering/can not see
ORA-06512: at the 'schema_name '. GENERATE_length', line 13
ORA-04088: error during execution of trigger ' schema_name. GENERATE_length'
Thank you.
SaraCREATE OR REPLACE TRIGGER schema_name.GENERATE_length -- is "table_name" real name of your table? AFTER INSERT ON table_name FOR EACH ROW BEGIN -- this update will change all rows in HR_ORG_TREE table -- specify WHERE for this update UPDATE HR_ORG_TREE SET name_length = LENGTH(:NEW.name); END;
Suppose your table_name is HR_ORG_TREE and you need to calculate the length of the name for just inserted row
After maybe the code will be useful (not tested)CREATE OR REPLACE TRIGGER schema_name.GENERATE_length BEFORE INSERT ON HR_ORG_TREE FOR EACH ROW BEGIN :new.name_length := LENGTH(:NEW.name); END;
Good luck
-
Generate the insert statement using columns in view all_tab_cols
I am trying to generate a dynamic insert statement using the columns of a table in the all_tab_cols view. If I do a select, I get the result as lines. How to convert the row of the columns so that I get something like this:
.INSERT INTO TABLE_NAME (COL1, COL2, COL3,COL4.....)
Any help will be appreciated!This can give you a tip.
SQL> ed Wrote file afiedt.buf 1 with tab_col 2 as 3 ( 4 select i.table_name, 5 column_name, 6 row_number() over(partition by i.table_name order by table_name) rno 7 from user_tab_cols i 8 ) 9 select 'INSERT INTO '||table_name||' ('||ltrim(sys_connect_by_path(column_name, ','), ',')||') 10 from tab_col 11 where connect_by_isleaf = 1 12 start with rno = 1 13 connect by rno = prior rno+1 14 and table_name = prior table_name 15* and rownum<4 SQL> / SQL_STATEMENT -------------------------------------------------------------------------------- INSERT INTO A (MAKER,TYPE) INSERT INTO ADAM_TEST (ACCT,CODE) INSERT INTO AREA_TBL (AREA_ID,ORG_ID,CLUSTER_ID) INSERT INTO B (MAKER) INSERT INTO BONUS (ENAME) INSERT INTO CLUSTER_TBL (CLUSTER_ID) INSERT INTO COMPANY (MANUFACTURER) INSERT INTO COUNTRIES (COUNTRY_ID)
-
value of the check box in the insert statement
I'm hand-coding an insert from the insert record sb construction will do for this application. The values of several form elements are inserted into the fields in the table. The problem that occur is a checkbox value in the form. If the box is checked, all is well and the value is 'True' inserted in the appropriate database field. However, if the checkbox is not checked I get syntax error message. The reason being that, while are passed on to the fields with null null, the checkbox is not transmitted at all. This is evident when changing the method of the form to 'Get' for testing purposes. There is no reference to this field check box in the query string.
My assumption is that this would require an If statement changing the value of the 'False' check box when the box is blocked. How I would go to this topic. With my knowledge limited to the ASP, I wrote the following, but it doesn't seem to work:
< input name = "emailprob_mor" type = "checkbox" id = "emailprob_mor" value = "< % If Not (IsNull (Request.Form ("emailprob_cus")) then Response.Write"True") Else Response.Write ("False") End If % >" >When you use the boxes, it is better to separate your Request.Form statement and your insert statement:
cbVal = '0 '.
If (Request.Form ("emailprob_mor") <> "") then cbVal = Request.Form ("emailprob_mor")Then in your SQL statement:
"& cbVal &"..."
For your real HTML:
"" ) then response.write(" checked='checked' ") %>>
It is true that if the user does not check the box, then it appears as if there is no when it is submitted, that is the reason why he must be given a default value when the record is inserted.
-
How to retrieve the value from the insert statement
Hello
How can I get a certain value of the insert and store it in a variable.
Suppose that I am inserting emp_no, emp_name, emp_salary for the employee table
and I want to record the emp_name in a variable for further processing,
How can I accomplish this? I guess I should use the trigger,
but do not know the procedure.
any help will be greatly appreciated
Thank youinsert into
values (...) return
in You can and should have found that using the SQL language reference manual
or
http://www.morganslibrary.org/reference/insert.html--------
Sybrand Bakker
Senior Oracle DBA -
CASE of PL/SQL in the INSERT statement
I'm trying to insert a record into a table, change the value of the field in the insert based on a condition. To simplify the code:
It of something that I can do in SQL Server but do not understand the right Oracle syntax. Can someone help me please?DECLARE true_or_false BOOLEAN; BEGIN true_or_false := FALSE; INSERT INTO table1 (column1) VALUES (CASE WHEN true_or_false = FALSE THEN 0 ELSE -1 END); END;
If the BOOLEAN data type is allowed for the PL/SQL variable, it is not in a query.
Something like that:SQL> DECLARE 2 true_or_false BOOLEAN:= FALSE; 3 var number; 4 BEGIN 5 if true_or_false then var:=-1; else var:=0; end if; 6 INSERT INTO table1 7 (column1) 8 VALUES 9 (var); 10 END; 11 / PL/SQL procedure successfully completed. SQL> SQL> select * from table1; COLUMN1 ---------- 0
Nicolas.
-
High logical reads with the INSERT statement
Hello
I have an INSERT query that is having a very high reading statspack logical reads. I've seen go Asktom announcement that this is due to the index. Link: [http://asktom.oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:6643159615303]
Can you please help to explain exactly what Oracle do and why you should read so the e/s logic. It's the that oracle must read the structure of the index for all (bundle branch block + all blocks of sheet) for each insertion line?
Thanks & appreciate the insight.
Rgds
UngOnly 5 bound for first INSERTION and only 1 for the next INSERTION.
This is false.
"db block ' is ALSO to the e/s logic." This is gets them in CURRENT mode. Oracle reads the Index blocks in the current mode to update the index blocks.
Your last statement is in direct contradiction with the previous paragraph
As Tom mentioned, oracle must change the index as well when records are inserted in > (or updated or deleted from) the table. This means oracle must first read the index blocks (in > compatibility mode (LIO) as well as in current mode) in addition to the blocks of the turntable when inserting new > records. So this must explain why LIOs are more when inserting in an indexed table from > inserting into a table not indexed.
What is correct.
Hemant K Collette
http://hemantoracledba.blogspot.com -
Question about the use of sequence in the INSERT statement
Hello
I have a problem with inserting data into a table. I created a sequence...
and Im trying to use it to insert an incrementing ID value in a column for the newly created table. Im getting an error message regarding the sequence.CREATE SEQUENCE ag_in_target_seq INCREMENT BY 1 START WITH 1 ;
"The specified sequence (CURRVAL and NEXTVAL) number is inappropriate here in education."
I just started looking at sequences, but not sure of my logic or syntax. (little a noob). If someone could point me in the right direction it would be much appreciated. Thanks to a witness of anomaly.
INSERT INTO AGENTSINFOTARGET SELECT a.code_name, i.information_id, i.gleaned_date, t.first_name, t.last_name, l.description, ag_in_target_seq.nextval FROM agents a INNER JOIN information i ON a.agent_id=i.agent_id INNER JOIN targets t ON i.target_id=t.target_id INNER JOIN locations l on t.location_id=l.location_id ORDER BY a.code_name desc ;
remove the order by clause. Or if you really want to match the id with the name, and then apply the sequence after you ordered.
not tested
INSERT INTO AGENTSINFOTARGET select s.code_name, s.information_id, s.gleaned_date, s.first_name, s.last_name, s.description ,ag_in_target_seq.nextval from (SELECT a.code_name, i.information_id, i.gleaned_date, t.first_name, t.last_name, l.description FROM agents a JOIN information i ON a.agent_id=i.agent_id JOIN targets t ON i.target_id=t.target_id JOIN locations l on t.location_id=l.location_id ORDER BY a.code_name desc ) s ;
But without an order by clause, it would be much better.
This sequence if he lies later as a primary key, then there is no logical reason for any specific order.Published by: Sven w. on August 13, 2009 15:39
Published by: Sven w. on August 13, 2009 15:43 - readbility improved statement
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