Type of account, reports of Auditors based on expenditures and income gaps

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• Select a type of user account (for example, standard user, restricted user, and other types) on computer XP pro?

  Hello.

  I have a question about how to select the type of user account for each user account.

  I read that if I type 'control userpasswords2' term, it will bring up a window of hidden user accounts.  In this window, select a name of the user account and click property, click on membership group and it will show all the type of account you can purchase (including the standard user, restricted user, the other who has many other types)

  Here is the link I read

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  I would like to try it myself, but I don't have XP pro computer with me right now, I'd appreciate it really if someone could help me with the answer.

  Hi greenyy,

  If you are the administrator of the machine Windows XP Professional, you can use the command 'control userpasswords2' and access the list of user accounts and change the type of account.

  You need not necessarily be on a domain, however, it may not work for some types of user accounts on a working group.

  A test, you can try to change the type of account for user accounts & check if it works.

  Reference: To change the type of user account 

  Hope the helps of information. Please post back and we do know.

  Concerning
  Joel S
  Microsoft Answers Support Engineer
  Visit our Microsoft answers feedback Forum and let us know what you think.

• HFM uses by default for the types of accounts

  Hi all

  Just work on eBusiness R12 data loading in HFM and trying to understand the signaling on the types of accounts.

  In EBS, we have the following as DEFAULT:

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  I'm just working on how Auditors plug should operate as currently they are doubling instead of compensation.

  for example, we have an asset of 100 and the responsibility of-100

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  Hello. In HFM four types are generally positive. The accounts of the plug are calculated correctly according to the types.

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  ericerikson.blogspot.com

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  This

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  is equivalent to a PL/SQL expression, such as

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  Scott

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