Understand esxtop output?

Similar Questions

• Understanding the output - AC db_stat, lockers, locks and lock objects

  I would like to understand this output. 80000045 transaction holds a lock for writing on page 11 and is waiting for a lock for writing on page 13, which, however, is not granted as long as transaction 80000051 retains its read lock.
  
  Is there something in this table explaining why 80000051 doesn't seem unwilling to move and release the read lock?
  
  And what makes SD = 37 average?
  
  Michael Ludwig
  

  Locks grouped by lockers:
  Locker   Mode      Count Status  ----------------- Object ---------------
        a1 dd=37 locks held 1    write locks 0    pid/thread 1284/4896
        a1 READ          1 HELD    test.dbxml                handle        2
        a4 dd=36 locks held 0    write locks 0    pid/thread 1284/4896
        a5 dd=35 locks held 1    write locks 0    pid/thread 1284/4896
        a5 READ          1 HELD    test.dbxml                handle        4
        a8 dd=34 locks held 0    write locks 0    pid/thread 1284/4896
        a9 dd=33 locks held 1    write locks 0    pid/thread 1284/4896
        a9 READ          1 HELD    test.dbxml                handle        6
        ac dd=32 locks held 0    write locks 0    pid/thread 1284/4896
        ad dd=31 locks held 1    write locks 0    pid/thread 1284/4896
        ad READ          1 HELD    test.dbxml                handle        8
        b0 dd=30 locks held 0    write locks 0    pid/thread 1284/4896
        b1 dd=29 locks held 1    write locks 0    pid/thread 1284/4896
        b1 READ          1 HELD    test.dbxml                handle       10
        b4 dd=28 locks held 0    write locks 0    pid/thread 1284/4896
        b5 dd=27 locks held 2    write locks 0    pid/thread 1284/4896
        b5 READ          1 HELD    test.dbxml                handle       12
        b5 READ          6 HELD    test.dbxml                handle        0
        b8 dd=26 locks held 0    write locks 0    pid/thread 1284/4896
        bc dd=25 locks held 1    write locks 0    pid/thread 1284/4896
        bc READ          1 HELD    test.dbxml                handle       14
        bf dd=24 locks held 0    write locks 0    pid/thread 1284/4896
        c0 dd=23 locks held 2    write locks 0    pid/thread 1284/4896
        c0 READ          1 HELD    test.dbxml                handle       16
        c0 READ          2 HELD    test.dbxml                handle        0
        c3 dd=22 locks held 0    write locks 0    pid/thread 1284/4896
        f1 dd=21 locks held 2    write locks 0    pid/thread 1284/4896
        f1 READ          1 HELD    test.dbxml                handle       18
        f1 READ          1 HELD    test.dbxml                handle        0
        f4 dd=20 locks held 0    write locks 0    pid/thread 1284/4896
        f5 dd=19 locks held 0    write locks 0    pid/thread 1284/2648
        f6 dd=18 locks held 0    write locks 0    pid/thread 1284/2648
        f7 dd=17 locks held 0    write locks 0    pid/thread 1284/2648
        f8 dd=16 locks held 0    write locks 0    pid/thread 1284/2648
        f9 dd=15 locks held 0    write locks 0    pid/thread 1284/2648
        fa dd=14 locks held 0    write locks 0    pid/thread 1284/2648
        fb dd=13 locks held 0    write locks 0    pid/thread 1284/2648
        fc dd=12 locks held 0    write locks 0    pid/thread 1284/4184
        fd dd=11 locks held 0    write locks 0    pid/thread 1284/2672
        fe dd=10 locks held 0    write locks 0    pid/thread 1284/4184
        ff dd= 8 locks held 0    write locks 0    pid/thread 1284/2672
       100 dd= 7 locks held 0    write locks 0    pid/thread 1284/2672
       101 dd= 5 locks held 0    write locks 0    pid/thread 1284/2648
       102 dd= 4 locks held 0    write locks 0    pid/thread 1284/2648
  80000044 dd= 9 locks held 0    write locks 0    pid/thread 1284/4184
  80000045 dd= 9 locks held 1    write locks 1    pid/thread 1284/4184
  80000045 WRITE         1 WAIT    test.dbxml                page         13
  80000045 WRITE         1 HELD    test.dbxml                page         11
  8000004d dd= 6 locks held 0    write locks 0    pid/thread 1284/4100
  8000004e dd= 6 locks held 0    write locks 0    pid/thread 1284/4100
  8000004e READ          1 WAIT    test.dbxml                page         11
  80000051 dd= 3 locks held 1    write locks 0    pid/thread 1284/2648
  80000051 READ          1 HELD    test.dbxml                page         13
  80000054 dd= 2 locks held 0    write locks 0    pid/thread 1284/5816
  80000054 READ          1 WAIT    test.dbxml                page         13
  80000055 dd= 1 locks held 0    write locks 0    pid/thread 1284/4824
  80000055 READ          1 WAIT    test.dbxml                page         13
  80000056 dd= 0 locks held 0    write locks 0    pid/thread 1284/2648
  80000057 dd= 0 locks held 0    write locks 0    pid/thread 1284/2648
  80000057 READ          1 WAIT    test.dbxml                page         11
  =-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
  Locks grouped by object:
  Locker   Mode      Count Status  ----------------- Object ---------------
  80000045 WRITE         1 HELD    test.dbxml                page         11
  8000004e READ          1 WAIT    test.dbxml                page         11
  80000057 READ          1 WAIT    test.dbxml                page         11
  
        b1 READ          1 HELD    test.dbxml                handle       10
  
        ad READ          1 HELD    test.dbxml                handle        8
  
        bc READ          1 HELD    test.dbxml                handle       14
  
  80000051 READ          1 HELD    test.dbxml                page         13
  80000045 WRITE         1 WAIT    test.dbxml                page         13
  80000054 READ          1 WAIT    test.dbxml                page         13
  80000055 READ          1 WAIT    test.dbxml                page         13
  
        b5 READ          1 HELD    test.dbxml                handle       12
  
        a1 READ          1 HELD    test.dbxml                handle        2
  
        b5 READ          6 HELD    test.dbxml                handle        0
        c0 READ          2 HELD    test.dbxml                handle        0
        f1 READ          1 HELD    test.dbxml                handle        0
  
        a9 READ          1 HELD    test.dbxml                handle        6
  
        a5 READ          1 HELD    test.dbxml                handle        4
  
        f1 READ          1 HELD    test.dbxml                handle       18
  
        c0 READ          1 HELD    test.dbxml                handle       16

  The problem here is that you have multiple active transactions on a single thread. The reason that the transaction wire 80000051 2648 is not moving forward and renounce its lock is because the thread is blocked with transaction 80000057 2648 thread waiting on page 11, that 80000045 holds. When a thread has several transactions in Berkeley DB XML built detection of blockages can not say he is in a bind, because it assumes that transactions are on different threads and therefore increase.

  Lauren Foutz

• Unable to understand the output...

  Hi gurus

  I was reading a little code and unable to understand a single line, can someone guide me to understand this line.

  Code example

  Set serveroutput on

  DECLARE

  n number;

  BEGIN

  n: = 2 * 33.

  dbms_output.put_line (n);

  end;

  Result

  8589934592

  
  Now, I would like to know how the calculation performed for n: = 2 * 33 in the background so it become 8589934592 result. Thanks in advance.

  One of these curiosities PL/SQL in SQL vs. In PL/SQL * is same as it is built based on POWER. 2 * 33 is identical to POWER (2.33). It is documented in the Precedence of the operators:

  Table 2-3. precedence of operators

  Operator	Operation
  **	Exponentiation

  SY.

• output and input simultaneously

  Hello

  I create a LabVIEW application in 2012 using a DAQ USB-6341 in the series X and DAQmx 9.5.5. I'm a bit ambiguous on the issue of handling the task. Here's what I want to do:

  The LabVIEW program will automate a study that will include a series of tests.

  Each trial starts with the push of a button.

  Once the trial begins, I want to taste three analog inputs on the acquisition of data continuously.

  A specified number of seconds after the start of the trial, I want to send a signal to one of the analog output DAQ channels that will communicate with a pacemaker.

  Then the trial will end by pressing another button and the tasks will be closed.

  That's what I'm not clear on: I understand that only an Analog input or output task can communicate with an acquisition of data at a time, when I try to perform a task that is greater than 1, I get error 50103. However, it is alo I understand that all the pathways involved in a task must be of the same type IO.

  So my question is: is it possible for me to taste constantly during my tests and also a signal of output during the trial and if so, how do I configure tasks? I have attached a VI with what I have created so far. It runs only the attached party. If someone could help me understand the output, I would be very grateful.

  Thank you

  Quinn

  Hey Quinn,

  You can set a task to separate with its own clock source analog output.  On the X series devices, tasks of analog input and analog output have their own internal timing engines on which you can use.

• Out of the understanding of: ucsm-B (nxos) # sh int br

  Hi all

  Could you please help me understand the output of the following command:

  ucsm-B (nxos) # sh int br

  I have a few questions about the number of interfaces eth1/1/1 to 1/1/8 eth:

  What governs the convetion of naming used for the ethernet ports from eth1/1/1 to 9/1/eth1?

  If I connect another chassis to YEW, he will start by eth2/1/1?

  I would like to understand how Eth1/x/x or x/x/Eth2 is decided by the UCS to name...

  --------------- truncated -----------------------------------------------------------------------------------------------------

  -------------------------------------------------------------------------------

  Vsan Admin Admin Port SFP Oper Oper status interface

  Mode Trunk Channel Speed Mode

  Mode                                 (Gbps)

  -------------------------------------------------------------------------------

  vfc684 102 F trunking - auto TF-

  vfc688 102 F trunking - auto TF-

  --------------------------------------------------------------------------------

  Ethernet port VLAN Mode State reason speed Type

  Interface                                                                   Ch #

  --------------------------------------------------------------------------------

  Vntag eth eth1/1/1 1 place no 10G (D)-

  Vntag eth 1 eth1/1/2 room no 10G (D)-

  Vntag eth eth1/1/3 1 place no 10G (D)-

  Eth1/1/4 1 eth access down administratively 10G (D).

  Eth1/1/5 1 eth access down administratively 10G (D).

  Eth1/1/6 1 eth access down administratively 10G (D).

  Eth1/1/7 1 eth access down administratively 10G (D).

  Eth1/1/8 1 eth access down administratively 10G (D).

  Trunk eth 4044 eth1/1/9 up to 10G (D) none-

  Hi Vikas,

  These are interfaces of hosts (HIF) / backplane ports on the FEX / IOM linking the impeller.

  ETH.

  "view details of fex" would provide additional information on ports FEX.

  The ninth interface offers a MMIC connectivity to blades,

  HTH

  Padma

• Unable to understand the result of the loop

  
  Hi all

  I got the tracking code:

  Code

  Set serveroutput ON

  DECLARE
  TYPE IS VARRAY months_array (12) STRING (3 CHAR);
  MONTHS months_array: = months_array ('Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec');
  BEGIN
  < < list_month > >
  FOR month number IN REVERSE 6.12
  LOOP
  dbms_output.put_line (' number month = ' | number month |) "Items =' | MONTH (MONTHNO));
  CONTINUE list_month
  WHEN number month < 9;
  END LOOP;
  END;

  Code output

  number months = 12 = Dec

  number month = 11 = Nov

  number months = 10 items = Oct

  number month = 9 elements = Sep

  number month = 8 = August

  number month = 7 cells = Jul

  number months = 6 items = Jun

  My question is if you notice the code condition which is CONTINUE list_month number months WHEN < 9 means loop must be output if number month < 9 and according to code loop starting with number months = 12 so system should display the 1st line of output that is number months = 12 elements = Dec , then exit because the loop exit condition is true that is list_month MORE WHEN number month < 9. Please, help me to understand the output.

  Hi Muzz,

  try something like this

  BEGIN
    FOR monthno IN REVERSE 6..12
    LOOP
      exit when monthno < 9;
      dbms_output.put_line('monthno= '||monthno||' Elements='||MONTH(monthno));
    END LOOP;
  END;
  

  concerning

  Kay

• Output of Get-NetworkAdapter interpretation help!

  Greetings!

  I have before me, to run a script on a block of newly migrated VMs and change the VLAN they are sitting on a simple mission.

  I thought it would be easier to enter the network card and changing the NetworkName field.  However, during initial Get-NetworkAdapter test output, I don't understand the output.

  The machine virtual itself, in vSphere shows as follows:

  • A single NETWORK (e1000), sitting on Vlan63 card.

  When I take the virtual machine and it's via $vm adapter | Get-NetworkAdapter, I get the following result:

  Name                 Type       NetworkName  MacAddress         WakeOnLan
                                                                    Enabled
  ----                 ----       -----------  ----------         ---------
  Network adapter 1    e1000      VM Networ... 00:50:56:a9:03:93       True
  Network adapter 1    Flexible   VM Networ... 00:50:56:a9:04:26       True
  

  That was weird, so I have that filtered down for this bit:

  Name                                        NetworkName                                
  ----                                        -----------                                
  Network adapter 1                           VM Network Vlan62                          
  Network adapter 1                           VM Network Vlan20   
  

  No idea how to interpret this, or why it displays how... through various other filters, it shows that the Vlan20 adapter is disconnected... but again once when I'm looking at the configuration of the virtual machine in vSphere, there is just a NETWORK card and it's on Vlan63.

  Thanks in advance for any help!

  Guess you have more $vm object, can I you check?

• What is the meaning of the content under "information of Projection column (identified by the operation identity card)" in the output of dbms_xplan

  Hi Experts,

  I have a question to understand the output of the explain Plan. I'm on Oracle 11.2.0.2 on Linux. I use this command:

  Select * from table (dbms_xplan.display_cursor (null, null, 'All allstats'));

  In the output, there is a section like this:

  Projection of the column information (identified by the operation identity card):
  -----------------------------------------------------------

  2 (#keys = 1; upd = 6, 7; cmp = 1, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16; cpy = 1, 5, 6, 8) 'A1 '. "CLNT_OID" [VARCHAR2, 16], 'G2' "." " CLNT_OID "[VARCHAR2, 16]..."

  I'm not "what it means, and how this information will be used. I look at several presentations on the plan to explain it, but I don't have any explanation for this. Can someone explain what meanings, and how this information is useful?

  Thank you!

  OrauserN

  Can someone explain what meanings, and how this information is useful?

  Nothing more than general comments because does not have the validation of the application and the entire plan.

  This article shows the projections of the column used for the specific steps of the execution plan. Each step is the operation identity card which has links with the plan which would be normally shown BEFORE the one-liner you posted.

  A "projection" shows the actual columns for this stage located in the workplace. Occasionally, you will find that many more columns (and therefore data) are presented that are actually used.

  Here is an article which presents and discusses, an extreme example.

  http://alexanderanokhin.WordPress.com/2012/07/18/dont-forget-about-column-projection/

  This example compares the projections for the two versions of an application from MERGER. It's version 1

  Fusion in t1 with a t2 on (t1.id = t2.id)

  when matched, then update set n = 1;
  . . .
  Be careful on the projection of the column of steps 3, 4, 5. It contains all THE columns in the tables T1 and T2, even though the query uses only some of them.

  It is the second version of the application of the MERGER:

  Fusion in (select id, n from t1) t1 2

  using (select id, n of the t2) t2 on (t1.id = t2.id) 3

  When 4 correspondent then update the value n = 1;

  Now, projection of the column does not unnecessary, the amount of memory required and a result of temp space quantity columns contain (employee-Tmp ~ 16 MB) and i/o (2032 physical reads and 2032 physics written by direct path read temp and see direct writing temp) was significantly reduced, and the instruction was executed about 20 seconds, instead of 8 minutes.

  What article and for example, try to show is that projection section can help show how much data a plan works for a particular stage of the plan.

  This first version of MERGE seems very simple and easy to write, but as the author has pointed out, the projection indicates that all columns of the two tables were actually put in the workspace.

  The almost as simple rewrite version 2 run time reduced to 20 seconds to 8 minutes, mainly because of significantly less data handled.

• Problem control and Simulation

  I worked in the module of control and simulation of NI Labview 2013 and created a VI as indicated in the attached file, but I don't understand the output of VI.

  I applied a progressive input signal to device to transfer function = 1 /(s+1) and the desired output (exp (-t)) appears in green color (drawn by me in MSPaint) but it displays the output as one shown in red color.

  As the inverse of 1 /(s+1) Laplace = exp (-t), the graph must be a value of 0.3678 at t = 1 and 0 to t--> infinite but the (red) output is exactly opposite.

  Can someone explain please exit this is why it is like that?

  Concerning

  When you apply a step response, you must multiply your transfer function of 1/s to account for the progressive input signal before making the transformation from Laplace to get the correct result. In your case, the transformation gives: (1 - e ^ (-t))

  There are many explanations of answers online, but here's onestep.

• Cannot delete file win xp sp3

  I have two files that I can't remove.  The name is avidemux_2.5_r7200_win32.exe I d/l from cnet.com somehow, they changed their date on themselves at the 06:43 04/30/1986 on all attempts, the error message is the same: it is used by another person or program.  I realize that there is a perion in the middle of the file name.

  I can't change the name.

  I tried to remove it by using the right click, delete file and tasks folder, cmd prompt del filename and cmd prompt deltree filename.

  I tried to change the attributes with the only success beint removing hidden.

  I am able to copy the files to another directory, but the copy is undeletable also (so now I have 4 copies).

  I'm unable to move the file to another directory.

  I used regedit and delete any key with this file name (the company is the nth file).

  I restarted in safe mode and cannot be removed using the foregoing.

  There's a copy on my backup NAT and I can not remove this file from here either.  Understand an output, please.

  Well, I thought I knew about the removal of things but...  I really need some help here.

  PLEASE

  This looks like a nasty piece of malware.  No legitimate program protects himself as well...

  My next step would be to start from an operating system on a CD.  I love the free Hirens Boot CD
  Hirens: <> http://www.hirensbootcd.org/download/ >

  Download the file .zip, extract it to the hard drive, and double-click the file ".cmd" generate/create a bootable CD.  Boot your system from the CD and select the option 'Mini Windows XP'.
  Booting from CD does several things for you.  First, it ensures that none of the files on the hard disk are "used" and in the second place, malicious programs on the disk hard which can actively prevent the deletion of one such file will not present when booting from a CD.

  AprΦs the dΘmarrage, you might want to make sure that there are no attributes system or hidden on the file that you want to delete and you will find a multitude of utilities on this CD that should be able to get rid of this file for you.  In my view, there are also utilities anti-malware on this CD that you can choose to run while you're started towards him.  Let me know if it helps

  HTH,
  JW

• I for the life of me can't figure out how to get my microphone to work

  I have tried everything I can think, I tried different ports, I tried to see if maybe my helmet had a specific driver, I need to download, I checked to see if it was silent or not several times, it worked until I reformatted so I know this isn't the helmet, I just want to understand this * output so I can play games You know? any help would be appreciated

  Hi Golfwang Amadeus,

  As you have tried various possible steps to solve the problem, try to test the headphones on another computer to make sure that the device is fine.

  -Which program you want to use your microphone with?

  We will try to test with XP built in tool.  Please follow the steps below.

  a. click on 'Start ' > select ' Control Panel ' > double-click "Sounds and Audio devices".
  b. Select the tab 'voice ' > under default device which device do you see? > click on "Test Hardware"
  If you get no sound, change your default device that I mentioned above, the parameter may be wrong.
   
  For more information, see:
  To set up a microphone

• Try to update the graphics card for Hp Slimline s3707c

  Hello

  I installed a 300w power supply and a 9800gt low profile with PIN 6 connected.  My computer does not read or use it. If it is connected directly the rest monitor orange and shows no display. Is is possible to upgrade this slimline for games?

  Hi wb2001,

  Thank you for your useful tips

  I use is:http://www.newegg.com/Product/Product.aspx?Item=N82E16817338042 which has a connector 6 pin. I don't understand power outputs very well so I'm not sure about the requirements of 12V. I use a giant fan to cool my computer and it keeps the temperatures low.

  This power supply 400w would work? http://www.newegg.com/Product/Product.aspx?Item=N82E16817338081. The idea to upgrade thinness comes from this forum with those who have had good results, but honestly I don't understand half of it :http://hardforum.com/showthread.php?t=1224011

  I am on a budget and would sincerely like to experience some of the newest games out there, so I'm very grateful for your help!

• scope of traceroute to check the bulk port

  Hello

  Our client says somewhere in the internet clould of our network's color port. Most of the time, if the client's complaint, I will use the technique of telnet that indicates that the firewall does not block:

  Telnet www.webserver.com 80/source-interface fa0/0

  However, northeast of my client showed that output of its router:

  router #trace

  Protocol [ip]:

  Target IP address: 192.168.100.1

  Source address:

  Digital display [n]:

  Timeout in seconds [3]:

  Probe County [3]:

  Minimum time to live [1]:

  Maximum time to live [30]:

  Port number [33434]: 137

  In bulk, Strict, Record, Timestamp, Verbose [no]:

  Type to abort escape sequence.

  The route to 192.168.100.1

  1 202.183.1.161! A * ! A

  What makes me confuse is the default port number 33434 but it changed to 137. Does it mean it will check the particular port along the jump?

  Any documentation to understand the output this above?

  Thank you.

  Maher

  Here is a link that will help you...

  http://www.Cisco.com/univercd/CC/TD/doc/product/software/ios123/123tcr/123tfr/cfrgt_12.htm#wp1058298

  When you use with Telnet port numbers, the port is a TCP port.

  When you use numbers to port with Traceroute, the port is a UDP port.

  And yes the! A way that blocks an access list.

  Hope this helps,

  ~ ron

• Authentication by default with Peer IPSEC

  Hello world

  You have to understand the output below

  3550SMIA # sh crypto isakmp policy

  World IKE policy

  Priority protection suite 50

  encryption algorithm: AES - Advanced Encryption Standard (128-bit keys).

  hash algorithm: Secure Hash Standard

  authentication method: pre-shared Key

  Diffie-Hellman group: #2 (1024 bits)

  lifetime: 86400 seconds, no volume limit

  Default protection suite

  encryption algorithm: - Data Encryption STANDARD (56-bit keys).

  hash algorithm: Secure Hash Standard

  authentication method: Rivest-Shamir-Adleman Signature

  Diffie-Hellman group: #1 (768 bits)

  lifetime: 86400 seconds, no volume limit

  For Phase 1 authentication with counterpart that makes this device use pre-shared key or the digital signature?

  Also what is difference between Protection Suite and default pretection suite?

  Concerning

  Mahesh

  Hello Manu,

  I'll try to answer your question. To authenticate the phase 1 in a site to another, the two VPN peers exchange the ike policy started with the decrease in the number. Less than the higher number is the priority.

  In your case if the other end is an initiator and send his game of ike policy, it will match against the IKE 50 strategy. IF it does not, then it will go to the next.

  The difference between Protection suite and the default protection suite is that protection suite is your configured and default protection suite is provided with the unit.

  I hope that answers your question.

  Thank you

  Jeet Kumar

• Ask about site to site VPN

  Hi Experts,

  We gave connectivity VPN site-to-site to our customer. They report that they are not able to access the network because of VPN downwards.

  I checked on my router, it's showing to Port 4500 & down to 500.

  Below, find the exit

  crypto session #sh remote 152.69.248.225

  Current state of the session crypto

  Interface: GigabitEthernet0/0/2

  The session state: UP-ACTIVE

  Peer: 152.69.248.225 port 4500

  IKE SA: local 3.148.197.4/4500 remote 152.69.248.225/4500 Active

  FLOW IPSEC: allowed host 3.148.197.0/255.255.255.0 ip 170.69.246.2

  Active sAs: 2, origin: card crypto

  Interface: GigabitEthernet0/0/2

  The session state: down

  Peer: 152.69.248.225 port 500

  FLOW IPSEC: allowed host 3.110.96.0/255.255.255.0 ip 152.69.246.2

  Active sAs: 0, origin: card crypto

  FLOW IPSEC: allowed host 3.110.97.0/255.255.255.0 ip 152.69.246.2

  Active sAs: 0, origin: card crypto

  #sh crypto session short distance 152.69.248.225

  Status: A - Active, upward, D - Down, I - S - U - verse Standby, N - Idle, negotiation

  K - no IKE

  ivrf = (none)

  I peer / group/Phase1_id F Username availability status

  152.69.248.225 Gi0/0/2 10.130.132.34 01:14:49 AU

  Can someone help me understand the output.

  Security purpose I changed Ip addresses, so do ' t mistaken for intellectual property.

  PL suggest also any document that clears my VPN concept

  Thanks in advance

  Surya

  Hi Surya,

  Please check out the common link L2L question ex below. It may not solve your problem 100%, but could help to understand the question...

  http://www.Cisco.com/en/us/products/ps6120/products_tech_note09186a00807e0aca.shtml

  In addition, if you can postyour device and endpoint remote end device config (if possible), it helps.

  THX

  MS