Use two temporary tables to assign 'color' to the results of the data

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  I use:
  
  Oracle SQL Developer (3.0.04) build hand - 04.34 Oracle Database 11 g Enterprise Edition 11.2.0.1.0 - 64 bit Production
  
  How do we use the function sum with a structure of matter inside.
  
  so I gave that looks like have an ID, date and value. I'm looking to get the day 7 medium for the date range of 04/01/2013 to 20/04/2013
  

  with t as (
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  select 1 ID_key,to_date('4/10/2013','mm-dd-yyyy'), 6 from dual union all
  select 1 ID_key,to_date('4/12/2013','mm-dd-yyyy'), 10 from dual union all
  select 1 ID_key,to_date('4/13/2013','mm-dd-yyyy'), 0 from dual union all
  select 1 ID_key,to_date('4/14/2013','mm-dd-yyyy'), 0 from dual union all
  select 1 ID_key,to_date('4/15/2013','mm-dd-yyyy'), 10 from dual union all
  select 1 ID_key,to_date('4/16/2013','mm-dd-yyyy'), 5 from dual union all
  select 1 ID_key,to_date('4/17/2013','mm-dd-yyyy'), 2 from dual union all
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  select 2 ID_key,to_date('4/3/2013','mm-dd-yyyy'), 12 from dual union all
  select 2 ID_key,to_date('4/5/2013','mm-dd-yyyy'), 15 from dual union all
  select 2 ID_key,to_date('4/6/2013','mm-dd-yyyy'), 5 from dual union all
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  select 2 ID_key,to_date('4/17/2013','mm-dd-yyyy'), 0 from dual union all
  select 2 ID_key,to_date('4/18/2013','mm-dd-yyyy'), 10 from dual union all
  select 2 ID_key,to_date('4/19/2013','mm-dd-yyyy'), 5 from dual
  )

  * Please let me know if the table does not load.
  
  I would get the average of 7 days, as long as there is date for the rank of enough previous dates, is it not, then it returns a null value.
  
  the results should look like this

  ID_Key      date_val     Value_num     7Day_Avg     7Day_Avg2
  1     4/1/2013     10          null          null
  1     4/2/2013     15          null          null
  1     4/3/2013     20          null          null
  1     4/5/2013     0          null          null
  1     4/8/2013     12          6.71          11.75
  1     4/9/2013     8          5.71          10.00
  1     4/10/2013     6          3.71          6.50
  1     4/12/2013     10          5.14          9.00
  1     4/13/2013     0          5.14          7.20
  1     4/14/2013     0          5.14          6.00
  1     4/15/2013     10          4.86          5.67
  1     4/16/2013     5          4.42          5.17
  1     4/17/2013     2          3.85          4.50
  1     4/20/2013     3          2.86          4.00
  2     4/3/2013     12          null          null
  2     4/5/2013     15          null          null
  2     4/6/2013     5          null          null
  2     4/7/2013     7          5.57          9.75
  2     4/9/2013     10          7.00          9.80
  2     4/11/2013     5          6.00          8.40
  2     4/12/2013     0          3.86          5.40
  2     4/13/2013     0          3.14          4.40
  2     4/15/2013     6          3.00          4.20
  2     4/16/2013     8          2.71          3.80
  2     4/17/2013     0          2.71          3.17
  2     4/18/2013     10          3.43          4.00
  2     4/19/2013     5          4.14          4.83

  As you can see, there are gaps in the dates, the value is then processed by zeros for the 7Day_Avg and then ignored for the 7Day_Avg2 (not counted in the number of days on average do to no valu_num line)
  I tried something like this at first, but becomes "missing keyword" error

  select
  t.*/,
  sum(
        case 
          when date_val between :day2 - 6 and :day2
          then value_num between date_val - 6 and date_val
          else null
          end
          )
          as 7Day_avg
  
  form t

  Should I have the structure outside the sum function?
  
  Any thoughts?
  
  Published by: 1004407 on June 7, 2013 11:06

  Hello

  If you want to calculate the average of the last 7 days, including the current day, then then RANGE should be 6 PRIOR, not 7.

  Try this:

  WITH got_min_date_val AS

  (

  SELECT id_key, date_val, value_num

  MIN (date_val) compared to (AS min_date_val)

  T

  WHERE the date_val BETWEEN TO_DATE (April 1, 2013 ', "dd-mm-yyyy")

  AND TO_DATE (April 20, 2013 ', "dd-mm-yyyy")

  )

  SELECT id_key, date_val, value_num

  CASE

  WHEN date_val > = min_date_val + 6

  THEN SUM (value_num) OVER (PARTITION BY id_key

  ORDER BY date_val

  PRIOR TO TIER 6

  )

  / 7

  END AS avg_7_day

  CASE

  WHEN date_val > = min_date_val + 6

  THEN AVG (value_num) OVER (PARTITION BY id_key

  ORDER BY date_val

  PRIOR TO TIER 6

  )

  END AS avg_7_day_2

  OF got_min_date_val

  ORDER BY id_key

  date_val

  ;

  Output:

  ID_KEY DATE_VAL VALUE_NUM AVG_7_DAY AVG_7_DAY_2

  ---------- --------- ---------- ---------- ------------

  1 1 APRIL 13 10

  1 2 APRIL 13 15

  1 APRIL 3, 13 20

  1 5 APRIL 13 0

  1 APRIL 8, 13 12 6.71 11.75

  1 APRIL 9, 13 8 5.71 10.00

  1 APRIL 10 13 6 3.71 6.50

  1 12 APRIL 13 10 5.14 9,00

  1 13 APRIL 13 0 5,14 7.20

  1 14 APRIL 13 0 5,14 6.00

  1 15 APRIL 13 10 4.86 5.67

  1 16 APRIL 13 5 4.43 5.17

  1 APRIL 17, 13 2 3.86 4.50

  1 APRIL 20, 13 3 2.86 4.00

  2 APRIL 3, 13 12

  2 5 APRIL 13 15

  2 6 APRIL 13 5

  2 7 APRIL 13 7 5.57 9.75

  2 9 APRIL 13 10 7,00 9.80

  2 11 APRIL 13 5 6.00 8.40

  2 12 APRIL 13 0 3.86 5.40

  2 13 APRIL 13 0 3.14 4.40

  2 15 APRIL 13 6 3.00 4.20

  2 16 APRIL 13 8 2.71 3.80

  2 17 APRIL 13 0 2.71 3.17

  2 18 APRIL 13 10 3.43 4.00

  2 APRIL 19, 13 5 4.14 4,83

  Post edited by: FrankKulash

  Sorry; I wanted to respond to OP, not Greg

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