Value SQL lower and upper

Hello

Could someone help me with the below script SQL code.

TABLE A:

Column1

8

11

13

17

19

TABLE B:

Column 1 column 2

5                  5.2

10                6.2

15                7.2

20                8.2

Result:

column 1 column 2 (Interpolation)

8 5.2+(6.2-5.2)*(8-5)/(10-5)

11 6.2+(7.2-6.2)*(11-10)/(15-10)

13 6.2+(7.2-6.2)*(13-10)/(15-10)

17 7.2+(8.2-7.2)*(17-15)/(20-15)

19 7.2+(8.2-7.2)*(19-15)/(20-15)

Thank you

Hello

So, each value in the new colonne_1 is like a table separated; in other words, lines with colonne_1 = 360 have no effect on the results for lines that colonne_1 = 216 and vice versa.  Is this fair?

In this case, add PARTITION BY colonne_1 to all analytical clauses and include colonne_1 in the join condition in the main query, like this:

WITH got_slope AS

(

SELECT column_1, column_2, column_3

Advance (column_2) OVER ( PARTITION BY colonne_1

ORDER BY column_2) AS next_2

(The LEAD (column_3) OVER ( PARTITION BY colonne_1

ORDER BY column_2)

-column_3

) / ((Column_2) ahead OF ( PARTITION BY colonne_1 )

ORDER BY column_2

)

-column_2

)                                     AS slope

OF table_b

)

SELECT a.column_1

a.column_2

, b.column_3 + ((a.column_2-b.column_2))

* slope

) AS column_3_interpolation

FROM table_a a

JOIN got_slope b ON a.column_1 = b.column_1

AND a.column_2 > = b.column_2

AND a.column_2< >

ORDER BY a.column_1 DESC

a.column_2

;

The rest of the query, it's just that I've posted before (except for the new column names).

Tags: Database

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