Where the content of the album is recorded

Similar Questions

• Drawing from records where the number of records of unique ID > = 6

  I have a table that contains the address information for everyone in the system. It has many areas, although I have included only a few in the create table query below for brevity. The PIDM uniquely identifies each record as belonging to a person especially in the database. A person can have multiple addresses in the table, although normally, we do not allow them to have more than one active address of a particular ATYP_CODE. Yet once again, I do it here for brevity. What I have to do is to shoot all the records for each PIDM, but only when there are > = 6 records by PIDM. The user does not care if the data is rotated (I can do this part if necessary). Pulling on the actual data is not the issue. I just need a little help to find how to get only the records of PIDMs with six or more records in the table. So, according to the sample data below, records for PIDM 12345 and 34567 are those which should be in the output, but those of PIDM 23456 should not.
  

  DROP TABLE SPRADDR;
  
  CREATE TABLE SPRADDR
  (PIDM              NUMBER(8),
   ATYP_CODE     VARCHAR2(2 CHAR),
   STREETLINE1   VARCHAR2(60 CHAR),
   CITY              VARCHAR2(60 CHAR),
   STATE              VARCHAR2(2 CHAR),
   ZIP              VARCHAR2(10));
  
  INSERT INTO SPRADDR VALUES (12345,'PR','1 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (12345,'MA','1 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (12345,'BU','1 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (12345,'PR','2 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (12345,'MA','3 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (12345,'PR','4 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (23456,'PR','1 MAIN','KENT','OH','44240');
  INSERT INTO SPRADDR VALUES (23456,'MA','1 MAIN','KENT','OH','44240');
  INSERT INTO SPRADDR VALUES (23456,'BU','1 MAIN','KENT','OH','44240');
  INSERT INTO SPRADDR VALUES (34567,'PR','1 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (34567,'MA','1 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (34567,'BU','1 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (34567,'PR','2 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (34567,'MA','3 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (34567,'PR','4 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (34567,'PR','6 MAIN','CANFIELD','OH','44406');
  
  COMMIT;

  I would be very happy any help you might be able to provide. I'm sure it's easy, but I've done so far has not worked, and I'm not including the code, I've tried because it is quite fishy and not working do not at all.
  
  Thank you
  Michelle Craig
  Data Coordinator
  Admissions and transfer systems
  Kent State University

  PIDM 12345 and 34567 are those who should.

  Why 12345? It is repeated 6 times where you asked > 6. In any case:

  SQL> select  *
    2    from  (
    3           select  s.*,
    4                   count(*) over(partition by pidm) cnt
    5             from  spraddr s
    6          )
    7    where cnt > 6
    8    order by pidm
    9  /
  
        PIDM AT STREETLINE1     CITY                 ST ZIP               CNT
  ---------- -- --------------- -------------------- -- ---------- ----------
       34567 PR 1 MAIN          CANFIELD             OH 44406               7
       34567 MA 1 MAIN          CANFIELD             OH 44406               7
       34567 BU 1 MAIN          CANFIELD             OH 44406               7
       34567 PR 2 MAIN          CANFIELD             OH 44406               7
       34567 MA 3 MAIN          CANFIELD             OH 44406               7
       34567 PR 4 MAIN          CANFIELD             OH 44406               7
       34567 PR 6 MAIN          CANFIELD             OH 44406               7
  
  7 rows selected.
  
  SQL> select  *
    2    from  (
    3           select  s.*,
    4                   count(*) over(partition by pidm) cnt
    5             from  spraddr s
    6          )
    7    where cnt >= 6
    8    order by pidm
    9  /
  
        PIDM AT STREETLINE1     CITY                 ST ZIP               CNT
  ---------- -- --------------- -------------------- -- ---------- ----------
       12345 PR 1 MAIN          CANFIELD             OH 44406               6
       12345 MA 1 MAIN          CANFIELD             OH 44406               6
       12345 BU 1 MAIN          CANFIELD             OH 44406               6
       12345 PR 2 MAIN          CANFIELD             OH 44406               6
       12345 MA 3 MAIN          CANFIELD             OH 44406               6
       12345 PR 4 MAIN          CANFIELD             OH 44406               6
       34567 PR 1 MAIN          CANFIELD             OH 44406               7
       34567 MA 1 MAIN          CANFIELD             OH 44406               7
  
        PIDM AT STREETLINE1     CITY                 ST ZIP               CNT
  ---------- -- --------------- -------------------- -- ---------- ----------
       34567 BU 1 MAIN          CANFIELD             OH 44406               7
       34567 PR 2 MAIN          CANFIELD             OH 44406               7
       34567 MA 3 MAIN          CANFIELD             OH 44406               7
       34567 PR 4 MAIN          CANFIELD             OH 44406               7
       34567 PR 6 MAIN          CANFIELD             OH 44406               7
  
  13 rows selected.
  
  SQL>  
  

  SY.

  Published by: Solomon Yakobson on 10 may 2012 10:02

• Make the albums and folders sync in Photos.app

  How can I get my albums and files, I created in the Photos.app on my Macbook Pro to sync on my iMac and iPhone? I have iCloud library lit on all these devices. I made changes that have not been updated elsewhere. What am I supposed to do?

  Thank you, Nadia

  Nadia,

  If you use iCloud photo library on all devices, the albums and records are supposed to synchronize with iCloud photo library on your devices.

  See: use Photos and photo library on several Macs - Apple Support iCloud

  What changes do not synchronize between?

  Smart albums will not sync on your iPhone, not only standard albums.

  And albums faces and thumbnails will be any, synchronizes only searchable keywords.

  One of the possible reasons for the changes don't no synchronization can be, that the upload of your photo library to iCloud is not yet completed.  Are you always see a progress bar, when you look at the Photos > Preferences > iCloud on your iMac or MacBook Pro?

  Léonie

• Pictures of the cover of the album Win Media Player

  The image files associated with album covers organized in WMP (for mp3); where are those stored? The automatic system sometimes gets bad photos and I want to change the picture of the cover of the Album.

  Hi Norman,

  Thanks to join Microsoft Community where you will find all necessary information about the Windows operating systems.

  Sometimes displayed the album cover photo is incorrect, you want to know where the album art and you want to change the picture of the cover of the album.

  To work with the number of the displayed album cover photo is false, run the troubleshooter in the Windows Media Player settings.

  See the site:

  Open the troubleshooting Windows Media Player settings Troubleshooter

  http://Windows.Microsoft.com/en-in/Windows7/open-the-Windows-Media-Player-settings-Troubleshooter

  Also check out the sites mentioned;

  Where is my album art?

  http://Windows.Microsoft.com/en-in/Windows-Vista/wheres-my-album-art-fixing-song-titles-artist-names-and-more-in-Windows-Media-Player

  Add or change album art in Windows Media Player

  http://Windows.Microsoft.com/en-in/Windows7/add-or-change-album-art-in-Windows-Media-Player

  I hope this helps. If the problem persists, or if you have problems of Windows in the future, let us know and we would be happy to help you.

• Organization of the albums in categories

  How can I find an album in a subcategory with the same name as a subcategory in a different category: for example a/b/c-b/x/z, where 'z' is the album which will be located in the 'b', 'x', NOT 'b' from 'a '?

  thesunking wrote:

  How can I find an album in a subcategory with the same name as a subcategory in a different category: for example a/b/c-b/x/z, where 'z' is the album which will be located in the 'b', 'x', NOT 'b' from 'a '?

  When you try to create an album with a name already in use, you receive a warning, but you can create a duplicate. In this case, when you use the "search details" for albums, you must select the name from a drop-down list that is sorted by album name followed in the names of categories where the albums are sorted by alphabetical order. This means that you must know the name of the parent category.

  In short, it is not a good idea to create duplicate album names unless their parents are obvious. For example, you can give the name of the album 'July' in different categories by year.

• How to display the scroll bar on every page of the tab where the content from the same block of data?

  Hi gurus,

  Is it possible to display the scroll bar on each tab on Web tab page where the display of content from the same block of data?

  for example:

  Block of data elements used:

  1. employee ID

  2. first name

  3 first name

  4 date of hire

  scroll bar appears on the page 1

  5 salary

  6 commission

  scroll bar appears on page 2

  Many thanks in advance,

  Kind regards

  Ferrere

  Dear fendy_chang,

  A data block can have only 1 scroll bar. If the form is for display purpose, you can create several data bloks that points to the same table for each tab.

  Manu.

• Select only records where the column values are not all equal to zero

  Hi everyone, it seems so easy, but it has left me speechless on the research in a way that is clean, easy to achieve. I know when someone replies, I'm going to kick me. So, let's assume this is what I have:
  

  with mytable as (
  select 'Type 1' as itemtype, 'JAN' as monthname, 0 as theval from dual union all
  select 'Type 1' as itemtype, 'FEB' as monthname, 1 as theval from dual union all
  select 'Type 1' as itemtype, 'MAR' as monthname, 5 as theval from dual union all
  select 'Type 1' as itemtype, 'APR' as monthname, 1 as theval from dual union all
  select 'Type 1' as itemtype, 'MAY' as monthname, 4 as theval from dual union all
  select 'Type 1' as itemtype, 'JUL' as monthname, 0 as theval from dual union all
  select 'Type 1' as itemtype, 'AUG' as monthname, 0 as theval from dual union all
  select 'Type 1' as itemtype, 'SEP' as monthname, 1 as theval from dual union all
  select 'Type 1' as itemtype, 'OCT' as monthname, 7 as theval from dual union all
  select 'Type 1' as itemtype, 'NOV' as monthname, 1 as theval from dual union all
  select 'Type 1' as itemtype, 'DEC' as monthname, 2 as theval from dual union all
  
  select 'Type 2' as itemtype, 'JAN' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'FEB' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'MAR' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'APR' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'MAY' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'OCT' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'NOV' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'DEC' as monthname, 0 as theval from dual
  )
  select
    itemtype,
    sum (case monthname when 'JAN' then theval else 0 end) as JAN,
    sum (case monthname when 'FEB' then theval else 0 end) as FEB,
    sum (case monthname when 'MAR' then theval else 0 end) as MAR,
    sum (case monthname when 'APR' then theval else 0 end) as APR,
    sum (case monthname when 'MAY' then theval else 0 end) as MAY,
    sum (case monthname when 'JUN' then theval else 0 end) as JUN,
    sum (case monthname when 'JUL' then theval else 0 end) as JUL,
    sum (case monthname when 'AUG' then theval else 0 end) as AUG,
    sum (case monthname when 'SEP' then theval else 0 end) as SEP,
    sum (case monthname when 'OCT' then theval else 0 end) as OCT,
    sum (case monthname when 'NOV' then theval else 0 end) as NOV,
    sum (case monthname when 'DEC' then theval else 0 end) as DEC
  from mytable
  group by itemtype
  order by itemtype

  I need an external application around it or something which will select only 'Type 1'... that is, if all months are each equal to zero, do not include the record in the result set.
  
  In summary to get a total of zero is not an option, because I could have-15 and + 15 in different columns, in which case, the recording should be displayed.
  
  Something as simple as... 'not the case (oct = 0 and 0 nov and dec = 0...) at the end is all it seems to me necessary. I thought to add a case for each column clause, but that seems not very effective. Ideas?
  
  Thanks in advance!
  Mark
  
  Edit... I know not what follows will work using the MINUS operator, but my actual query is really huge, and I don't want to have to write it twice...
  {code}
  Select
  ItemType,
  sum (case monthname when "JAN" then Val else 0 end) such as JAN,.
  sum (case when monthname 'FEB', then Val 0 otherwise end) by Feb.
  sum (case when monthname 'MAR', then Val 0 otherwise end) like MARS,
  sum (case monthname when "APR" then Val else 0 end) as APR.
  sum (case when monthname 'MAY', then Val else 0 end) either.
  sum (case when monthname "JUN", then Val 0 otherwise end) as JUN.
  sum (case monthname when "JUL" then Val else 0 end) as JUL,.
  sum (case monthname when "AUG" then Val else 0 end) as AUG.
  sum (case monthname when "MS" then Val else 0 end) as MS.
  sum (case monthname when "OCTS" then Val else 0 end) OCT.
  sum (case monthname when "NOV" then Val else 0 end) as NOV.
  sum (case monthname when 'DEC' then Val else 0 end) as DEC
  FROM MyTable
  Group of itemtype
  
  less
  
  Select
  ItemType,
  Jan, Feb, mar, Apr, may, June, July, August, Sept, oct, nov, dec
  de)
  Select
  ItemType,
  sum (case monthname when "JAN" then Val else 0 end) such as JAN,.
  sum (case when monthname 'FEB', then Val 0 otherwise end) by Feb.
  sum (case when monthname 'MAR', then Val 0 otherwise end) like MARS,
  sum (case monthname when "APR" then Val else 0 end) as APR.
  sum (case when monthname 'MAY', then Val else 0 end) either.
  sum (case when monthname "JUN", then Val 0 otherwise end) as JUN.
  sum (case monthname when "JUL" then Val else 0 end) as JUL,.
  sum (case monthname when "AUG" then Val else 0 end) as AUG.
  sum (case monthname when "MS" then Val else 0 end) as MS.
  sum (case monthname when "OCTS" then Val else 0 end) OCT.
  sum (case monthname when "NOV" then Val else 0 end) as NOV.
  sum (case monthname when 'DEC' then Val else 0 end) as DEC
  FROM MyTable
  Group of itemtype
  )
  where (oct = 0 & nov = 0 and dec = 0 and jan = 0 and 0 = Feb and mar = 0
  apr = 0 and may = 0 and = 0 jun and Jul = 0 and aug = 0 and Ms = 0
  )
  order of itemtype
  {code}
  
  Change again... OK, I guess that I am answering my own question here, but I think that by using a WITH to write the main request once clause and then selecting * twice using the MINUS operator between where the second query is where (oct = 0, etc.) is what I need. If anyone has better suggestions, please let me know! Here's the logic of nickname for what I come up with to date...
  
  {code}
  WITH mainquery as (select all)
  Select * from mainquery
  less
  Select * from mainquery where (oct = 0, nov = 0, etc...)
  {code}
  
  Thanks again!
  Mark
  
  Published by: user455268 on March 1, 2012 19:13
  
  Published by: user455268 on March 1, 2012 19:16

  Hello

  You can do it with a HAVING clause:

  select
    itemtype,
    sum (case monthname when 'JAN' then theval else 0 end) as JAN,
    sum (case monthname when 'FEB' then theval else 0 end) as FEB,
    sum (case monthname when 'MAR' then theval else 0 end) as MAR,
    sum (case monthname when 'APR' then theval else 0 end) as APR,
    sum (case monthname when 'MAY' then theval else 0 end) as MAY,
    sum (case monthname when 'JUN' then theval else 0 end) as JUN,
    sum (case monthname when 'JUL' then theval else 0 end) as JUL,
    sum (case monthname when 'AUG' then theval else 0 end) as AUG,
    sum (case monthname when 'SEP' then theval else 0 end) as SEP,
    sum (case monthname when 'OCT' then theval else 0 end) as OCT,
    sum (case monthname when 'NOV' then theval else 0 end) as NOV,
    sum (case monthname when 'DEC' then theval else 0 end) as DEC
  from mytable
  group by itemtype
  HAVING      MIN (theval)     != 0
  OR      MAX (theval)     != 0
  order by itemtype
  ;
  

  If the values are all 0, then the MIN and MAX will be 0.
  If the MIN or MAX is not 0, the values are all 0.

  This assumes that the combination (itemtype, monthname) is unique, because it is in your sample data.
  If this is not the case, start with a subquery that GROUPs BY itemtype, monthname, so that when you get to the main request, this combination will be unique.

• Try to count the number of records where some columns are met

  Using SQL in Toad against an Oracle table, I'm trying to count the number of records in a table where some columns are filled. For
  example, I need to know the total number of records from a table where
  
  ln_stop_cd is not null - 65000 records
  ln_process_cd is <>- 25000 0 records
  ln_opt_cd is not null - 7500 records
  
  and the record_type = "A".
  
  I know that the total individual records as described above. However, I do not know how
  the SQL to show for record_type = 'A' the total count is 97500 records. Any help would be
  appreciated.

  Hello

  It seems that the problem is that the indictment may overlap; You can count the same rank 0, 1, 2 or 3 times, depending on whether 0, 1, 2 or 3 of these 3 independent conditions are met.

  Try something like this:

  SELECT     COUNT (in_stop_cd)
        + COUNT (CASE WHEN in_process_cd  != 0        THEN 1 END)     -- this site doesn't like the other inequality operator
        + COUNT (in_opt_cd)        AS grand_total
  FROM    table1
  WHERE     dt          >= TO_DATE ('01-JUN-2011', 'DD-MON-YYYY')
  AND     dt          <  TO_DATE ('02-JUN-2011', 'DD-MON-YYYY')
  AND     record_type       = 'A'
  ;
  

  You want to make charges without making 3 assists separated through the table. The problem is the 3 original requests had slightly different WHERE clauses.
  Put these conditions in the WHERE clause and make other conditions apply only to the individual counties, either with a column instead of *, or using a CASE statement that contains the condition that applies only to the column.

  Also, the date is not a column name good. Do not compare the DATEs to strings. If your column is really a DATE and you want to ignore the hours, the minutes and seconds, then the best way is to compare the column with 2 other DATES, as shown above. It's more coding, but it is more efficient and more reliable.

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
  You don't have to display a large amount of data. You can probably give an excellent example of this problem with only 5 or 10 rows of sample data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using.

  Published by: Frank Kulash, August 4, 2011 11:27

• I downloaded an album of classical music, but impossible to find where the downloaded digital booklet done.

  I downloaded an album of classical music to iTunes that I have synced my old iPod.  He was supposed to come with a digital booklet, but I can't find the booklet on my laptop.  Any one help me?   Thanks Mitch

  It should be in the same directory as the music of the album files if you let iTunes manage your directory structure.

• Record for invoices where the State were represented?

  12.1 EBS accounts providers, Bill Workbench, tab: 1 general group: status, field: represented. Where this field comes from?

  Depending on whether you use cash or accrual accounting, the value comes from either the cash_posted_flag or the accrual_posted_flag of ap_invoice_distribtions all.

  Rhetorically, this value is returned by AP_INVOICES_V where the value is obtained as AP_INVOICES_PKG. GET_POSTING_STATUS ()

  HTH

• printing 2 lines exaclty where the repeatative ending image showing records

  Hello
  I develop a report. It has a frame repeatative. All fields (6) are inside it.
  Now, I want to print 2 lines exactly where the ends of executives repeatative.
  Suppose that for a particular condition, there are 6 ranks, then I want to print the lines exactly after the 6th.
  Suppose that for another condition, there are 10 lines, then I want to print the lines exactly after the 10th place.
  
  Could you please tell me how I can do?
  concerning

  Asif,

  I have proposed the use of the framework of group - assuming that there are other objects in the layout editor that could get out of a place without a group frame.

  If there is no other fields/frames other than the mentioned extensible framework, then it is useless for the frame in a group.

  However, I usually try to put executives from the group around a group of objects just because as a developer you more control where to print items - if not, they could get pushed in other frames based on the data.

  Kind regards
  Vincent

• Reflections on the order of the Album

  The Sansa clip, of course, use a format that does not reflect the structure of the file. On a related note, it has its own way to identify the albums little matter where they exist in the file tree, if you put them in folders. This is not inherent to .mp3 as far as I know. Microsoft is hiding things from me?

  It is the problem of confusion that is at the heart of my curiosity. How the clip identifies the albums? Files or simple numbering does not seem to do the trick. There is no hidden files, at least not on the cranberries album.

  Types of albums found so extreme-

  Division Bell - weird codec files, album art poster, play correctly when they are simply copied. I see promise in the present, but needs further study.

  Faithful departed-parts in good condition, no record, no codecs, play correctly when they are simply copied.

  The wall - Will is not in good condition, with the same numbering. No files, no hidden files, sync ineffective. I even tried to change the order of songs with Windows Media Center, without success, but maybe I have to give them all a number...

  Codecs may be the key, but there are other forces at work here. Namely: Sync and albums that play in order with no alteration.

  Synchronization supposedly creates a playlist, but the Clip is not yet the wall out of use even when the playlist has songs in order.

  Your clip navigates and gathers his from built-in metadata info, which is part of the file called an Id3tag track. So to put this into terms that anyone can get... Your file is 5.6 MB in size, some of which is a text file that tells any computer or your player or the program file information. This is true of all files. So, when you have a song where the ablum is part of the name of the file, and you open Windows Media or on your clip, the news of the album shows as unknown this is because the tag is not setup right.

  To solve your problems of downloading a program called mp3tag. This program allows you to edit and change the tags. If you set the heap the entire clip will play right back.

• Where the Flash installed

  Hello

  As a matter of interest where the Flash is installed in IE and Firefox?

  Am I right in thinking that Flash is used to display videos?

  Thank you

  C/Windows/System32/C:\windows\system32\macromed

  C/Windows/SysWOW64/C:\windows\system32\macromed

  These are the physical records where he's going.

  It is a "plugin" for the browser (s).

  Flash is used to display video, animations, and interactive content, such as games that also require the Shockwave plugin.

  There are three plugins for Windows

  ActiveX (for IE)

  Standard (for other browsers)

  PepperFlash (for Chrome - Google incorporated)

• Loading MS Word Documents for the Conversion DB Records?

  Here's what I'm working with...
  Oracle 10.2.0.3.x (w / cd installed companion)
  Fedora Core 7
  4 processors dual-core.
  16G RAM
  
  For a long time, our intranet has accepted uploaded word files and convert to PDF and each file associated with a db record that stores the location of the file on the disk, the name of the document, the owner and a few other details. The files are generally well formatted, each containing a line for the title, entry into force, author, owner, etc.
  
  We have reached a point where the PDF conversion is not work too well. In addition, our research via a google mini system returns obsolete files or which have not yet been published. Basically, we need a better solution.
  
  What I want to do is...
  1. use oracle text scan/load/import the word files,.
  2. use oracle text to analyze the word files identifying items such as the effective date, owner.
  3 load 2 results in a table that is searchable by oracle. I can use my intranet application to convert data to word or pdf or whatever the user needs.
  
  I'm here because I have a) do not know if this is possible, exactly b) how to go about the task.
  
  I would really like tips, pointers or links to useful documentation.
  Thank you.

  If this is the case,
  Step 1 - try to download the documents by using the following code

  http://snandan.blogspot.com/2007/07/how-to-insert-PDFDoc-files-into-table.html

  The above is indicated for the pdf file, but the same can be done for MS word too.

  Step 2 - create indexes of CONTEXT using AUTO_FILTER

  Step 3 - try which precedes for couple of documents and then perform a search using the keywords as TITLE, EFFECTIVE DATE etc.
  See the precision of the results, and then you can go further.

  The other part that I can think of - can be a bit complicated - but certainly much more efficient research and storage method will be.
  Once you save the file into the BLOB column - you can try to spend some time writing a small pl/sql script to read once more and obtain the necessary information like TITLE, EFFECTIVE DATE, etc, and store in the table.

  In fact we have implemented something like this before also

  We had PDFs like that.
  We inserted these pdf files in BLOB
  and had a sql script to extract the values you want and put it in a separate - intermediate table
  and once again - a perl script to set all of these properties and content in an XML document

  Now the advantage pf putting documents was felt when we had multiple queries running against them based on the properties and the content
  We used SURLABASEDESDONNEESDUFABRICANTDUBALLAST - 11g feature

  queries like

  text contains 'Insurance' and date > «»

• Alphabetically when you play the song on the album

  When I chose to play a song on an album, the next high feature shows the songs in alphabetical order, instead of the next song in the album. This happened after I updated iTunes to the latest version. 12.5.1

  How to disable this option? It's incredibly annoying.

  Thanks in advance.

  I have a similar problem... When you say alphabetical ordered song it is for your entire library or in the album. I have a problem where he plays the next alphabetical song in my library...

  If I have:

  (a) play a song and let it run all the way, the next piece seems to be the next song in alphabetical order in my entire library regardless of the artist/album.

  (b) if I start a song playing and press the "skip" button, the next piece seems to be the next song in alphabetical order in my entire library regardless of the artist/album too.

  I turned random and stopped playing the song seems to have been fixed, as if the random parameter was reversed on is off and visa versa... Although random shouldn't be alphabetical?