Why 4 numbers show the number of images (in the line of time)?

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• Numbering of the lines based on two columns

  Hello world
  
  I´d would like to know if there is a way to achieve the numbering shown in the second table below indicating only Oracle native functions, like ROW_COUNT() on the partition, etc.
  
  I m using Oracle 10 g.
  
  The logic used is:
  From 1, increment one each time that the ORIGIN is identical to the FIRST ORIGIN of the line (ID) group.
  

  ID    ORIGIN    DESTINATION    ORDER
  ------------------------------------
  1     A         B              1
  1     B         A              2
  1     A         B              3
  1     B         C              4
  1     C         A              5
   
  ID     ORIGIN    DESTINATION    ORDER    NUMBERING
  --------------------------------------------------
  1      A         B              1        1
  1      B         A              2        1
  1      A         B              3        2
  1      B         C              4        2
  1      C         A              5        2

  In order to compare the ORIGIN of each line with the FIRST ORIGIN of the group, I used the function LAG to create a column that will be the FIRST ORIGIN of the value in the group.
  
  However, I was not able to number the lines as shown above (column NUMBERING).
  
  Any help will be much appreciated.
  
  --------------------------------------------------------------------------------------------------------------
  
  Test query:

  WITH T AS
  (
    SELECT 1 ID, 'A' ORIGIN, 'B' DESTINATION, 1 ORDERING FROM DUAL UNION ALL
    SELECT 1 ID, 'B' ORIGIN, 'A' DESTINATION, 2 ORDERING FROM DUAL UNION ALL
    SELECT 1 ID, 'A' ORIGIN, 'B' DESTINATION, 3 ORDERING FROM DUAL UNION ALL
    SELECT 1 ID, 'B' ORIGIN, 'C' DESTINATION, 4 ORDERING FROM DUAL UNION ALL
    SELECT 1 ID, 'C' ORIGIN, 'A' DESTINATION, 5 ORDERING FROM DUAL
  )
    SELECT T.ID
         , T.ORIGIN
         , T.DESTINATION
         , T.ORDERING
         , LAG (T.ORIGIN, T.ORDERING -1, 0) OVER (PARTITION BY T.ID
                                                      ORDER BY T.ID
                                                             , T.ORDERING) FIRST_ORIGIN_OF_GROUP
      FROM T
  ORDER BY T.ID
         , T.ORDERING

  Hello

  Here's one way:

  WITH     got_first_origin     AS
  (
       SELECT     id, origin, destination, ordering
       ,     FIRST_VALUE (origin) OVER ( PARTITION BY  id
                                        ORDER BY         ordering
                                   ) AS first_origin
       FROM    t
  )
  SELECT     id, origin, destination, ordering
  ,     COUNT ( CASE
                      WHEN  origin = first_origin
                THEN  1
                  END
             )     OVER ( PARTITION BY  id
                         ORDER BY      ordering
                 ) AS numbering
  FROM     got_first_origin
  ;
  

  This assumes that the combination of id and order is unique. Within an id, you place your order does not have to be consecutive integers, or something like that.

  Analytical functions cannot be nested (the argument of the function of COUNTY anlytic can not call the analytical FIRST_VALUE function); The subquery is necessary.
  You could do something with a LAG, as you have tried, rather than FIRST_VALUE, but you would still need a subquery, for the same reason.

• How to trigger the new numbering of the lines in a group?

  Suppose we have an ORDER_DETAILS table with columns (ORDER_ID, LINE_NUMBER, DESCRIPTION).

  We have these lines:

  order_id, line_number, description

  17: 1, "A".

  17.2, 'G '.

  17.3, 'R '.

  17.4, "Q".

  Next, it inserts a new line

  17.2, 'K '.

  How to trigger the renumbering?

  This should be the result after renumbering.

  17: 1, "A".

  17.2, 'K '.

  17.3, 'G '.

  17.4, 'R '.

  17.5, "Q".

  Then we move the line 5 to line 2.

  How to trigger the renumbering?

  This should be the result after renumbering.

  17: 1, "A".

  17.2, "Q".

  17.3, 'K '.

  17.4, 'G '.

  17.5, 'R '.

  This question is related to another discussion:

  https://forums.Oracle.com/thread/1088303

  create the order_details table

  (number of order_id,

  number of line_number,

  Description varchar2 (30)

  )

  rowdependencies;

  Start

  insert into values order_details (17, 1, 'A');

  insert into values order_details (17.2, 'G');

  insert into values order_details (17.3, 'R');

  insert into values order_details (17.4, 'Q');

  end;

  Select * from order_details by line_number

  ORDER_ID	LINE_NUMBER	DESCRIPTION
  17	1	A
  17	2	G
  17	3	R
  17	4	Q

  create or replace renumber procedure (number p_order_id)

  Start

  Update order_details od

  Set line_number = (select rn

  from (select rowid, RID,)

  / * for autocommit APEX active, etc. * / row_number() on rn (order of line_number, ora_rowscn desc)

  / * for autocommit = OFF favorite above row_number() (line_number order, nulls first ora_rowscn) rn * /.

  of order_details

  where order_id = p_order_id

  )

  where rid = od.rowid

  )

  where order_id = p_order_id;

  end;

  Start

  insert into values order_details (17.2, 'K');

  RENUMBER (17);

  end;

  Select * from order_details by line_number

  ORDER_ID	LINE_NUMBER	DESCRIPTION
  17	1	A
  17	2	K
  17	3	G
  17	4	R
  17	5	Q

  Start

  Update order_details

  Line_number = 2 set

  where order_id = 17

  and line_number = 5;

  RENUMBER (17);

  end;

  Select * from order_details by line_number

  ORDER_ID	LINE_NUMBER	DESCRIPTION
  17	1	A
  17	2	Q
  17	3	K
  17	4	G
  17	5	R

  Concerning

  Etbin

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  Pls see data below. I want to display only 8 lines and lines of BRH NCC should be merged and displayed as - BRH 98 2 instead of 2 rows. The rest of the lines must remain as it is. Help, please.
  
  
  NCC SERVICES MANUFACTURING
  ASL 138 NA
  BRH 98 NA
  BRH NA 2
  C10000 NA 0
  C40000 NA 0
  DAO NA 10
  E10000 NA 0
  I10000 NA 0
  M10000 NA 0
  
  Published by: auxilia on November 7th, 2009 06:25

  with t as (
             select 'ASL' ccn,'138' services,'NA' manufacturing from dual union all
             select 'BRH','98','NA' from dual union all
             select 'BRH','NA','2' from dual union all
             select 'C10000','NA','0' from dual union all
             select 'C40000','NA','0' from dual union all
             select 'DAO','NA','10' from dual union all
             select 'E10000','NA','0' from dual union all
             select 'I10000','NA','0' from dual union all
             select 'M10000','NA','0' from dual
            )
  select  ccn,
          nvl(max(case services when 'NA' then null else services end),'NA') services,
          nvl(max(case manufacturing when 'NA' then null else manufacturing end),'NA') manufacturing
    from  t
    group by ccn
  /
  
  CCN    SERVICES             MANUFACTURING
  ------ -------------------- --------------------
  E10000 NA                   0
  C10000 NA                   0
  BRH    98                   2
  M10000 NA                   0
  C40000 NA                   0
  ASL    138                  NA
  I10000 NA                   0
  DAO    NA                   10
  
  8 rows selected.
  
  SQL>   
  

  SY.

  Published by: Solomon Yakobson on November 7th, 2009 06:46

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