Why can't I now clear the history of the last days or weeks, I was doing?

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• How to get the last day of a month for every 2 months for a given period?

  Hello

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  END as lastweekday,

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  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'MY

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  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• How to get the last day of the week?

  HII
  
  I can get the week number of calendar for a given date using
  
  SELECT to_char (to_date('04/04/2011','MM/DD/YYYY'), 'WW') FROM dual
  
  can any body tell me, how to get the last day of the week?
  
  and the answer should be: 04/08/2011(8th april)
  Thank you
  San
  
  Published by: sandeep9 on April 4, 2011 03:50

  Perhaps this...

  SQL> select trunc(sysdate,'WW')+6 from dual;
  
  TRUNC(SYSDATE,'WW')+
  --------------------
  08-APR-2011 00:00:00
  
  SQL>
  

• use to insert the last day of each month

  Hi, I wrote this code but it did not insert the 20 December and it is January 1, and next time running is 31 January... I would like to work to make this insert every last day of each month...
  

  begin
    sys.dbms_job.submit(job => :job,
                        what => 'INSERT INTO hisrtu 
                                          SELECT rtunum, linked, dbchkd, chaqty, dbvald, ctrltr, meaadj, qtyrtu, month, year, entity, rtunam 
                                          FROM qtyrtu;',
                        next_date => to_date('31-10-2010 01:00:03', 'dd-mm-yyyy hh24:mi:ss'),
                        interval => 'SYSDATE +30');
    commit;
  end;
  /

  I don't know if it's because I assigned the date 31-10... In November it's just but December has not...
  
  Best regards, hope you can help me.
  
  I use oracle 9i

  Hello

  If you want the job to run at 02:00 the last day of the next month, then the desired argument is:

  interval => 'ADD_MONTHS (TRUNC (SYSDATE, ''MONTH''), 2) - (22 / 24)'
  

  In other words, if she finishes running at 02:30 on 31 January, then
  TRUNC (SYSDATE, 'MONTH') will be at 00:00:00 January 1
  ADD_MONTHS (TRUNC (SYSDATE, 'MONTH'), 1) will be March 1st at 00:00:00
  ADD_MONTHS (TRUNC (SYSDATE, 'MONTH'), - 1) (22 / 24) will be 22 hours earlier, i.e. 02:00 on the last day of February.

  logandro wrote:
  I don't know if it's because I assigned the date 31-10... In November it's just but December has not...

  Do you mean this line?

  next_date-online to_date (October 31, 2010 01:00:03 ',' dd-mm-yyyy hh24:mi:ss'),

  I don't think that's a problem. The next_date specifies only when it work baptisms. I guess he ran on October 31; you said it was running well on 30 November, 30 days after that. Something has to happen after November 30.

  Note that the interval argument is relative when the task completes. If a task takes 30 minutes to run, then

  interval => 'SYSDATE +30'
  

  means that, if it turns to
  01:00:03 October 31, then it will run again about
  01:30:03 November 30, around
  02:00:03 on December 30.
  02:30:03 January 29 and so on. If your business does that for a few seconds, it won't matter much.

  If you decide to use LAST_DAY, don't forget not that the hours-minutes-seconds referring LAST_DAY are the same as those of his argument.

• How to get the last day of the year

  Hi all
  
  Thanks in advance...
  
  How do I get the last day of the year that I'm passing date at run time.
  
  I can manage to get the first day of the year by
  SELECT TRUNC(SYSDATE,'YEAR') AS FDAY_YEAR
  of the double
  
  Thanks in advance
  
  Concerning
  Sachin

    1*  select ADD_MONTHS(trunc(sysdate,'yyyy'),12)-1 dd from dual
  SQL> /
  
  DD
  -----------
  31-DEC-2010