Why the iPad Mini 4 costs the same as the iPad 2 air?

Similar Questions

• Why my ipad loses the wifi connection when I abandon my modem wireless of Qwest

  Why my ipad loses the wifi connection when I abandon my modem wireless of Qwest

  WiFi connections are losing their strength increases the distance between the router and so as a general rule, there are some conflicting objects

  Try the following steps please

  The following actions and after each test to see if the issue is resolved - if yes, then you can omit the following steps - I tried to list them in ascending order of the effort at least on a Mac and / or an iDevice

  1. Check if the problem is related to a single device and if other devices connect normally-
  2. If the answer 1 is 'yes' - try to connect the device assigned to somewhere else if possible - coffee or the University
  3. Perform a forced - restart cela do not delete or purge all data and allows to solve many problems - here is how - press and hold the Off / On Home button and at the same time for about 15-20 seconds, until the Apple logo appears. Allow normal startup upward.
  4. Settings - WiFi - < network name > - Click on forget network - do a restart forced according to 3 and then add again the network
  5. If home - reboot the router by unplugging it for 60 seconds (power) and the plug and reconnect - obviously, this step can be done in a public place like a cafe or airport or University. While you're there - make sure your router is working on the latest firmware (check manufacturer's website)
  6. Settings - general - reset - Reset network settings - remember to have very practical WiFi passwords because it erases the WiFi passwords
  7. If it is a new specific net device in your home - make sure that the router gives enough DNS for all numbers which must / wants a connection - stuff like the printer, Chromecast get overlooked - ask for more details on this so not sure option
  8. Backup the device to iTunes - restore as NEW (no) - see if solves problem - if yes - restore backup
  9. An appointment of 'Genius' to an Apple Store, or select another authorized service provider.

• Why the optimizer ignores Index Fast full Scan when much lower cost?

  Summary (tracking details below) - to improve the performance of a query on more than one table, I created an index on a table that included all the columns referenced in the query. With the new index in place the optimizer is still choosing a full Table Scan on an Index fast full scan. However, by removing the one query tables I reach the point where the optimizer suddenly use the Index Fast Full Scan on this table. And 'Yes', it's a lot cheaper than the full Table Scan it used before. By getting a test case, I was able to get the motion down to 4 tables with the optimizer still ignoring the index and table of 3, it will use the index.
  
  So why the optimizer not chooses the Index Fast Full Scan, if it is obvious that it is so much cheaper than a full Table Scan? And why the deletion of a table changes how the optimizer - I don't think that there is a problem with the number of join permutations (see below). The application is so simple that I can do, while remaining true to the original SQL application, and it still shows this reversal in the choice of access path. I can run the queries one after another, and he always uses a full Table Scan for the original query and Index fast full scan for the query that is modified with a table less.
  
  Watching trace 10053 output for the two motions, I can see that for the original query 4 table costs alone way of ACCESS of TABLE UNIQUE section a full Table Scan. But for the modified query with a table less, the table now has a cost for an Index fast full scan also. And the end of the join cost 10053 does not end with a message about exceeding the maximum number of permutations. So why the optimizer does not cost the IFFS for the first query, when it does for the second, nearly identical query?
  
  This is potentially a problem to do with OUTER joins, but why? The joins between the tables do not change when the single extra table is deleted.
  
  It's on 10.2.0.5 on Linux (Oracle Enterprise Linux). I did not define special settings I know. I see the same behavior on 10.2.0.4 32-bit on Windows (XP).
  
  Thank you
  John
  Blog of database Performance
  
  DETAILS
  I've reproduced the entire scenario via SQL scripts to create and populate the tables against which I can then run the queries. I've deliberately padded table so that the length of the average line of data generated is similar to that of the actual data. In this way the statistics should be similar on the number of blocks and so forth.
  
  System - uname - a

  Linux mysystem.localdomain 2.6.32-300.25.1.el5uek #1 SMP Tue May 15 19:55:52 EDT 2012 i686 i686 i386 GNU/Linux

  Database - v$ version

  Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - Prod
  PL/SQL Release 10.2.0.5.0 - Production
  CORE    10.2.0.5.0      Production
  TNS for Linux: Version 10.2.0.5.0 - Production
  NLSRTL Version 10.2.0.5.0 - Production

  Original query (complete table below details):

  SELECT 
      episode.episode_id , episode.cross_ref_id , episode.date_required , 
      product.number_required , 
      request.site_id 
  FROM episode 
  LEFT JOIN REQUEST on episode.cross_ref_id = request.cross_ref_id 
       JOIN product ON episode.episode_id = product.episode_id 
  LEFT JOIN product_sub_type ON product.prod_sub_type_id = product_sub_type.prod_sub_type_id 
  WHERE (
          episode.department_id = 2
      and product.status = 'I'
        ) 
  ORDER BY episode.date_required
  ;

  Execution of display_cursor after the execution plan:

  SQL_ID  5ckbvabcmqzw7, child number 0
  -------------------------------------
  SELECT     episode.episode_id , episode.cross_ref_id , episode.date_required ,
  product.number_required ,     request.site_id FROM episode LEFT JOIN REQUEST on
  episode.cross_ref_id = request.cross_ref_id      JOIN product ON episode.episode_id =
  product.episode_id LEFT JOIN product_sub_type ON product.prod_sub_type_id =
  product_sub_type.prod_sub_type_id WHERE (         episode.department_id = 2 and
  product.status = 'I'       ) ORDER BY episode.date_required
  
  Plan hash value: 3976293091
  
  -----------------------------------------------------------------------------------------------------
  | Id  | Operation             | Name                | Rows  | Bytes |TempSpc| Cost (%CPU)| Time     |
  -----------------------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT      |                     |       |       |       | 35357 (100)|          |
  |   1 |  SORT ORDER BY        |                     | 33333 |  1920K|  2232K| 35357   (1)| 00:07:05 |
  |   2 |   NESTED LOOPS OUTER  |                     | 33333 |  1920K|       | 34879   (1)| 00:06:59 |
  |*  3 |    HASH JOIN OUTER    |                     | 33333 |  1822K|  1728K| 34878   (1)| 00:06:59 |
  |*  4 |     HASH JOIN         |                     | 33333 |  1334K|       |   894   (1)| 00:00:11 |
  |*  5 |      TABLE ACCESS FULL| PRODUCT             | 33333 |   423K|       |   103   (1)| 00:00:02 |
  |*  6 |      TABLE ACCESS FULL| EPISODE             |   299K|  8198K|       |   788   (1)| 00:00:10 |
  |   7 |     TABLE ACCESS FULL | REQUEST             |  3989K|    57M|       | 28772   (1)| 00:05:46 |
  |*  8 |    INDEX UNIQUE SCAN  | PK_PRODUCT_SUB_TYPE |     1 |     3 |       |  0   (0)|          |
  -----------------------------------------------------------------------------------------------------
  
  Predicate Information (identified by operation id):
  ---------------------------------------------------
     3 - access("EPISODE"."CROSS_REF_ID"="REQUEST"."CROSS_REF_ID")
     4 - access("EPISODE"."EPISODE_ID"="PRODUCT"."EPISODE_ID")
     5 - filter("PRODUCT"."STATUS"='I')
     6 - filter("EPISODE"."DEPARTMENT_ID"=2)
     8 - access("PRODUCT"."PROD_SUB_TYPE_ID"="PRODUCT_SUB_TYPE"."PROD_SUB_TYPE_ID")

  Updated the Query:

  SELECT 
      episode.episode_id , episode.cross_ref_id , episode.date_required , 
      product.number_required , 
      request.site_id 
  FROM episode 
  LEFT JOIN REQUEST on episode.cross_ref_id = request.cross_ref_id 
       JOIN product ON episode.episode_id = product.episode_id 
  WHERE (
          episode.department_id = 2
      and product.status = 'I'
        ) 
  ORDER BY episode.date_required
  ;

  Execution of display_cursor after the execution plan:

  SQL_ID  gbs74rgupupxz, child number 0
  -------------------------------------
  SELECT     episode.episode_id , episode.cross_ref_id , episode.date_required ,
  product.number_required ,     request.site_id FROM episode LEFT JOIN REQUEST on
  episode.cross_ref_id = request.cross_ref_id      JOIN product ON episode.episode_id =
  product.episode_id WHERE (         episode.department_id = 2     and product.status =
  'I'       ) ORDER BY episode.date_required
  
  Plan hash value: 4250628916
  
  ----------------------------------------------------------------------------------------------
  | Id  | Operation              | Name        | Rows  | Bytes |TempSpc| Cost (%CPU)| Time     |
  ----------------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT       |             |       |       |       | 10515 (100)|          |
  |   1 |  SORT ORDER BY         |             | 33333 |  1725K|  2112K| 10515   (1)| 00:02:07 |
  |*  2 |   HASH JOIN OUTER      |             | 33333 |  1725K|  1632K| 10077   (1)| 00:02:01 |
  |*  3 |    HASH JOIN           |             | 33333 |  1236K|       |   894   (1)| 00:00:11 |
  |*  4 |     TABLE ACCESS FULL  | PRODUCT     | 33333 |   325K|       |   103   (1)| 00:00:02 |
  |*  5 |     TABLE ACCESS FULL  | EPISODE     |   299K|  8198K|       |   788   (1)| 00:00:10 |
  |   6 |    INDEX FAST FULL SCAN| IX4_REQUEST |  3989K|    57M|       |  3976   (1)| 00:00:48 |
  ----------------------------------------------------------------------------------------------
  
  Predicate Information (identified by operation id):
  ---------------------------------------------------
     2 - access("EPISODE"."CROSS_REF_ID"="REQUEST"."CROSS_REF_ID")
     3 - access("EPISODE"."EPISODE_ID"="PRODUCT"."EPISODE_ID")
     4 - filter("PRODUCT"."STATUS"='I')
     5 - filter("EPISODE"."DEPARTMENT_ID"=2)

  Creating the table and Population:
  1 create tables
  2. load data
  3 create indexes
  4. collection of statistics
  

  --
  -- Main table
  --
  create table episode (
  episode_id number (*,0),
  department_id number (*,0),
  date_required date,
  cross_ref_id varchar2 (11),
  padding varchar2 (80),
  constraint pk_episode primary key (episode_id)
  ) ;
  --
  -- Product tables
  --
  create table product_type (
  prod_type_id number (*,0),
  code varchar2 (10),
  binary_field number (*,0),
  padding varchar2 (80),
  constraint pk_product_type primary key (prod_type_id)
  ) ;
  --
  create table product_sub_type (
  prod_sub_type_id number (*,0),
  sub_type_name varchar2 (20),
  units varchar2 (20),
  padding varchar2 (80),
  constraint pk_product_sub_type primary key (prod_sub_type_id)
  ) ;
  --
  create table product (
  product_id number (*,0),
  prod_type_id number (*,0),
  prod_sub_type_id number (*,0),
  episode_id number (*,0),
  status varchar2 (1),
  number_required number (*,0),
  padding varchar2 (80),
  constraint pk_product primary key (product_id),
  constraint nn_product_episode check (episode_id is not null) 
  ) ;
  alter table product add constraint fk_product 
  foreign key (episode_id) references episode (episode_id) ;
  alter table product add constraint fk_product_type 
  foreign key (prod_type_id) references product_type (prod_type_id) ;
  alter table product add constraint fk_prod_sub_type
  foreign key (prod_sub_type_id) references product_sub_type (prod_sub_type_id) ;
  --
  -- Requests
  --
  create table request (
  request_id number (*,0),
  department_id number (*,0),
  site_id number (*,0),
  cross_ref_id varchar2 (11),
  padding varchar2 (80),
  padding2 varchar2 (80),
  constraint pk_request primary key (request_id),
  constraint nn_request_department check (department_id is not null),
  constraint nn_request_site_id check (site_id is not null)
  ) ;
  --
  -- Activity & Users
  --
  create table activity (
  activity_id number (*,0),
  user_id number (*,0),
  episode_id number (*,0),
  request_id number (*,0), -- always NULL!
  padding varchar2 (80),
  constraint pk_activity primary key (activity_id)
  ) ;
  alter table activity add constraint fk_activity_episode
  foreign key (episode_id) references episode (episode_id) ;
  alter table activity add constraint fk_activity_request
  foreign key (request_id) references request (request_id) ;
  --
  create table app_users (
  user_id number (*,0),
  user_name varchar2 (20),
  start_date date,
  padding varchar2 (80),
  constraint pk_users primary key (user_id)
  ) ;
  
  prompt Loading episode ...
  --
  insert into episode
  with generator as 
  (select rownum r
            from (select rownum r from dual connect by rownum <= 1000) a,
                 (select rownum r from dual connect by rownum <= 1000) b,
                 (select rownum r from dual connect by rownum <= 1000) c
           where rownum <= 1000000
         ) 
  select r, 2,
      sysdate + mod (r, 14),
      to_char (r, '0000000000'),
      'ABCDEFGHIJKLMNOPQRSTUVWXYZ' || to_char (r, '000000')
    from generator g
  where g.r <= 300000
  /
  commit ;
  --
  prompt Loading product_type ...
  --
  insert into product_type
  with generator as 
  (select rownum r
            from (select rownum r from dual connect by rownum <= 1000) a,
                 (select rownum r from dual connect by rownum <= 1000) b,
                 (select rownum r from dual connect by rownum <= 1000) c
           where rownum <= 1000000
         ) 
  select r, 
         to_char (r, '000000000'),
         mod (r, 2),
         'ABCDEFGHIJKLMNOPQRST' || to_char (r, '000000')
    from generator g
  where g.r <= 12
  /
  commit ;
  --
  prompt Loading product_sub_type ...
  --
  insert into product_sub_type
  with generator as 
  (select rownum r
            from (select rownum r from dual connect by rownum <= 1000) a,
                 (select rownum r from dual connect by rownum <= 1000) b,
                 (select rownum r from dual connect by rownum <= 1000) c
           where rownum <= 1000000
         ) 
  select r, 
         to_char (r, '000000'),
         to_char (mod (r, 3), '000000'),
         'ABCDE' || to_char (r, '000000')
    from generator g
  where g.r <= 15
  /
  commit ;
  --
  prompt Loading product ...
  --
  -- product_id prod_type_id prod_sub_type_id episode_id padding 
  insert into product
  with generator as 
  (select rownum r
            from (select rownum r from dual connect by rownum <= 1000) a,
                 (select rownum r from dual connect by rownum <= 1000) b,
                 (select rownum r from dual connect by rownum <= 1000) c
           where rownum <= 1000000
         ) 
  select r, mod (r, 12) + 1, mod (r, 15) + 1, mod (r, 300000) + 1,
         decode (mod (r, 3), 0, 'I', 1, 'C', 2, 'X', 'U'),
         dbms_random.value (1, 100), NULL
    from generator g
  where g.r <= 100000
  /
  commit ;
  --
  prompt Loading request ...
  --
  -- request_id department_id site_id cross_ref_id varchar2 (11) padding 
  insert into request
  with generator as 
  (select rownum r
            from (select rownum r from dual connect by rownum <= 1000) a,
                 (select rownum r from dual connect by rownum <= 1000) b,
                 (select rownum r from dual connect by rownum <= 1000) c
           where rownum <= 10000000
         ) 
  select r, mod (r, 4) + 1, 1, to_char (r, '0000000000'),
  'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz01234567890123456789' || to_char (r, '000000'),
  'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789012345678' || to_char (r, '000000')
    from generator g
  where g.r <= 4000000
  /
  commit ;
  --
  prompt Loading activity ...
  --
  -- activity activity_id user_id episode_id request_id (NULL) padding 
  insert into activity
  with generator as 
  (select rownum r
            from (select rownum r from dual connect by rownum <= 1000) a,
                 (select rownum r from dual connect by rownum <= 1000) b,
                 (select rownum r from dual connect by rownum <= 1000) c
           where rownum <= 10000000
         ) 
  select r, mod (r, 50) + 1, mod (r, 300000) + 1, NULL, NULL
    from generator g
  where g.r <= 100000
  /
  commit ;
  --
  prompt Loading app_users ...
  --
  -- app_users user_id user_name start_date padding 
  insert into app_users
  with generator as 
  (select rownum r
            from (select rownum r from dual connect by rownum <= 1000) a,
                 (select rownum r from dual connect by rownum <= 1000) b,
                 (select rownum r from dual connect by rownum <= 1000) c
           where rownum <= 10000000
         ) 
  select r, 
         'User_' || to_char (r, '000000'),
         sysdate - mod (r, 30),
         'ABCDEFGHIJKLMNOPQRSTUVWXYZ' || to_char (r, '000000')
    from generator g
  where g.r <= 1000
  /
  commit ;
  --
  
  prompt Episode (1)
  create index ix1_episode_cross_ref on episode (cross_ref_id) ;
  --
  prompt Product (2)
  create index ix1_product_episode on product (episode_id) ;
  create index ix2_product_type on product (prod_type_id) ;
  --
  prompt Request (4)
  create index ix1_request_site on request (site_id) ;
  create index ix2_request_dept on request (department_id) ;
  create index ix3_request_cross_ref on request (cross_ref_id) ;
  -- The extra index on the referenced columns!!
  create index ix4_request on request (cross_ref_id, site_id) ;
  --
  prompt Activity (2)
  create index ix1_activity_episode on activity (episode_id) ;
  create index ix2_activity_request on activity (request_id) ;
  --
  prompt Users (1)
  create unique index ix1_users_name on app_users (user_name) ;
  --
  prompt Gather statistics on schema ...
  --
  exec dbms_stats.gather_schema_stats ('JB')

  10053 sections - original query

  ***************************************
  SINGLE TABLE ACCESS PATH
    -----------------------------------------
    BEGIN Single Table Cardinality Estimation
    -----------------------------------------
    Table: REQUEST  Alias: REQUEST
      Card: Original: 3994236  Rounded: 3994236  Computed: 3994236.00  Non Adjusted: 3994236.00
    -----------------------------------------
    END   Single Table Cardinality Estimation
    -----------------------------------------
    Access Path: TableScan
      Cost:  28806.24  Resp: 28806.24  Degree: 0
        Cost_io: 28738.00  Cost_cpu: 1594402830
        Resp_io: 28738.00  Resp_cpu: 1594402830
  ******** Begin index join costing ********
    ****** trying bitmap/domain indexes ******
    Access Path: index (FullScan)
      Index: PK_REQUEST
      resc_io: 7865.00  resc_cpu: 855378926
      ix_sel: 1  ix_sel_with_filters: 1
      Cost: 7901.61  Resp: 7901.61  Degree: 0
    Access Path: index (FullScan)
      Index: PK_REQUEST
      resc_io: 7865.00  resc_cpu: 855378926
      ix_sel: 1  ix_sel_with_filters: 1
      Cost: 7901.61  Resp: 7901.61  Degree: 0
    ****** finished trying bitmap/domain indexes ******
  ******** End index join costing ********
    Best:: AccessPath: TableScan
           Cost: 28806.24  Degree: 1  Resp: 28806.24  Card: 3994236.00  Bytes: 0
  ***************************************

  10053 - updated the Query

  ***************************************
  SINGLE TABLE ACCESS PATH
    -----------------------------------------
    BEGIN Single Table Cardinality Estimation
    -----------------------------------------
    Table: REQUEST  Alias: REQUEST
      Card: Original: 3994236  Rounded: 3994236  Computed: 3994236.00  Non Adjusted: 3994236.00
    -----------------------------------------
    END   Single Table Cardinality Estimation
    -----------------------------------------
    Access Path: TableScan
      Cost:  28806.24  Resp: 28806.24  Degree: 0
        Cost_io: 28738.00  Cost_cpu: 1594402830
        Resp_io: 28738.00  Resp_cpu: 1594402830
    Access Path: index (index (FFS))
      Index: IX4_REQUEST
      resc_io: 3927.00  resc_cpu: 583211030
      ix_sel: 0.0000e+00  ix_sel_with_filters: 1
    Access Path: index (FFS)
      Cost:  3951.96  Resp: 3951.96  Degree: 1
        Cost_io: 3927.00  Cost_cpu: 583211030
        Resp_io: 3927.00  Resp_cpu: 583211030
    Access Path: index (FullScan)
      Index: IX4_REQUEST
      resc_io: 14495.00  resc_cpu: 903225273
      ix_sel: 1  ix_sel_with_filters: 1
      Cost: 14533.66  Resp: 14533.66  Degree: 1
  ******** Begin index join costing ********
    ****** trying bitmap/domain indexes ******
    Access Path: index (FullScan)
      Index: IX4_REQUEST
      resc_io: 14495.00  resc_cpu: 903225273
      ix_sel: 1  ix_sel_with_filters: 1
      Cost: 14533.66  Resp: 14533.66  Degree: 0
    Access Path: index (FullScan)
      Index: IX4_REQUEST
      resc_io: 14495.00  resc_cpu: 903225273
      ix_sel: 1  ix_sel_with_filters: 1
      Cost: 14533.66  Resp: 14533.66  Degree: 0
    ****** finished trying bitmap/domain indexes ******
  ******** End index join costing ********
    Best:: AccessPath: IndexFFS  Index: IX4_REQUEST
           Cost: 3951.96  Degree: 1  Resp: 3951.96  Card: 3994236.00  Bytes: 0
  ***************************************

  I mentioned that it is a bug related to the ANSI SQL standard and transformation probably.

  As suggested/asked in my first reply:
  1. If you use a no_query_transformation then you should find that you get the use of the index (although not in the plan you would expect)
  2. If you use the traditional Oracle syntax, then you should not have the same problem.

• IPad 3 no comparable with iOS 10. Then why the App Store keep sending updates?

  I understand that the iPAD 3 will not accept iOS 10. Why the APPLE APP STORE continue to try to push updates of my apps?

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  DDoes anyone know why the Pro is not compatible with Amazon prime? I can get the first one on my iPad two old as well as my partners air2.

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• Why the temperature shows on my watch always different temperature on the watch of my husband when they use the same application?

  Why the temperature still showing on my watch shows a different temperature than on my husband watch when they both use the same weather app?

  Hi Jodie

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• Why is my update for the iPad 2 Air Watch software ios 9.2.1 is the latest version of ios while apple launches 9.3 yesterday?

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• Why the last OS update cost me gigabytes of data when you are connected directly to my computer and ISP via Itunes February 29, 2016

  Why the last OS update cost me gigabytes of data when you are connected directly to my computer and ISP via Itunes.  29 February 2016

  While it is connected to ITunes via my Dell system, I was informed of the latest OS update for my IPhone 6.  I decided that the direct connection to the internet would be the fastest way to download and install the software.  During the process I started to have some warning of our AT & T account that I approach the limit of our data plan, then in quick succession, only warnings, said I've reached the limit and then passed in the data, limit charges.  At the time it was done, I had accumulated more than 2 gigabytes of additional data charges.

  Until that point, I was very pleased with the device and confident in the ability to use Wifi and data.  Due to this incident, I became very suspicious of the camera and the huge potential for data overcharges. It is extremely disconcerting as it happened while it is directly connected to the internet using my computer at home.

  Please note that, in the episode my ISP and the computer is remained connected to the WEB with no sign of connectivity issues.

  Someone at - he had a similar experience and understand what went wrong?

  Thanks for your support,

  Jerry

  JerrolK wrote:

  Why the last OS update cost me gigabytes of data when you are connected directly to my computer and ISP via Itunes.  29 February 2016

  While it is connected to ITunes via my Dell system, I was informed of the latest OS update for my IPhone 6.  I decided that the direct connection to the internet would be the fastest way to download and install the software.

  You have chosen the option of direct download, you have received a message of warning from AT & T about it yet.

  He did what you asked it to do.

• Why the same photo's file size different in Photos and in the Finder?

  I have a photo size 4608 x 3456. When I open the file information in the Apple's Photos app, it says that the file is 7.8 MB. When I open the same photo in the Finder and look at the news file, it is said that it is 3.1 MB on the disk. Why does this happen? All other metadata is the same in the pictures, Finder, Lightroom or Photoshop, but I can't understand why the file size seems to have changed since I dragged photo pictures to the Finder.

  Thank you.

  How you view the photo in the finder (you shouldn't be messing around inside the photo library)?

  If you export or drag / drop you create a new file with a different compression - using export allows you to control what

  LN

• Why the Info screen called my back camera air ipad 2

  Why the Info screen name my back camera air ipad 2?

  You have two cameras - the front and rear camera - this information window that you have pursued photography

  LN

• When I updated the shock of the clans for my daughter on his iPad, it has its own apple ID. and iCloud, my ID apple came on his id for the update, where it has its own apple ID now. Please can someone tell me why the update came not through its id.

  When I updated the shock of the clans for my daughter on his iPad, it has its own apple ID. and iCloud, my ID apple came on his id for the update, where it has its own apple ID now. Please can someone tell me why the update came not through its ID thanks

  It seems that if the application has been downloaded on his iPad while it is connected to your Apple ID. If so, he'll always want to be updated with your Apple ID.

  You must remove the application from his iPad and then download it again while it is connected to its own code of Apple.

• What Canon app will connect my iPad on a new Canon PIXMA MG2920 printer and why my iPad seek only an AirPrinter but couldn't find the gun?

  The title of MY topic is the summary.

  Your printer without wire - but unfortunately is not able Airprint. That's why your ipad do not.  There is a Canon print app available that can help you - its called PPS - then take a look in the app store.

• "Why the 2 screws are not same speed?

  HI comrades LabVIEW in love.

  Could someone let me know why the 2 screws attached do not run at the same speed I expect?

  Thanks in advance.

  Bryan

  Inside the event, value is only designed for the value of signalling events on the time-out, i.e. every 100 ms.

  Outside of the event is happening at the same time, so he writes to each iteration of the loop, and the timeout never occurs.

• Why the upgrade to removed 12.1.0.2 fix listener security COST

  Hoping someone can explain to me why the database upgrade from 11g to 12 c (with the help of the program DBUA) removed my earphone COST security settings.    The plan is to add the security COST return patch.  I do not understand why it changed the value of "LOCAL_LISTENER" init.ora at 'LISTENER_SID' remove my fixed COST value.  He also added a corresponding 'LISTENER_SID' entry in the tnsnames file.

  Thank you for taking my question!  Kathie

  > > > BEFORE the upgrade:

  SID_LIST_LISTENER =

  (SID_LIST = (SID_DESC = (SID_NAME = CLRExtProc) ))

  (ORACLE_HOME = E:\oracle\product\11.2.0\db_4) (PROGRAM = extproc)

  (ENVS = "EXTPROC_DLLS=ONLY:E:\oracle\product\11.2.0\db_4\bin\oraclr11.dll")

      )    )

  LISTENER = (DESCRIPTION_LIST = (DESCRIPTION =(ADDRESS = (PROTOCOL = TCP)(HOST =xxxxxxxx.db.xxx.local) (PORT = 1521)) ))

  (ADDRESS = (PROTOCOL = IPC)(KEY = XXREGISTER))     )  )

  ADR_BASE_LISTENER = E:\oracle

  SECURE_REGISTER_LISTENER = (CPI)

  > > > AFTER the UPGRADE

  SID_LIST_LISTENER = (SID_LIST =(SID_DESC =(SID_NAME = CLRExtProc) ))

  (ORACLE_HOME = E:\oracle\product\12.1.0\db_2) (PROGRAM = extproc)

  (ENVS = "EXTPROC_DLLS=ONLY:E:\oracle\product\12.1.0\db_2\bin\oraclr12.dll")

      )  )

  LISTENER = (DESCRIPTION_LIST = (DESCRIPTION = (ADDRESS = (PROTOCOL = TCP) (HOST = XXXXXX.db.xxx.local)(PORT= 1521)) ))

  (ADDRESS = (PROTOCOL = IPC)(KEY =EXTPROC1521)) ) )

  If you read the referenced note in Doc ID 1453883.1, i.e.

  Valid node checking registration (VNCR) (Doc ID 1600630.1)

  It is said

  Without correct configuration a listener (default) 12 c will not save their instances of database of remote servers.

  This COST should not be necessary more. In addition, if you read the original review of VECS (CVE-2012-1675), 12 c is not listed as an affected version:

  Products and Versions

  Oracle Database 11 g Release 2, versions 11.2.0.2, 11.2.0.3, 11.2.0.4

  Oracle Database 11 g Release 1, version 11.1.0.7

  Oracle Database 10 g Release 2, versions 10.2.0.3, 10.2.0.4, 10.2.0.5

  Kind regards

  Bob

• I have synced my LR my android mobile. Why the images in a different order from the catalogue on the PC and how can I get them in the same order?

  I have synced my LR my android mobile. Why the images in a different order from the catalogue on the PC and how can I get them in the same order?

  You can check the order of Lightroom Mobile synchronization.

  Click on the collection name and choose the last option to sort.

  It should be similar to this screenshot:

  

  Once you get to know Lightroom Mobile images sort order, you can set the same sort order on your desktop of Lightroom.